ĐỀ và đáp án THI đại học khoi a 2002 2013

) !"#$% &'( * ThS LU HUNH V N LONG (0986.616.225) (Gi ng viờn Tr ng H Th D u M t Bỡnh Dng) KH I A, A1 (TON Lí HểA ANH) NM H C: 2002-2013 ! " LU HNH N I B 11/2013 giáo dục đào tạo Kỳ thi tuyển sinh đại học, cao ĐẳnG năm 2002 -Môn thi : toán Đề thức (Thời gian làm bài: 180 phút) _ Câu I (ĐH : 2,5 điểm; CĐ : 3,0 điểm) Cho hàm số : y = x + 3mx + 3(1 m ) x + m m (1) ( m tham số) Khảo sát biến thiên vẽ đồ thị hàm số (1) m = Tìm k để phơng trình: x + x + k 3k = có ba nghiệm phân biệt Viết phơng trình đờng thẳng qua hai điểm cực trị đồ thị hàm số (1) Câu II.(ĐH : 1,5 điểm; CĐ: 2,0 điểm) log 32 x + log 32 x + 2m = Cho phơng trình : (2) ( m tham số) m = Giải phơng trình (2) Tìm m để phơng trình (2) có nghiệm thuộc đoạn [ ; 3 ] Câu III (ĐH : 2,0 điểm; CĐ : 2,0 điểm ) cos 3x + sin 3x Tìm nghiệm thuộc khoảng (0 ; ) phơng trình: sin x + = cos x + + sin x Tính diện tích hình phẳng giới hạn đờng: y =| x x + | , y = x + Câu IV.( ĐH : 2,0 điểm; CĐ : 3,0 điểm) Cho hình chóp tam giác S ABC đỉnh S , có độ dài cạnh đáy a Gọi M N lần lợt trung điểm cạnh SB SC Tính theo a diện tích tam giác AMN , biết mặt phẳng ( AMN ) vuông góc với mặt phẳng ( SBC ) Trong không gian với hệ toạ độ Đêcac vuông góc Oxyz cho hai đờng thẳng: x = 1+ t x 2y + z = : y = + t : x + y 2z + = z = + 2t a) Viết phơng trình mặt phẳng ( P) chứa đờng thẳng song song với đờng thẳng b) Cho điểm M (2;1;4) Tìm toạ độ điểm H thuộc đờng thẳng cho đoạn thẳng MH có độ dài nhỏ Câu V.( ĐH : 2,0 điểm) Trong mặt phẳng với hệ toạ độ Đêcac vuông góc Oxy , xét tam giác ABC vuông A , phơng trình đờng thẳng BC x y = 0, đỉnh A B thuộc trục hoành bán kính đờng tròn nội tiếp Tìm tọa độ trọng tâm G tam giác ABC Cho khai triển nhị thức: n n n n x x x x x x x x 2 + = C n0 2 + C n1 2 + L + C nn 2 + C nn ( n số nguyên dơng) Biết khai triển C n = 5C n số hạng thứ t 20n , tìm n x Hết Ghi chú: 1) Thí sinh thi cao đẳng không làm Câu V n 2) Cán coi thi không giải thích thêm Họ tên thí sinh: Số báo danh: giáo dục đào tạo - Kỳ thi tuyển sinh đại học, cao đẳng năm 2002 Đáp án thang điểm môn toán khối A ĐH m = y = x + 3x x = y' = x2 = Tập xác định x R y ' = x + x = x( x 2) , y" = x + = 0, CĐ 1,0 đ 1,5 đ 0,25 đ 0,5đ 0,5 đ 0,5 đ 0,25 đ 0,5 đ y" = x = Bảng biến thiên x y' + + lõm U CT CĐ lồi x = y=0 , x = Đồ thị: + + y" y y (1) = y -1 x ( Thí sinh lập bảng biến thiên) Ta có x + x + k 3k = x + x = k + 3k Đặt a = k + 3k Dựa vào đồ thị ta thấy phơng trình x + x = a có nghiệm phân biệt < a < < k + 3k < < k < 0k Cách II Ta có x + x + k 3k = ( x k ) x + (k 3) x + k 3k ] = có nghiệm phân biệt f ( x) = x + (k 3) x + k 3k = có nghiệm phân biệt khác k = 3k + 6k + > < k < 2 k k k + k 3k + k 3k [ 0,5 đ 0,5 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25đ 0,25 đ 0,25 đ 0,25 đ 1,0 đ 1,0 đ x = m y' = x2 = m + Ta thấy x1 x y ' đổi dấu qua x1 x hàm số đạt cực trị x1 x y1 = y ( x1 ) = m + 3m y = y ( x ) = m + 3m + Phơng trình đờng thẳng qua điểm cực trị M m 1; m + 3m M m + 1; m + 3m + là: 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ x m + y + m 3m + = y = 2x m2 + m ' y = 3x + 6mx + 3(1 m ) = 3( x m) + , Ta thấy 2 ' = 9m + 9(1 m ) = > y ' = có nghiệm x1 x y ' đổi dấu qua x1 x hàm số đạt cực trị x1 x Ta có y = x + 3mx + 3(1 m ) x + m m m = x x + 6mx + 3m + x m + m 3 Từ ta có y1 = x1 m + m y = x m + m Vậy phơng trình đờng thẳng qua điểm cực trị y = x m + m 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,5 đ 1,0 đ 0,25 đ 0,5 đ y ' = 3x + 6mx + 3(1 m ) = 3( x m) + , ( ) ( ) ( ) Với m = ta có log x + log x + = 3 Điều kiện x > Đặt t = log 32 x + ta có t 1+ t = t + t = t = t2 = 2 t1 = (loại) , t = log 32 x = log x = x = 0,25 đ 0,5 đ x = thỏa mãn điều kiện x > (Thí sinh giải trực tiếp đặt ẩn phụ kiểu khác) 1,0 đ 1,0 đ log x + log x + 2m = 3 Điều kiện x > Đặt t = log 32 x + ta có t + t m = t + t 2m = 0,25 đ 0,25 đ 0,25 đ 0,25 đ x [1,3 ] log x t = log 32 x + Vậy (2) có nghiệm [1,3 ] (3) có nghiệm [ 1,2 ] Đặt f (t ) = t + t Hàm số f (t ) hàm tăng đoạn [1; 2] Ta có f (1) = f (2) = Phơng trình t + t = 2m + f (t ) = 2m + có nghiệm [1;2] m + f (1) 2m + m m + f (2) 2m + TH1 Phơng trình (3) có nghiệm t1 ,t thỏa mãn < t1 t < t +t Do = < nên không tồn m 2 TH2 Phơng trình (3) có nghiệm t1 ,t thỏa mãn t1 t t1 t 2m(4 2m ) m 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ (Thí sinh dùng đồ thị, đạo hàm đặt ẩn phụ kiểu khác ) cos x + sin x sin x + = cos x + Điều kiện sin x + sin x cos x + sin 3x sin x + sin x sin x + cos x + sin x Ta có sin x + = + sin x + sin x (2 sin x + 1) cos x sin x + cos x cos x + cos x + sin 3x =5 = cos x =5 + sin x + sin x Vậy ta có: cos x = cos x + cos x cos x + = cos x = (loại) cos x = x = + 2k (k Z ) 3 1,0 đ 1,0 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ x = Ta thấy x1 , x thỏa mãn điều 3 kiện sin x Vậy nghiệm cần tìm là: x1 = x = 3 (Thí sinh sử dụng phép biến đổi khác) Vì x (0 ; ) nên lấy x1 = y 0,25 đ 0,25 đ 1,0 đ 1,0 đ -1 -1 x Ta thấy phơng trình | x x + |= x + có nghiệm x1 = x = Mặt khác | x x + | x + x [0;5] Vậy ( ) ( ) ( 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25đ 0,25đ 1đ 1đ ) S = x + | x x + | dx = x + x + x dx + x + + x x + dx 0 ( ) + x + x + x dx ( ) ( ) ( ) S = x + x dx + x x + dx + x + x dx 1 3 5 S = x3 + x + x3 x + 6x + x3 + x 2 13 26 22 109 S= + + = (đ.v.d.t) 3 (Nếu thí sinh vẽ hình không thiết phải nêu bất đẳng thức | x x + | x + x [0;5] ) S N I M A C 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ 