Tài liệu Circuits & Electronics P15 docx
Tài liệu Circuits & Electronics P15 docx
... 6.002 Fall 2000 Lecture
1
15
6.002
CIRCUITS
AND
ELECTRONICS
Second-Order Systems
6.002 Fall 2000 Lecture
10
15
0
2
2
=+
H
H
v
d
t
vd
LC
Solution ... back and forth between the
Capacitor and the inductor
6.002 Fall 2000 Lecture
19
15
RLC Circuits
See A&L Section 12.2
add
R
no
R
+
–
C
R
L
+
–
)(
tv
)(tv
I
)(
ti
)(
tv
t
Damped sinusoids ... Method
1
2
3
Write DE for circuit by a...
Tài liệu Circuits & Electronics P13 docx
... 6.002 Fall 2000 Lecture
1
13
6.002
CIRCUITS
AND
ELECTRONICS
Digital Circuit
6.002 Fall 2000 Lecture
10
13
Falling Delay t
f
Equivalent circuit
Tài liệu Circuits & Electronics P21 docx
... feedback
+
–
2
R
o
v
1
R
i
v
21
1
RR
Rv
v
o
+
=
+
21
1
RR
RV
v
S
+
=
+
21
1
RR
RV
v
S
+
−
=
−
So
Vv
+=
15
So
Vv
−=
15−
15
e.
g.
21
=
=
S
V
RR
5.7v
v)vv(
i
>
>=
−
+−
5.7−<
<
−
+
−
v
vv
i
v
6.002 Fall 2000 Lecture
11
21
Why is hysteresis useful?
e.g., ... disturbance to v
o
(noise).
Now, let’s build some useful circuits with
positive feedback.
+
>
−
γγif
stableeKv
positiveisT...
Tài liệu Circuits & Electronics P17 docx
... 6.002 Fall 2000 Lecture
1
17
6.002
CIRCUITS
AND
ELECTRONICS
The Impedance Model
6.002 Fall 2000 Lecture
10
17
The Big Picture…
tV
i
ω
cos
[]
pp
VtV
∠+
ω
cos
set
up
DE
usual
circuit
model
nightmare
trig.
6.002
Tài liệu Circuits & Electronics P16 pptx
... 6.002
CIRCUITS
AND
ELECTRONICS
Sinusoidal Steady State
6.002 Fall 2000 Lecture
16
1
2
Fourth try to find ...
+
–
R
i
C
+
v
I
v
C
–
v
I
(
t
)
= V
i
cos
ω
t
for
t ≥
0 (
V
i
real)
= 0
for
t <
0
v
C
(0)
=
0
for
t =
0
I
v
0
t
6.002 Fall 2000 Lecture
16
4
1
1
1
1
e
c
t
u
r
Example:
Tài liệu Circuits & Electronics P14 pptx
... 6.002 Fall 2000 Lecture
1
14
6.002
CIRCUITS
AND
ELECTRONICS
State and Memory
6.002 Fall 2000 Lecture
10
14
A
Stored value leaks away
store
pulse width >>
R
ON
C
Building a memory element ... resistance
R
IN
B
Second attempt buffer
R
IN
store
buffer
d
IN
d
OUT
C
*
5
ln
OH
IN
V
CRT −=
LIN
RR >>
Better, but still not perfect.
Demo
Building a memory element …
6.002 Fall 20...
Tài liệu Circuits & Electronics P12 pdf
... 6.002 Fall 2000 Lecture
1
12
6.002
CIRCUITS
AND
ELECTRONICS
Capacitors
and First-Order Systems
6.002 Fall 2000 Lecture
10
12
2
Homogeneous ... 55
RC
t
e
−
5
RC
=
τ
Remember
demo
B
Examples
6.002 Fall 2000 Lecture
2
12
5V
0V
C
A
B
5V
A
B
C
5
0
5
0
5
0
Reading:
Chapters 9 & 10
Demo
5V
Expected
Observed
Expect this, right?
But observe this!
Delay!
Motivation
6.002
Tài liệu Circuits & Electronics P11 pdf
... the
same KVL, KCL equations
BOUTA
VVV
++++
"""
so, we can cancel them out
BOUTA
vvv
++++++
""""
1
bouta
vvv
++++
"""
Leaving
2
Since small signal models ... circuit.
Foundations: (Also see section 8.2.1 of A&L)
KVL, KCL applied to some circuit C yields:
III The Small Signal Circuit View
bBoutOUTaA
vVvVvV
+++++++
"""
Replace...
Tài liệu Circuits & Electronics P10 doc
... 6.002
CIRCUITS
AND
ELECTRONICS
Amplifiers
Small Signal Model
6.002 Fall 2000 Lecture
10
1
Graphically ...
)
2
V
O
= V
S
−
R
L
K
(
V
I
−V
T
)
2
2
2
substituting
v
I
= V
I
+ v
i
v
i
<< V
I
v
O
= V
S
−
R
L
K
(
[
V
I
+ v
i
]
− v
T
)
2
2
= V
S
−
R
L
K
(
[
V
I
−V
T ...
corresponding
v
I
−V
T
interesting
v
I
−V
T
region for v
O
v
I
−V
T
S...
Tài liệu Circuits & Electronics P9 doc
... MODEL
DS
v
DS
i
Demo
TGS
Vv
<
TGS
Vv
<
2GS
v
3GS
v
+
–
DS
v
+
–
DS
i
GS
v
TGSDS
Vvv
−=
Cutoff
region
6.002 Fall 2000 Lecture
7
9
Graphically
DS
v
DS
i
TGS
Vv
≥
TGS
Vv
<
TGS
Vv
≥
1GS
v
Saturation
region
T
r
i
o
d
e
... resistor model would have you believe.
D
S
G
D
S
TGS
Vv
<
G
TGS
Vv
≥
?
6.002 Fall 2000 Lecture
6
9
Graphically
DS
v
DS
i
TGS
Vv
≥
TGS
Vv
<
TGS
Vv
≥
1GS
v
Sat...
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