T.Blog.B.01.03.Qua trinh nhan doi cua ADN

www.tuhoc.edu.vn TOPPER Chú ý htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn TOPPER Chú ý – gyraza), ADN (enzim helicaza prôtêin SSB 5' 3' – Enzim ADN – pôlimeraza 5' – 3' enzim gyraza enzim helicaza prôtêin SSB ADN – pôlimeraza 3' ARN – pôlimeraza 5' enzim 5' – 3' 3' 5' ARN – pôlimeraza ADN – pôlimeraza ligaza htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn Có Có Khác prơtêin tham gia nhanh Có Có prơtêin tham gia htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn A) C) B) D) A) B) C) D) A B) ADN C) D) A) B) C) D) A) 1, 2, C) 3, 2, B) 3, 1, D) 2, 3, htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn A) 3' B) C) D) A) C) B) D) A) 1, B) 2, C) 2, D) 3, không A) B) C) D) htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn TOPPER Chú ý k k k – k – VD1: toàn n a) 25 = 32 n b) 25 – = 31 c) 25 – = 30 A–C A A) 16 B) 32 C) 64 D) 63 A) 32 B) 62 C) 63 D) 64 A) 32 B) 62 C) 63 D) 64 B C D–F D A) 32 B) 64 C) 128 D) 256 A) 30 B) 32 C) 60 D) 64 A) 56 B) 60 C) 62 D) 64 E htttp://tuhoc.edu.vn/blog F www.tuhoc.edu.vn G A) B) C) D) A) B) 10 C) 15 D) 20 A) B) C) D) 11 H I J E coli 15 14, 15 E coli trình A) B) C) D) K E coli 15 E coli N14 E coli 14? A) 32 B) 30 C) 16 D) A) B) C) D) L htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn TOPPER Chú ý k gen n – N' = (2k – 1) × N n – A' = T' = (2k – 1) × A = (2k – 1) × T – G' = X' = (2k – 1) × G = (2k – 1) × X VD2: (1) N = (2) Lgen 3,4 20 =S (3) A = T; G = X (4) A + G = (5) Lgen = – (3) G = X = 700; A = T = X = 350 N N × 3,4 (Å) (6) H = 2A + 3G (7) Mgen = 300 × N A' = T' = (25 – 1) × 350 = 10850 G' = X' = (25 – 1) × 700 = 21700 VD3: nuclêôtit 4080 3, – (1) – (4) A = T = 500 G=X= N nuclêôtit = 2400 A 2400 500 = 700 A' = T' = (23 – 1) × 500 = 3500 G' = X' = (23 – 1) × 700 = 4900 htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn TOPPER Chú ý 1nm = 10 Å A = T = A1 + A2 = T1 + T2 = A1 + T1 = A2 + T2 G = X = G1 + G2 = X1 + X2 = G1 + X1 = G2 + X2 M–N M A) A = T = 600; G = X = 900 C) A = T = 1200; G = X = 300 B) A = T = 900; G = X = 600 D) A = T = 300; G = X = 1200 N A) A = T = 18000; G = X = 4500 B) A = T = 4500; G = X = 18000 C) A = T = 9000; G = X = 13500 D) A = T = 13500; G = X = 9000 O–P O A) A = T = 720; G = X = 1680 C) A = T = 1680; G = X = 720 B) A = T = 360; G= X = 840 D) A = T = 840; G = X = 360 A) 5520 C) 3240 P B) 14880 Q D) 2760 A) A = T = 4200; G = X = 8400 C) A = T = 8400; G = X = 4200 B) A = T = 6300; G = X = 4200 D) A = T = 8400; G = X = 4200 A) 4800 C) 2400 R S B) 3600 D) 1200 Å A) A = T = 600; G = X = 900 C) A = T = 1800; G = X = 2700 B) A = T = 1200; G = X = 1800 D) A = T = 2400; G = X = 3600 htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn TOPPER Chú ý k Hp = (2k hình thành trình – thành = 2k–1 1) × H = (2k 1) × (2A + 3G) k HHT = 2k × H = 2k × (2A + 3G) HHT ×H VD4: A = T = 800; G = X = 400 b) HP = (23 – 1) × 2800 = 19600 c) HHT = 23 × 2800 = 22400 T–U Gen dài 4080 T A) 2640 nuclêôtit B) 81840 C) 84480 D) 3360 B) 81840 C) 84480 D) 163680 U A) 79200 htttp://tuhoc.edu.vn/blog 10 www.tuhoc.edu.vn Câu D B B A B A A Câu B C D E F G H C B B C A C B Câu L M N O P Q R B A C B C A D C A I J A A S T C B A C K B U C htttp://tuhoc.edu.vn/blog 11 ... gyraza), ADN (enzim helicaza prôtêin SSB 5' 3' – Enzim ADN – pôlimeraza 5' – 3' enzim gyraza enzim helicaza prôtêin SSB ADN – pôlimeraza 3' ARN – pôlimeraza 5' enzim 5' – 3' 3' 5' ARN – pôlimeraza ADN. .. www.tuhoc.edu.vn Có Có Khác prơtêin tham gia nhanh Có Có prơtêin tham gia htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn A) C) B) D) A) B) C) D) A B) ADN C) D) A) B) C) D) A) 1, 2, C) 3, 2, B) 3,