... biến giả so sánh hồi qui Chuyên đề: Sử dụng biến giả nghiên cứu kinh tế 5.1 Tác động tương tác biến giả 5.2 Biến giả phân tích mùa 5.3 Hồi quy tuyến tính khúc 5.4 Biến giả mô hình logarit Chương ... cứu + Số liệu thu thập xửlý + Ước lượng kiểm định khuyết tật + Phân tích, đánh giá kiến nghị 7.4 Lịch thi kiểm tra: - Kiểm tra định kỳ: Sauchương - Thi hết môn: Saukết thúc môn học Bảng 1: ... QUI BỘI CHƯƠNG 4: 1 1 NHỮNG VẤN ĐỀ CƠ BẢN CỦA MÔ HÌNH HỒI QUI ĐƠN CHƯƠNG 2: ƯỚC LƯỢNG VÀ KIỂM ĐỊNH GIẢ THUYẾT HỒI QUY VỚI BIẾN GIẢCHƯƠNG 5: CHỈ ĐỊNH MÔ HÌNH CHƯƠNG 6: ĐA CỘNG TUYẾN CHƯƠNG 7:...
... diễn tả sau: B = A + Vốn vay - Trả lãi nợ vay (C) Cơ quan ngân sách quyền Ơ “C” tính đến tác động dự án đầu tư theo quan điểm quan quản lý ngân sách quyền Một dự án cần chi ngân sách dạng trợ ... biên dạng ngân lưu ròng dự án, thẩm định kinh tế biên dạng cho thấy lợi ích kinh tế ròng dự án sinh Chương bước giải thích cách xây dựng biên dạng ngân lưu dự án, đồng thời thảo luận tác động quan ... tổ chức tài hay quan quản lý ngân sách quyền, dự án gặp khó khăn khâu xin phép phê chuẩn tìm nguồn tài trợ Hay ngược lại, dự án có lợi theo quan điểm ngân hàng hay quan quản lý ngân sách khơng...
... ground { akи wə zishиən ən trakиiŋ dar } ¯ ¨ acre [MECH] A unit of area, equal to 43,560 square feet, or to 4046.8564224 square meters { aиkər } ¯ acrometer [ENG] An instrument to measure the density ... lelz } adjustable square [ENG] A try square with an arm that is at right angles to the ruler; the position of the arm can be changed to form an L or a T Also known as double square { ə jəsиtəи ... feasible solution; an 31 artificial voice artificial variable is used for equality constraints and for greater-than or equal inequality constraints { ¦ardиə¦fishиəl verиeиəиbəl } ¨ ¯ artificial voice...
... illustration, information can be either quantitative or nonquantitative Quantitative information is information that is expressed in numbers Examples of nonquantitative information are visual impressions, ... The concept can be written as an equation: Assets ϭ Liabilities ϩ Owners’ equity This equation is fundamental It governs all accounting We can write a similar equation in a form that emphasizes ... Purpose of Accounting ILLUSTRATION Information 1–1 Types of information Consists of Nonquantitative information Quantitative information Consists of Accounting information Nonaccounting information...
... induced voltage on this wire can be calculated from the equation shown below The voltage on the wire is positive downward because the vector quantity v × B points downward eind = ( v × B) ⋅ l = vBl ... SOLUTION The induced voltage on this wire can be calculated from the equation shown below The total voltage is zero, because the vector quantity v × B points into the page, while the wire runs in the ... 90.1 + 77.3 (0.0033 Wb) = 0.00229 Wb The flux density in the air gaps can be determined from the equation φ = BA : Bleft = φleft Bright = 1-7 Aeff = φ right Aeff 0.00193 Wb (0.07 cm )(0.07 cm )(1.05)...
... supplied by the source, the total current flow decreases 1-20 Demonstrate that Equation (1-59) can be derived from Equation (1-58) using simple trigonometric identities: p (t ) = v( t ) i (t ) = ... T ) = 200 N, to the right (b) The no-load steady-state speed of this bar can be found from the equation VB = eind = vBl v= VB 100 V = = 200 m/s Bl ( 0.5 T )(1 m ) (c) With a load of 25 N opposite ... 2.128 Ω To convert the equivalent circuit to the secondary side, divide each impedance by the square of the turns ratio (a = 230/115 = 2) The resulting equivalent circuit is shown below: REQ,s...
... supplied by the transformers is equal to the power consumed by the loads (within roundoff error), while the total reactive power Q A + QB supplied by the transformers is equal to the reactive power ... respectively Note that line currents are shifted by 30° due to the difference between line and phase quantities, and by a further 33.9° due to the power factor of the load IAP = 14.8∠-63.9° A IAS = ... below: + NSE + 600 V NC 120 V (b) The kVA rating of the autotransformer can be found from the equation S IO = (c) - N SE + N C NC + NC SW = (5000 VA ) = 6250 VA N SE 4NC The maximum primary current...
... regions by the two transformers If the per-unit base quantities in Region are chosen to be S base1 = 1000 kVA and VL ,base1 = 480 V, then the base quantities in Regions and will be as shown above ... vC(t) on the capacitor, we can write a Kirchhoff's Current Law equation at the node above the capacitor and solve the resulting equation for vC(t) i1 + i2 = (since the DIAC is an open circuit ... The natural response is the solution to the differential equation d vC + vC = dt RC The solution to the natural response differential equation is vC ,n ( t ) = A e − t RC where the constant A...
