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Annals of Mathematics
On thevolumeofthe
intersection oftwo
Wiener sausages
By M. van den Berg, E. Bolthausen, and F. den
Hollander
Annals of Mathematics, 159 (2004), 741–783
On thevolumeofthe intersection
of twoWiener sausages
By M. van den Berg, E. Bolthausen, and F. den Hollander
Abstract
For a>0, let W
a
1
(t) and W
a
2
(t)bethea-neighbourhoods oftwo indepen-
dent standard Brownian motions in R
d
starting at 0 and observed until time
t. We prove that, for d ≥ 3 and c>0,
lim
t→∞
1
t
(d−2)/d
log P
|W
a
1
(ct) ∩ W
a
2
(ct)|≥t
= −I
κ
a
d
(c)
and derive a variational representation for the rate constant I
κ
a
d
(c). Here, κ
a
is the Newtonian capacity ofthe ball with radius a. We show that the optimal
strategy to realise the above large deviation is for W
a
1
(ct) and W
a
2
(ct) to “form
a Swiss cheese”: thetwoWienersausages cover part ofthe space, leaving
random holes whose sizes are of order 1 and whose density varies on scale t
1/d
according to a certain optimal profile.
We study in detail the function c → I
κ
a
d
(c). It turns out that I
κ
a
d
(c)=
Θ
d
(κ
a
c)/κ
a
, where Θ
d
has the following properties: (1) For d ≥ 3: Θ
d
(u) < ∞
if and only if u ∈ (u
, ∞), with u
a universal constant; (2) For d =3: Θ
d
is
strictly decreasing on (u
, ∞) with a zero limit; (3) For d =4: Θ
d
is strictly
decreasing on (u
, ∞) with a nonzero limit; (4) For d ≥ 5: Θ
d
is strictly
decreasing on (u
,u
d
) and a nonzero constant on [u
d
, ∞), with u
d
a constant
depending on d that comes from a variational problem exhibiting “leakage”.
This leakage is interpreted as saying that thetwoWienersausages form their
intersection until time c
∗
t, with c
∗
= u
d
/κ
a
, and then wander off to infinity in
different directions. Thus, c
∗
plays the role of a critical time horizon in d ≥ 5.
We also derive the analogous result for d = 2, namely,
lim
t→∞
1
log t
log P
|W
a
1
(ct) ∩ W
a
2
(ct)|≥t/ log t
= −I
2π
2
(c),
∗
Key words and phrases. Wiener sausages, intersection volume, large deviations, vari-
ational problems, Sobolev inequalities.
742 M. VAN DEN BERG, E. BOLTHAUSEN, AND F. DEN HOLLANDER
where the rate constant has the same variational representation as in d ≥ 3
after κ
a
is replaced by 2π. In this case I
2π
2
(c)=Θ
2
(2πc)/2π with Θ
2
(u) < ∞
if and only if u ∈ (u
, ∞) and Θ
2
is strictly decreasing on (u
, ∞) with a zero
limit.
Acknowledgment. Part of this research was supported by the Volkswagen-
Stiftung through the RiP-program at the Mathematisches Forschungsinstitut
Oberwolfach, Germany. MvdB was supported by the London Mathematical
Society. EB was supported by the Swiss National Science Foundation, Contract
No. 20-63798.00.
1. Introduction and main results: Theorems 1–6
1.1. Motivation. In a paper that appeared in “The 1994 Dynkin
Festschrift”, Khanin, Mazel, Shlosman and Sinai [9] considered the following
problem. Let S(n),n∈ N
0
, be the simple random walk on Z
d
and let
R = {z ∈ Z
d
: S(n)=z for some n ∈ N
0
}(1.1)
be its infinite-time range. Let R
1
and R
2
be two independent copies of R and
let P denote their joint probability law. It is well known (see Erd¨os and Taylor
[7]) that
P (|R
1
∩ R
2
| < ∞)=
0if1≤ d ≤ 4,
1ifd ≥ 5.
(1.2)
What is the tail ofthe distribution of |R
1
∩R
2
| in the high-dimensional case?
