5α dht on herg protein level in the presence of erk1 2 inhibitors
Performance of microwave activated adsorption cycle theory and experiments
Ngày tải lên :
11/09/2015, 10:16
... Organization of the Thesis Literature Review 2. 1 Introduction 2. 2 Adsorption Process Chapter - Introduction 2. 2.1 Adsorbent-adsorbate working pair for adsorption cooling system 2. 2 .2 Enhancement of the ... not only in the field of communication but also in the medical industry, material sintering process, in food industry, in drying industry because of its energy saving potential, reducing the ... operation mode based on the adsorbate concentration Table C.1 The lists of errors of the comparative analysis among the linear and non linear model of First order and Second order reaction equations...
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báo cáo sinh học:" What can health care professionals in the United Kingdom learn from Malawi?" pdf
Ngày tải lên :
18/06/2014, 17:20
... for corruption, replicate systems of inappropriate training and encourage urbanization of resources and personnel, leading to emigration of trained personnel [9] Increasing cooperation between ... interesting to speculate whether nurses in the United Kingdom are sufficiently proud of their hard work to sing a song about it in front of their patients Malawian clinics fly the national flag ... village custom of conveying a message to peers Patients in the United Kingdom would certainly remember a smoking cessation advice session that included singing and dancing with their doctor or...
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Báo cáo lâm nghiệp: "Field trials of potential attractants and inhibitors for pine shoot beetles in the Yunnan province, China" pps
Ngày tải lên :
08/08/2014, 00:21
... their application in combination with verbenone did not inhibit attacks in comparison with verbenone application alone Neither the Jilin nor Yunnan monoterpene blends appeared attractive to the ... transformation prior to analysis crown on Yunnan pines [29 ] Studies investigating the appropriate number and placement of verbenone elution devices on individual trees and the timing of the applications ... (20 04) 416– 422 [7] Fäldt J., Volatile constituents in conifers and conifer-related wooddecaying fungi: Biotic influences on the monoterpene compositions in pines, Thesis, Royal Institute of Technology,...
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Ceftriaxone-induced up-regulation of cortical and striatal GLT1 in the R6/2 model of Huntington’s disease pps
Ngày tải lên :
10/08/2014, 05:21
... membranes [20 ], is reduced in HD mice, including palmitoylation of GLT1 [21 ] Whether ceftriaxone increases GLT1 palmitoylation is the focus of ongoing research It is unlikely that other glutamate ... Institutional Animal Care and Use Committee at Indiana University Bloomington Page of Table Body weight Age WTs R6/2s WTc R6/2c 9-week 27 .53 ± 1.18 (N = 4) 26 . 52 ± 1. 02 (N = 4) 27 .27 ± 1. 02 (N = 4) 28 .06 ... in Huntington’s disease Prog Neurobiol 20 07, 81(5-6) :25 3 -27 1 14 Walker AG, Miller BR, Fritsch JN, Barton SJ, Rebec GV: Altered information processing in the prefrontal cortex of Huntington’s disease...
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báo cáo khoa học: " Can learning organizations survive in the newer NHS?" pps
Ngày tải lên :
11/08/2014, 05:22
... penetrating question is whether at the level of its constituent organisations, conditions in the NHS are equally inhospitable to learning organisations At that level, the combination of marketisation ... local experience of their implementation 19 20 21 22 23 24 25 26 27 28 29 30 References Secretary of State for Health: A first class service: quality in the new NHS London: Department of Health; 1998 ... pointed out some tensions between learning organisation norms and the institutions through which the clinical professions continue to train and socialise their members These interests constrain...
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Trường điện từ - electromagnetic field theory
Ngày tải lên :
12/10/2012, 15:00
... dS dθ dϕ Trong Π tb = r (2. 79) I2 l2k m sin θ 32 r ωεε Vi phân mặt cầu dS = r2sinθdθdϕ Suy I2 l2k3 m Pbx = 32 r ωεε 2 π µµ I = m R bx εε I2 l2k m ∫ dϕ∫ sin θdθ = 12 0 (2. 80) Trong lk R ... = εε0µµ0 ∂t (2. 22) Trong đó: Γ gọi vector Hertz điện E Thay (2. 22) vào (2. 6) ta ( ) ∂ H= ∇× A E = εε0 ∇× ΓE µµ0 ∂t ( ) (2. 23) Thay (2. 22) vào hệ thức chuẩn (2. 11) ta ( ) (2. 24) ϕ = − Γ ... (2. 25) Thay (2. 22) (2. 25) vào (2. 8) ta 32 ∂A E 2 ΓE E =− − ∇ϕE = ∇ ∇.ΓE − εε0µµ0 ∂t ∂t ( Nhận xét: E H (2. 26) ) đươc biểu diễn qua vector Hertz điện Γ E Tìm Γ ? E Thay (2. 22) ...
