bài tập hình học lớp 9 có lời giải

... tròn đáy của hình trụ. 14 Bài 5: Cho hình chóp S.ABC có các cạnh SA, SB, SC vuông góc với nhau từng đôi một và SA = a, SB = b, SC = c. Tính bán kính mặt cầu ngọai tiếp hình chóp đó. Giải. ... Bài 3: Cho hình nón đỉnh S có đường sinh là a, góc giữa đường sinh và đáy là  . a) Tính thể tích và diện tích xung quanh của hình nón. b) Một mặt phẳng hợp với đáy một góc 60 0 và cắt hình ... RcbaSO acbSA          222 222 2 2 1 442 . Bài 6: Cho hình chóp S.ABCD có đáy ABCD là hình chữ nhật và có cạnh bênSA vuông góc với đáy. a) Xác định tâm mặt cầu ngọai tiếp hình chóp SABCD. b) Gọi (P) là mặt...

Ngày tải lên: 26/01/2014, 15:20

Ngày tải lên: 05/07/2014, 13:00

Ngày tải lên: 30/07/2014, 11:20

Ngày tải lên: 06/07/2014, 03:00

... O⇒Cung AC=CB =90 o . Ta lại có: Hình 19 2 Lời nói đầu: Trong quá trình ôn thi tốt nghiệp cho học sinh lớp 9, chúng ta đều nhận thấy học sinh rất ngại chứng minh hình học. Cũng do học sinh còn ... chữa một vài bài tập mà thôi. Do để học sinh có thể chủ động trong quá trình làm bài, các bài tập trong tài liệu này chỉ có tính cất gợi ý phương án chứng minh chứ chưa phải là bài giải hoàn hảo ... ta có: BC 2 =DB 2 +CD 2 =(BO+OD) 2 +CD 2 = =BO 2 +2.OB.OD+OD 2 +CD 2 .(1) Mà OB=R.∆AOC cân ở O có OAC=30 o . Hình 20 CI KJ FI AK = MỘT TRĂM BÀI TẬP HÌNH HỌC LỚP 9. Phần 1: 50 bài...

Ngày tải lên: 22/10/2013, 07:11

... nội tiếp . Lời giải: 1. Ta có : ACB = 90 0 ( nội tiếp chắn nửc đờng tròn ) => MCI = 90 0 (vì là hai góc kề bù). ADB = 90 0 ( nội tiếp chắn nửc đờng tròn ) => MDI = 90 0 (vì là ... + M 1 = 90 0 ( do tam giác AHM vuông tại H) => C 1 + C 4 = 90 0 => C 3 + C 2 = 90 0 ( vì góc ACM là góc bẹt) hay OCK = 90 0 . Xét tứ giác KCOH Ta có OHK = 90 0 ; OCK = 90 0 => ... đồng quy. Lời giải: 1. Xét hai tam giác ABC và EDB Ta có BAC = 90 0 ( vì tam giác ABC vuông tại A); DEB = 90 0 ( góc nội tiếp chắn nửa đờng tròn ) => DEB = BAC = 90 0 ; lại có ABC là...

Ngày tải lên: 25/11/2013, 20:12

... cao tương ứng đều có độ dài 8cm. 39 Bài tập hình học lớp 9 TTBDVH: Lửa Việt thuộc về đường tròn cố định có đường kính OA b) Tia OI cắt đường tròn tại C. Chứng tỏ tứ giác OACB là hình thoi, tính ... AB. 3 Bài tập hình học lớp 9 TTBDVH: Lửa Việt Định nghĩa và sự xác định đường tròn 1. Tính bán kính đường tròn đi qua 3 đỉnh của tam giác cân có cạnh đáy bằng đường cao tương ứng h. 2. Hình chữ ... minh AC⊥OB. 7 Bài tập hình học lớp 9 TTBDVH: Lửa Việt c) Cho A, B di động nhưng vẫn có OA⊥OB. Chứng minh các điểm M thuộc về một đường tròn cố định. 6. Trên đường trình (O; R) có ba điểm A, B,...