0,25 đ K B Gọi K trung điểm BC I = SK MN Từ giả thiết a MN = BC = , MN // BC I trung điểm SK MN 2 Ta có SAB = SAC hai trung tuyến tơng ứng AM = AN AMN cân A AIMN (SBC )( AMN ) (SBC ) ( AMN ) = MN AI(SBC ) AISK Mặt khác AI ( AMN ) AIMN Suy SAK cân A SA = AK = a 3a a a SK = SB BK = = 4 2 2 SK AI = SA SI = SA = Ta có S AMN 3a a a 10 = a 10 = MN AI = (đvdt) 16 ý 1) Có thể chứng minh AIMN nh sau: BC(SAK ) MN(SAK ) MNAI 2) Có thể làm theo phơng pháp tọa độ: Chẳng hạn chọn hệ tọa độ Đêcac vuông góc Oxyz cho a a a a ;0 , S 0; K (0;0;0), B ;0;0 , C ;0;0 , A 0; ;h 2 h độ dài đờng cao SH hình chóp S ABC 2a) Phơng trình mặt phẳng (P) chứa đờng thẳng có dạng: (x y + z 4) + (x + y z + 4) = ( + ) ( + )x (2 ) y + ( )z + = r r Vậy n P = ( + ;2 + ; ) Ta có u = (1;1;2 ) // M (1;2;1) r r n P u = = (P ) // Vậy (P ) : x z = M (1;2;1) (P ) M (P ) 0,5 đ 1,0 đ 0,25 đ 0,5 đ 0,25 đ 0,5 đ 0,25 đ 0,5 đ 0,25 đ 0,5 đ 0,5 đ 1,0 đ 0,25 đ 0,5 đ 0,25 đ 0,5 đ 0,25 đ 0,25 đ 0,5 đ 0,5 đ Ta chuyển phơng trình sang dạng tham số nh sau: x = 2t ' Từ phơng trình suy x z = Đặt x = 2t ' : y = 3t '2 z = 4t ' r M (0;2;0) , u1 = (2;3;4) // (Ta tìm tọa độ điểm M cách cho x = y = z = Cách II r 1 1 = (2;3;4) ) tính u1 = ; ; 2 2 r Ta có u = (1;1;2 ) // Từ ta có véc tơ pháp mặt phẳng (P) : r r r n P = [u1 , u ] = (2;0;1) Vậy phơng trình mặt phẳng (P) qua M (0;2;0 ) r n P = (2;0;1) là: x z = Mặt khác M (1;2;1) (P ) phơng trình mặt phẳng cần tìm là: x z = b) H H (1 + t ,2 + t ,1 + 2t ) MH = (t 1; t + 1;2t 3) MH = (t 1) + (t + 1) + (2t 3) = 6t 12t + 11 = 6(t 1) + đạt giá trị nhỏ t = H (2;3;3) Cách II H H (1 + t ;2 + t ;1 + 2t ) r MH nhỏ MH MH u = t = H (2;3;4) 2 2 Ta có BC I Ox = B(1;0 ) Đặt x A = a ta có A(a; o) ( 1đ ) xC = a y C = 3a Vậy C a; 3a 2a + (a 1) xG = ( x A + x B + x C ) ; ta có G Từ công thức yG = ( y A + y B + yC ) Ta có : AB =| a |, AC = | a |, BC = | a | Do 0,25 đ S ABC = Ta có Vậy (a 1)2 AB AC = 2 2S (a 1) | a 1| = r= = = AB + AC + BC | a | + | a | +1 | a |= + 0,25 đ 0,25 đ 7+4 6+2 ; TH1 a1 = + G1 3 ; TH2 a = G2 3 Cách II y C 0,25 đ I O B A x Gọi I tâm đờng tròn nội tiếp ABC Vì r = y I = x Phơng trình BI : y = tg 30 0.( x 1) = xI = TH1 Nếu A O khác phía B x I = + Từ d ( I , AC ) = 7+4 6+2 ; a = x I + = + G1 TH Nếu A O phía B x I = Tơng tự ; ta có a = x I = G2 3 0,25 đ 0,25 đ đ Từ 0,25 đ C n3 = 5C n1 ta có n n! n! n(n 1)(n 2) =5 = 5n n 3n 28 = (n 1)! 3!(n 3)! n1 = (loại) n2 = Với n = ta có x21 C 0,25 đ 0,25 đ 3x = 140 35.2 x 2.2 x = 140 x = x = 0,5 đ Cõu 9: Trong i u ki n thớch h p, x y cỏc ph n ng sau: (a) 2H2SO4 + C 2SO2 + CO2 + 2H2O (b) H2SO4 + Fe(OH)2 FeSO4 + 2H2O (c) 4H2SO4 + 2FeO Fe2(SO4)3 + SO2 + 4H2O (d) 6H2SO4 + 2Fe Fe2(SO4)3 + 3SO2 + 6H2O Trong cỏc ph n ng trờn, ph n ng x y v i dung d ch H2SO4 loóng l A (d) B (a) C (c) D (b) Cõu 10: Dóy cỏc ch t u tỏc d ng c v i dung d ch Ba(HCO3)2 l: A HNO3, NaCl v Na2SO4 B HNO3, Ca(OH)2 v KNO3 C NaCl, Na2SO4 v Ca(OH)2 D HNO3, Ca(OH)2 v Na2SO4 Cõu 11: Cho 100 ml dung d ch amino axit X n ng 0,4M tỏc d ng v a v i 80 ml dung d ch NaOH 0,5M, thu c dung d ch ch a gam mu i Cụng th c c a X l A NH2C3H6COOH B NH2C3H5(COOH)2 C (NH2)2C4H7COOH D NH2C2H4COOH Cõu 12: Ch t no sau õy khụng t o k t t a cho vo dung d ch AgNO3? A HCl B K3PO4 C KBr D HNO3 Cõu 13: Trong m t bỡnh kớn ch a 0,35 mol C2H2; 0,65 mol H2 v m t ớt b t Ni Nung núng bỡnh m t th i gian, thu c h n h p khớ X cú t kh i so v i H2 b ng S c X vo l ng d dung d ch AgNO3 NH3 n ph n ng hon ton, thu c h n h p khớ Y v 24 gam k t t a H n h p khớ Y ph n ng v a v i bao nhiờu mol Br2 dung d ch? A 0,20 mol B 0,10 mol C 0,25 mol D 0,15 mol Cõu 14: tr ng thỏi c b n, c u hỡnh electron c a nguyờn t Na (Z = 11) l A 1s22s22p53s2 B 1s22s22p63s1 C 1s22s22p63s2 D 1s22s22p43s1 Cõu 15: Cho 1,37 gam Ba vo lớt dung d ch CuSO4 0,01M Sau cỏc ph n ng x y hon ton, kh i l ng k t t a thu c l A 2,33 gam B 0,98 gam C 3,31 gam D 1,71 gam Cõu 16: H n h p X g m Ba v Al Cho m gam X vo n c d , sau cỏc ph n ng x y hon ton, thu c 8,96 lớt khớ H2 (ktc) M t khỏc, hũa tan hon ton m gam X b ng dung d ch NaOH, thu c 15,68 lớt khớ H2 (ktc) Giỏ tr c a m l A 16,4 B 29,9 C 24,5 D 19,1 Cõu 17: Dung d ch axit axetic ph n ng c v i t t c cỏc ch t dóy no sau õy? A NaOH, Cu, NaCl B Na, NaCl, CuO C NaOH, Na, CaCO3 D Na, CuO, HCl Cõu 18: Cho s cỏc ph n ng: to X + NaOH (dung d ch) Y + Z; 1500o C t o ,CaO T + P; Y + NaOH (r n) t o ,xt Z Q + H2 ; Q + H2O T Trong s trờn, X v Z l n l t l: A CH3COOCH=CH2 v CH3CHO B HCOOCH=CH2 v HCHO C CH3COOCH=CH2 v HCHO D CH3COOC2H5 v CH3CHO Cõu 19: H n h p X ch a ba axit cacboxylic u n ch c, m ch h , g m m t axit no v hai axit khụng no u cú m t liờn k t ụi (C=C) Cho m gam X tỏc d ng v a v i 150 ml dung d ch NaOH 2M, thu c 25,56 gam h n h p mu i t chỏy hon ton m gam X, h p th ton b s n ph m chỏy b ng dung d ch NaOH d , kh i l ng dung d ch t ng thờm 40,08 gam T ng kh i l ng c a hai axit cacboxylic khụng no m gam X l A 15,36 gam B 9,96 gam C 12,06 gam D 18,96 gam Cõu 20: Th c hi n cỏc thớ nghi m sau: (a) Cho dung d ch HCl vo dung d ch Fe(NO3)2 (b) Cho FeS vo dung d ch HCl (c) Cho Si vo dung d ch NaOH c (d) Cho dung d ch AgNO3 vo dung d ch NaF (e) Cho Si vo bỡnh ch a khớ F2 (f) S c khớ SO2 vo dung d ch H2S Trang 2/6 - Mó thi 193 Trong cỏc thớ nghi m trờn, s thớ nghi m cú x y ph n ng l A B C D Cõu 21: Kim lo i s t tỏc d ng v i dung d ch no sau õy t o mu i s t(II)? A HNO3 c, núng, d B CuSO4 C H2SO4 c, núng, d D MgSO4 Cõu 22: Phenol ph n ng c v i