Báo cáo toán học: "Composition matrices, (2 + 2)-free posets and their specializations" doc

... that they are indeed equivalent. 2 (2 + 2)-free posets and composition matrices In this section we present and prove a bijection between (2 + 2)-free posets and compo- sition matrices. We call ... electronic journal of combinatorics 18 (20 11), #P44 6 Composition matrices, (2 + 2)-free posets and their specializations Mark Dukes ∗ Department...

Ngày tải lên: 08/08/2014, 12:23

... − ν j + j)=O(n m(m−1) 2 ), Γ(λ i + δ i +1 + j + δ j ) (ν j + m − j)! = (λ i + δ i + ν j + δ j )! (ν j + m − j)! ≤ (λ i + δ i + ν j + δ j ) λ i + i +l−m = O(n λ i + i +l−m ), n! (|λ| + l 2 ) n = ... − ν j + j)=n l(l−1) 2 V (α) · (1 + o(1)), Γ(λ i + δ i +1 + j + δ j ) (ν j + δ j )! = Γ(λ i + δ i +1 +...

Ngày tải lên: 07/08/2014, 06:20

... 1)(r +1 )!(n − r −1)! < {2r !+( r +1 )!}(n − r)!. Thus we get n!t n = r−1  k=0 d k (n − k)! + O((n − r)!) and hence t n = 1+ r−1  k=1 d k [n] k + O(n −r ) where [n] k = n(n − 1) (n − k + 1). ... )=log(1+Y ), D(X)= 1/E(X)andB(X)=T (X) in Bender’s theorem. Then condition (i) is clearly satisfied and (ii) holds for every integer r ≥ 1 since for n>2r n−r  k=r k!...

Ngày tải lên: 07/08/2014, 13:21

... that x c n  1+ s n xc n  log  1+ xc n s n  ≥ x c n  1+ s n xc n   xc n s n + xc n + 1 2  xc n s n + xc n  2  1+ 2 3 log  1+ xc n s n   = x c n + x 2 2 ( s n + xc n )  1+ 2 3 log  1+ xc n s n  . Shen ... {2, 2a, a +1 }, we have by (4.9), (4.10), and (4.12) that lim sup n→∞ (a + μ n ) α E(a + X n ) − α ≤ lim sup n→∞...

Ngày tải lên: 20/06/2014, 22:20

... HIV epidemic and during the 2003 SARS outbreak. With an influenza pandemic looming as an imminent probability, all physicians need to ask what sacrifices are demanded in the name of their profession and ... influenza pandemic looms, preparation is underway to cope with what may be the most lethal public health crisis to confront the world [1]. By virtue of their training and experti...

Ngày tải lên: 13/08/2014, 11:22

Ngày tải lên: 05/08/2014, 15:20

Ngày tải lên: 05/08/2014, 10:20

... following scheme. Exchange π 1 and 1 and then sort π 2 , ,π p 1 into ascending order. Next exchange π p 1 +1 and the minimum of π p 1 +1 , ,π n and then sort π p 1 +2 , ,π p 2 into ascending order. ... potential U(z)=z + tz 2 . Setting t = −ω 2 , and making a change of gauge φ(z)=exp(ωz)ψ(z) transforms (4.4) into z 2 ψ  (z )+( 1− ν)zψ  (z )+2 ωz 2 ψ  (z)+z (ω(...

Ngày tải lên: 07/08/2014, 06:20

... combinatorics 8 (20 01), #R1 4 This leads to the system a  + b  = n c  + d  = n e  + f  = n g  + h  = n a  − b  + c  − d  − e  + f  − g  + h  =0 a  − b  − c  + d  − e  + f  + g  − ... J. Combin. 7 (20 00), #R1. the electronic journal of combinatorics 8 (20 01), #R1 9 rows have the form: nnnn    + ··· + ···  ...

Ngày tải lên: 07/08/2014, 06:22

... (51):               ρ p+q−1+N 1 ρ p+q−2+N 1 ρ N 1 . . . . . . . . . . . . ρ p+q−1+N p ρ p+q−2+N p ρ N p ρ p+q−1 p+1 ρ p+q−2 p+1 ρ 0 p+1 . . . . . . . . . . . . ρ p+q−1 p+q ρ p+q−2 p+q ρ 0 p+q                      ρ p+q−1 1 ρ p+q−2 1 ... ρ 0 p+q                      ρ p+q−1 1 ρ p+q−2 1 ρ 0 1 . . . . . . . . . . . . ρ p+q−1 p+q ρ p+q...

Ngày tải lên: 07/08/2014, 08:22