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•Tap chiKHKTMo Bia chdt sd31, 712010, tr 88 92 NGHIEN Ciru ANH Hl/ONG CUA MlTC D Q BAP VO DAT DA BANG NO MIN DEN CONG TAC XUC BOC TREN MOT SO MO THAN L Q THIEN VUNG QUANG NINH LE VAN QUYEN TrUdng Dgi[.]
•Tap chiKHKTMo - Bia chdt sd31, 712010, tr.88-92 NGHIEN Ciru ANH Hl/ONG CUA MlTC D Q BAP VO DAT DA BANG NO MIN DEN CONG TAC XUC BOC TREN MOT SO MO THAN L Q THIEN VUNG QUANG NINH LE VAN QUYEN TrUdng Dgi hgc Md - Dia chdt Tdm tat: Mire dp dap vd (MDDV) ddt dd bdng nd duoc dgc tnmg bdi kich thudc cue tnmg binh D,b Khi thay ddi MDDV (D,b thay ddi) se anh huong true tiip tdi ndng sudt mdy xiic thdng qua dgi lugng dgc tnmg la hi sd xiic K^ (lie sd xiic day Kj vd he sd nd rdi ciia ddt dd gdu K,.g) Thdng qua cdc sd lieu thuc nghiem tren mot sd md than Id thiin vd ngoai nude, bdng phirang phdp thdng ke, truy hdi thdng ki, binh phirong bi nhdt, kit qud xu ly trin mdy vi tinh, tdc gid thiit lap dugc mdi quan he phu thuge ciia he so xiic (dgi lugng ddc tnmg cho ndng sudt mdy xiic) vdo kich thudc cue trung binh ciia ddng da nd tiiy theo dung tich hinh hgc ciia gdu xiic Dim vdo quy lugt ndy cd thi gidi bdi todn vi MDDV hgp ly bdng nd thuan Igi He sd bd rdi dat da gau (Krg) la ty sd Mddau giua the tich dat da thuc xiic dugc gau Nhu chiing ta biet, ehi phi xiic bdc tinh tren xiic va the tich dat da xiic dugc quy vl nguyen mot met khdi da nd phu thudc vao loai thiet bi, khdi: Krg = EJ Eo the hien do'n gia cua mot ca xiic, hieu qua He sd xiic (K^) la ty sd giua the tich dat da cua cdng tac xiic bdc hay nang suat xiic thuc te thuc xiic dugc gau quy ve nguyen khdi Nang suat xiic phu thudc vao thai gian, chu ky xiic, he sd xiic va cac dai lugng khac va dung tich hinh hgc ciia gau xiic: K^ = Eo /E He sd xiic phu thudc vao miic bd rdi ciia dat Trong dieu kien cac md thuge Lien Xd cu Vien sT V.V Rzevski da nghien ciiu thdng ke da gau va kha nang xiic day gau thuc nghiem mdi quan he phu thudc ciia he sd He sd xiic quan he vdi he sd xiic day gau va xiic day gau, he sd nd rdi ciia dat da gau he sd nd rdi dat da gau theo bieu thiic: cung nhu he sd xiic vao MDDV (dudng kinh K, = Kd/Krg ^ (1) trung binh cua cd hat) vdi cac may xiic mot gau De tien hanh xac djnh cac he sd tren, can cd dung tich khac [2] Tuy nhien, phai tien hanh thdng ke, theo doi mot thdi dieu kien cac md Id thien Idn d Viet Nam, viec gian dai thuc te boat dgng ciia cac khau cdng nghien ciiu anh hudng cua MDDV den he sd nghe d md Md hinh thirc nghiem theo tieu xiic thi chua dugc sang td Vi vay, viec nghien chudn hi sd xiic day Kd bdng 1, tirong irng ciiu mot each toan dien anh hudng cua MDDV ddt dd gdu bdng miing gdu xiic De giiip dat da den nang suat xiic (the hien qua he sd cho cdng viec nghien ciiu thuan Igi, dat dugc xiic) bang dudng thuc nghiem cho mot sd hieu qua nhanh chdng, nhung van dam bao loai may xiic tay gau phd bien d cac md Id thien chinh xac, tac gia da thuc hien theo cac phuong vung Quang Ninh la rat can thiet phap truy hdi thdng ke, thdng ke tai thuc dja Cdng tac thuc nghiem dugc tien hanh Cac thdng sd dac trung cho hieu qua xiic nhieu nam tren cac md Id thien chinh d viing bdc bao gdm he sd nd rdi dat da gau