C. BAI TAP NANG CAO
b) Phan ufng: (C6Hio05) n+ nHg O) nCgHiaOe
(gam) 16,2 18 (gam)
CeHiaOe + AgsO ^^^"/^"^ ) CgHiaOy + 2Ag4.
18 x
1 8 X 2 X 1 0 8 8 0
Vi H = 80% nen mAg thu dirge thitc té = -^QQ
ai 16. Goi c6ng thufc tong qudt cua X, Y, Z, T la CxHyỘ^
Ta c6: n
= 1 7 , 2 8 (gam).
"^'^ = 0,1 (mol); riH 0 = ^ = 0,1 (mol) Phucfng trinh hoa hoc cua phan iJfng dot chay:
CxHyÔ + ' y x + - — 4 2 (mol) x + — — y z 4 2 O2 - > X C O 2 + ^ H a O ax 0,5ay Theo phaang trinh hoa hoc tren ta c6: xa = 0,5ay => y = 2x.
y z
X + -^^ = xa
4 2
(1) Thay y = 2x vao (1) ta c6: x + 0,5x - 0,5z = x => x = z Thay y = 2x vao (1) ta c6: x + 0,5x - 0,5z = x => x = z
Cong thufc tong quat cua cAc hap chat hufu cof X, Y, Z, T la: CJl2xỘ
Ma Mx : M Y : Mz : M T = 6 : 1 : 3 : 2. Mx 16n nhgit. My nho nhat vi X
khong quA 6 nguyen tuf C nen Y chi c6 the c6 1 C . Vay X la CeiiM; Y: C H 2 O ; Z: CsHsOg; T : C2H4O2. ai 17. Phifotng trinh phan ufng hoa hoc:
(C6H702(OH)3)„ + 2n(CH3CO)20
> (C6H702(OH)(OOCH3)2)„ + 2nCH3COOH
(C6HY02(OH)3)n + 3n(CH3CO)20
-> (C6H702(OOCH3)3)n + SnCHgCOOH
Khoi liiong xenlulozcf 950 tan trong d6 285 tan phan ufng tao diaxetat xenlulozd, 570 tan phan ufng tao th&nh triaxetat xenluloza, kh6l luang xenluloza khong phan ufng 95 tan.
285
Khoi liicfng diaxetat xenluloza: m i = —— x 204 = 358,9 tan.
162 570
Khoi liTcfng triaxetat xenluoza: m i = x 246 = 865,6 tan.
162
Khoi lufang h5n hgp san pham: m = 358,9 + 865,6 + 95 + 5 = 1324,5 tan.
3ai 18- Ban dau chi c6 mantoza phan ufng vdi brom
R-CHO + Bra + H 2 O > R-COOH + 2HBr
Ta c6: nmantoza = 10 X 0,05 X 0,01 = 5.10^^ (mol) hay khoi lifcfng mantoza = 1,71 gam, chiem 50% khoi liforng h6n hcfp daụ
Khi dun nong dung dich vdri HCl ca saccaroza, mantoza dau bi thuy phan
t"
Saccaroz0 + H 2 O > Glucoza + Fructoza
t"
( C i 2 H 2 2 0 i i + H 2 O > C6H12O6 + C6H12O6)
Mantoza + H 2 O > Glucoza + glucoza
(C12H22O11 + H 2 O > C6H12O6 + C6H12O6)
Do vay so mol B r 2 phan ufng la = 2nn,antozo + nsaccarozo = 1,5.10"^ mol =i> the tich dung dich nufdc brom 0,05 M tham gia phan ufng la: 30 ml.
Bai 19. Ban dau chi c6 mantoza, glucoza phan ufng trang bac theo t i le 1 : 2
R - C H O + 2AgN03 + 3NH3 + H 2 O
> R-COONH4 + 2Ag + 2NH4NO3
( C i 2 H 2 2 0 n + 2AgN03 + 3NH3 + H 2 O
> C12H22O12NH4 + 2Ag + 2 N H 4 N O 3 )
Va (C6H12O6 + 2AgN03 + 3NH3 + H 2 O
> C6H11O7NH4 + 2Ag + 2NH4NO3) Khi thuy phan: Mantoza + H 2 O > Glucoza + glucoza
(C12H22O11 + H 2 O — > C6H12O6 + C6H12O6)
Trong thi nghiem 1: so mol mantoza la x, glucoza la y trong 10 m l dung
dich, ta c6: 2(x + y)108 = 0,324
Mat khac: 10(342x + 180y) = 4,32 x = 1.10"^ mol va y = 5.10'* mol.
Trong thi nghiem 2: sau k h i thuy phan so mol glucozo trong 10,0 ml la
2,5.10-3 mol khoi luang Ag tao ra: 108 x 2 x 2,25.10-' = 0,54 gam.