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Một phần của tài liệu Phân dạng và phương pháp giải hóa học 11 phần vô cơ (Trang 64)

BAI TAP M A U VA BAI TAP AP D U N G

Bai 1. Lap phtfdng trinh h6a hoc cua cic phan tfng sau dSy :

a) C + H 2 S 0 4 d 5 cC O 2 + S O 2 + ? b) C + H N O 3 dj. NO2 + C O 2 + ? b) C + H N O 3 dj. NO2 + C O 2 + ? c) C + CaO CaCz + CO 126 I d) C + SiOj > Si + CỌ Gidi a) C + 2 H 2 S O 4 , , , . b) C + 4HN03,^, c) 3C + CaO — ^ d) 2C + SiOz — ^ + 4 COj + 2 S O 2 + 2 H 2 O 4 N 0 2 + C 6 2 + 2 H 2 0 C a C 2 + CO Si + 2C0.

Bai 2. Viet cac phiTdng trinh phan iJng theo scJ do sau :

C a C l 2 - ^ CaS04 ^^^CaO (9) ( 7 ? (8) (1) (2) (3) (4) (5) (6) (7) (8) (9) CO2 Ca3(P04)2 Giai -> CaCOj + 2KC1 Ca(HC03)2 C a C l 2 + K2C03

CaCOj CaO + CO2

CaO + C O 2 > CaCOs

Ca(HC03)2 CaCOj + CO2 + H2O

CaC03 + C O 2 + H2O > Ca(HC03)2 CaCOj + 2HC1 > CaClz + C02t + H2O

3CaC03 + 2H,P04 > Ca3(P04)2 + SCOjT + 3H2O

3CaO + 2H3P04 > Ca3(P04)2 + SHjO Ca(HC03)2 + 2HC1 > CaCb + 2CO2 + 2H2O (10) CaC03 + H2S04 > CaS04 + CO2 + H2Ọ

B4i3.

a) Lam the nao de chuyen NaHCOj thknh Na2C03, CăHC03)2 thanh CaC03 va ngi/dc laị ngi/dc laị

b) Khi nung ndng kem oxit vdi than c6c thi tao th^nh mot chat khi chdy di/dc. Viet phiTdng trinh phan tfng hoa hoc cua phan tfng. Viet phiTdng trinh phan tfng hoa hoc cua phan tfng.

Giai

a)* chuyen NaHCOj thanh Na2C03 ta cho NaHC03 tic dung vdi dung dich

NaOH.

NaHC03 + NaOH > Na2C03 + H2O

* D l chuyen CăHC03)2 thanh CaC03 ta dem muoi CăHC03)2 khan nung

Phan dgng phJong ph^p giSi H6a hgc 11 va cO - D8 Xufln Hung

CăHC03)2 CaCOj + CO2 + H2O

* NgiTdc lai : chuyen NajCOj thanh NaHCOj va CaCOj th^nh Ca(HC03)2 ta

cho hai muoi Na2C03 va CaCOs Ian liTcJt vao dung dich CO2 bao hoạ

Na2C03 + CO2 + H2O > 2NaHC03 CaCOa + C O 2 + H2O > Ca(HC03)2. CaCOa + C O 2 + H2O > Ca(HC03)2.

b) ZnO + C Z n + CO 2 C 0 + 0 2 - ^ 2CO2.

Bai 4. Hoan thanh can hkng cac phan uTng oxi hoa khuT sau :

a) Ca3(S04)2 + CI2 + C > P O C I 3 + CO + C a C l 2

b) C S 2 + 0 2 ^ C O 2 + ?

c) FexOy + CO FeO + CO2

d) CuO + C ^ ? + C O 2

e) Ca3(P04)2 + Si02 + C P + CaSiOj + CO f) Mn04 +C6H|206 + H^ f) Mn04 +C6H|206 + H^ (adsbygoogle = window.adsbygoogle || []).push({});

g) C,2H220n + H2S04dac-

> Mn^* + C O 2 + ...

a) Ca3(P04)2 + 6CL + 6C

-> COzt + H2O + SOzt.