dung d ch no sau õy? A NaCl B HCl C NaHCO3 D KOH Cõu 23: Cho h n h p X g m 0,01 mol Al v a mol Fe vo dung d ch AgNO3 n ph n ng hon ton, thu c m gam ch t r n Y v dung d ch Z ch a cation kim lo i Cho Z ph n ng v i dung d ch NaOH d i u ki n khụng cú khụng khớ, thu c 1,97 gam k t t a T Nung T khụng khớ n kh i l ng khụng i, thu c 1,6 gam ch t r n ch ch a m t ch t nh t Giỏ tr c a m l A 6,48 B 3,24 C 8,64 D 9,72 Cõu 24: Cho b t Fe vo dung d ch g m AgNO3 v Cu(NO3)2 Sau cỏc ph n ng x y hon ton, thu c dung d ch X g m hai mu i v ch t r n Y g m hai kim lo i Hai mu i X v hai kim lo i Y l n l t l: A Fe(NO3)2; Fe(NO3)3 v Cu; Ag B Cu(NO3)2; AgNO3 v Cu; Ag C Cu(NO3)2; Fe(NO3)2 v Cu; Fe D Cu(NO3)2; Fe(NO3)2 v Ag; Cu Cõu 25: ng v i cụng th c phõn t C4H10O cú bao nhiờu ancol l ng phõn c u t o c a nhau? A B C D Cõu 26: Tờn thay th (theo IUPAC) c a (CH3)3CCH2CH(CH3)2 l A 2,2,4,4-tetrametylbutan B 2,4,4-trimetylpentan C 2,2,4-trimetylpentan D 2,4,4,4-tetrametylbutan Cõu 27: Hũa tan hon ton m gam Al b ng dung d ch HNO3 loóng, thu c 5,376 lớt (ktc) h n h p khớ X g m N2, N2O v dung d ch ch a 8m gam mu i T kh i c a X so v i H2 b ng 18 Giỏ tr c a m l A 21,60 B 18,90 C 17,28 D 19,44 Cõu 28: Ch t no sau õy un núng v i dung d ch NaOH thu c s n ph m cú anehit? A CH3COOCH2CH=CH2 B CH3COOC(CH3)=CH2 C CH2=CHCOOCH2CH3 D CH3COOCH=CHCH3 Cõu 29: Liờn k t húa h c gi a cỏc nguyờn t phõn t HCl thu c lo i liờn k t A c ng húa tr cú c c B hiro C c ng húa tr khụng c c D ion Cõu 30: Cho X l hexapeptit AlaGlyAlaValGlyVal v Y l tetrapeptit GlyAlaGlyGlu Th y phõn hon ton m gam h n h p g m X v Y thu c amino axit, ú cú 30 gam glyxin v 28,48 gam alanin Giỏ tr c a m l A 73,4 B 77,6 C 83,2 D 87,4 Cõu 31: Cho 0,1 mol tristearin ((C17H35COO)3C3H5) tỏc d ng hon ton v i dung d ch NaOH d , un núng, thu c m gam glixerol Giỏ tr c a m l A 27,6 B 4,6 C 14,4 D 9,2 Cõu 32: Cho cỏc cõn b ng húa h c sau: N2O4 (k) 2HI (k) (a) H2 (k) + I2 (k) (b) 2NO2 (k) 2SO3 (k) 2NH3 (k) (d) 2SO2 (k) + O2 (k) (c) 3H2 (k) + N2 (k) nhi t khụng i, thay i ỏp su t chung c a m i h cõn b ng, cõn b ng húa h c no trờn khụng b chuy n d ch? A (b) B (a) C (c) D (d) Cõu 33: Dung d ch no sau õy lm phenolphtalein i mu? A axit axetic B alanin C glyxin D metylamin Cõu 34: H n h p X g m Na, Ba, Na2O v BaO Hũa tan hon ton 21,9 gam X vo n c, thu c 1,12 lớt khớ H2 (ktc) v dung d ch Y, ú cú 20,52 gam Ba(OH)2 H p th hon ton 6,72 lớt khớ CO2 (ktc) vo Y, thu c m gam k t t a Giỏ tr c a m l A 15,76 B 39,40 C 21,92 D 23,64 Trang 3/6 - Mó thi 193 Cõu 35: Hũa tan hon ton 1,805 gam h n h p g m Fe v kim lo i X b ng dung d ch HCl, thu c 1,064 lớt khớ H2 M t khỏc, hũa tan hon ton 1,805 gam h n h p trờn b ng dung d ch HNO3 loóng (d ), thu c 0,896 lớt khớ NO (s n ph m kh nh t) Bi t cỏc th tớch khớ u o i u ki n tiờu chu n Kim lo i X l A Zn B Cr C Al D Mg Cõu 36: Khi c chi u sỏng, hirocacbon no sau õy tham gia ph n ng th v i clo theo t l mol : 1, thu c ba d n xu t monoclo l ng phõn c u t o c a nhau? A neopentan B pentan C butan D isopentan Cõu 37: Lờn men m gam glucoz t o thnh ancol etylic (hi u su t ph n ng b ng 90%) H p th hon ton l ng khớ CO2 sinh vo dung d ch Ca(OH)2 d , thu c 15 gam k t t a Giỏ tr c a m l A 7,5 B 15,0 C 18,5 D 45,0 Cõu 38: Cho m gam Fe vo bỡnh ch a dung d ch g m H2SO4 v HNO3, thu c dung d ch X v 1,12 lớt khớ NO Thờm ti p dung d ch H2SO4 d vo bỡnh thu c 0,448 lớt khớ NO v dung d ch Y Bi t c hai tr ng h p NO l s n ph m kh nh t, o i u ki n tiờu chu n Dung d ch Y hũa tan v a h t 2,08 gam Cu (khụng t o thnh s n ph m kh c a N+5) Bi t cỏc ph n ng u x y hon ton Giỏ tr c a m l A 2,40 B 4,06 C 3,92 D 4,20 Cõu 39: H p ch t X cú thnh ph n g m C, H, O, ch a vũng benzen Cho 6,9 gam X vo 360 ml dung d ch NaOH 0,5M (d 20% so v i l ng c n ph n ng) n ph n ng hon ton, thu c dung d ch Y Cụ c n Y thu c m gam ch t r n khan M t khỏc, t chỏy hon ton 6,9 gam X c n v a 7,84 lớt O2 (ktc), thu c 15,4 gam CO2 Bi t X cú cụng th c phõn t trựng v i cụng th c n gi n nh t Giỏ tr c a m l A 13,2 B 11,1 C 12,3 D 11,4 Cõu 40: Bi t X l axit cacboxylic n ch c, Y l ancol no, c hai ch t u m ch h , cú cựng s nguyờn t cacbon t chỏy hon ton 0,4 mol h n h p g m X v Y (trong ú s mol c a X l n h n s mol c a Y) c n v a 30,24 lớt khớ O2, thu c 26,88 lớt khớ CO2 v 19,8 gam H2O Bi t th tớch cỏc khớ o i u ki n tiờu chu n Kh i l ng c a Y 0,4 mol h n h p trờn l A 11,4 gam B 19,0 gam C 9,0 gam D 17,7 gam II PH N RIấNG (10 cõu) Thớ sinh ch A Theo ch c lm m t hai ph n (Ph n A ho c Ph n B) ng trỡnh Chu n (10 cõu, t cõu 41 n cõu 50) Cõu 41: H n h p X g m H2, C2H4 v C3H6 cú t kh i so v i H2 l 9,25 Cho 22,4 lớt X (ktc) vo bỡnh kớn cú s n m t ớt b t Ni un núng bỡnh m t th i gian, thu c h n h p khớ Y cú t kh i so v i H2 b ng 10 T ng s mol H2 ó ph n ng l A 0,070 mol B 0,050 mol C 0,015 mol D 0,075 mol Cõu 42: Cho cỏc phỏt bi u sau: (a) Trong b ng tu n hon cỏc nguyờn t húa h c, crom thu c chu kỡ 4, nhúm VIB (b) Cỏc oxit c a crom u l oxit baz (c) Trong cỏc h p ch t, s oxi húa cao nh t c a crom l +6 (d) Trong cỏc ph n ng húa h c, h p ch t crom(III) ch úng vai trũ ch t oxi húa (e) Khi ph n ng v i khớ Cl2 d , crom t o h p ch t crom(III) Trong cỏc phỏt bi u trờn, nh ng phỏt bi u ỳng l: A (b), (c) v (e) B (a), (c) v (e) C (b), (d) v (e) D (a), (b) v (e) Cõu 43: Dóy cỏc ch t u cú kh n ng tham gia ph n ng th y phõn dung d ch H2SO4 un núng l: A glucoz , tinh b t v xenluloz B saccaroz , tinh b t v xenluloz C glucoz , saccaroz v fructoz D fructoz , saccaroz v