syntheses of the effects of employment based welfare and anti poverty policies
A study on the teachers' application of task-based method and the 10th form students' use of learning strategies in their listening lessons at Tran Phu High Sch
... knowledge of socio-cultural rules of language and of discourse This type of competence reveals an understanding of the social context in which language is used, of the roles of the participant, of the ... place in the classroom Secondly, the aim of the method is to ensure the accuracy of the rules and structures but not the meaning and the actual use of language in communication That is why there ... see the distinctive feature of the method, i.e the sentence is the basic unit of teaching and language practice and much of the lesson is devoted to translating sentences into and out of the...
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The syntheses of bis guanidium salts and their applications in asymmetric mukaiyama type SN2 alkylation reactions
... Chapter The Syntheses of Various Bis-Guanidium Salts Chapter The Syntheses of Various Bis-Guanidium Salts Chapt r 1: The Syntheses of Various Bis-Guanidium Salts 11 Chapter The Syntheses of Various ... obtained, and for most of the substrates, the yields were good Two catalytic systems were studied, and each of them had their advantages and disadvantages At the last of this work, suggestions to further ... phase to the other and enhance the reactivity In the middle to late 1960s, Starks, Makosza and Brandstorm discovered and built the foundation of phase transfer reactions.4,5 Based on their own...
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syntheses of tio2(b) nanowires and tio2 anatase nanowires by hydrothermal and post-heat treatments
... preheated oven of 100–900 1C After h heat-treatment, they were taken out from the oven and cooled down to the room temperature 2.3 Characterization The microstructures of the as-synthesized and the heat-treated ... nanowires Those of (c) and (d) show both nanowires and small amount of particles Over 800 1C, the surfaces of nanowires became smooth because of the progress of surface diffusion (At 4800 1C, they may ... 900 1C) Figs and show the SEM images and XRD patterns of the heat-treated samples: (a)–(d) are samples heated for h at 600, 700, 800 and 900 1C, respectively The SEM images of (a) and (b) show...
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báo cáo hóa học: " Back disorders and lumbar load in nursing staff in geriatric care: a comparison of home-based care and nursing homes" pptx
... interpreted the data and drafted the manuscript AN participated in the design of the study and interpreted the data BBB participated in the coordination of the study and helped to draft the manuscript ... condition of their general health, their work ability in relation to the demands of the work and their mental resources than did their colleagues in nursing homes This agrees with the Page of (page ... assessed their general state of health, their mental resources and their ability to handle the physical and psychological demands of the job as being better than staff in nursing homes There was...
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Báo cáo hóa học: " Research Article Interference Mitigation Technique for Coexistence of Pulse-Based UWB and OFDM" doc
... a0n and a1n become the same when the total number of subcarriers in the OFDM is an even number For the MBOFDM system, cos(φ) and cos(π fc TFFT + φ) become the K Ohno and T Ikegami 100 The APD of ... sequence) and add “+1” to set the code length The OFDM signal used is a MB-OFDM PAN system The bandwidth of the MB-OFDM signal is wider than the gap that exists in the DS-UWB spectrum depending on the ... the signal is passed through the BPF in the OFDM receiver and does not depend on the pulse waveform under the assumption that UWB bandwidth is wider than the OFDM system The BER performance of...
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A textbook of Computer Based Numerical and Statiscal Techniques part 62 docx
... Enter the no of term –5 Enter the value in form of x– Enter the value of x1 – Enter the value of x2 – Enter the value of x3 – 11 Enter the value of x4 – 13 Enter the value of x5 – 17 Enter the ... value in the form of y– Enter the value of y1 – 150 597 598 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Enter the value of y2 – 392 Enter the value of y3 – 1452 Enter the value of y4 – ... printf( the exact value of the function = %f”, s); getch(); } OUTPUT Enter the interval = 0.5 The exact value of the function = 1.103846 13.30 ALGORITHM FOR SIMPSON’S 1/3 RULE Step Step Start of the...
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A textbook of Computer Based Numerical and Statiscal Techniques part 1 ppt
... Preface The present book ‘Computer Based Numerical and Statistical Techniques’ is primarily written according to the unified syllabus of Mathematics for B Tech II year and M.C.A I year students of ... suggestions to improve the book and it will be gratefully accepted The authors wish to express their thanks to New Age International (P) Limited, Publishers and the editorial department for the inspiration ... discussed in detail and lucid manner so that the students should feel no difficulty to understand the subject A unique feature of this book is to provide with an algorithm and computer program...
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A textbook of Computer Based Numerical and Statiscal Techniques part 2 ppsx
... solution The inherent error arises either due to the simplified assumptions in the mathematical formulation of the problem or due to the errors in the physical measurements of the parameters of the ... maximum relative error Therefore it shows that X X X X when the given numbers are added then the magnitude of absolute error in the result is the sum of the magnitudes of the absolute errors in ... precision computing aids and by correcting obvious errors in the data Round-off Error: The round-off error is the quantity, which arises from the process of rounding off numbers It sometimes...
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A textbook of Computer Based Numerical and Statiscal Techniques part 3 ppsx
... decimal places are 0.1429 and 0.0909 11 respectively Find the possible relative error and absolute error in the sum of 0.1429 and 0.0909 Example Approximate values of Sol The maximum error in each ... value of 30.5286 = 7.342 = 30.4647 0.241 7.342 lies between 30.4647 – 0.0639 = 30 4008 and 30.4647 + 0.0639 = 0.241 Example 12 Find the product of 346.1 and 865.2 and state how many figures of the ... accurately should the length and time of vibration of a pendulum should be measured in order that the computed value of g is correct to 0.01% Sol Period of vibration T is given by T = 2π Therefore,...
