chuyên đề bài tập hóa lớp 8

... Bài tập 1: Hoà tan hoàn toàn 16 .8 gam sắt kim loại vào dung dịch Axit HCl. Tính thể tích khí thu được ở điều kiện tiêu chuẩn và khối lượng muối thu được. Giải: Theo bài ra ta có: Fe Fe m 16 .8 n ... n.22.4 = I. Hệ thống bài tập hoá học: Loại 1. Theo quy tắc hoá trị Loại 2. Bài toán tính theo công thức hoá học Loại 3. Tính theo phương trình hoá học Dạng 1: Tính theo phương trình hóa học Dạng 2. ... 0,05 .80 = 7,2 gam 4 %CuO .100% 50% 8 = = Dạng 2; Bài toán lượng dư Khi hiệu suất phản ứng đạt 100%. Trong các chất tham gia phản ứng thì sau phản ứng vẫn còn dư một chất tham gia. Đối với bài...

... Ca(OH) 2 . Bài 10: Phân biệt 4 dd sau: Na 2 CO 3 ; CuSO 4 ; MgCl 2 ; K 2 S. 11 13 CHUN ĐỀ BÀI TẬP HĨA HỌC 9 Chun đề 1: BÀI TẬP NHẬN BIẾT. A. Nhận biết không hạn chế thuốc thử. A.1: Phương pháp. A.2: Bài ... CHẤT. Chun đề 6: TOÁN LIÊN QUAN ĐẾN NỒNG ĐỘ DUNG DỊCH. Chun đề 7: TÌM TP% CỦA CÁC CHẤT TRONG HH. Chun đề 8 : TOÁN LIÊN QUAN ĐẾN CHẤT KHÍ. Chun đề 9: TOÁN LIÊN QUAN ĐẾN HIỆU SUẤT PHẢN ỨNG. Chun đề 10: BÀI ... trước. Hãy xác định nồng độ HCl sau pư? Chun đề 12: CÁC BÀI TỐN CĨ SỬ DỤNG KHỐI LƯỢNG MOL TRUNG BÌNH. * Phương pháp: * Bài tập áp dụng: Bài 1: Hịa tan 2 ,84 g hh 2 muối CaCO 3 và MgCO 3 bằng dd...

... + (5a/ 68) 32 – (6a/ 68) 18 = 120a / 68 (g) ⇒ n NO = m NO : 30 = 4a/ 68 (mol) Ta có : m O = m O(NO) + m O(H2O) = (4a/ 68) .16 + (6a/ 68) .16 = 160a/ 68 Mà : m O(O2) = 5a/ 68 .32 = 160a/ 68 (g) ... công thức hóa học của A . Biết A chỉ chứa một nguyên tử nitơ . ( Đề thi HSG LỚP 9 Tỉnh BĐ 02-03 ) Bài giải ⇒ Trong A không chứa O . ⇒ Vậy A là hợp chất của N và H . Gọi công thức hóa học của ... của oxit sắt . (Đề HSGiỏi Tỉnh BĐ 04 - 05) Lập công thức hợp chất Bài tập 1 : Đốt cháy hoàn toàn a gam một hợp chất A của Nitơ cần 5a/ 68 mol O 2 chỉ thu được NO và 6a/ 68 mol H 2 O . Xác...

... + 65y ) + 85 x + 136y = 4 ,86 => x + y = (4 ,86 – 2.02) : 71 = 0,04 Bài giải  Vậy chất rắn không tan ở TN1 và TN2 chỉ gồm CuO nên phải nặng bằng nhau => mâu thuẫn với đề bài .  So ...  Trong TN2 có tất cả 16+2=18g Al 2 O 3 tan trong dd KOH . Theo PT ta có :  số mol K 2 O = ½ số mol KOH tan = 18: 102 (mol)  Khối lượng K 2 O = ( 18: 102 ). 94 = 16,59g . Bài tóan về lượng chất ... . Tính khối lượng mỗi oxit trong hh A . Bài tóan về lượng chất dư  Cho 2,02g hỗn hợp Mg và Zn vào cốc (1)đựng 200ml dd HCl .Sau phản ứng cô cạn dd được 4 ,86 g chất rắn .  Cho 2,02g hỗn hợp Mg...

... khí có 2 thành phần là Nitơ (N 2 ) và Oxi (O 2 ). Nitơ lỏng sôi ở 196 o C, còn Oxi lỏng sôi ở 183 o C. Làm thế nào để tách đợc Nitơ ra khỏi không khí? Nguyên tử 11.a, Nguyên tử là gì? b, So ... tử Na có nguyên tử khối 23 đvc, số hạt p = 11 Nguyên tử O có nguyên tử khối 16 đvc, số hạt p = 8 Nguyên tử H có nguyên tử khối 1 đvc ...