In [9] it is shown that for every d ≥ 5 and δ>0 there exists a t
0
= t
0
(d, δ)
such that
exp
− t
d−2
d
+δ
≤ P
|R
1
∩ R
2
|≥t
≤ exp
− t
d−2
d
−δ
∀t ≥ t
0
.(1.3)
Noteworthy about this result is the subexponential decay. The following prob-
lems remained open:
(1) Close the δ-gap and compute the rate constant.
(2) Identify the “optimal strategy” behind the large deviation.
(3) Explain where the exponent (d−2)/d comes from (which seems to suggest
that d = 2, rather than d = 4, is a critical dimension).
In the present paper we solve these problems for the continuous space-time
setting in which the simple random walks are replaced by Brownian motions
and the ranges by Wiener sausages, but only after restricting the time horizon
to a multiple of t. Under this restriction we are able to fully describe the
large deviations for d ≥ 2. The large deviations beyond this time horizon will
ON THEVOLUMEOFTHEINTERSECTIONOFTWOWIENER SAUSAGES
743
remain open, although we will formulate a conjecture for d ≥ 5 (which we plan
to address elsewhere).
Our results will draw heavily on some ideas and techniques that were
developed in van den Berg, Bolthausen and den Hollander [3] to handle the
large deviations for thevolumeof a single Wiener sausage. The present paper
can be read independently.
Self-intersections of random walks and Brownian motions have been stud-
ied intensively over the past fifteen years (Lawler [10]). They play a key role
e.g. in the description of polymer chains (Madras and Slade [13]) and in renor-
malisation group methods for quantum field theory (Fern´andez, Fr¨ohlich and
Sokal [8]).
1.2. Wiener sausages. Let β(t), t ≥ 0, be the standard Brownian motion
in R
d
– the Markov process with generator ∆/2 – starting at 0. The Wiener
sausage with radius a>0 is the random process defined by
W
a
(t)=
0≤s≤t
B
a
(β(s)),t≥ 0,(1.4)
where B
a
(x) is the open ball with radius a around x ∈ R
d
.
Let W
a
1
(t), t ≥ 0, and W
a
2
(t), t ≥ 0, be two independent copies of (1.4),
let P denote their joint probability law, let
V
a
(t)=W
a
1
(t) ∩ W
a
2
(t),t≥ 0,(1.5)
be their intersection up to time t, and let
V
a
= lim
t→∞
V
a
(t)(1.6)
be their infinite-time intersection. It is well known (see e.g. Le Gall [11]) that
P (|V
a
| < ∞)=
0if1≤ d ≤ 4,
1ifd ≥ 5,
(1.7)
in complete analogy with (1.2). The aim ofthe present paper is to study the
tail ofthe distribution of |V
a
(ct)| for c>0 arbitrary. This is done in Sections
1.3 and 1.4 and applies for d ≥ 2. We describe in detail the large deviation
behaviour of |V
a
(ct)|, including a precise analysis ofthe rate constant as a
function of c. In Section 1.5 we formulate a conjecture about the large deviation
behaviour of |V
a
| for d ≥ 5. In Section 1.6 we briefly look at the intersection
volume of three or more Wiener sausages. In Section 1.7 we discuss the discrete
space-time setting considered in [9]. In Section 1.8 we give the outline of the
rest ofthe paper.
1.3. Large deviations for finite-time intersection volume.Ford ≥ 3, let
κ
a
= a
d−2
2π
d/2
/Γ(
d−2
2
) denote the Newtonian capacity of B
a
(0) associated
with the Green’s function of (−∆/2)
−1
. Our main results for the intersection
volume oftwoWienersausages over a finite time horizon read as follows:
744 M. VAN DEN BERG, E. BOLTHAUSEN, AND F. DEN HOLLANDER
Theorem 1. Let d ≥ 3 and a>0. Then, for every c>0,
lim
t→∞
1
t
(d−2)/d
log P
|V
a
(ct)|≥t
= −I
κ
a
d
(c),(1.8)
where
I
κ
a
d
(c)=c inf
φ∈Φ
κ
a
d
(c)
R
d
|∇φ|
2
(x)dx
(1.9)
with
Φ
κ
a
d
(c)=
φ ∈ H
1
(R
d
):
R
d
φ
2
(x)dx =1,
R
d
1 − e
−κ
a
cφ
2
(x)
2
dx ≥ 1
.
