... expenses 21 ,000 22 ,750 23 , 625 EBIT $ 20 4,600 $ 22 1,650 $ 23 0,175 Interest 12, 500 12, 500 12, 500 Taxable income $ 1 92, 100 $ 20 9,150 $ 21 7,675 Taxes (35%) 67 ,23 5 73 ,20 3 76,186 Net income $ 124 ,865 ... $4,9 12. 23 + 2, 621 .49 = $7,533. 72 And finally, we are ready to solve the balance sheet identity as: NFA = TA – CA = $7,533. 72 – 1 ,27 4 = $6 ,25 9. 72 21 . Child: Profit margin = NI / S = $2. 00 ... 0 .25 ( $25 K) + 0.34( $25 K) + X($100K); X($100K) = $68K – 22 .25 K = $45.75K X = $45.75K / $100K X = 45.75% 25 . Balance sheet as of Dec. 31, 20 06 Cash $2, 528 Accounts payable $2, 656 ...
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fundamentals of electric circuits
... i 1 and i 2 as in Eq. (2. 8.1). Equation (2. 8.4) becomes 6i 3 = 3i 2 ⇒ i 3 = i 2 2 (2. 8.5) Substituting Eqs. (2. 8.3) and (2. 8.5) into (2. 8 .2) gives 30 − 3i 2 8 − i 2 − i 2 2 = 0 or i 2 = 2 A. From ... Solving 18 1.9 Summary 21 Review Questions 22 Problems 23 Comprehensive Problems 25 2. 1 Introduction 28 2. 2 Ohm’s Laws 28 † 2. 3 Nodes, Branches, and Loops 33 2. 4 Kirchhoff’s Laws 35 2. 5 Series Resistors ... use Kirchoff’s voltage law to check the results. i 1 = v 1 − 5 2 = 2 − 5 2 =− 3 2 =−1.5A i 2 = i 8 = 0 .25 A i 3 = v 1 + 3 4 = 2 + 3 4 = 5 4 = 1 .25 A i 1 + i 2 + i 3 =−1.5 + 0 .25 + 1 .25 = 0 (Checks.) Applying...
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... where () 2 A DL 0.1m 25 m 7.85m . == ì= Hence, () () 22 824 444 q 7.85m 10 W/m K 150 25 K 0.8 5.67 10 W/m K 423 29 8 K =+ìì ()() 22 q 7.85m 1 ,25 0 1,095 w/m 9813 85 92 W 18,405 ... sur h4T TTT2 εσ ==+ For the condition of ε = 0.05, T s = T sur + 10 = 35°C = 308 K and T sur = 25 °C = 29 8 K, find that () ( ) 824 22 3 2 r h 0.05 5.67 10 W m K 308 29 8 308 29 8 K 0.32W m K =ìì ... T 2 = -15°C are ( ) 2 12 x 25 C 15 C dT T T q k k 1W m K 133.3W m dx L 0.30m −− − ′′ =− = = ⋅ = . (1) 22 xx q q A 133.3W m 20 m 26 67W =ì= ì = . (2) < Combining Eqs. (1) and (2) ,...
Ngày tải lên: 08/08/2014, 17:20
fundamentals of heat and mass transfer solutions manual phần 2 docx
... 0 −= Hence, ( ) () ()() [] s ,2 s,1 2 2s ,2 12 TT h4r T T 1r 1r 4 k π π ∞ − −= − ()() [] () () s ,2 s,1 2 21 2 s ,2 TT k r1r 1r h TT ∞ − −= − () () ( ) () s ,2 s,1 22 2 11 1 s ,2 TT r r k 1.5W m K 30 1 r ... lens: () t,wo 23 2- 3 33111 Rm 4 0.35 W/m K 10 .2 12. 7 10 12W/m K4 10 .2 10 m =+ ì ì () 2 2-3 3 191 .2 K/W+13 .2 K/W +24 6.7 K/W=451.1 K/W 6 W/m K4 12. 7 10 m += ì With lens: t,w 3 3111 R 191 .2 K/W+13 .2 K/W+ ... outer surface of the insulation, it follows that cond conv rad qqq ′′′ =+ () ()() s,1 s ,2 s ,2 s ,2 sur 21 2 2r TT TTTT ln r r 2 k 1 2 r h 1 2 r h ππ π ∞ −−− =+ where () () 22 r s ,2 sur s ,2 sur hTTTT εσ =+...