Ngày tải lên: 10/02/2014, 00:54

... 60).0,1 = 12,4 Vậy M = 64 tức Cu. 2 LỜI NÓI ĐẦU Để giúp cho các em học tốt môn Hoá học lớp 9 do vậy chúng tôi biên soạn cuốn “ Bài tập hoá học 9 . Sách được biên soạn theo chương trình ... 90 0g dung dịch NaCl bão hòa ở 90 o C. Bài tập 16 Tính khối lượng các muối thu được sau khi cho 28,8g axit photphoric tác dụng với 300g dung dịch KOH nồng độ 8,4%. Bài tập 17 30 Bài tập ... DẪN GIẢI BÀI TẬP NÂNG CAO Bài tập 1 - Na 2 O + H 2 O  2NaOH - SO 2 + 2 NaOH  Na 2 SO 3 + H 2 O - Na 2 SO 3 + H 2 SO 4  Na 2 SO 4 + SO 2  + H 2 O - SO 2 + K 2 O  K 2 SO 3 Bài tập...

Ngày tải lên: 25/02/2014, 17:14

... TUYỂN TẬP 80 BÀI TOÁN HÌNH HỌC LỚP 9 3. Theo trên ∠COD = 90 0 nên tam giác COD vuông t i O có OM ạ ⊥ CD ( OM là ti p tuy n ).ế ế Áp d ng h th c gi a c nh và đ ng cao trong tam giác vuông ta có ... i gi i:ờ ả 1. Xét t giác CEHD ta có: ứ ∠ CEH = 90 0 ( Vì BE là đ ng cao)ườ ĐẶNG NGỌC THANH TRƯỜNG THCS TỐNG VĂN TRÂN 1 TUYỂN TẬP 80 BÀI TOÁN HÌNH HỌC LỚP 9 T (1) và (2) => BAF là tam giác ... TUYỂN TẬP 80 BÀI TOÁN HÌNH HỌC LỚP 9 Bài 1. Cho tam giác ABC có ba góc nh n n i ti p đ ng tròn (O). Các đ ng cao AD, BE, CF c t nhauọ...

Ngày tải lên: 08/03/2014, 19:02

... quy tại 1 điểm Bài 49/ : Cho tam giác ABC có 3 góc nhọn nội tiếp đường tròn (O) có AB<AC.Vẽ 3 đường cao AD,BE,CF của tam giác ABC cắt nhau tại H 1/Tìm 3 tứ giác nội tiếp có đỉnh là H rồi ... điểm L thuộc (O) 4/Chứng minh : 3 đường thẳng EL,BD,AK cắt nhau tại 1 điểm Bài 39/ : Cho tam giác ABC có 3 góc nhọn nội tiếp đường tròn (O) ,3 đường cao AD,BE,CF cắt nhau tại H 2/Chứng ... .Chứng tỏ : tâm đường tròn ngoại tiếp tam giác DHS nằm trên OA Bài 45/Cho tam giác ABC có 3 góc nhọn nội tiếp (O:R) có góc BAC<60độ.Vẽ 2 đường cao BD và CE của tam giác ABC cắt nhau...

Ngày tải lên: 03/04/2014, 05:20

... MỘT TRĂM BÀI TẬP HÌNH HỌC LỚP 9. Phần 1: 50 bài tập cơ bản. 1 Lời nói đầu: Trong quá trình ôn thi tốt nghiệp cho học sinh lớp 9, chúng ta đều nhận thấy học sinh rất ngại chứng minh hình học. Cũng ... nghèo vì vậy học sinh yếu kỹ năng vận dụng nếu chúng ta chỉ chữa một vài bài tập mà thôi. Do để học sinh có thể chủ động trong quá trình làm bài, các bài tập trong tài liệu này chỉ có tính cất ... chưa phải là bài giải hoàn hảo nhất. Bên cạnh đó để có bài tập riêng của từng giáo viên,người giáo viên cần biết biến đổi bài tập trong tài liệu này sao cho phù hợp với đối tượng học sinh. Tài...