(1.10)
Theorem 2. Let d =2and a>0. Then, for every c>0,
lim
t→∞
1
log t
log P
|V
a
(ct)|≥t/ log t
= −I
2π
2
(c),(1.11)
where I
2π
2
(c) is given by (1.9) and (1.10) with (d, κ
a
) replaced by (2, 2π).
Note that we are picking a time horizon of length ct and are letting t →∞
for fixed c>0. The sizes ofthe large deviation, t respectively t/ log t, come
from the expected volumeof a single Wiener sausage as t →∞, namely,
E|W
a
(t)|∼
κ
a
t if d ≥ 3,
2πt/ log t if d =2,
(1.12)
as shown in Spitzer [14]. So thetwoWienersausages in Theorems 1 and 2 are
doing a large deviation onthe scale of their mean.
The idea behind Theorem 1 is that the optimal strategy for thetwo Brow-
nian motions to realise the large deviation event {|V
a
(ct)|≥t} is to behave
like Brownian motions in a drift field xt
1/d
→ (∇φ/φ)(x) for some smooth
φ: R
d
→ [0, ∞) during the given time window [0,ct]. Conditioned on adopting
this drift:
– Each Brownian motion spends time cφ
2
(x) per unit volume in the neigh-
bourhood of xt
1/d
, thus using up a total time t
R
d
cφ
2
(x)dx. This time
must equal ct, hence the first constraint in (1.10).
– Each corresponding Wiener sausage covers a fraction 1 − e
−κ
a
cφ
2
(x)
of
the space in the neighbourhood of xt
1/d
, thus making a total intersection
volume t
R
d
(1 − e
−κ
a
cφ
2
(x)
)
2
dx. This volume must exceed t, hence the
second constraint in (1.10).
The cost for adopting the drift during time ct is t
(d−2)/d
R
d
c|∇φ|
2
(x)dx. The
best choice ofthe drift field is therefore given by minimisers ofthe variational
problem in (1.9) and (1.10), or by minimising sequences.
ON THEVOLUMEOFTHEINTERSECTIONOFTWOWIENER SAUSAGES
745
Note that the optimal strategy for thetwoWienersausages is to “form a
Swiss cheese”: they cover only part ofthe space, leaving random holes whose
sizes are of order 1 and whose density varies on space scale t
1/d
(see [3]). The
local structure of this Swiss cheese depends on a. Also note that the two
Wiener sausages follow the optimal strategy independently. Apparently, under
the joint optimal strategy thetwo Brownian motions are independent on space
scales smaller than t
1/d
.
1
A similar optimal strategy applies for Theorem 2, except that the space
scale is
t/ log t. This is only slightly below the diffusive scale, which explains
why the large deviation event has a polynomial rather than an exponential cost.
Clearly, the case d =2iscritical for a finite time horizon. Incidentally, note
that I
2π
2
(c) does not depend on a. This can be traced back to the recurrence
of Brownian motion in d = 2. Apparently, the Swiss cheese has random holes
that grow with time, washing out the dependence on a (see [3]).
There is no result analogous to Theorems 1 and 2 for d = 1: the variational
problem in (1.9) and (1.10) certainly continues to make sense for d = 1, but it
does not describe theWiener sausages: holes are impossible in d =1.
1.4. Analysis ofthe variational problem. We proceed with a closer
analysis of (1.9) and (1.10). First we scale out the dependence on a and c.
Recall from Theorem 2 that κ
a
=2π for d =2.
Theorem 3. Let d ≥ 2 and a>0.