tinh b t Cõu 44: Cho cỏc c p oxi húa - kh c s p x p theo th t t ng d n tớnh oxi húa c a cỏc ion kim lo i: Al3+/Al; Fe2+/Fe; Sn2+/Sn; Cu2+/Cu Ti n hnh cỏc thớ nghi m sau: Trang 4/6 - Mó thi 193 (a) Cho s t vo dung d ch ng(II) sunfat (b) Cho ng vo dung d ch nhụm sunfat (c) Cho thi c vo dung d ch ng(II) sunfat (d) Cho thi c vo dung d ch s t(II) sunfat Trong cỏc thớ nghi m trờn, nh ng thớ nghi m cú x y ph n ng l: A (a) v (b) B (b) v (c) C (a) v (c) D (b) v (d) Cõu 45: Cho X v Y l hai axit cacboxylic m ch h , cú cựng s nguyờn t cacbon, ú X n ch c, Y hai ch c Chia h n h p g m X v Y thnh hai ph n b ng Ph n m t tỏc d ng h t v i Na, thu c 4,48 lớt khớ H2 (ktc) t chỏy hon ton ph n hai, thu c 13,44 lớt khớ CO2 (ktc) Ph n tr m kh i l ng c a Y h n h p l A 42,86 % B 57,14% C 85,71% D 28,57% Cõu 46: Cho 25,5 gam h n h p X g m CuO v Al2O3 tan hon ton dung d ch H2SO4 loóng, thu c dung d ch ch a 57,9 gam mu i Ph n tr m kh i l ng c a Al2O3 X l A 60% B 40% C 80% D 20% Cõu 47: Trong cỏc dung d ch: CH3CH2NH2, H2NCH2COOH, H2NCH2CH(NH2)COOH, HOOCCH2CH2CH(NH2)COOH, s dung d ch lm xanh qu tớm l A B C D Cõu 48: t chỏy hon ton h n h p X g m 0,07 mol m t ancol a ch c v 0,03 mol m t ancol khụng no, cú m t liờn k t ụi, m ch h , thu c 0,23 mol khớ CO2 v m gam H2O Giỏ tr c a m l A 2,70 B 2,34 C 8,40 D 5,40 Cõu 49: Thớ nghi m v i dung d ch HNO3 th ng sinh khớ c NO2 h n ch khớ NO2 thoỏt t ng nghi m, ng i ta nỳt ng nghi m b ng: (a) bụng khụ (b) bụng cú t m n c (c) bụng cú t m n c vụi (d) bụng cú t m gi m n Trong bi n phỏp trờn, bi n phỏp cú hi u qu nh t l A (d) B (a) C (c) D (b) Cõu 50: Cho ph ng trỡnh ph n ng aAl + bHNO3 cAl(NO3)3 + dNO + eH2O T l a : b l A : B : C : D : B Theo ch ng trỡnh Nõng cao (10 cõu, t cõu 51 n cõu 60) Cõu 51: Cho 12 gam h p kim c a b c vo dung d ch HNO3 loóng (d ), un núng n ph n ng hon ton, thu c dung d ch cú 8,5 gam AgNO3 Ph n tr m kh i l ng c a b c m u h p kim l A 45% B 55% C 30% D 65% Cõu 52: Cho cỏc phỏt bi u sau: (a) x lớ th y ngõn r i vói, ng i ta cú th dựng b t l u hu nh (b) Khi thoỏt vo khớ quy n, freon phỏ h y t ng ozon (c) Trong khớ quy n, n ng CO2 v t quỏ tiờu chu n cho phộp gõy hi u ng nh kớnh (d) Trong khớ quy n, n ng NO2 v SO2 v t quỏ tiờu chu n cho phộp gõy hi n t ng m a axit Trong cỏc phỏt bi u trờn, s phỏt bi u ỳng l A B C D +Cl2 , d + dungdịch NaOH, d Cõu 53: Cho s ph n ng Cr X Y to Ch t Y s trờn l A Na[Cr(OH)4] B Na2Cr2O7 C Cr(OH)2 D Cr(OH)3 Cõu 54: Cho 13,6 gam m t ch t h u c X (cú thnh ph n nguyờn t C, H, O) tỏc d ng v a v i dung d ch ch a 0,6 mol AgNO3 NH3, un núng, thu c 43,2 gam Ag Cụng th c c u t o c a X l A CH2=C=CHCHO B CH3C CCHO C CH CCH2CHO D CH C[CH2]2CHO Cõu 55: Cho cỏc phỏt bi u sau: (a) Glucoz cú kh n ng tham gia ph n ng b c (b) S chuy n húa tinh b t c th ng i cú sinh mantoz Trang 5/6 - Mó thi 193 (c) Mantoz cú kh n ng tham gia ph n ng b c (d) Saccaroz c c u t o t hai g c -glucoz v -fructoz Trong cỏc phỏt bi u trờn, s phỏt bi u ỳng l A B C D Cõu 56: H n h p X g m ancol metylic, ancol etylic v glixerol t chỏy hon ton m gam X, thu c 15,68 lớt khớ CO2 (ktc) v 18 gam H2O M t khỏc, 80 gam X hũa tan c t i a 29,4 gam Cu(OH)2 Ph n tr m kh i l ng c a ancol etylic X l A 23% B 16% C 8% D 46% Cõu 57: Cho ph ng trỡnh ph n ng aFeSO4 + bK2Cr2O7 + cH2SO4 dFe2(SO4)3 + eK2SO4 + fCr2(SO4)3 + gH2O T l a : b l A : B : C : D : Cõu 58: Tr ng h p no sau õy khụng x y ph n ng? to (a) CH2=CHCH2Cl + H2O (b) CH3CH2CH2Cl + H2O t o cao, p cao (c) C6H5Cl + NaOH ( c) ; (v i C6H5 l g c phenyl) to (d) C2H5Cl + NaOH A (b) B (a) C (d) D (c) Cõu 59: Peptit X b th y phõn theo ph ng trỡnh ph n ng X + 2H2O 2Y + Z (trong ú Y v Z l cỏc amino axit) Th y phõn hon ton 4,06 gam X thu c m gam Z t chỏy hon ton m gam Z c n v a 1,68 lớt khớ O2 (ktc), thu c 2,64 gam CO2; 1,26 gam H2O v 224 ml khớ N2 (ktc) Bi t Z cú cụng th c phõn t trựng v i cụng th c n gi n nh t Tờn g i c a Y l A lysin B axit glutamic C glyxin D alanin Cõu 60: Tr ng h p no sau õy, kim lo i b n mũn i n húa h c? A Kim lo i s t dung d ch HNO3 loóng B Thộp cacbon khụng khớ m C t dõy s t khớ oxi khụ D Kim lo i k m dung d ch HCl H T Trang 6/6 - Mó thi 193 B GIO D C V O T O P N THI TUY N SINH I H C N M 2013 Mụn thi: HểA H C; Kh i A ( ỏp ỏn cú 02 trang) THI CHNH TH C Cõu 617 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 D B D A A B C C C A D C A D D B A D C D C C D B C C C D A A B C B B D A D B B C D C B 531 D C B B B D D C A B C D C A A B D B B D B A B A A C C A D D A D C C D D C B A C A C D Mó - ỏp ỏn 463 374 B B C D D D D B D C C C C A B A B D B A B C D C A D B C B C D A C D B B A A C A A A C C C D A A B D B A A B A B D D C A D B B C D C C C C B D A D B A A A A C B B D A D A B 286 193 B C D B B D B C A C B B C C D A B A D A B A B C C B D A A C B C D D B C D D C B A D C A D B B B B B B D D A D D B C C C A C A B D C D A C A D A C D B D A C B B B C A D B B Cõu 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 617 531 C D C B A A B B D D B A A B A A A C A B D C B B D B A A B C A D C A Mó - ỏp ỏn 463 374 D B B A C A B C A D D A C B D D A B B B C C D C D C A C A D B D D C 286 193 A C A A C D D A B D D B A A C A D C A D D D C D A C A C C A A A C B B GIO D C V O T O CHNH TH C ( cú trang) THI TUY N SINH I H C N M 2013 Mụn: TI NG ANH; Kh i A1 Th i gian lm bi: 90 phỳt, khụng k th i gian phỏt Mó thi 248 H , tờn thớ sinh: S bỏo danh: THI G M 80 CU (T QUESTION N QUESTION 80) Mark the letter A, B, C, or D on your answer sheet to indicate the correct answer