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fundamentals of heat and mass transfer solutions manual phần 3 pdf
... 22 8.9 22 8.3 22 6 .2 222 .6 21 7 .2 209.7 20 0.1 188.4 175.4 161.6 147.5 75 25 5.0 25 4.4 25 2.4 24 8.7 24 3.1 23 5.0 22 3.9 20 9.8 194.1 177.8 100 28 2.4 28 1.8 28 0.1 27 6.9 27 1.6 26 3.3 25 0.5 23 2.8 21 3.5 125 310.9 ... 125 150 175 20 0 22 5 25 0 27 5 300 0 180.7 180 .2 178.4 175.4 171.1 165.3 158.1 149.6 140.1 129 .9 119.4 108.7 98.0 25 20 4 .2 203.6 20 1.6 198 .2 193.3 186.7 178.3 168.4 157.4 145.6 133.4 121 .0 50 22 8.9 ... 105.6 119 131.7 151.6 20 0 50 88 .2 117.4 138.7 156.1 174.6 20 0 50 99.6 137.1 1 62. 5 179 .2 190.8 20 0 50 123 .0 168.9 194.9 20 7.6 20 9.4 20 0 50 173.4 22 0.7 24 0.6 24 6.8 23 9.0 20 0 - 300 300 300 300 300...
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fundamentals of heat and mass transfer solutions manual phần 4 docx
... 315.3 324 .5 325 325 325 325 325 3 54 29 4.7 313.7 320 .3 324 .5 325 325 325 325 4 72 293.0 307.8 318.9 322 .5 324 .5 325 325 325 5 90 28 7.6 305.8 315 .2 321 .5 323 .5 324 .5 325 325 6 108 28 5.6 301.6 ... 319.3 322 .7 324 .0 324 .5 325 7 126 28 1.8 29 9.5 310.5 317.9 321 .4 323 .3 324 .2 8 144 27 9.8 29 6 .2 308.6 315.8 320 .4 322 .5 9 1 62 276.7 29 4.1 306.0 314.3 319.0 10 180 27 4.8 29 1.3 304.1 3 12. 4 Hence, ... Eqs. (2) and (4). The results are tabulated below. p t(s) T 0 T 1 T 2 T 3 T 4 T 5 T 6 T 7 (K) 0 0 325 325 325 325 325 325 325 325 1 18 304 .2 324 .7 325 325 325 325 325 325 2 36 303 .2 315.3...
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fundamentals of heat and mass transfer solutions manual phần 5 ppsx
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fundamentals of heat and mass transfer solutions manual phần 7 pot
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fundamentals of heat and mass transfer solutions manual phần 10 doc
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Fundamentals of Ecological Modelling, Third Edition pot
... 22 5 5.1 Introduction 22 5 5 .2 Network Models 22 6 5.3 Network Analysis 23 0 5.4 ECOPATH Software 23 6 5.5 Response Models 24 8 6. Modelling Population Dynamics 25 7 6.1 Introduction 25 7 6 .2 ... Conceptual Models 21 1 4.1 Introduction 21 1 4 .2 Application of Conceptual Diagrams 21 1 4.3 Types of Conceptual Diagrams 21 4 4.4. The Conceptual Diagram as Modelling Tool 22 1 Problems 22 3 5. Static ... Concepts 25 7 6.3 Growth Models in Population Dynamics 25 8 6.4 Interaction between Populations 26 2 6.4 Matrix Models 27 3 Problems 27 6 7. Dynamic Biogeochemical Models 27 7 7.1 Introduction 27 7...
Ngày tải lên: 23/03/2014, 01:20
unit operation of chemical engineering 6th ed, solutions manual
Ngày tải lên: 01/04/2014, 11:53
unit operation of chemical engineering 7th ed, solutions manual
... student using this Manual, you are using it without permission. Page 26 - 2 PROPRIETARY MATERIAL. â The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual may be ... are using it without permission. Page 22 - 1 PROPRIETARY MATERIAL. â The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual may be displayed, reproduced or distributed ... are using it without permission. Page 25 - 2 PROPRIETARY MATERIAL. â The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual may be displayed, reproduced or distributed...
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