xiic, Quang Ninh nhu Cao Son, Ha Tu, Cgc sau, Deo he sd chat day gau va he sd xiic Nai, Niii Beo, Khe Sim,., theo phuong phap Ggi: E la dung tich hinh hgc ciia gau xiic, m^; trinh biy [1]: - Do dac (blng trie dja) E, la the tich dat da thuc xiic gau, m^; khdi lugng bai nd (Vi); E(i la the tich dat da thuc xiic gau quy ve nguNen khdi m'\ - Xac djnh he sd xiic (kx) thdng qua sd giu Hf sd xiic day gau (Kj) la ty sd giira thi xue thirc tl xiic dly I xe d to (Ug,) (dam bao kd,, = tich dat da thuc xiic dugc gau xiic va dung 1) va sd chuyen d td ehd hit dong da no (Noh) (chi tich hinh hgc cua gau xiic: Kd = EJ E su dung loai may xiic va d td); Xac Jn,h k^ theo: 88 HE s o NO ROI CUA DAT DA TRONG GAU XUC CUA MA V XVC TAY CAC THEO SO U E U KHAO SAT CUA NGA VA TA kN = V,/ng|.N,-,h.E (2) - Xac dinh he sd nd rdi cua dlt da giu krg thdng qua viec thdng ke sd giu thuc tl xiic dly xe ng, theo dung md hinh xe(kd6 = 1) vdi he sd xiic day gau blng (kj = I) va so chuyin d td cho het ddng da nd (N,-,h) xac dinh krg theo: krg =E ng,_ N o h / y , (3) - Dua vao sd lieu thdng ke sd giu xiic dly ,\e Ugi va ng, d tren ta xac dinh dugc he sd xiic day gau kd theo: kd = n g , / n g i _ s ^^'''S'"^.-'''!!!^-^^''^ ^ - ^ ^ ^ ^ ^ • " ^ ^ ^ ^ ^ Krg(E4) Krg (El 2.3) -LiiKiuOOgCElOJ) (4) Tren ca sd cac sd lieu ciia Vien sT V.V Rjevski sd lieu thuc nghiem d cac md Cao Son, Cgc Sau Deo Nai, Niii beo Ha Tu cac loai da thuge nhdm 11,111 ddi vdi cac may xiic tay gau ed dung tich (E) tii den 12,5 m^ ta tien hanh nghien ciiu cac trudng hgp sau: He so nd roi ciia dat da gau xiic (krg) Sd lieu dugc phan anh tren dd thi hinh Phan tich dd thi hinh chi rang tang kich thudc cue trung binh ciia cue da thi he sd bd rdi dat da gau tang len va ngugc lai Khi kich thudc cue trung binh giam rat nhd thi he sd nd rdi it chju anh hudng ciia dung tich gau xiic HE so NO ROI CUA DAT DA TRONO OAU XUC 1.8 17 16 ^^^r^^;;S^^\ • i Krg(E6) Krg(E4.6) Unear(Krg(E ^ - x 02 ^ ^ 0.00 Sii dung phuong phap binh phuong be nhat cho phep thiet lap gan diing qui luat phu thudc cua he sd nd rdi ciia dat da gau vao kich thudc cue trung binh ed dang tuyen tinh (hinh 2) • KtJ{E4) 0.20 40 • Kd(B8) - » - KdCEfl) 60 - "• * ao Ki](E10) • • 00 K0(ei3.5) • Did m l nme^.ff) Hinh Dang phu thudc thuc te ciia he sd xiic dly gau vao kich thudc cue trung binh ciia ddng da nd vdi may xiic tay gau cd dung tich la 4; 4,6; 6; 8; 10; 12.5 m-' 89 Sii dung phuang phap binh phuong be nhat cho phep thiet lap gan diing quy luat phu thudc cua he sd chat day gau vao kich thudc cue trung binh cd dang tuyen tinh (hinh 4) nhu sau: Hinh Dang phu thudc gan diing cua ht sd xiic day gau vao kich thudc cue trung binh cua ddng da nd vdi cac loai may xiic tay gau cd dung tich la 4; 4,6; 6; 8; 10; 12,5 m' He so XUC He sd xiic phu thuge vao he sd bd rdi dat da gau va be sd xiic day gau, nd dugc xac dinh theo cdng thiic (1), hoac theo sd lieu thu dugc true tiep tu thuc nghiem Sd lieu dugc phan anh tren thj hinh Phan tich thi (hinh 5) chi rang tang D,b thi he sd xiic giam xudng va ngugc lai Khi kich thudc cue trung binh giam rlt nhd vdi Dtb < 0,2m thi he sd xiic dat Idn han 0,8, vdi cac may xiic cd dung tich gau nam pham vi tir den 12,5 