... 1) x + 4m3 + m x+m mx + 2m2 x 3m3 ( x + m) g ( x ) = mx + 2m x 3m3 = (1) ycb (1) cú nghim phõn bit x1 , x2 khc m cho: 0,25 x < < x y ( x1 ) y ( x2 ) < Cõaõu II (2im) m P = 3m < 2 ... = 0(vụ nghiờm) x+m m m + 1)2 4m(4m3 + m) < 15m 2m + < y = (m m m 1 m > m < m > 1 m< m> ỏp s: 5 tgx + tg2x= - sin3x.cos2x sin 3x = sin x.cos x cos x.cos x ẹieu kieọn cosx.cos2x ... 0, - b), b > 1 VBCMN = VMOBC + VNOBC = MO.SOBC + NO.SOBC 3 = SOBC ( MO + ON ) = (a + b) 3 VBCMN nh nht ch MN ngn nht 0,25 0,5 Xỏc nh a, b MN ngn nht r uuur uuuu r n = MB, MC = (0, 2a, 3) ...