fundamentals of electric circuits 5th edition solutions chapter 5

... cross-section of the conductor in 20 seconds 25 C0 t q=∫idt=∫ tdt= = Trang 46t2 25A, -2t0 A, Trang 5idt Trang 615 152 1510110idt 0 =++ = ×+ A lightning bolt with 8 kA strikes an object for 15 μ s How ... lamp, (b) the cost of operating the light for one non-leap year if electricity costs 12 cents per kWh Chapter 1, Solution 28 A0.25 2436530pt W b) Chapter 1, Problem 29 An electric stove with ... W,30W, 45W, 60W, Trang 15Chapter 1, Problem 19 Find I in the network of Fig 1.30 I 1A + + Trang 17hr 60 4 kW 1.2 Trang 18Chapter 1, Problem 26 A flashlight battery has a rating of 0.8 ampere-hours

Ngày tải lên: 13/09/2018, 13:31

... >> Y=[1.125,0,0,-0.125;0,0.75,-0.25,0;0,-0.25,0.75,0;-0.125,0,0,1.125] Y = 1.1250 0 0 -0.1250 0 0.7500 -0.2500 0 0 -0.2500 0.7500 0 -0.1250 0 0 1.1250 >> I=[4,-4,-2,2]' ... Y=[0.35,-3.25,3;-0.25,0.95,-0.5;0,-0.5,0.5] Y = 0.3500 -3.2500 3.0000 -0.2500 0.9500 -0.5000 0 -0.5000 0.5000 >> I=[-2,0,6]' I = -2 0 6 >> V=inv(Y)*I V = -164.2105 -77.8947 ... 84 4 V 25 0 V 75 0 0 4 V V 2 0 V 2 V 75 0 V 25 0 0 2 2 0 V 4 V V 32 32 2 V 125 1 V 125 0 0 1 0 V 8 V V 4 V 125 1 0 0 125 0 0 75 0 25 0 0 0 25 0 75 0 0 125 0 0 0 125 1 Now we can

Ngày tải lên: 13/09/2018, 13:31

... 4||10 = 5 + 20/7 = 55/7 i2 = [5/(5 + 55/7)]2 = 7/9, io3 = [-10/(10 + 4)]i = -5/9 2 io = (12/9) – (6/9) – (5/9) = 1/9 = 111.11 mA Trang 25Use superposition to obtain v in the circuit of Fig 4.85 Check ... 13/2)]2 = 3/8 = 0.375 i = 2.5 + 0.375 - 1 = 1.875 A p = i2R = (1.875)23 = 10.55 watts Trang 23Given the circuit in Fig 4.84, use superposition to get i oFigure 4.84 Trang 24Chapter 4, Solution ... the voltage source to obtain the circuit in Fig (b) 10||10 = 5 ohms, i = [5/(5 + 4)](2 – 1) = 5/9 = 555.5 mA Trang 36Chapter 4, Problem 23 Referring to Fig 4.91, use source transformation to

Ngày tải lên: 13/09/2018, 13:31

... circuit of Fig 5.51 Assume that the op Trang 14v k 10 0.27mA + 0.018mA = 288 μA Trang 15Determine the output voltage vo in the circuit of Fig 5.53 Figure 5.53 for Prob 5.14 Chapter 5, Solution ... determine the value of v in order to make 23 3 2 2 1 1 5 2 9 ) 1 ( 50 50 20 50 ) 2 ( 10 50 v v v R R v R R v R − = Thus, V 3 5 2 9 5 Trang 42+ _ Figure 5.77 For Prob 5.40 Chapter 5, Solution 40 ... For Prob 5.59 Trang 67Determine v in the circuit of Fig 5.88 oTrang 68Chapter 5, Problem 62 Obtain the closed-loop voltage gain v /v of the circuit in Fig 5.89 o i Figure 5.89 Chapter 5, Solution