... vC(t) on the capacitor, we can write a Kirchhoff's Current Law equation at the node above the capacitor and solve the resulting equation for vC(t) i1 + i2 = (since the PNPN diode is an open circuit ... a forced response The natural response is the solution to the equation d vC + vC = dt RC The solution to the natural response equation is vC ,n ( t ) = A e − t RC where the constant A must be ... ω B2 sin ω t ) + V ( B1 sin ω t + B2 cos ωt ) = M sin ω t RC RC cosine equation: ω B1 + B2 = ⇒ RC B2 = −ω RC B1 sine equation: −ω B2 + V B1 = M RC RC ω RC B1 + ω RC + V B1 = M RC RC V B1 = M...
... VL / = 3464 V The induced voltage per phase in this machine (which is equal to Vφ at no-load conditions) is given by the equation E A = 2π N C φ f so φ= 4-5 EA = 2π N C f 3464 V = 0.0078 Wb 2π ... equal to 2300 V when the generator is running at no load? (b) What is the internal generated voltage of this machine at rated conditions? (c) How much field current is required to make VT equal ... (103 rad/s ) = 5.30 sin 2ω t W Note that the amount of mechanical power consumed by the loop is equal to the amount of electrical power created by the loop This machine is acting as a generator,...
... The total power that they must supply is 100 kW, so the system frequency can be found from the equations PLOAD = P + P2 ( ) ( PLOAD = sP1 f nl1 − fsys + sP f nl2 − f sys ( ) ) ( 100 kW = ( 0.1 ... = (1.5 MW/Hz )(61.0 Hz − 59.61 Hz ) = 2.09 MW PB = sPB PC = sPC (b) nlB − f sys nlC − fsys The equation in part (a) can be re-written slightly to express system frequency as a function of load ... 1.961fsys 5.137 fsys = 313.2 − PLOAD f sys = 313.2 − PLOAD 5.137 A MATLAB program that uses this equation to determine the power sharing among the generators as a function of load is shown below:...
... this information, we can calculate I A for any given load from equation IA = E A − Vφ jX S and the resulting reactive power from the equation Q = 3Vφ I A sin θ where θ is the impedance angle, which ... resistance is ignored, the internal generated voltage E A will increase as flux increases, but the quantity E Asin δ will remain constant Therefore, the voltage for any flux can be found from the ... voltage E A = 13,590 V, and the torque angle δ = 23° (c) Ignoring losses, the input power would equal the output power Since POUT = (0.85)(100 MVA ) = 85 MW and 120 f e 120 (50 Hz ) = = 3000 r/min...
... synchronous motor, so we can apply the power equation for synchronous motors to this system P= 3E A, g E A,m X S , g + X S ,m sin γ where γ = δ g + δ m From this equation, γ = sin −1 (X S ,g ) + X S ,m ... by the equation Pconv = PIN − PCU PCU = I A2 RA = (156 A ) ( 0.08 Ω ) = 5.8 kW Pconv = PIN − PCU = 110 kW − 5.8 kW = 104.2 kW (g) The mechanical, core, and stray losses are given by the equation ... is the slip at rated load? (c) What is the speed at one-quarter of the rated load? (d) What is the rotor’s electrical frequency at one-quarter of the rated load? SOLUTION (a) This machine has...
... result to derive the expression for the pullout torque [Equation (754)] SOLUTION The current flowing in this circuit is given by the equation IL = IL = V RS + jX S + RL + jX L V ( RS + RL ) + ... 7-17 Plot the following quantities for the motor in Problem 7-14 as slip varies from 0% to 10%: (a) τ ind (b) Pconv (c) Pout (d) Efficiency η At what slip does Pout equal the rated power of the ... circuit must be the same as the power consumed by the original circuit.) (Note that I A2 RF is equal to I 2 PAG = I 2 (d) R2 = 3I A RF = ( 38 A ) ( 2.197 Ω ) = 9.52 kW s The power converted from...
... equations for E A and τ ind [Equations (8-38) and (8-49)] to prove that E A I A = τ ind ω m ; that is, prove that the electric power disappearing at the point of power conversion is exactly equal ... (8-6) eind = φ ω π is just a special case of the general equation for induced voltage in a dc machine EA = K φ ω (8-38) SOLUTION From Equation 8-38, where EA = K φ ω ZP K= 2π a For the simple ... one current path through the machine) Therefore, K= ZP ( ) ( ) = 2π a 2π (1) π and Equation 8-38 reduces to Equation 8-6 8-4 A dc machine has poles and a rated current of 100 A How much current...
... 237 % Calculate the resulting speed from Equation (9-13) n = ( e_a / e_a0 ) * n_0; % Calculate the induced torque corresponding to each % speed from Equations (8-55) and (8-56) t_ind = e_a * i_a ... interp1(if_values,ea_values,i_f); % Calculate the resulting speed from Equation (9-13) n = ( e_a / e_a0 ) * n_0; % Calculate the induced torque corresponding to each % speed from Equations (8-55) and (8-56) t_ind = e_a * i_a ... interp1(if_values,ea_values,i_f); % Calculate the resulting speed from Equation (9-13) n = ( e_a / e_a0 ) * n_0; % Calculate the induced torque corresponding to each % speed from Equations (8-55) and (8-56) t_ind = e_a * i_a...
... (r_f + r_adj) * i_f; % Find the point where the difference between the two % lines is exactly equal to i_a*r_a This will be the % point where the line line "Ea - Vt - i_a*r_a" goes % negative ... (r_f + r_adj) * i_f; % Find the point where the difference between the two % lines is exactly equal to i_a*r_a This will be the % point where the line line "Ea - Vt - i_a*r_a" goes % negative ... Therefore, the actual armature resistance is R A = (0.04)(1.058 Ω ) = 0.0423 Ω Continuing to solve the equation for Pconv , we get 0.0423 I A − 230 I A + 40, 000 = I A2 − 5434.8 I A + 945180 = I A = 179.9...