... n 0, 11 n 2, 1, 5n 0, 75 0, 12 75 Theo bi Cụng thc ca pentapeptit l C11H19O6 N5 Bo ton lng C, ta tớnh c n M ỏp ỏn A Cõu 14 Bi gii : CuSO4 Cu n O2 n CO2 11 0, 01 (mol) m 3, 17 (gam) ... Gii h (1) ;(2) ta c x 0, (mol); y 0, 15 (mol) n e ( ) 3.0, 0, 15 1, (mol) Tuyt nh Luyn Húa Hc THPT Quc Gia 2 015 n HNO3 = n NO (mui) + n NO = 1, 5 + 0,2 = 1, 7 (mol) a = 2(M) Cỏch 2: 18 , 367.39, ... Cõu 12 Bi gii : Do X thy phõn to X1; X2 u cú kh nng tham gia phn ng gng nờn X1 ; X2 l saccarozo C12 H22O 11 C6 H12O6 (glucozo) C6 H12O6 (fructozo) Glucoz v fructoz l ng phõn ca Khi tham gia...