Tài liệu Circuits & Electronics P20 pdf
Tài liệu Circuits & Electronics P20 pdf
... resistor
i
R
v
I
→
O
O
v
d
t
dv
RC
>>
when
I
O
v
d
t
dv
RC
≈
dtv
RC
1
v
t
IO
∫
∞−
≈
or
IO
O
vv
d
t
dv
RC
=+
R
v
larger the RC,
smaller the
v
O
for good
integrator
ωRC >> 1
I
v
+
–
i
+
–
O
v
C
R
v
+
–
R
Demo
6.002 ... converters
Filters
Clock generators
Amplifiers
Adders
Integrators & Differentiators
Reading: Chapter 15.5 & 15.6 of A & L.
+
–
Review
∞ input resistanc...
Tài liệu Circuits & Electronics P12 pdf
... 6.002 Fall 2000 Lecture
1
12
6.002
CIRCUITS
AND
ELECTRONICS
Capacitors
and First-Order Systems
6.002 Fall 2000 Lecture
10
12
2
Homogeneous ... 55
RC
t
e
−
5
RC
=
τ
Remember
demo
B
Examples
6.002 Fall 2000 Lecture
2
12
5V
0V
C
A
B
5V
A
B
C
5
0
5
0
5
0
Reading:
Chapters 9 & 10
Demo
5V
Expected
Observed
Expect this, right?
But observe this!
Delay!
Motivation
6.002
Tài liệu Circuits & Electronics P11 pdf
... the
same KVL, KCL equations
BOUTA
VVV
++++
"""
so, we can cancel them out
BOUTA
vvv
++++++
""""
1
bouta
vvv
++++
"""
Leaving
2
Since small signal models ... circuit.
Foundations: (Also see section 8.2.1 of A&L)
KVL, KCL applied to some circuit C yields:
III The Small Signal Circuit View
bBoutOUTaA
vVvVvV
+++++++
"""
Replace...
Tài liệu Circuits & Electronics P7 pdf
... 6.002 Fall 2000 Lecture
1
7
6.002
CIRCUITS
AND
ELECTRONICS
Incremental Analysis
6.002 Fall 2000 Lecture
10
7
()
D
Vv
D
D
DD
v
vd
vfd
Vfi
DD
∆⋅+≈
=
)(
equating
Tài liệu Circuits & Electronics P6 pdf
... 6.002 Fall 2000 Lecture
1
6
6.002
CIRCUITS
AND
ELECTRONICS
Nonlinear Analysis
6.002 Fall 2000 Lecture
10
6
Problem:
The LED is nonlinear ... Superposition
m5 X Thévenin, Norton
any
circuit
linear
circuits
Review
6.002 Fall 2000 Lecture
3
6
Discretize value t Digital abstraction
X Subcircuits for given “switch”
setting are linear! So, ... Introduction to incremental analysis
6.002...
Tài liệu Circuits & Electronics P22 pdf
...
1
22
6.002
CIRCUITS
AND
ELECTRONICS
Energy and Power
6.002 Fall 2000 Lecture
10
22
Putting the two together:
Energy dissipated in each cycle
2
S
2
S
CV
2
1
CV
2
1
+=
21
EEE
+=
C gdischargin & ... Lecture
13
22
We can show (see section 12.2 of A & L)
()
()
2
ONL
2
L
2
S
ONL
2
S
RR
R
fCV
RR2
V
P
+
+
+
=
fCV
R2
V
P
2
S
L
2
S
+=
when
R
L
>>
R
ON
What is for gate?
P
r
e
m
e...
Tài liệu Circuits & Electronics P19 pdf
... 6.002 Fall 2000 Lecture
1
19
6.002
CIRCUITS
AND
ELECTRONICS
The Operational Amplifier
Abstraction
6.002 Fall 2000 Lecture
10
19
e.g.
v
IN
= ... for
more complex circuits (of course, need
to be careful about input and output).
Today
Introduce a more powerful amplifier
abstraction and use it to build more
complex circuits.
Reading: ... powerful amplifier
abstraction and use it t...
Tài liệu Circuits & Electronics P16 pptx
... 6.002
CIRCUITS
AND
ELECTRONICS
Sinusoidal Steady State
6.002 Fall 2000 Lecture
16
1
2
Fourth try to find ...
+
–
R
i
C
+
v
I
v
C
–
v
I
(
t
)
= V
i
cos
ω
t
for
t ≥
0 (
V
i
real)
= 0
for
t <
0
v
C
(0)
=
0
for
t =
0
I
v
0
t
6.002 Fall 2000 Lecture
16
4
1
1
1
1
e
c
t
u
r
Example:
Tài liệu Circuits & Electronics P15 docx
... 6.002 Fall 2000 Lecture
1
15
6.002
CIRCUITS
AND
ELECTRONICS
Second-Order Systems
6.002 Fall 2000 Lecture
10
15
0
2
2
=+
H
H
v
d
t
vd
LC
Solution ... back and forth between the
Capacitor and the inductor
6.002 Fall 2000 Lecture
19
15
RLC Circuits
See A&L Section 12.2
add
R
no
R
+
–
C
R
L
+
–
)(
tv
)(tv
I
)(
ti
)(
tv
t
Damped sinusoids ... Method
1
2
3
Write DE for circuit by a...
Tài liệu Circuits & Electronics P14 pptx
... 6.002 Fall 2000 Lecture
1
14
6.002
CIRCUITS
AND
ELECTRONICS
State and Memory
6.002 Fall 2000 Lecture
10
14
A
Stored value leaks away
store
pulse width >>
R
ON
C
Building a memory element ... resistance
R
IN
B
Second attempt buffer
R
IN
store
buffer
d
IN
d
OUT
C
*
5
ln
OH
IN
V
CRT −=
LIN
RR >>
Better, but still not perfect.
Demo
Building a memory element …
6.002 Fall 20...