m^ Khi Dtb loTi hon 0,7m thi he sd xiic giam nhd dudi 0,1 Ha xuo oua may xuo oua may xuo mot gau 0.2 ' 0.1 ' Hinh Dang phu thudc thuc te cua he sd xiic vao kich thudc cue trung binh ciia dd'ng da sau nd \'di may xiic tay gau cd dung ti'ch la 4; 4.6:6:8; 10; 12,5 m' 90 Sir dung phuong phap binh phuang be nhat cho phep thilt lap gin diing quy luat phu thudc ciia he sd xiic vao Dtb cd dang tuyIn tinh (hinh 6) Hinh Dang phu thuoc gan diing ciia he sd xiic vao kich thudc cue trung binh ciia ddng da no vdi cac loai may xiic cd dung tich gau xiic khac tir den 12,5 m'' He sd xiic phan anh su phu thudc cua nang suat thuc te ciia-may xue vao cd hat cua dat da hay mu'c dap vd dat da Phan tich cac thj hinh va ddi vdi cac may xiic khac nhau, nhan thay rang: cd hat dat da rat nhd thi he sd XUC bang Kx=l Nhu vay cac dudng thang md ta qui luat phu thudc ciia he sd xue vao D,|, ciia cac loai may xue tay gau cd dung tich khac pham vi khao sat la mot hg cac dudng thang di qua diem (0,1) he toa (KxODtb) Sir dung phuong phap binh phuong nhd nhat nhan dugc cac hg dudng thang md ta su phu thudc cua Kx vao Dtb ciia cac loai may xiic nghien ciru Can cii vao ket qua nghien cuu d tren, tien hanh thilt lap hg dudng thing Kx di qua dilm cd dinh (0,1) deu cho he so chinh xac cua dudng cong xIp xi R^> 0,98, vi vay kit qua hoan toan cd the chap nhan dl sir dung tinh toan Hg cac dudng thing K^ di qua dilm cd dinh (0,1) dugc md ta hinh Phan tich hinh chi ring he sd gdc ciia cac dudng thing Kx tuong iing vdi dung tich giu xue thay doi theo qui luat: May xiic cd dung tich Idn han thi he sd gdc Idn han Sir phu thudc dugc phan anh qua hinh va bang 1: Kx vao dung ti'ch giu xiic dugc md ta tren hinh va cd dang sau: i a = 0.6335E3 - , , R ^ = 0,9746 (5) HE S O XUC QUI CraiAN CUA MAY XUC TAY QAU VI co: • • Kx (EB) Kl (E4,e) U»ar[Kx (E6)J • A Kx[Ee) — Uwar [Kx 1E4)) Lnejf (K« (B)) Kx (E10) LJnMflKi(E12.5)) - linear (Kx (E10)) Dlb(rn] dD tb , thay vao phuong trinh (5) ta dK ^ = 0.6335E3-2,3267 dD„ (6) Lly tich phan phuang trinh (6) ta cd: jdK, = J[0.6335E^-2,3267 ]dD,, Hinh Hg cac dudng thang md ta sir phu thudc gan diing cua he sd xue vao kich thudc cue trung binh cua ddng da vdi cac loai may xiic cd dung tich gau xiic khac di qua diem cd djnh (0,1) K , =0,6335 E D , b - , D , b + C (7) do: C - hang sd xac dinh tir dieu kien Dtb = 0, Kx = vdi mgi dung tich giu xiic pham vi nghien ciiu, thay vao (7) nhan dugc C = 1, vi vay phuong trinh (7) cd dang: U PHU THUOC HE SO GOC DUONG THANG Kx VAO DUNG TICH GAU XUC 110- 1.50 1.60 1.70 1.80 * 1.B0 200 ! 2.,10 i • ' 1 2.20 230 10 *, •/•''^ ( • / ^ y = 0,6335x-2.3267 R* = 0.9746 j -1.2 K , =[0,6335 E ^ - , ] D , b + • (8) Phuong trinh (8) md ta qui luat phu thuge ciia Kx vao dung tich gau xiic va dudng kinh trung binh cua ca hat ddng da nd min, dugc sir dung de tinh toan pham vi dung tich gau tir den gidi han 49,5 m Ddi vdi cac may xiic cd dung tich tir din 12,5 m^, tri sd ^ * ã ô dKx/dDib ( E ) i n (m) Hinh Quy luat phu thudc cua he sd gdc cua hg cac dudng thang Kx vao dung tich gau xiic Bang Tdng hgp su phu thudc ciia he sd gdc cac dudng thang kx vao dung tich gau xue E(m'': 4,6 10 12,5 Hes6(-l,3184 1,3125 ,1492 ,037 0,9411 