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TRƯỜNG ĐIỆN TỪ - ELECTROMAGNETIC FIELD THEORY - chương 2
Ngày tải lên :
17/10/2013, 17:15
... V (1.19) Mặt khác r r I = ∫ JdS (1 .20 ) S Suy r r ∂ρ ∫ JdS = − V ∂t dV ∫ S (1 .21 ) r r v ∂ρ JdS = ∫ (∇.J )dV = − ∫ dV ∫ S V V ∂t (1 .22 ) v ∂ρ ∇.J + =0 ∂t (1 .23 ) Theo định lý OG Suy Đây dạng vi phân ... ebonic, nguyên tố đất μ < : chất nghịch từ : khí hiếm, ion Na+, Cl- có lớp electron giống khí hiếm, chất khác Pb, Zn, Si, Ge, S, CO2, H2O, thuỷ tinh, đa số hợp chất hữu μ >> : chất sắt từ : môi trường ... cường độ điện trường xoáy dọc theo đường cong kín giá trị tuyệt đối trái dấu với tốc độ biến thiên theo thời gian từ thông gửi qua diện tích giới hạn đường cong kín Theo giải tích vector (công...
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TRƯỜNG ĐIỆN TỪ - ELECTROMAGNETIC FIELD THEORY - chương 3
Ngày tải lên :
20/10/2013, 05:15
... ⎛k ε cos ψ = − ⎜ sin ϕ t ⎟ ≈ − sin ϕ t ⎟ ⎜k 2 ⎠ ⎝ Nếu môi trường điện môi có μ1 = 2 = μ (3.55) viết lại (3.56) ε1 cos ϕ t − ε − ε1 sin ϕ t 2 ε1 cos ϕ t + ε − ε1 sin ϕ t 2 R ng = (3.57) ε1 ... Z1 cos ϕt − Z2 cos ψ Z1 cos ϕt + Z2 cos ψ Rđ = 2Z2 cos ϕt Tđ = Z1 cos ϕt + Z2 cos ψ (3.58) Tđ Rđ liên hệ với theo công thức: + R đ = Tđ Z1 Z2 (3.59) Nếu môi trường điện môi có μ1 = 2 = μ (3.58) ... + Z2 Tng = Z2 Z2 + Z1 Z2 Tđ = Z1 + Z2 (3.61) 3.5.4 Sự phản xạ toàn phần Nếu môi trường có chiết suất lớn môi trường n1 > n2, theo (3.50) ta có: sin ψ = n1 sin ϕt n2 (3. 62) có nghĩa ψ > ϕt Khi...
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TRƯỜNG ĐIỆN TỪ - ELECTROMAGNETIC FIELD THEORY - chương 4
Ngày tải lên :
20/10/2013, 05:15
... ∂t (2. 22) r Trong đó: ΓE gọi vector Hertz điện Thay (2. 22) vào (2. 6) ta ( ) r r r ∂ H= ∇ × ΓE ∇ × A E = εε ∂t μμ ( Thay (2. 22) vào hệ thức chuẩn (2. 11) ta ) (2. 23) ( ) (2. 24) r ϕE = −∇.ΓE (2. 25) ... dϕ Trong dθ r dS r r Π tb = r (2. 79) I2 l2k m sin θ 32 r ωεε0 Vi phân mặt cầu dS = r2sinθdθdϕ Suy Pbx = I2 l2k3 m 32 r ωεε 2 π 0 ∫ dϕ∫ sin θdθ = μμ I = m R bx εε I2 l2k m 12 (2. 80) Trong R ... Thay (2. 22) (2. 25) vào (2. 8) ta r r r r ∂A E ∂ ΓE E=− − ∇ϕE = ∇ ∇.ΓE − εε 0μμ0 ∂t ∂t r r r Nhận xét: E H đươc biểu diễn qua vector Hertz điện ΓE r Tìm ΓE ? ( ) (2. 26) Thay (2. 22) vào (2. 12) ta...