Gidi -> 2POCI3 + 6 C 0 + 3CaCl2 -> 2POCI3 + 6 C 0 + 3CaCl2 +2 - I 0 b) CSj + 3O2 - ^ - ^ +2y/x +2 c) Fe^O, + ( y - x ) C O + 4 - 2 + 4 - 2 CO2 + 2SO2 +2 + 4 xFeO + ( y - x ) CÔ +2 0 d) 2CuO + C + 4 2Cu + CO, e) Ca3(P04)2 + 3 S i 0 2 + 5C 0 2 4 M n O ; + 5QH,206 + 72H*• 2P + 3CaSi03+ 5 CO 24Mn^++ 3OCO2 + 66H2O 24 X 5 X + 7 Mn +5e- 0 6C +2 -> Mn + 4 -> 6 C + 6 X 4e

hay 24KMn04 + SCfiHuOe + 36H2SO4 • -> 24MnS04 + I2K2SO4 +

+ 3 0 C O 2 t + 66H2O g) C,2H220„ + 24H2SO4 + 4 -> 12 CO J + 3 5 H 2 O + 24SO2T 1 X 24 X 0 12c — + 6 S +2e- + 4 -> 12c+4 + 12x4e -> S . 128

ai 5. Bo tuc chuSi phan ufiig, viet cdc phtfdng trinh phan uTng (m6i mui ten 1^ mot

phan tfng). Cho biet B Ik khi dting nap cho c^c binh chỉa lufa (dap t^t luTa). A Ik khodng san phd bien thUcJng dilng 6i san xuS't voi song. khodng san phd bien thUcJng dilng 6i san xuS't voi song.

A,

^'

NaQH D

HCl (Trich TS DHQC TP.HCM)

Gidi

A:CaC03 B : CO2 C : NaHC03 D : NazCOj

E:Că0H)2 F : CaCb

CaCOj CaO + CO2

C02 + NaOH >NaHC03

C02 + 2NaOH >Na2C03 + H20

NaHC03 + NaOH > Na2C03 + H2O

Na2C03 + HCl > NaHC03 + NaCl

NaHC03 + Ca(0H)2 > NaOH + CaCOj + H2O

NasCOj + CaCla > CaCOj + 2NaCl.

Bai 6. Tur nguyen lieu chinh Ih muoi an, đ voi, ntfdc, khong khi va chát xuc tic

c6 dụ Viet cac phiTdng trinh dieu che cac chát sau:

a) N H 4 H C O 3 b) (NH4)2C03 c) NajCOj.

Gidi

a) 2NaCl + 2H2O — . > 2NaOH + Hzt + C^t

^ C O m a n g ngSn ^ CaC03 CaO + CO2

(H6a long khong khi sau do chiftig cS't phan doan Ian luTdt ISy N2 roi den O2). (adsbygoogle = window.adsbygoogle || []).push({});

N2 + 3H2 , • 2NH3

p

CO2 + N H 3 + H 2 O > N H 4 H C O 3 b) N H 4 H C O 3 + NH3 > (NH4)2C03

c) (NH4)2C03 + 2NaOH > NazCOj + 2NH3 + 2H2O hoac C02 + 2NaOH >Na2C03 + H20. hoac C02 + 2NaOH >Na2C03 + H20.

Bai 7. Cho cic chát CaC03, dung dich NaOH, dung dich NaHCOj, dung dich HCl. Vid't cdc phiTdng trmh phan tfng hoa hoc xay ra khi cho cic chS't tac HCl. Vid't cdc phiTdng trmh phan tfng hoa hoc xay ra khi cho cic chS't tac

dung vdi nhau tilfng d6i mot.

(TNTHPT)

Phan d?ng va phuong ph&p giai H6a hpc 11 V6 cd - D8 XuSn Hung

Gidi

CaCOj + 2HC1 > CaCb + COzt + H2O

NaOH + NaHCOj > NaiCOj + H2O

NaOH + HCl > NaCl + H2O

NaHCOj + HCl > NaCl + COst + HjỌ

Bai 8. Co cac chat sau : CO2, Na2C03, C, NaOH, NazSiOj, HjSiOj. Hay lap

thanh mot day chuyen hoa gifl"a cac chat va viét cac phiTcJng trinh hoa hpc.

Gidi

Day sd do bien hoa :

C CO2 N&iCOi NaOH NazSiOj HiSiOj

t <5>

(1) C + 0 2- ^ C 0 2

(2) CO2 + 2Na0H > NaiCOj + H2O

(3) Na2C03 + Bă0H)2 > BaCOj + 2NaOH (4) 2 N a O H + Si02 > NazSiOj + H2O

(5) NazSiOj + 2HC1 > 2NaCl + H2Si03

(6) Na2Si03 + CO2 + H2O > NazCOj + H2Si03.