(i) For every c>0,
I
κ
a
d
(c)=
1
κ
a
Θ
d
(κ
a
c),(1.13)
where Θ
d
:(0, ∞) → [0, ∞] is given by
Θ
d
(u) = inf
∇ψ
2
2
: ψ ∈ H
1
(R
d
), ψ
2
2
= u,
(1 − e
−ψ
2
)
2
≥ 1
.(1.14)
(ii) Define u
= min
ζ>0
ζ(1 − e
−ζ
)
−2
=2.45541 Then Θ
d
= ∞ on
(0,u
] and 0 < Θ
d
< ∞ on (u
, ∞).
(iii) Θ
d
is nonincreasing on (u
, ∞).
(iv) Θ
d
is continuous on (u
, ∞).
(v) Θ
d
(u) (u −u
)
−1
as u ↓ u
.
Next we exhibit the main quantitative properties of Θ
d
.
1
To prove that the Brownian motions conditioned onthe large deviation event {|V
a
(ct)|
≥ t} actually follow the “Swiss cheese strategy” requires substantial extra work. We will not
address this issue here.
746 M. VAN DEN BERG, E. BOLTHAUSEN, AND F. DEN HOLLANDER
Theorem 4. Let 2 ≤ d ≤ 4. Then u → u
(4−d)/d
Θ
d
(u) is strictly decreas-
ing on (u
, ∞) and
lim
u→∞
u
(4−d)/d
Θ
d
(u)=µ
d
,(1.15)
where
µ
d
=
inf
∇ψ
2
2
: ψ ∈ H
1
(R
d
), ψ
2
=1, ψ
4
=1
if d =2, 3,
inf
∇ψ
2
2
: ψ ∈ D
1
(R
4
), ψ
4
=1
if d =4,
(1.16)
satisfying 0 <µ
d
< ∞.
2
Theorem 5. Let d ≥ 5 and define
η
d
= inf{∇ψ
2
2
: ψ ∈ D
1
(R
d
),
(1 − e
−ψ
2
)
2
=1}.(1.17)
(i) There exists a radially symmetric, nonincreasing, strictly positive min-
imiser ψ
d
of the variational problem in (1.17), which is unique up to transla-
tions. Moreover, ψ
d
2
2
< ∞.
(ii) Define u
d
= ψ
d
2
2
. Then u → θ
d
(u) is strictly decreasing on (u
,u
d
)
and
Θ
d
(u)=η
d
on [u
d
, ∞).(1.18)
0
s
u
u
d
η
d
(iii)
0 u
µ
4
(ii)
0 u
(i)
Figure 1 Qualitative picture of Θ
d
for: (i) d =2, 3; (ii) d = 4; (iii) d ≥ 5.
Theorem 6. (i) Let 2 ≤ d ≤ 4 and u ∈ (u
, ∞) or d ≥ 5 and u ∈ (u
,u
d
].
Then the variational problem in (1.14) has a minimiser that is strictly positive,
radially symmetric (modulo translations) and strictly decreasing in the radial
component. Any other minimiser is ofthe same type.
(ii) Let d ≥ 5 and u ∈ (u
d
, ∞). Then the variational problem in (1.14)
does not have a minimiser.
2
We will see in Section 5 that µ
4
= S
4
, the Sobolev constant in (4.3) and (4.4).
ON THEVOLUMEOFTHEINTERSECTIONOFTWOWIENER SAUSAGES
747
We expect that in case (i) the minimiser is unique (modulo translations).
In case (ii) the critical point u
d
is associated with “leakage” in (1.14); namely,
L
2
-mass u − u
d
leaks away to infinity.
1.5. Large deviations for infinite-time intersection volume. Intuitively,
by letting c →∞in (1.8) we might expect to be able to get the rate constant
for an infinite time horizon. However, it is not at all obvious that the limits
t →∞and c →∞can be interchanged. Indeed, theintersectionvolume might
prefer to exceed the value t on a time scale of order larger than t, which is not
seen by Theorems 1 and 2. The large deviations on this larger time scale are
a whole new issue, which we will not address in the present paper.