Ngày tải lên: 13/09/2018, 13:31

... L + L = 2L L L L L Lx L L L L 5 0 2 5 0 2 5 0 // + + = + (b) L//L = 0.5L, L//L + L//L = L Leq = L//L = 500 mL Trang 50= +5 L L 3 5 Lx L 3 2 L L 8 5 Trang 51Determine the Leq that can be ... (6) 2.5( 6) 12.5 2.5 2.5 4 10 t x v t dt v t t x − = ∫ + = − + = − ⎪ ⎧ < < < < < < < < − − + s 8 t 6 s 6 t 4 s 4 t 2 s 2 t 0 , V 5 2 t 5 2 , V 5 12 , V t 5 2 5 22 ... 6, Solution 54 ( 10 0 6 12 ) ) 3 9 ( 4 = 4 + 12 ( 0 + 4 ) = 4 + 3 Leq = 7H Trang 49Find Leq in each of the circuits of Fig 6.77 Figure 6.77 Chapter 6, Solution 55 (a) L//L = 0.5L, L + L

Ngày tải lên: 13/09/2018, 13:31

... the prior Chapter 7, Problem 54 Obtain the inductor current for both t < 0 and t > 0 in each of the circuits in Fig 7.120 Figure 7.120 For Prob 7.54 Trang 52Chapter 7, Solution 54. (a) ... V 15 ) 30 ( 1 1 2 2 ) ( + + = ∞ Ω = + = ( 1 1 ) || 2 1 k Rth 4 1 10 4 1 10 C = τ ( 1 e ) , t 0 15 ) t ( v i 1 5 7 ) t ( ( 1 e ) mA 5 7 ) t ( Thus, mA e 5 7 5 7 30 ) t ( = ) t ( Trang 48Chapter ... 1 e ) 0 1054 6 1 ) 1 ( i = − - 1 = 2 1 6 1 3 1 ) ( i ∞ = + = 1) - -(te ) 5 0 1054 0 ( 5 0 ) t ( 1) - -(te 3946 0 5 0 ) t ( Thus, = ) t ( 1 t 0 A e 1 6 1 -1) (t - t Trang 605 0 RLth =

Ngày tải lên: 13/09/2018, 13:31

... reserved No part of this Manual may be displayed, reproduced or distributed in any form or by any means, without the prior t5505.1t 45.6 45 6 Be Ae ) 0 ( di but e 5505 1 Ae 45 6 dt Trang 32PROPRIETARY ... [Acos0.5t + Bsin0.5t], i(0) = 12 = A v = -Ldi/dt, and -v/L = di/dt = 0.5[-12sin0.5t + Bcos0.5t], which leads to -v(0)/L = 0 = B Hence, i(t) = 12cos0.5t A and v = 0.5 However, v = -Ldi/dt = -4(0.5)[-12sin0.5t] ... in Figure (c) i(f) = -5(4)/(3 + 5) = -2.5 A v(f) = 5(4 – 2.5) = 7.5 V  Trang 9PROPRIETARY MATERIAL © 2007 The McGraw-Hill Companies, Inc All rights reserved No part of this Manual may be displayed,

Ngày tải lên: 13/09/2018, 13:31

... = − = + = ) 5 2 j 5 2 5 2 ( j 5 4 30 − + = + ) j 5 )( 30 8 Trang 38Find Io in the circuit of Fig 9.60 4 x 6 j Z , 1 j 1 45 6569 5 90 8 4 j 4 4 x − = 5 1 j 5 1 4 j 4 ) 5 1 j 5 9 ( ) 10 ... is 4 j 3 2 j 5 j 1 + + I Therefore, = ) t ( is 25 cos(2t – 53.13 °) A Trang 37If Vo = 8 ∠ 30oV in the circuit of Fig 9.59, find I .5 j 5 j 5 25 j 5 j || + = + s 2 1 1 4 5 2 j 5 12 10 I I ... µ 50 ) 50 )( 0 1 = V ) 50 )( 2 ( ) 100 j 20 j 50 )( 0 1 ( V 80 j 150 100 80 j 50 in in Trang 45For the circuit in Fig 9.70, find the value of ZT⋅.450 j 200 z , 333 13 j 30 15 j 450 j 200 z 45