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TRƯỜNG ĐIỆN TỪ - ELECTROMAGNETIC FIELD THEORY - chương 5
Ngày tải lên :
24/10/2013, 04:15
... sin θ sin ϕ + θ cos θ sin ϕ − ϕ cos ϕ Khi đó: 14 (4.45) ⎛ ka ⎞ ⎛ kb ⎞ sin ⎜ sin θ cos ϕ ⎟ sin ⎜ sin θ sin ϕ ⎟ e ⎝ 2R ⎠ ⎝ 2R ⎠ φ = ab ka kb R sin θ cos ϕ sin θ sin ϕ 2R 2R − ikR x ϕ y (4.46) M ... R a /2 b /2 ∫ ∫e −a / −b / ik xx′+ yy′ R e −ikR R i kxx dx ′dy′ = e R R ikx ′ a /2 R i kyy e R iky −a / ⎛ ka ⎞ ⎛ kb ⎞ sin ⎜ x ⎟ sin ⎜ y⎟ e ⎝ 2R ⎠ ⎝ R ⎠ = ab kb ka R x y 2R 2R ′ b /2 = −b / (4. 42) ... sóng góc 2 * xác định từ điều kiện: ⎛ kb sin θ ∗ ⎞ ⎟=0 sin ⎜ ⎜ ⎟ ⎝ ⎠ (4.51) Nếu lấy không điểm ta có: kb sin θ ∗ =π (4. 52) Với góc θ* nhỏ θ* ≈ sinθ* độ rộng búp sóng 2 ∗ ≈ sin θ∗ = 2 b (4.53)...
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Tài liệu FIELD INTENSITY and POWER DENSITY doc
Ngày tải lên :
12/12/2013, 09:15
... 66x10- 12 24x10- 12 11x10- 12 2.7x10- 12 -99 -1 02 -106 -110 -116 -59 - 62 -66 -70 -76 7x10-5 5x10-5 3x10-5 2x10-5 1x10-5 37 34 30 26 20 1.3x10-11 6.6x10- 12 2.4x10- 12 1.1x10- 12 2.7x10-13 -109 -1 12 -116 ... -107 .2 -167 .2 volts/meter 1 62. 8 42. 8 -17 .2 42. 8 -77 .2 -137.7 Eq [8], Section 3-1, terms (m2) Pr = PDAe E1 µv/meter PD= E2/ 120 B Pr ˆ Pr = ( E2/ 120 B = c /f )( 82G/4B) terms mW (dBm) (v2/m2S)(m2) ... 137 134 130 126 120 13 066 024 011 0 027 -9 - 12 -16 -20 -26 1.3x10-5 6.6x10-6 2. 4x10-6 1.1x10-6 2. 7x10-7 -49 - 52 -56 -60 -66 013 66x10-4 24 x10-4 11x10-4 2. 7x10-4 -19 -22 -26 -30 -36 +21 +18 +14...
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Tài liệu TRƯỜNG ĐIỆN TỪ - ELECTROMAGNETIC FIELD THEORY - chương 1 pptx
Ngày tải lên :
26/01/2014, 02:20
... a y = (2) a1, a2 hàm biến x Định lí Nếu y1 = y1(x) y2 = y2(x) nghiệm (2) y = C1y1 + C2y2 (trong C1, C2 số tuỳ ý) nghiệm phương trình Hai hàm y1(x) y2(x) độc lập tuyến tính y1 (x ) ≠ const , ngược ... sin y ) Hàm mũ hàm tuần hoàn có chu kì 2 i Thực vậy, ta có e kπi = cos 2kπ + i sin 2kπ = Suy e z + kπi = e z e kπi = e z Công thức Euler eiy = cosy +isiny Khi số phức z = r eiϕ = r(cosϕ +isinϕ) ... có nghiệm k1 k2 sau - k1 k2 số thực khác nhau, nghiệm riêng phương trình vi phân (7) y1 = e k x , y2 = ek x Hai nghiệm riêng ( 12) độc lập từ trường ( 12) y1 = e ( k −k y2 )x ≠ const (13) Do nghiệm...
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Báo cáo khoa học: Ferrous Campylobacter jejuni truncated hemoglobin P displays an extremely high reactivity for cyanide – a comparative study ppt
Ngày tải lên :
16/03/2014, 06:20
... ª 20 08 The Authors Journal compilation ª 20 08 FEBS 643 Cyanide binding to Camplylobacter jejuni trHbP 21 22 23 24 25 26 27 28 29 30 31 32 33 644 A Bolli et al dibranchiata monomer hemoglobin ... of the incoming ligand, or the protonation of the outgoing cyanide anion [18] This interpretation is in agreement with the very slow kinetics of cyanide binding to Glycera dibranchiata monomeric ... (loff ¼ 2. 8 · 10)1 s)1 and 9.0 · 10)1 s)1, respectively) [24 ,26 ] Values of lon for cyanide binding to most heme(III) proteins range between · 1 02 m)1Æs)1 and · 1 02 m)1Æs)1 [18 ,20 ,21 ,25 ,27 – 32] In...
