... High cholesterol ðnÞ Diabetes ðnÞ No diseases ðnÞ 58 50 3/ 55 12 /38 18 34 63 –85 23 . 1 73. 7 20 13 56 20 90 S Koskinen et al / Appetite 41 ( 20 0 3) 87–96 presented a list of four possible odors and ... willingness to eat the product again (F 1; 10 6 Þ ¼ 6 :34 ; p ¼ 0: 0 13 ) , to buy it (F 1; 10 6 Þ ¼ 8 : 12 ; p ¼ 0: 005 ), and to recommend it to a friend (F 1; 10 5 Þ ¼ 6:89; p ¼ 0: 0 10 ) The heightened aroma concentration ... sample (F 1; 93 ¼ 13 :04 ; p # 0: 001 ) The intake of neither age group changed during the period of home-use health group (n ¼ 31 ; 23 females, males, mean age 74 .2 years) was 15 .1 (0. 31 , 10 16 ) and...
... (−A 01 (Q) E ∗ − A 00 (Q)) (1 − A1 (Q)) C ∗ − ( [1 − A1 (Q)] E ∗ − A0 (Q)) (−A 01 (Q) C ∗ ) = ∂Q ( [1 − A1 (Q)] C ∗ )2 −A 00 (Q) (1 − A1 (Q)) C ∗ − A0 (Q) A 01 (Q) C ∗ = ( [1 − A1 (Q)] C ∗ )2 −A 00 (Q) ... their cost of capital (e.g., Botosan, 19 97; Botosan and Plumlee, 20 0 2; Francis et al., 20 0 4; Ashbaugh-Skaife et al., 20 0 5; Berger et al., 20 0 5; and Core et al., 20 0 5) In addition, our study provides ... +Cc2 c2 ef −V Uc2 −C f − ef −c2 c ef −c2 − V Uef −V U c2 −C ef +Cc2 c2 V eU +V ef −V V U ef −V U c2 −C ef +C c2 c ef −c2 e − ef −c2 f − ef −c2 c ef −c2 f ef −c2 c − ef −c2 c ef −c2 e − ef −c2 c...
... allowances 26 19 Integrated value partners agreement 27 20 Co-advertising services 28 21 Retail markdown compensation 29 22 Scan deals 30 23 Provision for returns from resellers/ wholesalers 31 24 Slotting ... redeemed ( 50% ), so its fair value is CU (CU x 50% ) When the revenue is deferred using the fair value of the coupon, the cash received of CU 20 , 000 (CU 20 x 1 ,00 0) is allocated to revenue (CU 19 ,00 0) ... 10 Brands and CGUs 11 Sales to a franchisee 12 Tax implications of brands with indefinite lives 13 Up-front fees 14 Useful life of brands 15 10 Franchise arrangements 16 Page 27 Shrinkage 36 28 ...
... ……………………………………………………………… 13 15 20 25 28 31 CHAPTER HYPOTHESES AND METHODOLOGY 3.13.23.2 .1 3.2.23.2 .3 3 .2. 4 Hypotheses ……………………………………………………………… 33 Methodology …………………………………………………………… 39 Audit Fees of ... the post- 20 02 period when compared to the pre- 20 02 period My first hypothesis (in alternative form) is: H1: Audit fees paid by clients of Second-Tier audit firms are higher in the post 20 02 period ... audit fees paid in 20 0 4 Audit fees for 20 0 4 increased 92 percent over 20 03 for 5 73 companies in the S&P 600 smallcap Audit fees data were analyzed for the 5 73 companies on the S&P 600 smallcap list...
... m 2 i =1 αi ξi 1 T− − ξi ) , (t, u, v) ∈ [0, 1] T × [0, l1 d1 ] × [−d1 , d1 ]; b1 − m 2 i =1 βi m 2 i =1 βi (T m 2 i =1 βi m 2 i =1 βi ξi − ξi ) , (t, u, v) ∈ [0, 1] T × [b1 , b1 / 1 ] × [−d1 ... u1 , u2 , u3 satisfying max ui (t) ≤ d1 , t∈ [0, 1] T i = 1, 2, 3; b < |u1 (t)|; a1 < max |u2 (t)|, |u2 (t)| < b1 ; t∈ [0, 1] T t∈ [0, 1] T t∈ [0, 1] T max |u3 (t)| ≤ a1 t∈ [0, 1] T The proof of Theorem 4 .1 ... positive solutions u1 , u2 , u3 satisfying max ui (t) ≤ d, i = 1, 2, 3; t∈ [0, 1] T b < |u1 (t)|; a < max |u2 (t)|, |u2 (t)| < b; t∈ [0, 1] T t∈ [0, 1] T t∈ [0, 1] T max |u3 (t)| ≤ a (3. 3) t∈ [0, 1] T Proof It is...
... m 2 i =1 αi ξi 1 T− − ξi ) , (t, u, v) ∈ [0, 1] T × [0, l1 d1 ] × [−d1 , d1 ]; b1 − m 2 i =1 βi m 2 i =1 βi (T m 2 i =1 βi m 2 i =1 βi ξi − ξi ) , (t, u, v) ∈ [0, 1] T × [b1 , b1 / 1 ] × [−d1 ... u1 , u2 , u3 satisfying max ui (t) ≤ d1 , t∈ [0, 1] T i = 1, 2, 3; b < |u1 (t)|; a1 < max |u2 (t)|, |u2 (t)| < b1 ; t∈ [0, 1] T t∈ [0, 1] T t∈ [0, 1] T max |u3 (t)| ≤ a1 t∈ [0, 1] T The proof of Theorem 4 .1 ... positive solutions u1 , u2 , u3 satisfying max ui (t) ≤ d, i = 1, 2, 3; t∈ [0, 1] T b < |u1 (t)|; a < max |u2 (t)|, |u2 (t)| < b; t∈ [0, 1] T t∈ [0, 1] T t∈ [0, 1] T max |u3 (t)| ≤ a (3. 3) t∈ [0, 1] T Proof It is...
... f 23 382 . 709 4, so that f u ≥ Finally, as limu → ∞ f u 23 M 36 8, 6.5 400 0 · 23 2 / 23 2 u ∈ a , 2a 500 0 ≈ 6.6 400 0, f u ≤ 400 0 < c N 500 0, u ∈ 0, c , 6.7 and D2 of iii holds Thus by Theorem 4 .1, ... s φ 10 T N 1 m 2 i 1 − 1/ 4 bi a τ ∇τ Δs ⎛ φ 1 ⎝ s s l /2 sds m 2 i a τ ∇τ 11 /3 · 1/ 2 − 1 /3 ds 1/ 5, a Clearly f is always increasing If we take d , 16 ξi a τ ∇τ m 2 i ⎞ ⎠Δs 6 .3 23 , c 500 0, then ... − 1 T ϕ 0 T ϕ 01 T bi m 2 i m 2 i s Δs − m 2 i 0 s Δs bi 1 T ϕ ξi m 2 i s Δs s Δs − T ϕ ξi s Δs bi s Δs bi ≥ 0, 2 .15 T − u T 0 s Δs B T − T ϕ 00 s Δs s Δs − 1 m 2 i T ϕ ξi m 2 i bi 1 ...