Bai 9. Nhiet phan mot lirpng CaC03, sau mot th6i gian di/cJc chS't r^n A khi

B. Cho khi B hap thu hoan toan vao dung dich KOH, thu difdc dung dich D.

Dung dich tic dung dÚdc vdi dung dich BaCl2 va vdi dung dich NaOH. Cho r^n A tac dung vdi dung dich HCl di/, diTdc khi B va dung dich Ẹ Co can

dung dich E difdc muoi khan F. Dipn phan muoi F nong chay, di/dc kim loai M. Viet phiTdng trinh hoa hoc cua cac phan tfng xay rạ

Giai

KHCO, (adsbygoogle = window.adsbygoogle || []).push({});

A : CaO; CaC03 duf B : CO2 Dung dich D

[K2CO3

Muoi khan F : CaClj Dung dich E : CaCl2 M : Cạ CaCOj CaO + CO2

CO2 + KOH )-KHC03

CO2 + 2K0H — y K2CO3 + H2O

Ca0 + 2HC1 >CaCl2 + H20

CaC03 + 2HCl > CaClz + COzt + H2O K2CO3 + BaClz > BaCOjJ- + 2KC1

2KHGO3 + 2 N a O H > K2CO3 + Na2C03 + 2H2O

CaClj -^2SL> Ca + C b t .

'Bai 10. Viet cdc phiTcfng trinh h6a hoc theo cdc set do sau :

a) Silic dioxit > natri silicâ—-+^aÂ^ dioxit magie silixua < silic magie silixua < silic

b) CO2 > CaC03 > Ca(HC03)2 > CO2 > C > CO >• CO2.

Gidi

a) Si02 >-Na2Si03 • HzSiOs >• Si02

Mg2Si < Si

Si02 + 2NaOH > NazSiOj + H2O

Na2Si03 + CO2 + H2O > Na2C03 + H2Si03

H2Si03 -A Si02 + H2O

Si02 + 2C Si + 2C0

Si + O2 SiOz

Si + 2Mg Mg2Si

Si + 2NaOH + H2O > Na2Si03 + 2H2t.

b) CO2 + Ca(OH)2 > CaC03 + H2O

CaC03 + CO2 + H2O >Ca(HC03)2

Ca(HC03)2 CaC03 + CO2 + H2O CO2 + 2Mg 2MgO + C

C + CO2 2C0

CO + O2 CO2.

Bai 11.

a) Viét phuTdng trinh hoa hoc cua phan iJng m6 ta thuy tinh bi axit H F an m6n.

Biet r!ing thanh phan chu yeu cua thiiy tinh Ik NaiSiOj (Na20.Si02) (adsbygoogle = window.adsbygoogle || []).push({});

CaSi03 (CaO.Si02).

b) Tilf Si02 vk c&c hda cha't can thiet khac hay v i ^ t phifdng trinh hda hpc c i a cic phan urng dieu c h ^ axit silixic. cic phan urng dieu c h ^ axit silixic.

Gidi

a) Na2Si03 + 6 H F - - -> SiF4t + 2NaF + 3H2O

CaSiOa + 6HF > SiF^ + CaF2 + SH.O

b) Si02 + 2 N a O H > NajSiOj + H2O

Bai 12. Bo tuc va hoan thanh cac phan iJng sau : Cacbon + HNO3 jsc > A + NO2 + HjO Cacbon + HNO3 jsc > A + NO2 + HjO A + cacbon > B B + CI2 photgen HCOOH B + H2O B + O2 A A + NaOH >C + H20 C + Si02 > D + A D + A + H2O >C + E E Si02 + H2Ọ Gidi A:C02 B : C O C: Na2C03

D : Na2Si03 E : H2Si03 Photgen : COCI2.

C + 4HNO3 JSC > CO2 + 4NO2 + 2H2O CO2 + C- A 2 C O

CO + CI2 ^ COCI2

HCOOH "a^Q^dac^ CO + H2O 2C0 + 0 2 - ^ 2CO2

C02 + 2NaOH )• Na2C03 + H2O

Na2C03 + Si02 Na2Si03 + CO2

Na2Si03 + CO2 + H2O >Na2C03 + H2Si03

H2Si03 Si02 + H2Ọ

Dang 2. Nhcjn bi§'t, tach rdi, tinh chd' c 6 c chd't: CO, CO2, SiOa, muoi cacbonat

BAI TAP MAU VA BAI T^P AP DyNG

Bai 1. C6 ba khi gom CO, HCl va SO2 difng trong ba binh rieng bi$t. Trlnh bay phUdng phdp hoa hoc de phan bi$t tiTng khị Viet c^c phiTdng trinh h6a hoc. phUdng phdp hoa hoc de phan bi$t tiTng khị Viet c^c phiTdng trinh h6a hoc.

Giai

- Dan ba khi trdn Ian lifdt vao dung dich ntfdc voi trong dir. khi n^o tao kd't tua tr^ng la SO2, con lai la CO va HCl.

Một phần của tài liệu Phân dạng và phương pháp giải hóa học 11 phần vô cơ (Trang 64)