in each of the following questions Question 1: Thanh: Lans the best singer in our school. Nadia: A Yes, tell me about it! B I cant agree with you more! C Thats OK! D Yes, please Question 2: You can use my car you drive carefully A though B as though C as long as D lest Question 3: His honesty is ; nobody can doubt it A in question B beside the question C without question D out the question Question 4: In our hospital, patients every morning A are examined B were examining C have examined D can examine Question 5: The Moon is much closer to Earth , and thus it had greater influence on the tides A but the Sun is B where the Sun is C than is the Sun D unlike the Sun Question 6: Connecticut was the fifth of the original thirteen states the Constitution of the United States A to ratify B ratify C ratified D have ratified Question 7: I'll give this dictionary to wants to have it A anyone B whatever C everyone D whoever Question 8: No one can avoid by advertisements A to be influenced B having influenced C influencing D being influenced Question 9: He wasn't attending the lecture properly and missed most of A things said by the teacher B that the teacher said C which the teacher said D what the teacher said Question 10: It is work of art that everyone wants to have a look at it A such an unusual B such unusual a C a so unusual D so an unusual Question 11: The children ran away as if they a ghost A have seen B had seen C would see D see Question 12: I would join that running competition A when I was years older B if I were years younger C if it would happen years ago D unless I were years younger Question 13: We decided to take a late flight we could spend more time with our family A so as to B in order C so that D in order to Question 14: He's sometimes bad-tempered but he's a good fellow A at heart B by heart C with heart D in heart Question 15: Scarcely had he stepped out of the room he heard a loud laughter within A then B until C than D when Question 16: What if the earth stopped moving? A happened B would happen C happens D will happen Question 17: Mai: Do you want another serving of chicken soup? Scott: . A No way B No comment C No thanks D No longer Question 18: We expressed the missing child would be found alive A the hope for B the hope which C as we hoped D the hope that Trang 1/6 - Mó thi 248 Question 19: A large number of workmen because of the economic recession A have laid down B has laid aside C have been laid off D has been laid out Question 20: Her mother, has been working for thirty years, is retiring next month A who B that C whom D whose Question 21: My brother tried to learn Japanese at a night school, he gave up after months A therefore B when C until D but Question 22: Having traveled to different parts of our country, A we have learned a lot about interesting lifestyles and customs B we are seeing a lot of interesting lifestyles and customs C many interesting lifestyles and customs have been learned by us D much has been learned about interesting lifestyles and customs Question 23: The government was finally by a minor scandal A put back B brought down C pulled down D taken down Question 24: The water supply of our home city has failed to average purity requirements A see B meet C own D hold Question 25: Books and magazines around made his room very untidy A that lie B laying C which lied D lying Mark the letter A, B, C, or D on your answer sheet to indicate the sentence that is CLOSEST in meaning to the sentence given in each of the following questions Question 26: Peters main subject at university is electronics A The university lets Peter major in electronics B Electronics is among the subjects that Peter likes C Peter thinks electronics is a special subject D Peter majors in electronics at university Question 27: I wish I hadnt accepted the invitation to her birthday party A I insisted on having been invited to her birthday party B I was very glad to accept the invitation to her birthday party C I regret accepting the invitation to her birthday party D If only I had come to her birthday party Question 28: No one but Jane succeeded in giving the correct answer A All but Jane managed to produce the correct answer B Only Jane failed to answer the question correctly C Jane was among those who failed to guess the answer D Everyone but Jane failed to provide the correct answer Question 29: Thanks to the efforts of environmentalists, people are becoming better aware of the problems of endangered species A Environmentalists are expressing their gratitude towards people who are better aware of the problems of endangered species B People owe their growing awareness of the problems of endangered species to the efforts of environmentalists C People have no idea about the problems of endangered species in spite of the efforts of environmentalists D Environmentalists are doing their best to make people aware of the problems of endangered species Question 30: I could not get the job because I did not speak English well A I would have spoken English well if I could get that job B I wish I had got the job so that I could speak English well C Despite my poor English, I was successful in the job D I failed to get the job because of my poor English Question 31: Although the teacher explained the theory clearly, the students found it hard to understand it A Though explained clearly, the