cơ học lý thuyết tập 2 - phần động lực học

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... Pumping Water into a Tank Problem A tall tank has a cross-sectional area of 340 cm 2 and is open to the air (Pa = 101 kPa). The top portion of the tank contains 156 ... liters of water. A horizontal tube connected to the tank at the bottom has a cross-sectional area of 11.0 mm 2 . Water is forced into the tank through the tube which is connected to a pump. ... that of the atmospheric pressure when steady-state equilibrium flow is established. We could use this information to determine the velocity of the fluid-flow in the tube if were open to the air....

... zkcos) 2 = x 2 k ( 1 - cos 2 ) + y 2 k ( 1 - Chú 2 k = x 2 k ( cos 2  + cos 2  ) + y 2 k (cos 2  + cos 2  )+ z 2 k (cos 2  + cos 2  ) –d 2 k = ( y 2 k +z 2 k kykcoscos - Do ... yk: 2 k = x 2 k + y 2 k + z 2 k – (xkcos 2 ) + z 2 k ( 1 - cos 2  ) –2xkykcoscos - 2xkzkcoscos – 2ykzkcoscos. ý rng : cos 2  + cos 2  + cos 2  = 1 Ta có : d2xkykcoscos ... Ta có : d2xkykcoscos - 2xkzkcoscos – 2ykzkcoscos )cos  + ( z 2 2k + x 2 k )cos  + ( x 2 2k + y 2 k )cos  – 2x 2 2xkzkcoscos – 2ykzkcoscos. a vt đi...

... -3 4- Bảng 2- 2 Fr1Fr Tr1Tr 2 RrARrBX1Y1Z1mx(F) my(F) mz(F) 0 Fcos -Fsin -F.r 2 Fsin.b Fcos.b 0 Thép 45 0 T1r10 -T1.a 0 T 2 0 -T 2 r10 -T 2 a ... bảng ( 2- 1) hình chiếu các lực lên 3 trục của hệ tọa độ oxyz nh sau: Bảng 2- 1 F1P1P 2 R1R 2 R3x1y1z10 -P 0 -P 0 0 0 R1sin -R1cos R 2 sinsin R 2 sincos -R 2 cos ... = 2T 2 = 27 0 kN; ZB = basinP.b+ = 60405,0.180.60+ = 54 kN; YB =bacosPbT3.a 2 + = 6040 2 3.60.180135.3.40+ = 69 kN YA =- Pcos-3T 2 - YB = -1 80. 2 3 -3 .13 5- 69 -6 30KN...