Nevertheless, Figure 1(iii) clearly suggests that for d ≥ 5 the limits can
be interchanged:
Conjecture. Let d ≥ 5 and a>0. Then
lim
t→∞
1
t
(d−2)/d
log P
|V
a
|≥t
= −I
κ
a
d
,(1.19)
where
I
κ
a
d
= inf
c>0
I
κ
a
d
(c)=I
κ
a
d
(c
∗
)=
η
d
κ
a
(1.20)
with c
∗
= u
d
/κ
a
.
The idea behind this conjecture is that the optimal strategy for the two
Wiener sausages is time-inhomogeneous: they follow the Swiss cheese strategy
until time c
∗
t and then wander off to infinity in different directions. The
critical time horizon c
∗
comes from (1.13) and (1.18) as the value above which
c → I
κ
a
d
(c) is constant (see Fig. 1(iii)). During the time window [0,c
∗
t] the
Wiener sausages make a Swiss cheese parametrised by the ψ
d
in Theorem
5; namely, (1.9) and (1.10) have a minimising sequence (φ
j
) converging to
φ =(c
∗
κ
a
)
−1/2
ψ
d
in L
2
(R
d
).
We see from Figure 1(ii) that d =4iscritical for an infinite time horizon.
In this case the limits t →∞and c →∞apparently cannot be interchanged.
Theorem 4 shows that for 2 ≤ d ≤ 4 the time horizon in the optimal
strategy is c = ∞, because c → I
κ
a
d
(c) is strictly decreasing as soon as it
is finite (see Fig. 1(i–ii)). Apparently, even though lim
t→∞
|V
a
(t)| = ∞ P -
almost surely (recall (1.7)), the rate of divergence is so small that a time of
order larger than t is needed for theintersectionvolume to exceed the value
t with a probability exp[−o(t
(d−2)/d
)] respectively exp[−o(log t)]. So an even
larger time is needed to exceed the value t with a probability of order 1.
1.6. Three or more Wiener sausages. Consider k ≥ 3 independent
Wiener sausages, let V
a
k
(t) denote their intersection up to time t, and let
748 M. VAN DEN BERG, E. BOLTHAUSEN, AND F. DEN HOLLANDER
V
a
k
= lim
t→∞
V
a
k
(t). Then the analogue of (1.7) reads (see e.g. Le Gall [11])
P (|V
a
k
| < ∞)=
0if1≤ d ≤
2k
k−1
,
1ifd>
2k
k−1
.
(1.21)
The critical dimension 2k/(k −1) comes from the following calculation:
E|V
a
k
| =
R
d
P
σ
B
a
(x)
< ∞
k
dx =
R
d
1 ∧
a
|x|
d−2
k
dx,(1.22)
where σ
B
a
(x)
= inf{t ≥ 0: β(t) ∈ B
a
(x)}. The integral converges if and only
if (d − 2)k>d.
It is possible to extend the analysis in Sections 1.3 and 1.4 in a straight-
forward manner, leading to the following modifications (not proved in this
paper):
(1) Theorems 1 and 2 carry over with:
– V
a
replaced by V
a
k
;
– c replaced by kc/2 in (1.9);
–
R
d
(1 − e
−κ
a
cφ
2
(x)
)
2
dx replaced by
R
d
(1 − e
−κ
a
cφ
2
(x)
)
k
dx in (1.10).
(2) Theorems 3, 4 and 5 carry over with:
–
(1 − e
−ψ
2
)
2
replaced by
(1 − e
−ψ
2
)
k
in (1.14) and (1.17);
– u
= min
ζ>0
ζ(1 −e
−ζ
)
−k
;
– ψ
4
replaced by ψ
2k
in (1.16).
For k = 3, the critical dimension is d = 3, and a behaviour similar to that
in Figure 1 shows up for: (i) d = 2; (ii) d = 3; (iii) d ≥ 4, respectively. For
k ≥ 4 the critical dimension lies strictly between 2 and 3, so that Figure 1(ii)
drops out.