Ngày tải lên: 16/04/2014, 13:58

... ABC. ĐS: Bài 5. Cho hình thang ABCD có µ µ A D 0 90 = = và hai đường chéo vuông góc với nhau tại O. a) Chứng minh hình thang này có chiều cao bằng trung bình nhân của hai đáy. b) Cho AB = 9, CD ... + • Thể tích: V R h 2 π = Bài 25.Một hình trụ có bán kính đáy bằng 1 4 đường cao. Khi cắt hình trụ này bằng một mặt phẳng đi qua trục thì mặt cắt là một hình chữ nhật có diện tích là cm 2 50 . ... của hình trụ. ĐS: xq S cm 2 64 ( ) π = . Bài 27.Một hình trụ có bán kính đáy là cm3 . Biết diện tích toàn phần gấp đôi diện tích xung quanh. Tính chiều cao của hình trụ. ĐS: h R cm3( )= = . Bài...

Ngày tải lên: 01/05/2014, 16:47

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+9/ H9Ph7j1V2ve7/fd5+nDwEA1QUAoLoAAFQXAACqCwBAdQEAoLoAAFQXAIDqAgBAdQEAqC4AANUFAIDqAgBQXQAAqC4AANUFAKC6AABQXQAAqgsAANUFAKC6AABUFwAAqgsAQHUBAKguAABUFwCA6vqoUqmcn58n5I29vr4mZ5gQws3NTaVSMQMAqK4YpNPppaWlwcHBJOROKpXKZrMJGeZNW1vbxsZGc7snCTN8iGOTJHYSIxnmLzs20HzFYrERL5vJZGr1yOfzjXuPk5OT1Wq1rnkauuZnZ2dfn6RBG3RxcVFLgEwmk8/n 692 dRhgYGEjIJLlcLpfLlcvlWmIkcKTJycmE7FetVjs7O8tkMsViMQnDJOckLy8v5/P5RB0baLqWarV6e3sb17V8ZGQkhLC3tzc9PV3XEyuVSqlUijcsZmdnHx8ft7a25ubmUqlUXc+9ubmJd5i7u7uxsbFMJrO5udnX11fXz4txbVChUFhYWIgwQwihVCqtrKzEHn+Xl5cXFxddXV0RtqlSqRwdHcU1yf7+CHUYÊN...

Ngày tải lên: 26/06/2014, 23:20

Ngày tải lên: 27/06/2014, 16:20

Ngày tải lên: 16/07/2014, 15:12

Ngày tải lên: 27/07/2014, 16:17

Ngày tải lên: 27/07/2014, 16:32

Ngày tải lên: 12/08/2014, 02:22

... nên có pháp vectơ 2 n   Góc phẳng nhị diện (B; SA; C) bằng 60 o . 2 o 22 22 22 aa a 0.x x.0 33 9 cos60 9x a aa 0 x x 0 9 99          2 22 1a 2 9x a   2 2 2 2 2 a 9x ... 2a 2x 9         22 3ax 2 IM 2 9x 2a   .  Ta có:  o BIC 60  oo 22 a 2 3.3ax 2 BIM 30 BM IM.tg30 2 2 9x 2a        2 2 2 2 2 2 2 2 2 9x 2a 3x 3 9x 2a 27x a 18x 2a 9x ... . 2 2 2       BÀI 7 Câu 1: Cho hình chóp đều S.ABC, đáy ABC có cạnh bằng a, mặt bên tạo với đáy một góc bằng oo (0 90 )    . Tính thể tích khối hình chóp S.ABC và khoảng...

Ngày tải lên: 17/08/2013, 10:04

... 2 o 22 22 22 aa a 0.x x.0 33 9 cos60 9x a aa 0 x x 0 9 99          2 22 1a 2 9x a   2 2 2 2 2 a 9x a 2a 9x a x . 3         Vậy, a x. 3  BÀI 5 Câu 1: Trong không gian Oxyz, ... Trang 9  Mặt phẳng (SAC) có cặp vectơ chỉ phương SA, SC   nên có pháp vectơ 2 n   Góc phẳng nhị diện (B; SA; C) bằng 60 o . 2 o 22 22 22 aa a 0.x x.0 33 9 cos60 9x a aa 0 ... (x 1) (y 1) (x 1) 9      có tâm I(1; -1; 1) và bán kính R = 3. (P) tiếp xúc (S) d[I, (P)] R 2 2 2 2 2 2 2 m 3m 1 9 m 2 2.1 2.( 1) 1.1 m 3m 3 m 3m 1 9 m5 m 3m 1 9 2 2 1       ...

Ngày tải lên: 17/08/2013, 10:04