theory of teaching was difficult to the students B Although the teaching theory was clear, it was a real challenge to the students Trang 2/6 - Mó thi 248 C In spite of explaining the theory clearly, the students themselves found it hard to understand it D Despite the teachers clear explanation of the theory, the students had difficulty understanding it Question 32: How brave you are! he said to the firemen A He blamed the firemen for their discouragement B He criticized the firemen for their discouragement C He praised the firemen for their courage D He asked how brave the firemen were Question 33: I would have worn the right shoes if I had known I was going to all this climbing A I would love to go climbing, but I not have any shoes that would be suitable B As I did not know I was going to so much climbing, I did not wear suitable shoes C I did not go climbing because I did not have the right shoes D I would have gone on the climb if I had been wearing the right shoes Question 34: The man in that painting reminds me of my uncle A Whenever I see the man in that painting, I remember to meet my uncle B Whenever my uncle sees the man in that painting, he misses me C Memories of my uncle come back whenever I see the man in that painting D I am recalling my uncle whenever I look at the man in that painting Question 35: A small hotel was the only choice of place to stay at during my trip to London A I had no alternative but to stay at a small hotel during my trip to London B I was talked into staying at a small hotel during my trip to London C There were a lot of hotels for me to choose from during my trip to London D I had different choices of where to stay during my trip to London Read the following passage and mark the letter A, B, C, or D on your answer sheet to choose the word or phrase that best fits each of the numbered blanks from 36 to 45 In a world where billion people live in homes that don't have light bulbs, technology holds the key (36) banishing poverty Even the simplest technologies can transform lives and save money Vaccines, crops, computers and sources of solar energy can all reduce poverty in developing countries For example, cheap oral-rehydration therapy developed in Bangladesh has dramatically cut the death (37) from childhood diarrhoea But even when such technologies exist, the depressing fact is that we cant make them (38) for those who most need them Solar panels, batteries and light bulbs are still beyond the purse of many, but where they have been installed they change lives A decent light in the evening gives children more time for homework and extends the productive day for adults Kenya has a thriving solar industry and six years ago Kenyan pioneers also (39) connecting schools to the Internet via radio links These people were fortunate (40) being able to afford solar panels, radios and old computers How much bigger would the impact be if these things (41) and priced specifically for poor people? Multinationals must become part of the solution, because (42) they own around 60 per cent of the world's technology, they seldom make products for poor customers Of 1,223 new drugs marketed worldwide from 1975 to 1996, for example, just 13 were for tropical diseases People think those enterprises should more to provide vital products such as medicines (43) different prices around the world to suit (44) people can afford Alternatively, they could pay a percentage of their profit towards research and development for (45) Adapted from The Price is Wrong in Focus on IELTS Foundations by Sue OConnell, Pearson Longman, 2006 Question 36: A to Question 37: A amount Question 38: A enough cheaply Question 39: A were starting Question 40: A in Question 41: A have been made Question 42: A unless Question 43: A with Question 44: A which Question 45: A the poor B at B penalty B cheap enough B had started B at B were made B however B to B what B the rich C with C toll C enough cheap C started C by C are made C when C at C where C the wealthy D for D number D cheaply enough D have been starting D on D made D while D on D that D the better-off Trang 3/6 - Mó thi 248 Read the following passage and mark the letter A, B, C, or D on your answer sheet to indicate the correct answer to each of the questions from 46 to 55 Archimedes' Principle is a law of physics that states that when an object is totally or partially immersed in a fluid, it experiences an upthrust equal to the weight of the fluid displaced The principle is most frequently applied to the behaviour of objects in water, and helps to explain floating and sinking, and why objects seem lighter in water It also applies to balloons The key word in the principle is upthrust, which refers to the force acting upward to reduce the apparent weight of the object when it is under water If, for example, a metal block with a volume of 100 cm3 is dipped in water, it displaces an equal volume of water, which has a weight of approximately N (3.5 oz) The block therefore seems to weigh about N less An object will float if its average density is less than that of water If it is totally submerged, the weight of the water it displaces (and hence the upthrust on it) is greater than its own weight, and it is forced upward and out of the water, until the weight of the water displaced by the submerged part is exactly equal to the weight of the floating