Scott Mackenzie, The 8051 Microcontroller Serial Port • RXDP3.0 and TXDP3.1 pins • Full Duplex: simultaneous transmission and reception • 2 special function registers: SCONand SBUF • SCO
Trang 1Chapter 5 Serial Port Operation
The 8051 Microcontroller
Lê Chí Thông Ref I Scott Mackenzie, The 8051 Microcontroller
Serial Port
• RXD(P3.0) and TXD(P3.1) pins
• Full Duplex: simultaneous transmission and reception
• 2 special function registers: SCONand SBUF
• SCON: status bits and control bits
• SBUF: same address but 2 buffers; 1 buffer for transmission and 1 buffer for reception
• Baud rate (serial port frequency of operation) is supplied and programmed by Timer1
Trang 2Serial port block diagram
Writing to SBUF loads data to be transmitted Reading SBUF accesses received data
P→ → S buffer S→ → P buffer
SCON Register
Trang 3SCON Register
Mode 0: 8-Bit Shift Register
• RXD is used for both data input and output
• Serial data enter and exit (LSB first) through RXD
• TXD line serves as the clock
• TXDoutputs the shift clock
• Baud rate = 1/12 fOSC
Trang 4Mode 0: 8-Bit Shift Register
• Transmissionis initiated by instruction that writes data to SBUF (eg MOV SBUF,A)
Mode 0: 8-Bit Shift Register
• Receptionis initiated when REN is 1 and RI is 0
• Set REN at the beginning of a program
• Clear RI to begin a data input operation
Trang 5Mode 0: 8-Bit Shift Register
• One application of shift register mode is to expand the out capability of the 8051
• A serial-to-parallel shift register IC can be connected to the 8051 TXD and RXD lines to provide an extra output lines
Mode 1: 8-Bit UART with Variable Baud Rate
• UART: Universal Asynchronous Receiver/Transmitter
• A data frame includes a start bit (low), data bits, and a stop bit (high)
• A parity bitis sometimes inserted between the last data bit and the stop bit
• Mode 1:10 bits are transmitted on TXD or received on RXD, including a start bit (0), 8 data bits (LSB first), and a stop bit (1)
• The stop bit goes into RB8 in SCON
• Baud rate is set by the Timer 1 overflow rate
Trang 6Mode 1: 8-Bit UART with Variable Baud Rate
• Transmission is initiated by writing to SBUF.
• TI is set at the end of character transmission and
indicates “transmit buffer empty”.
WAIT:JNB TI,WAIT ;Check TI until set
MOV SBUF,A ;Send character
synchronization event stop
Mode 1: 8-Bit UART with Variable Baud Rate
• Reception is initiated by a 1-to-0 transition on RXD.
1 The stop bit goes into RB8 in SCON
2 SBUF is loaded with 8 data bits
3 RI is set at the end of character reception and indicates “receiver buffer full”.
• Conditions for reception:
1 RI=0, and
2 SM2=0, or SM2=1 and the received stop bit = 1
WAIT:JNB RI,WAIT ;Check RI until set
MOV A,SBUF ;Read character
Trang 7Serial Port Baud Rates
1MHz (12 MHz crystal)
To set SMOD:
375K/187.5K (12 MHz crystal)
Using Timer 1 as the Baud Rate Clock
• Usually use Timer 1 Mode 2 to provide baud rate clock
• Baud Rate = Timer 1 overflow rate / 32 (SMOD=0)
• Baud Rate = Timer 1 overflow rate / 16 (SMOD=1)
• Eg Calculate Timer 1 overflow rate to provide 1200 baud operation (12 MHz crystal)
• fOSC= 12 MHz fCLK= 1 MHz TCLK= 1 μs
• Assume SMOD=0: Timer 1 overflow rate = 1200 x
32 = 38.4 KHz Toverflow= 1/38.4 kHz = 26.04 μs
• An overflow requires Toverflow/TCLK≈ 26 clocks
The reload value for Timer 1 is -26
Trang 8Error in Baud Rate
• Due to rounding, there is a slight error Generally, a 5%
error is tolerable
• Exact baud rates are possible using an 11.0592 MHz crystal
• Eg Calculate Timer 1 overflow rate to provide 1200 baud operation (11.0592 MHz crystal)
• fOSC= 11.0592 MHz TCLK= 12/11.0592 μs
• Assume SMOD=0: Timer 1 overflow rate = 1200 x
32 = 38.4 KHz Toverflow= 1/0.0384 [μs]
• An overflow requires Toverflow/TCLK= 24 clocks
The initial value for Timer 1 is -24
Baud Rate Summary
Trang 9Initialize the Serial Port
ORG 0000H MOV SCON,#01010010B ;Serial port mode 1 MOV TMOD,#00100000B ;Timer 1 mode 2 MOV TH1,#-26 ;reload count for 1200 baud
…
Initialize the Serial Port (SMOD=1)
ORG 0000H MOV SCON,#01010010B ;Serial port mode 1 MOV A,PCON
MOV PCON,A MOV TMOD,#00100000B ;Timer 1 mode 2 MOV TH1,#-26 ;reload count for 2400 baud
…
Trang 10Example 1: Transmission
ORG 0000H MOV SCON,#01010010B ;Serial port mode 1 MOV TMOD,#00100000B ;Timer 1 mode 2 MOV TH1,#-24 ;reload count for 1200 baud
MOV R2,#10 ;number of loops MOV R0,#30H ;starting address
DJNZ R2,LOOP ;loop 10 times SJMP DONE
SEND: JNB TI,$ ;transmit buffer empty? No:check again
MOV A,SBUF ; send data
DONE: NOP
END
Assume a 10-byte string of data is stored in the internal RAM from the location 30H.
