Tài liệu Circuits & Electronics P25 pptx

... 6.002 Fall 2000 Lecture 1 25 6.002 CIRCUITS AND ELECTRONICS Violating the Abstraction Barrier 6.002 Fall 2000 Lecture 10 25 Why? Consider crosstalk! 1 R 0 R DEMO 2 R C dt dV α DEMO ok dt dV C 6.002 ... signals characteristic impedance →R T2 T 5 2.5 0 V5 0 V5 0 V5 6.002 Fall 2000 Lecture 6 25 Question: So why did our circuits work? More in 6.014 t V5 V5.2 3. Termination P a r a l l...

Ngày tải lên: 22/12/2013, 19:17

... 6.002 CIRCUITS AND ELECTRONICS Sinusoidal Steady State 6.002 Fall 2000 Lecture 16 1 2 Fourth try to find ... + – R i C + v I v C – v I ( t ) = V i cos ω t for t ≥ 0 ( V i real) = 0 for t < 0 v C (0) = 0 for t = 0 I v 0 t 6.002 Fall 2000 Lecture 16 4 1 1 1 1 e c t u r Example:

Ngày tải lên: 12/12/2013, 22:15

... 6.002 Fall 2000 Lecture 1 14 6.002 CIRCUITS AND ELECTRONICS State and Memory 6.002 Fall 2000 Lecture 10 14 A Stored value leaks away store pulse width >> R ON C Building a memory element ... resistance R IN B Second attempt  buffer R IN store buffer d IN d OUT C * 5 ln OH IN V CRT −= LIN RR >> Better, but still not perfect. Demo Building a memory element … 6.002 Fall 20...

Ngày tải lên: 12/12/2013, 22:15

... 10 -3 Amp·Volt R = 1kΩ Dependent Sources: Examples 6.002 – Fall 2002: Lecture 8 1 6.002 CIRCUITS AND ELECTRONICS Dependent Sources and Amplifiers 6.002 – Fall 2002: Lecture 8 8 Another dependent ... Fall 2002: Lecture 8 22 One nit … D i S V O v L R VCCS 1 I v O v For v O >0 , VCCS consumes power: v O i D For v O <0 , VCCS must supply power! () 2 1 2 −−= ILSO vR K Vv () 2 1 2 −...

Ngày tải lên: 12/12/2013, 22:15

... 6.002 Fall 2000 Lecture 1 24 6.002 CIRCUITS AND ELECTRONICS Power Conversion Circuits and Diodes 6.002 Fall 2000 Lecture 10 24 Now consider — a half-wave ... Conversion Circuits (PCC) Power efficiency of converter important, so use lots of devices: MOSFET switches, clock circuits, inductors, capacitors, op amps, diodes Reading: Chapter 16 and 4.4 of A & ... u s e r es i s t...

Ngày tải lên: 22/12/2013, 19:17

... switching capacitor. independent of f. MOSFET ON half the time. STATIC P DYNAMIC P constant time "RC" 2 T RR ONL >> >> Square wave input f T 1 = Demo Review In standby mode, half the gates ... 6.002 Fall 2000 Lecture 1 23 6.002 CIRCUITS AND ELECTRONICS Energy, CMOS 6.002 Fall 2000 Lecture 10 23 For our previous example — 1,MHz100f,V5VF,f1C S === “keep ... MOSFET...

Ngày tải lên: 22/12/2013, 19:17

... 6.002 Fall 2000 Lecture 1 15 6.002 CIRCUITS AND ELECTRONICS Second-Order Systems 6.002 Fall 2000 Lecture 10 15 0 2 2 =+ H H v d t vd LC Solution ... back and forth between the Capacitor and the inductor 6.002 Fall 2000 Lecture 19 15 RLC Circuits See A&L Section 12.2 add R no R + – C R L + – )( tv )(tv I )( ti )( tv t Damped sinusoids ... Method 1 2 3 Write DE for circuit by a...

Ngày tải lên: 12/12/2013, 22:15

... 6.002 Fall 2000 Lecture 1 13 6.002 CIRCUITS AND ELECTRONICS Digital Circuit 6.002 Fall 2000 Lecture 10 13 Falling Delay t f Equivalent circuit

Ngày tải lên: 12/12/2013, 22:15

... 6.002 Fall 2000 Lecture 1 12 6.002 CIRCUITS AND ELECTRONICS Capacitors and First-Order Systems 6.002 Fall 2000 Lecture 10 12 2 Homogeneous ... 55 RC t e − 5 RC = τ Remember demo B Examples 6.002 Fall 2000 Lecture 2 12 5V 0V C A B 5V A B C 5 0 5 0 5 0 Reading: Chapters 9 & 10 Demo 5V Expected Observed Expect this, right? But observe this! Delay! Motivation 6.002

Ngày tải lên: 12/12/2013, 22:15

... the same KVL, KCL equations BOUTA VVV ++++ """ so, we can cancel them out BOUTA vvv ++++++ """" 1 bouta vvv ++++ """ Leaving 2 Since small signal models ... circuit. Foundations: (Also see section 8.2.1 of A&L) KVL, KCL applied to some circuit C yields: III The Small Signal Circuit View bBoutOUTaA vVvVvV +++++++ """ Replace...

Ngày tải lên: 12/12/2013, 22:15