1.7. Back to simple random walks. We expect the results in Theorems 1
and 2 to carry over to the discrete space-time setting as introduced in Section
1.1. (A similar relation is proved in Donsker and Varadhan [6] for a single
random walk, respectively, Brownian motion.) The only change should be
that for d ≥ 3 the constant κ
a
needs to be replaced by its analogue in discrete
space and time:
κ = P(S(n) =0∀n ∈ N ),(1.23)
the escape probability ofthe simple random walk. The global structure of the
Swiss cheese should be the same as before; the local structure should depend
on the underlying lattice via the number κ.
ON THEVOLUMEOFTHEINTERSECTIONOFTWOWIENER SAUSAGES
749
1.8. Outline. Theorem 1 is proved in Section 2. The idea is to wrap
the Wienersausages around a torus of size Nt
1/d
, to show that the error com-
mitted by doing so is negligible in the limit as t →∞followed by N →∞,
and to use the results in [3] to compute the large deviations ofthe intersection
volume onthe torus as t →∞for fixed N. The wrapping is rather delicate
because typically theintersectionvolume neither increases nor decreases under
the wrapping. Therefore we have to go through an elaborate clumping and re-
flection argument. In contrast, thevolumeof a single Wiener sausage decreases
under the wrapping, a fact that is very important to the analysis in [3].
Theorem 2 is proved in Section 3. The necessary modifications of the
argument in Section 2 are minor and involve a change in scaling only.
Theorems 3–6 are proved in Sections 4–7. The tools used here are scaling
and Sobolev inequalities. Here we also analyse the minimers ofthe variational
problems in (1.14) and (1.17).
2. Proof of Theorem 1
By Brownian scaling, V
a
(ct) has the same distribution as tV
at
−1/d
(ct
(d−2)/d
).
Hence, putting
τ = t
(d−2)/d
,(2.1)
we have
P
|V
a
(ct)|≥t
= P
|V
aτ
−1/(d−2)
(cτ)|≥1
.(2.2)
The right-hand side of (2.2) involves theWienersausages with a radius that
shrinks with τ. The claim in Theorem 1 is therefore equivalent to
lim
τ→∞
1
τ
log P
|V
aτ
−1/(d−2)
(cτ)|≥1
= −I
κ
a
d
(c).(2.3)
We will prove (2.3) by deriving a lower bound (§2.2) and an upper bound
(§2.3). To do so, we first deal with the problem on a finite torus (§2.1) and
afterwards let the torus size tend to infinity. This is the standard compactifi-
cation approach. Onthe torus we can use some results obtained in [3].
2.1. Brownian motion wrapped around a torus. Let Λ
N
be the torus
of size N>0, i.e., [−
N
2
,
N
2
)
d
with periodic boundary conditions. Let β
N
(s),
s ≥ 0, be the Brownian motion wrapped around Λ
N
, and let W
aτ
−1/(d−2)
N
(s),
s ≥ 0, denote its Wiener sausage with radius aτ
−1/(d−2)
.