Write a program that sends this string to the 8051 serial port (1200 baud, crystal 11.0592 MHz)
19
Lê Chí Thông Ref I Scott Mackenzie
Example 2: Reception
ORG 0000H MOV SCON,#01010010B ;Serial port mode 1 MOV TMOD,#00100000B ;Timer 1 mode 2 MOV TH1,#-12 ;reload count for 2400 baud
MOV R2,#20 ;number of loops MOV R0,#40H ;starting address LOOP: ACALL RECEIVE ;receive data
DJNZ R2,LOOP ;loop 10 times SJMP DONE
RECEIVE:
JNB RI,$ ;receive buffer full? No: check again
MOV SBUF,A ; send data
DONE: NOP
Write a program that receives a 20-byte string from the 8051 serial port (2400 baud, crystal 11.0592 MHz) and then stores in the internal RAM from the location 40H.
Trang 11Mode 2: 9-Bit UART with Fixed Baud Rate
• Mode 2:11 bits are transmitted on TXD or received on RXD, including a start bit (0), 9 data bits (LSB first), and a stop bit (1)
• On transmission, the 9thbit is whatever has been put in TB8 in SCON
• On reception, the 9thbit received is placed in RB8
in SCON
• Baud rate is either fOSC/64 (SMOD=0)
or fOSC/32 (SMOD=1)
Mode 3: 9-Bit UART with Variable Baud Rate
• 9-bit UART: same as mode 2
• Variable baud rate: same as mode 1
Trang 12Adding a Parity Bit
• A common use for the 9thbit is to add parity to a character
• The P bit in PSW register is set or cleared to establish even paritywith 8 bits in A register
• Eg Put even parity bit in TB8, which becomes the 9th
data bit to be transmitted:
MOV C,P ;put even parity bit in C flag MOV TB8,C ;and move to the 9 th data bit MOV SBUF,A;move from A to SBUF to transmit
Adding a Parity Bit
• Eg Put odd parity bit in TB8, which becomes the 9th
data bit to be transmitted:
MOV C,P ;put even parity bit in C flag CPL C ;convert to odd parity
MOV TB8,C ;and move to the 9 th data bit MOV SBUF,A;move from A to SBUF to transmit
Trang 13Example 3
Assume a 10-byte string of 8-bit ASCII codes is stored in internal RAM from the location 30H Write a program that transmits this string out the 8051 serial port (4800 baud, crystal 11.0592 MHz) with odd parity added as the 9 th bit
ORG 0000H MOV SCON,#11010010B ;Serial port mode 3 (9-bit) MOV TMOD,#00100000B ;Timer 1 mode 2
MOV TH1,#-6 ;reload count for 4800 baud
MOV R2,#10 ;number of loops MOV R0,#30H ;starting address
DJNZ R2,LOOP ;loop 10 times SEND: JNB TI,$ ;check TI empty? No: check again
MOV A,SBUF ; send data
END
Example 4
Assume a 10-byte string of 7-bit ASCII codes is stored in internal RAM from the location 30H Write a program that transmits this string out the 8051 serial port (4800 baud, crystal 11.0592 MHz) with odd parity added as the 8 th bit
ORG 0000H MOV SCON,#01010010B ;Serial port mode 1 (8-bit) MOV TMOD,#00100000B ;Timer 1 mode 2
MOV TH1,#-6 ;reload count for 4800 baud
MOV R2,#10 ;number of loops MOV R0,#30H ;starting address
DJNZ R2,LOOP ;loop 10 times SEND: JNB TI,$ ;check TI empty? No: check again
MOV A,SBUF ; send data
Trang 14Multiprocessor Communications
• When SM2=1, reception is done only if RB8=1.
• The master first sends out an address byte that has 1 in the 9 th bit So all slave can receive the address byte and examine it to test if it is being addressed.
• The addressed slave will clear its SM2 bit and prepare to receive the data bytes that follow The 9 th bit in data byte is 0
• The slaves that were not addressed leave their SM2 bits set and ignore the incoming data bytes
References
• I Scott Mackenzie, The 8051 Microcontroller
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