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Electromagnetic field theory - bo thide
Ngày tải lên :
17/03/2014, 13:45
... or = (2 ) + 2i  à k2 + i (2. 37) = k2 (2. 38) = (2. 39) k2 20 Squaring the latter and combining with the former, one obtains the second order algebraic equation (in ) (2 k2 ) = k 42 (2. 40) ... (2. 31) Let us consider the minus sign in the exponent in Equation (2. 29) above This corresponds to a wave which propagates in the direction of increasing Inserting this solution into Equation ... and (2. 20c), we conclude that the only longitudinal component of B must be constant in both time and space In other words, the only non-static solution must consist of transverse components 2. 2.1...
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selfridge, arnold, warnick. teaching electromagnetic field theory using differential forms
Ngày tải lên :
24/04/2014, 16:51
... boundary The 32 IEEE TRANSACTIONS ON EDUCATION direction of ow along the lines of the 1-form can be found using the right-hand rule on the direction of H1 ? H2 in region above the boundary (b) ... Interestingly, none of these concepts are intrinsically more di cult than other aspects of EM theory; rather, they are unclear because of the limitations of the mathematical language traditionally ... is given by the right-hand rule applied to the orientations of the surfaces making up the walls of a tube The orientation of dx is in the +x direction, and dy in the +y direction, so the ux due...
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Charged particle in a electromagnetic field 2
Ngày tải lên :
24/05/2014, 19:10
... notes in a particular case of a single particle of charge q Comparing the expression for the Lorentz force in the form (22 ) with the definition (2) of the generalized force in terms of the velocity-dependent ... is T + qϕ = const (29 ) Since the second term in this equation is nothing but the potential energy of a charge particle, we see that in this case the total energy of the system is conserved as ... ∂vx (22 ) where we introduce the function q q U = qϕ − v · A = qϕ − A · v c c (23 ) Note that the term in the right-hand side of this equation coincides with the potential V defined by Eq (2. 119)...
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Charged particle in a electromagnetic field 3
Ngày tải lên :
24/05/2014, 19:10
... about antisymmetrizing the many-electron wave-function, etc Think of one electron interfering with itself, in the same sense as a 2- slit experiment Then ψ is the amplitude the electron follows path ... choice Hamiltonian is (convention: electron has charge -e) (ˆ + eA )2 p 2m = p2 + p2 + 2eBxˆy + (eB )2 x2 ˆ ˆy p 2m x H = (28 ) (29 ) Note that [H, py ] = 0, so we may write all eigenfctns of H as eigenfctns ... p as −i¯ , following the prescription to replace the canonical momentum h in the classical theory by −i¯ to preserve the canonical commutation h relations [x, p] = i¯ To convince yourself this...
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Lagrangian of charged particle in electromagnetic field
Ngày tải lên :
24/05/2014, 19:12
... ru r L = T − q ϕ − v.A ( mà ) nên: r2 ur r 1 r2 T = mv L = mv − q ϕ − A.v 2 Trọng hệ tọa độ Cartes thì: r & && v = (x; y;z) r u A = (A x ;A y ; A z ) 2 & & & T = m x + y + z ⇒ & & & ... qϕ − qv.A = −q = −q A + v ÷ = −q A.i = −q x & & & ∂& dt ∂x dt 2x3 ∂& dt ∂x dt ∂x {x ÷ dt dt =0 =0 u không phụ thuộc tường minh vào u r r & x ∂ ( qϕ ) ∂A ϕ; A = 0; =0 & & ∂x ∂x Vậy, ru r...
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maxwell jc - a dynamic theory of the electromagnetic field
Ngày tải lên :
04/06/2014, 12:44
... each other in virtue of their connexion with the magnetization of the propose to examine, conductors in the The second is field The first result of this connexion that I the induction of one current ... Note on the Attraction of Gravitation ( 82) After tracing to the action of the surrounding medium both the magnetic and the electric attractions and repulsions, and finding them to depend on the inverse ... depends only on the form and relative position of the circuits on the form and relative position of the motion of the conductors It will quantities of the nature of lines, that form of the first...
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