Proposition 1. (|W
aτ
−1/(d−2)
N
(cτ)|)
τ>0
satisfies the large deviation prin-
ciple on R
+
with rate τ and with rate function
J
κ
a
d,N
(b, c)=
1
2
c inf
ψ∈Ψ
κ
a
d,N
(b,c)
Λ
N
|∇ψ|
2
(x)dx
,(2.4)
[...]... The proof of Proposition 4 will require quite a bit of work The hard part is to show that theintersectionvolumeoftheWienersausageson Rd is close to theintersectionvolumeoftheWienersausages wrapped around ΛN when N is large Note that theintersectionvolume may either increase or decrease when theWienersausages are wrapped around ΛN , so there is no simple comparison available Proof The. .. T )/T , which is the factor in the second term onthe right-hand side ofthe analogue of (2.86) The integral onthe right-hand side of (3.9) is of order 1/2 log(1/ ) Hence we get C 5/6 log(1/ ) for the second term onthe right-hand side ofthe analogue of (2.93) 4 Proof of Theorem 3 In Sections 4–6 we prove Theorems 3–5 The proof follows the same line of reasoning as in [3, §5], but there are some subtle... the rate function (compare (2.4) with (2.7)) comes from the fact that both Brownian motions have to follow the drift field ∇φ/φ The proof is a straightforward adaptation and generalization ofthe proof of Proposition 3 in [3] We outline the main steps, while skipping the details Step 1 One ofthe basic ingredients in the proof in [3] is to approximate thevolumeoftheWiener sausage by its conditional... √ These two bounds will play a crucial role in the sequel We will pick η = N and M = log N , do our reflections with respect to the central hyperplanes in ONTHEVOLUME OF THEINTERSECTIONOF TWO WIENERSAUSAGES 759 J S√N ,N , and use the fact that for large N both the number of crossings and the J intersectionvolume in S√N ,N are small because of (2.56) This fact will allow us to control both the. .. N The rest ofthe proof of Proposition 4 will be based on Propositions 5 and 6 below Proposition 5 states that theintersectionvolume has a tendency to clump: the blocks where theintersectionvolume is below a certain threshold have a negligible total contribution as this threshold tends to zero Proposition 6 states that, at a negligible cost as N → ∞, the Brownian motions can be J reflected in the. .. 2 ≥b ΛN The last equality, showing that the variational problem reduces to the diagonal φ1 = φ2 , holds because if φ2 = 1 (φ2 + φ2 ), then 2 2 1 (2.34) 2|∇φ|2 ≤ |∇φ1 |2 + |∇φ2 |2 , 2 2 (1 − e−cκa φ1 )(1 − e−cκa φ2 ) ≤ (1 − e−cκa φ )2 This completes the proof of Proposition 2 2 2 2 ONTHEVOLUMEOFTHEINTERSECTIONOFTWOWIENERSAUSAGES 755 2.2 The lower bound in Theorem 1 In this section we prove:... we proceed with the proof of Proposition 6(ii) Proof Each reflection of an excursion beginning with an exit-point and ending with an entrance-point costs a factor 2 in probability Onthe event Ccτ,log N,√N , the total number of excursions ofthetwo Brownian motions is √N bounded above by d logN cτ Moreover, onthe event Ocτ the number of central hyperplanes available for the reflection is bounded above... Lemma 6 This completes the proof of Proposition 4 and hence of Theorem 1 3 Proof of Theorem 2 In this section we indicate how the arguments given in Section 2 for theWienersausages in d ≥ 3 can be carried over to d = 2 The necessary modifications are minor and only involve a change in the choice ofthe scaling parameters By Brownian scaling, V a (ct) has the same distribution as × (c log t), t > 1... expectation given a discrete skeleton We do the same here Abbreviate (2.9) −1/(d−2) aτ Wi (cτ ) = Wi,N (cτ ) , V (cτ ) = W1 (cτ ) ∩ W2 (cτ ) i = 1, 2, ONTHEVOLUME OF THEINTERSECTIONOF TWO WIENERSAUSAGES 751 Set X i,cτ,ε = {βi (jε)}1≤j≤cτ /ε , (2.10) i = 1, 2, where βi (s), s ≥ 0, is the Brownian motion onthe torus ΛN that generates theWiener sausage Wi (cτ ) Write E cτ,ε for the conditional expectation... that onthe complement ofthe event onthe left-hand side of (2.62) we have 0 ≤ |V aτ (2.63) −1/(d−2) J |Vcτ,√N ,N,in (z)| ≤ 2δ (cτ )| − z∈Z J,N The sum onthe right-hand side is invariant under the reflections (because the J |Vcτ,√N ,N,in (z)| with z ∈ Z J,N end up in disjoint N -boxes), and therefore the estimate in (2.63) implies that most oftheintersectionvolume is unaffected by the reflections . bit of work. The hard part
is to show that the intersection volume of the Wiener sausages on R
d
is close to
the intersection volume of the Wiener sausages. completes the proof of Proposition 2.
ON THE VOLUME OF THE INTERSECTION OF TWO WIENER SAUSAGES
755
2.2. The lower bound in Theorem 1. In this section we prove:
Proposition