Ngày tải lên: 13/09/2018, 13:31

... Trang 15= 39 46 1936 1 22 15 86 4 ) 61 61 4502 1 ( 4 2758 1 j 69 4 ) 2758 1 j 6896 0 ( 4 2 j 5 2 xj 5 3 j 4 2 j 5 2 xj 5 3 j 4 VTh 5 Ω – 40 ) 17 67 4123 0 ( V ) 55 46 5235 0 ... 2 Trang 3515 t 5 t 2 20 )t ( i 15 2 15 5 2 2 20 1 I 5 2 2 5 1 I 3 15 5 3 2 2 3 t 3 t t 10 t 100 5 1 I 332 33 ] 33 83 33 83 [ 5 Trang 36Compute the rms value of the waveform depicted in Fig ... waveform of Fig 11.59 as well as the average power absorbed by a 2- Ω resistor when the voltage is applied across the resistor 0 2 2 5 1 V 533 8 ) 8 ( 15 16 3 t 16 5 1 0 3 2 V P 2 Trang 3515 t 5 t

Ngày tải lên: 13/09/2018, 13:31

... its equivalent T-section 5, 25520, 1055) =+ ++ =+ + 74 )4(627)6//( )4 ( j j j j j j j Th j j Trang 25H,5525Trang 26 Determine currents I1, I2, and I3 in the circuit of Fig 13.89 Find the energy ... mesh 1, j12 = (4 + j10 – j5)I 1 + j5I 2 + j5I 2 = (4 + j5)I 1 + j10I 2 (1) For mesh 2, 0 = 20 + (8 + j10 – j5)I 2 + j5I 1 + j5I 1 ++ 10j5j420 12j w = 0.5L 1 i 1 + 0.5L 2 i 2 – Mi 1 i 2 Since ... 40/7.767∠11.89° = 5.15∠–11.89° S = 0.5vsI1* = (20∠0°)(5.15∠11.89°) = 103∠11.89° VA (b) I2 = –I1/n, n = 2.5 I3 = –I2/n’, n = 3 I3 = I1/(nn’) = 5.15∠–11.89°/(2.5x3) = 0.6867∠–11.89° p = 0.5|I2|2(18) =

Ngày tải lên: 13/09/2018, 13:31

... without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Fundamentals of Electric Circuits 6th Edition by Alexander Full file at ... without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Fundamentals of Electric Circuits 6th Edition by Alexander Full file at ... without the prior written consent of McGraw-Hill Education Full file at https://TestbankDirect.eu/ Solution Manual for Fundamentals of Electric Circuits 6th Edition by Alexander Full file at

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... Library of Congress Control Number: 2008938520 ISBN-13: 978-0-495-55509-4 ISBN-10: 0-495-55509-6 Brooks/Cole 10 Davis Drive Belmont, CA 94002-3098 USA Cengage Learning is a leading provider of customized ... dollar $6500 gross income Ϫ 295 car lease Ϫ 225 car lease Ϫ 75 education loan Ϫ 105 cable bill Ϫ 60 telephone bill Ϫ 125 monthly credit card payment $5615 Now, 36% of that amount is 0.36 ϫ $5615 ϭ ... ϫ 6500 ϭ $1820 Gasoline/Car Maintenance 4.75% ϫ 6500 ϭ $308.75 Telephone Bill $60 Utilities 4.5% ϫ 6500 ϭ $292.50 Miscellaneous $230.25 remains for this category Education Loan $75 Food 7.5%

Ngày tải lên: 18/05/2017, 10:17

... record of a real estate company for the month of May shows the following house prices (rounded to the nearest $1,000) Values are in thousands of dollars 105 30 55 60 45 75 85 79 75 95 This edition ... some of the employees of Bastien's, Inc have taken during the first quarter of the year (rounded to the nearest hour) 19 23 36 12 59 a b c d 22 47 25 20 39 27 11 34 28 48 24 55 16 29 32 28 25 45 ... data on the ages of employees at a company Construct a stem-and-leaf display 26 52 41 42 32 44 53 44 28 36 55 40 45 42 48 36 58 27 32 37 This edition is intended for use outside of the U.S only,