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A textbook of Computer Based Numerical and Statiscal Techniques part 5 ppsx
... negative and f(b) be positive Then there is a root of f(x) = 0, lying between a and b Let the first approximation be x1 = (a + b) (i.e., average of the ends of the range) Now of f(x1) = then x1 ... division of mantissa of the numerator by that of the denominator and denominator exponent is subtracted from the numerator exponent The resultant exponent is obtained by adjusting it appropriately and ... normalizes the quotient mantissa Example 10 Calculate the sum of given floating-point numbers: 0.4546e5 and 0.5433e7 0.4546e5 and 0.5433e5 Sol When the exponent is not equal, the operand is kept...
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A textbook of Computer Based Numerical and Statiscal Techniques part 6 pptx
... iterations, the root of f ( x) = x3 − x − = up to three places of decimals is 1.325, which is of desired accuracy Example Find the root of the equation x3 – x – = between and to three places of decimal ... f(0.5) is negative and f(1) is positive Then the root lies between 0.5 and 40 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Second approximation: The second approximation to the root is given ... approximate value of the roots x7 and x8, we observed that, up to two places of decimal, the root is 2.74 approximately Example Using Bisection Method, find the real root of the equation f(x)...
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A textbook of Computer Based Numerical and Statiscal Techniques part 7 potx
... COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Since f(2) and f(3) are of opposite signs, therefore the root lies between and 3, so taking x0 = 2, x1 = 3, f(x0) = – 9, f(x1) = 1, then by ... 0.10203 Since, x3 and x4 are approximately the same upto four places of decimal, hence the required root of the given equation is 1.4036 54 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES ... using the formula x2 = x0 f ( x1 ) − x1 f ( x0 ) f ( x1 ) − f ( x0 ) and also evaluate f(x2) Step 3: Step 4: If f(x2) f(x1) < 0, then go to the next step If not, rename x0 as x1 and then go to the...
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A textbook of Computer Based Numerical and Statiscal Techniques part 8 doc
... loge – 12 = – 4.0986 and f(4) = 42 – loge – 12 and 2.6137 Therefore, f(3) and f(4) are of opposite signs Therefore, a real root lies between and For the approximation to the root, taking x0 = ... of the equation x – e–x = correct to three decimal places [Ans 0.567] Find the real root of the equations: (a) x = tan x (b) x2 – loge x – 12 = (c) 3x = cos x + Find the rate of convergence of ... Hence the required root is 2.365 correct to four significant digits 61 ALGEBRAIC AND TRANSCENDENTAL EQUATION PROBLEM SET 2.2 Find the real root of the equation x3 – 2x – = by the method of Falsi...
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A textbook of Computer Based Numerical and Statiscal Techniques part 9 docx
... Similarly, PROBLEM SET 2.3 Use the method of Iteration to find a positive root between and of the equation xex – [Ans 0.5671477] Find the Iterative method, the real root of the equation 3x – log10 x ... each step is proportional to the square of the previous error and as such the convergence is quadratic Example Find the real root of the equation x2 – 5x + = between and by NewtonRaphson’s method ... −xn < ε, where ε is the prescribed accuracy 2.7.2 Order (or Rate) of Convergence of Newton-Raphson Method Let α be the actual root of equation f(x) = i.e., f(a) = Let xn and xn+1 be two successive...
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A textbook of Computer Based Numerical and Statiscal Techniques part 10 ppt
... replace the function f ( x) by a straight line passing through the points ( xn , f ( x n )) and ( xn −1 , f ( xn −1 )) and take the point of intersection of the straight line with the x-axis as the ... convergence of the secant method is superlinear The purpose of this document is to show the following theorem: Roots of above equation are ∞ Theorem 2.1: Let {xk }k be the sequence produced by the secant ... find a root of the equation x3 – 3x – = (U.P.T.U 2005) [Ans 2.279] Find the four places of decimal, the smallest root of the equation e–x = sin x [Ans 0.5885] Find the cube root of 10 [Ans 2.15466]...
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A textbook of Computer Based Numerical and Statiscal Techniques part 11 pdf
... for the approximated values of p and q Since R and S are both functions of the two parameters p and q then the improved values are given by R(p + ∆p, q + ∆q) = .(4) S(p + ∆p, q + ∆q) = Expand ... Find the quadratic factor of the equation x4 – 6x3 + 18x2 – 24x + 16 = using Bairstow’s method where p0 = – 1.5 and q0 = Also, find all the roots of the equation Sol Let the quadratic factor of the ... remainder terms must vanish, therefore the problem is then to find p and q such that R(p, q) = and S (p, q) = .(3) If we regularly change the values of p and q, we can make the remainder zero or at...
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A textbook of Computer Based Numerical and Statiscal Techniques part 12 pdf
... ∆1(2) can be computed since the other quantities are known (2) If a q-element is at the top, then the sum of one pair is equal to that of the other pair For example, in the rhombus ∆(1) q(0) q(1) ... ∆(1) (0) ∆3 Remarks: (1) If an ∆ element is at the top of the rhombus, then the product of one pair is equal to that of the other pair For example, in the rhombus (2) q1 (1) ∆1 ∆1 (2) (1) q2 We have ... find the complex roots and multiple roots of polynomials and also for determining the Eigen values of a matrix An important feature of the method is that it gives approximate values of all the...
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