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(DH+GDIb$%K's: $/$RU&,?$%&zs1"kJ:J,/U&g,? G\&8 {G86 (DG9&zs&(9&zs9_(962s9G )/(DH9K's9_H9K's6Ks90Ks PkJ1(9G962s H9I90Ks {G8&HDI9&zs8Y86 (9 0 6 H10(9H6 5/(DH9K's& R6"/&35:8(D0(9K's (9K'st296&1Ks H9K's6&1Ks90q1Ks PkJ1(9G96&1Ks H9I90q1Ks z ,5BC5,5 V/zt)E-B/'1K6p5"/.,O RB,/0}'',O R)?5E.(96K'1 5?:7BT.I90'' I:S7,8"/[,T,?- $I:S7,8"/[,T,?5? <AT= G.c - 9'1K6p59K6''( ⇒ ;9 # 210 & 90''' ⇒ &(D&H9;90'''6 P/7c`BL9&(D0H90}''& &(D&H90'''6 G6"/&.T&(D0H90}''& H:8 (9l''^H9}'' G[,T,?(9G9 s6''{ # 9&'s^H9I9 s6''{ % 90's PkJ (9G9l''9&'s H9I9}''90's $G.765?9 & 96K'' G-:$/.( 6 9G & 96K'G-;GVW )/ (9( 6 D( & 9l'' ⇒ ( & 9l''6K'92K'9G 6 P/ H 6 9I & 90''G-;GVW ( 6 DG 6 DH 6 DI 6 9 & 96K'' ⇒ I 6 96K''6K'D2K'D0''9l'' G[,T,?f5*5? ( 6 9G & 9 s6''{ & 6 # 96's G 6 9( & 9 s6''{ & 6 90's H 6 9I & 9 s6''{ & 6 % 9&'s } ,5BC5,5 I 6 9H & 9 s6''{ & 6 $ 92's PkJ ( 6 9G & 96K'96's G 6 9( & 92K'90's H 6 9I & 90''9&'s I 6 9H & 9l''92's V/})E-. 7,8,/} × 5 10 :"G:..(96'K' ,- 6G357,8,-,?G1H1I- &B/-$%$O µ 5 0W7,8$,-O(i;]5(i; 2H-.O.Z5m.:85E-45$O5~ B/-:.fB?=>$k6VR%B/$3 65,/0 o A <AT= *<Y"/JO$U.(9G96'K',- H-. 7,8,/} × 5 10 :"PkJU7,--,/ 5 9 10 300 × 90''',- PkJ H9I9 3.000 2 −6'K'92K',- EB/-=>,/ 6 µ 5 × 3.000 2 × 012 × 4 10 − 9'1K6 µ 5 CW7,8$,-O5(i;,/ 3.000 2 96K''$,- YW7,855/-O.Z5m.:8,/ 6' ,5BC5,5 [...]... 498 axit amin Vậy chiều dài của phân tử protein bậc 1 được tổng hợp tư gen trên là: o × A 498 3 = 1494 Bài 10 Khối lượng phân tử của 5 phân tử protein đồng loại đang thực hiện chức năng sinh học bằng 229.900 đvC (mỗi phân tử protein là một chuỗi pôlipeptit) 1 Tính chiều dài cấu trúc bậc 1 của phân tử protein Biết chiều dài trung bình của o A mỗi axit amin là 3 2 Chiều . 3 <AT= G.)9;0'':"9&2''0''9q&'''':" $G.9 &' ;9&'9&'l'96&'')9;0'':"90l'''':" V/2tH-B/0''K1l( 1T7,?G"X,?. /0,0U V/6H-B/'12'z p5 . 7,8,/ (0l'''':" Vq&'''':" K2'''':" <2l'''':" V/&)E-. 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