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a ) x  x  1  x 1  x 0 Dk :   x 1 x  x     x  x  (1  x)  x2  x2  x 1  x  x  0  x    x  x2  b) 0  x  12 x  TH 1:  x  0   x  12 x    x  0  x  1*   3x  12 x    x  Từ * ** ta có 6 39 x  39 **  39 TH :  x  0   x  12 x    x  0    x 1***   3x  12 x    x   x  Từ *** **** 6 39 6 39 ****

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