object Thus a block of wood with a density six tenths that of water will float with six tenths of its volume under water, since at that point the weight of fluid displaced is the same as the blocks own weight If a dense material is made into a suitable shape, it will float because of Archimedes principle A ship floats, whereas a block of iron of the same mass sinks It is also because of Archimedes principle that ships float lower in the water when they are heavily loaded (more water must be displaced to give the necessary upthrust) In addition, they cannot be so heavily loaded if they are to sail in fresh water as they can if they are to sail in the sea, since fresh water is less dense than sea water, and so more water must be displaced to give the necessary upthrust This means the ship is lower in the water, which can be dangerous in rough weather From "Archimedes' Principle", Microsoftđ Student 2008 [DVD] Microsoft Corporation, 2007 Question 46: What happens when something is immersed in a fluid? A It will be pushed further down with a force, equal to the weight of the fluid displaced B It receives an upward force, equal to the weight of the fluid displaced C It receives a downward force, equal to the weight of the fluid displaced D The fluid will expand the object and overflow to the floor Question 47: The word volume in the passage refers to A loudness B quantity C frequency D length Question 48: The word displaces in the passage almost means A takes the place of B takes place C replaces with a new one D puts in position Question 49: If an objects average density is less than that of water, the object will A sink B float C inflate D drift Question 50: A block of wood with a density seven tenths that of water will A go up and down then sink B float with a half of its volume under water C float with an equal volume of its volume under water D sink immediately when submerged Question 51: A ship floats, whereas a block of iron of the same mass sinks because the ship A is made of wood B is lighter C has buoys D has a special shape Question 52: The phrase six tenths in the passage means A and 10 B 10/6 C 10 of D 6/10 Question 53: The word upthrust in the passage refers to the A upward push B upper side of an object C upturned force D upside-down turn Question 54: Ships cannot be so heavily loaded if they want to sail in fresh water as they sail in the sea, because A fresh water is lighter than sea water B theres too much salt in sea water C sea water is saltier than fresh water D fresh water is more polluted Question 55: Archimedes' Principle explains why A all objects will float B Archimedes became famous C objects seem lighter in water D humans can swim Trang 4/6 - Mó thi 248 Mark the letter A, B, C, or D on your answer sheet to indicate the word(s) OPPOSITE in meaning to the underlined word(s) in each of the following questions Question 56: We are now a 24/7 society where shops and services must be available all hours A an active society B an inactive society C a physical society D a working society Question 57: A chronic lack of sleep may make us irritable and reduces our motivation to work A uncomfortable B responsive C calm D miserable Question 58: We'd better speed up if we want to get there in time A slow down B turn down C put down D lie down Question 59: She is a very generous old woman She has given most of her wealth to a charity organization A mean B amicable C kind D hospitable Question 60: Her thoughtless comments made him very angry A honest B kind C pleasant D thoughtful Read the following passage and mark the letter A, B, C, or D on your answer sheet to indicate the correct answer to each of the questions from 61 to 70 In 1826, a Frenchman named Niộpce needed pictures for his business He was not a good artist, so he invented a very simple camera He put it in a window of his house and took a picture of his yard That was the first photograph The next important date in the history of photography was 1837 That year, Daguerre, another Frenchman, took a picture of his studio He used a new kind of camera and a different process In his pictures, you could see everything clearly, even the smallest details This kind of photograph was called a daguerreotype Soon, other people began to use Daguerre's process Travelers brought back daguerreotypes from all around the world People photographed famous buildings, cities, and mountains In about 1840, the process was improved Then photographers could take pictures of people and moving things The process was not simple and photographers had to carry lots of film and processing equipment However, this did not stop photographers, especially in the United States After 1840, daguerreotype artists were popular in most cities Matthew Brady was one well-known American photographer He took many portraits of famous people The portraits were unusual because they were lifelike and full of personality Brady was also the first person to take pictures of a war His 1862 Civil War pictures showed dead soldiers and ruined cities They made the war seem more real and more terrible In the 1880s, new inventions began to change photography Photographers could buy film readymade in rolls, instead of having to make the film themselves Also, they did not have to process the film immediately They could bring it back to their studios and develop it later They did