0,8894 goc ciia k Xir ly sd lieu bang tren chuong trinh may tinh, cho phep nhan dugc su phu thudc ciia he sd gdc (a) ciia hg cac dudng thang [0,6335E3-2,3267] < , vi vay phuang trinh hoan toan nhat quan vdi cac thi ciia hg cac dudng thang md ta su phu thudc ciia he sd xiic vao dudng kinh trung binh ciia cd hat Qui luat chi rang: Dtb tang thi he sd xiic giam va ngugc lai Qui luat phan anh tinh dung dan thuc tien, Dtb tang thi he sd nd rdi dat da gau xue tang, he sd xue day gau giam vi vay he sd xiic se giam Qui luat dugc thiet lap d tren diing de giai bai toan lua chgn MDDV hgp ly cho nhirng md khai thac than Id thien cd dieu kien tuong tu ve tu nhien va ky thuat Ket luan Til' ket qua thdng ke sd lieu thu dugc tir thuc nghiem d mot sd md than Id thien viing Quang Ninh ket hgp phuong phap truy hdi thdng ke cac sd lieu ciia cac tac gia nude ngoai 91 tac gia da xa\ dung dugc mdi quan he phu TAI LIEU THAM KHAO thudc tdng quat ciia he sd xue vao kich thudc j , ^ ^ ^ ^^^-^ 2004 Phuong phap xac eye trung binh cua ddng da nd va dung tich ^.^^^ ^^^^ ^^^^ ^'^^ ^^ ,^gj ^5 he sd hoat gau xue theo qui luat dugc md ta d (8) Ket qua ^, ^.^- ^^^^ ^^^^ j ^ ^ ^,^j ^ a n g nghiep Md s6 tren ed the giup cho cac nha nghien cii'u iing A 2004 dung de tinh toan lua chon MDDV dat da hop ^^, ^" „ r^ r-, imo n«^,,^„ ,:J ~ , ' ^-x- ,, ,x , •*; [21 P>KeBCKHH B B., 1978 Hpoueccbi Iv bane no mm dieu kien thuc te cac mo •- -• ^ ;TI •• \A^^ „^ ' ,, , • • OTKpbiTbix ropHbix padoT, "Heiipa , MocKBa Ig thien nuoc ta • r r r SUMMARY Study the effects Rock fragmentation to work with the contact loading in some coal surface mine Region of Quang Ninh province Le Van Quyen, University Mining and Geology Rock fragmentation by blasting is characterized by medium size Dtb- When changing rock fragmentation (Dtb change) will affect directly the productivity of excavators through general characteristic is the promotion of K^ (full contact Kd coefficients and coefficients of expansion left in the bucket rock Krg) Through the experimental data on some coal mines in the country and abroad, with statistical methods, retraces statistical smallest squared, the result of processing on the computer, the authors established a connection dependent relationship of exposure coefficients (age-specific productivity of excavators) at an average size of blasting rock piles, depending on the geometry of the bucket capacity of contact Based on these rules contribute to solve the problem by blastingphan Rockbien: fragmentation reasonably favorable Ngudi Nhir Vdn Bach NGHIEN C i r u LlTA CHON KHOANG VAT SET (tiip theo trang 87) [5] Rong M Z., Zhang M Q., Zheng Y X., Zeng H M., Walter R., Friedrich K, 2000 Irradiation graft polymerization on nano-inorganic particles: An effectivemeans to design polymer-based nanocomposites Journal of Materials Science Letters, Vol 19, No 13, p 1159-1161 [6] Fischer H, 2003 Polymer nanocomposites: From fundamental research to specific applications Materials Science and Engineering C, Vol 23, No 6, p 76.3-772 SUMMARY Investigation on selection of clay mineral to produce bolt shank from polymer claynano composite NguyenManhKhai, State President Ofice J