... 43,2 (g) Ta có 4,5 2M = 2,34 288 2 + M - 7,2 M = 1,17 144 + M - 17,1M = 2,7M+ 388 ,8 - 14,4M= 388 ,8 M= 4,14 8, 388 = 27(g) M= 27 đó là nhôm (Al) b, Nal = 27 4,5 = 0,2(mol) a) Tỡm CTHH ca nhụm ... Cu còn lại là: 1 28 – 85 ,332 = 42,668g %Cu = 42,6 68 149,333 . 100 = 28, 57% ; %CuO = 71,43% Bài 4: a) Đặt kim loại và khối lượng mol nguyên tử của nó là M, hoá trị n. Theo đề bài ta có: 2 2 ... của KCl ở 80 o C bằng 51g ở 20 o C là 34g Đa: 68g Bài 4. Độ tan của NaNO 3 ở 100 o C là 180 g, ở 20 o C là 88 g. Hỏi có bao nhiêu gam NaNO 3 kết tinh lại khi hạ nhiệt độ của 84 g dung dịch...

... x 1 08 = 10 ,8 g - Nếu vừa xong cả phản ứng (1) và (2) thì khi đó chất rắn A gồm: 0,1 mol Ag và 0,1 mol Cu m A = 0,1 ( 1 08 + 64 ) = 17,2 g theo đề cho m A = 15, 28 g ta có: 10 ,8 < 15, 28 < ... 319,8g và dung dịch NaOH 15% cần lấy là 295,2g 31 3 10 - 8 10 8 8 - 3 m 1 m 2 Tài liệu bồi d ỡng học sinh giỏi môn hoá học Chuyên đề 1: Viết phơng trình hoá học I/ Phản ứng vừa có sự thay ... + 18. 0,03 => x = 10,33 gam Bài toán 2: Cho 7 ,8 gam hỗn hợp kim loại Al và Mg tác dụng với HCl thu đợc 8, 96 lít H 2 (ở đktc). Hỏi khi cô cạn dung dịch thu đợc bao nhiêu gam muối khan. Bài...

... lợng sắt chứa 1kg e . Bài 3:Nguyên tử oxi có 8 p trong hạt nhân.Cho biết thành phần hạt nhân của 3 nguyên tử X,Y ,Z theo bảng sau: Nguyên tử Hạt nhân X 8p , 8 n Y 8p ,9n Z 8p , 10 n Những nguyên ... trên, A. quì tím B. dung dịch phenolphthalein C. dung dịch AgNO 3 D. tất cả đều sai chuyên đề 8 dung dịch L u ý khi làm bài tập: 1. Sự chuyển đổi giữa nồng độ phần trăm và nồng độ mol ã Công thức ... các muối tạo thành. Đáp số: a) 28 gam Fe và 32,5 gam kẽm b) 22,4 lít c) 2 FeCl m = 63,5gam và 2 ZnCl m = 68 gam Chuyên đề 7 : Oxi- hiđro và hợp chất vô cơ Bài 1: Có 4 bình đựng riêng các khí...

... là. gm FeSO 24, 18 100 84 4,14 .88 ,122 4 == Lợng muối sắt bị kết tinh là : gm FeSO 7 68, 12 100 70 .24, 18 4 == 0,5đ Gọi CTPT của tinh thể muối là : FeSO 4 .nH 2 O Theo bài ra ta có : 352,23 152 181 52 .7 68, 12 ... x16 = 6,4 gam Vậy m = 28, 4 + 6,4 = 34 ,8 gam Fe x O y +y H 2 xFe+ y H 2 O 0,4mol 0,4mol b/ mFe = 59,155 x 28, 4= 16 ,8 gam =>Khối lợng oxi là mO = 34 ,8 16 ,8 = 18 gam Gọi công thức oxit ... = 80 (0,5 điểm) Giaiû phương trình trên ta có : a = 465g (1,0 điểm) Trờng THCS Phù lÃng Năm học 2007 20 08 *** 0O0 *** Đề chính thức Đáp án Đề thi chọn HSG dự thi cấp huyện Môn: Hoá học lớp 8. Thời...

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... : A /Hóa xanh B /Hóa đỏ C /Hóa vàng D/Không đổi màu Câu 4 : Trong phản ứng : Fe 2 O 3 + 3CO t 0 2Fe + 3CO 2 A/ Fe 2 O 3 là chất khử B/ CO là chất khử C/ CO là chất ôxi hóa D/ Fe là chất ôxi hóa ... khí tronng nước : a) Đều tăng b) Đều giảm 8 A/Nước là chất tan, rượu là dung môi. B/Nước là dung môi, rượu là chất tan. C/Nước và rượu đều là chất tan D/Nước và rượu đều là dung môi. Phần ... : TỰ LUẬN ( 6 điểm ) Bài 1 : (1,5 điểm) Nêu tính chất hóa học của hiđro? viết phương trình minh họa Bài 2 : Hoàn thành các phương trình hóa học sau? Chỉ ra sự khử ,sự oxi hóa nếu có (1,5đ _điểm) CuO...