not have to carry lots of equipment And finally, the invention of the small handheld camera made photography less expensive With a small camera, anyone could be a photographer People began to use cameras just for fun They took pictures of their families, friends, and favorite places They called these pictures "snapshots" Documentary photographs became popular in newspapers in the 1890s Soon magazines and books also used them These pictures showed true events and people They were much more real than drawings Some people began to think of photography as a form of art They thought that photography could more than show the real world It could also show ideas and feelings, like other art forms From Reading Power by Beatrice S Mikulecky and Linda Jeffries Question 61: The first photograph was taken with A a small handheld camera B a very simple camera C a daguerreotype D new types of film Question 62: Daguerre took a picture of his studio with A a new kind of camera B a very simple camera C special equipment D an electronic camera Trang 5/6 - Mó thi 248 Question 63: The word this in the passage refers to the A carrying of lots of film and processing equipment B stopping of photographers from taking photos C fact that daguerreotype artists were popular in most cities D taking of pictures of people and moving things Question 64: The word ruined in the passage is closest in meaning to A poorly-painted B heavily-polluted C terribly spoiled D badly damaged Question 65: The word lifelike in the passage is closest in meaning to A moving B realistic C touching D manlike Question 66: The latest invention mentioned in the passage is the invention of A handheld cameras B processing equipment C daguerreotypes D rolls of film Question 67: The word handheld in the passage is closest in meaning to A handling manually B held by hand C controlling hands D operated by hand Question 68: Matthew Brady was well-known for A inventing daguerreotypes B the small handheld camera C taking pictures of French cities D portraits and war photographs Question 69: As mentioned in the passage, photography can A print old pictures B convey ideas and feelings C show the underworld D replace drawings Question 70: Which of the following could best serve as the title of the passage? A Different Steps in Film Processing B Story of Photography C Photography and Painting D Story of Famous Photographers Mark the letter A, B, C, or D on your answer sheet to indicate the word whose underlined part differs from the other three in pronunciation in each of the following questions Question 71: A exact Question 72: A work Question 73: A aboard Question 74: A reign Question 75: A pressure B examine B stork B keyboard B reindeer B assure C eleven C force C cupboard C protein C assist D elephant D form D overboard D vein D possession Mark the letter A, B, C, or D on your answer sheet to indicate the underlined part that needs correction in each of the following questions Question 76: I like the fresh air and green trees of the village which I spent my vacation last year A B C D Question 77: Some people often say that using cars is not as convenient than using motorbikes A B C D Question 78: It was not until the end of prehistoric times that the first wheeled vehicles appearing A B C D Question 79: In the early 1900's, Pennsylvania's industries grew rapidly, a growth sometimes A B accompanied by disputes labor C D Question 80: Looking from afar, the village resembles a small green spot dotted with tiny fireballs A B C D THE END Trang 6/6 - Mó thi 248 B GIO D C V O T O THI CHNH TH C Cõu 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 248 B C C A C A D D D A B B C A D B C D C A D A B B D D C D B D D C B C A A C B C A B D C 475 C D D B A C C D C C D D A D D D A C B B D A A C D B A B A D A B B D D A B A B B B D B P N THI TUY N SINH I H C N M 2013 Mụn thi: TI NG ANH; Kh i A1 ( ỏp ỏn cú 02 trang) Mó - ỏp ỏn 526 693 D B C D B B C D D A A A B A A C B B A C A D B B C A B D D C A C C A D B D D D D A B A B D B A A A A A B B B C C C A A A B A B C A D A D B B B A D C B D A C B D A B C D C C 729 D C B A C C A D B C B A A B C C D D D A B A D B D C D C D A D C B C A C C A B A D A D 951 B C A C C D A B B D D D B B B B B C C B C B B C D C A B A D B A B B D C D A C A A D C Cõu 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 248 B A B B A B C D D A A C B C A A D B A A D B A B D B B D A C C C C C D D A 475 D A C B B A A B A C C C C B B B C A D C C A C A B A C D B A D C C C D D A Mó - ỏp ỏn 526 693 D B D B B D C C A C B A A D A B B C C C C A D D A C C A B D C B D B C C C D A D D A D B D D D A B C C C B A D C C A D D B B C C B D C B C A D A D C 729 C D B A D D A C B B B A C B D B C A A A B B C A D A C B B D C D A B D B C 951 C D D A B A A C B A A B D C D C A C A D A A D C A C A B D D B D D A C D C ... sinh thi hệ cao đẳng (1điểm) Máy quang phổ hoạt động dựa vào tợng tán sắc ánh sáng Bộ phận thực tán sắc lăng kính Nguyên nhân tợng tán sắc ánh sáng là: Chiết suất môi trờng suốt ánh sáng đơn... Ghi chú: Cán coi thi không giải thích thêm Họ tên thí sinh: Số báo danh: Bộ giáo dục đào tạo kỳ thi tuyển sinh đại học, cao đẳng năm 2003 đáp án thang điểm đề thi thức Môn thi : toán Khối A... sinh thi cao đẳng không làm câu V Hết Cán coi thi không giải thích thêm Họ tên thí sinh : Số báo danh : kỳ thi tuyển SINH đại học, cao đẳng năm 2002 Đáp án thang điểm đề thức Đại