Ngày tải lên: 27/10/2017, 09:24

... to $35.00/oz of gold B) devalued; $35.00/oz to $20.67/oz of gold C) revalued; $20.67/oz to $35.00/oz of gold D) revalued; $35.00/oz to $20.67/oz of gold Answer: A Diff: Topic: 2.1 History of the ... Jerry paid C$5.50 for a six-pack of beer while he was in Canada while his roommate, Ben, paid $5.75 for a six-pack of the same beer in the states If the current exchange rate is $1.0335/C$, who ... Fundamentals of Multinational Finance, 5e (Moffett et al.) Chapter The International Monetary System Multiple Choice and True/False Questions 2.1 History of the International

Ngày tải lên: 27/10/2017, 09:25

... Buys $4,000 of supplies on account  Pays $5,000 cash for new equipment  Pays off $3,000 of accounts payable  Pays off $1,500 of notes payable Required: Part a Show the effect of these transactions ... Accounts +4,000 Payable +5,000 –5,000 Accounts –3,000 –3,000 Payable Notes –1,500 –1,500 Payable Stockholders’ Equity Test Bank—Fundamentals of Financial Accounting, 5e Copyright © 2016 McGraw-Hill ... company pays $550,000 in cash and borrows $150,000 from a bank to buy new equipment No other transactions took place during July, Year Test Bank—Fundamentals of Financial Accounting, 5e Copyright

Ngày tải lên: 27/10/2017, 09:25

... Claims D None of the above 54 Which of the following are primary sources of tax authority? A Statutory sources B Administrative sources C Judicial sources D All of the above 55 Which of the following ... Objective: 54 Which of the following are primary sources of tax authority? A Statutory sources B Administrative sources C Judicial sources D All of the above Learning Objective: 55 Which of the following ... Learning Objective: 58 Which of the following refers to an income tax regulation? A Reg §1.162-5 B Reg §20.2032-1 C Reg §25.2503-4 D Reg §31.3301-1 Learning Objective: 59 Which of the following

Ngày tải lên: 27/10/2017, 09:26

... D $75.00 150.00 45.00 a 45.00 30.00 $75.00 150.00 45.00 b 40.91 N/A 90.00 81.82 c d $75.00 150.00 45.00 40.91 30.00 81.82 $270.00 $435.00 $392.73 $422.73 $324.00 $522.00 $471.28 $507.28 $45.00 ... Test Bank for Fundamentals of Cost Accounting 5th edition by William N Lanen, Shannon W Anderson, Michael W Maher Chapter 1: Cost Accounting: Information for Decision Making Solutions to Review ... can help managers of not-for-profit organizations by highlighting the costs of various activities, identifying sources of revenue, and measuring performance of managers In terms of organizational

Ngày tải lên: 28/02/2019, 17:08

... fundamentals of advanced accounting 6th edition chapter solutions fundamentals of advanced accounting 6th edition chapter solutions fundamentals of advanced accounting 6e solutions manual fundamentals of ... 6th edition pdf fundamentals of advanced accounting 6th edition chapter solutions fundamentals of advanced accounting 6th edition chapter solutions fundamentals of advanced accounting 6th edition ... link: fundamentals of advanced accounting 6th edition solutions pdf fundamentals of advanced accounting 6th edition test bank fundamentals of advanced accounting 6th edition chapter solutions fundamentals

Ngày tải lên: 01/03/2019, 08:49

... ft i.c Kz  152 Face 140ʹ E (a) Compute Variation of Wind Pressure on Windward qz = qs IK z K zt K d leeward C p = -0.5 qz = 49.05(1.52) = 74.556 p = 74.556 GC p = 74.556(0.85)(-0.5) Eq 2.8 Eq ... for Fundamentals of Structural Analysis 5th Edition By Leet FUNDAMENTALS OF STRUCTURAL ANALYSIS 5th Edition Kenneth M Leet, Chia-Ming Uang, Joel T Lanning, and Anne M Gilbert SOLUTIONS MANUAL CHAPTER ... 481.8[4.6 × 20] + 510.2[1.5 × 20] + 532.9[1.5 × 20] + 555.6[1.4 × 20] qz = qs IK z K zt K d FW = 91,180 N qz = 980.8(1)(K z )(1)(0.85) = 833.7 K z For Leeward Wall - 4.6 m: qz = 833.7(0.85) = 708.6

Ngày tải lên: 20/08/2020, 12:02

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Ngày tải lên: 27/08/2020, 09:10