fundamentals of electric circuits 3rd edition solutions manual chapter 5

... $68K = 0. 15( $50 K) + 0. 25( $25K) + 0.34($25K) + X($100K); X($100K) = $68K – 22.25K = $ 45. 75K X = $ 45. 75K / $100K X = 45. 75% 25. Balance sheet as of Dec. 31, 2006 Cash $2 ,52 8 Accounts ... .55 (TA – E) / TA = . 45 (TA / TA) – (E / TA) = .55 (TA / TA) – (E / TA) = . 45 1 – (E / TA) = .55 1 – (E / TA) = . 45 E / TA = . 45 E / TA = .55 E = . 45( TA) E = .55 (TA) Rearranging ROA, ... Sales Growth 35% Sales Growth Sales $1,014,000 $1,098 ,50 0 $1,140, 750 Costs 788,400 854 ,100 886, 950 Other expenses 21,000 22, 750 23,6 25 EBIT $ 204,600 $ 221, 650 $ 230,1 75 Interest 12 ,50 0 12 ,50 0 12 ,50 0 ...

Ngày tải lên: 01/07/2014, 14:22

... 52 8 13.2 Mutual Inductance 52 8 13.3 Energy in a Coupled Circuit 53 5 13.4 Linear Transformers 53 9 13 .5 Ideal Transformers 54 5 13.6 Ideal Autotransformers 55 2 † 13.7 Three-Phase Transformers 55 6 13.8 PSpice ... use Kirchoff’s voltage law to check the results. i 1 = v 1 − 5 2 = 2 − 5 2 =− 3 2 =−1.5A i 2 = i 8 = 0. 25 A i 3 = v 1 + 3 4 = 2 + 3 4 = 5 4 = 1. 25 A i 1 + i 2 + i 3 =−1 .5 + 0. 25 + 1. 25 = 0 (Checks.) Applying ... Measurement 4.11 Summary 153 Review Questions 153 Problems 154 Comprehensive Problems 162 5. 1 Introduction 166 5. 2 Operational Amplifiers 166 5. 3 Ideal Op Amp 170 5. 4 Inverting Amplifier 171 5. 5 Noninverting...

Ngày tải lên: 08/05/2014, 15:37

... differences of 50 to 100°C. Coefficients (W/m 2 ⋅K) T s (°C) ε h r h r,a h 35 0. 05 0.32 0.32 2.1 0.9 5. 7 5. 7 1 35 0. 05 0 .51 0 .50 4.7 0.9 9.2 9.0 100 300 50 0 700 900 Surroundings ... () 2 A DL 0.1m 25m 7.85m . == ì= Hence, () () 22 824444 q 7.85m 10 W/m K 150 25 K 0.8 5. 67 10 W/m K 423 298 K =+ìì ()() 22 q 7.85m 1, 250 1,0 95 w/m 9813 859 2 W 18,4 05 W=+=+= < ... air, P max = 200 W/m 2 ⋅ K(0.0 05 m) 2 ( 85 - 15) ° C = 0. 35 W. < In the dielectric liquid P max = 3000 W/m 2 ⋅ K(0.0 05 m) 2 ( 85- 15) ° C = 5. 25 W. < COMMENTS: Relative...

Ngày tải lên: 08/08/2014, 17:20

... PROBLEM 3 .50 (Cont.) 0.0 35 0.0 45 0. 055 0.0 65 0.0 75 Outer radius of insulation, r3(m) 0 400 800 1200 1600 2000 Heat loss, qprime(W/m) q1 0.0 35 0.0 45 0. 055 0.0 65 0.0 75 Outer radius of insulation, ... D h 52 3K T T 293K ln 75/ 60 0.6m 50 0 W/m K 0.075m 25 W/m K 2 56 .5 W/m K +0.8 0.075m 5. 67 10 W/m K επ σ πππ ππ π π ∞∞ −− − −− =+ + = ìì + ì ì ì ììì 44 4 4 s,o s,o s,o 84 4 s,o T 293 K 52 3 ... solution, T s,o ≈ 50 2K. Hence the heat loss is () ( ) 44 oo s,o ,o o s,o sur q = D h T T D T T πεπσ ∞ ′ −+ − () ( )() 28444 24 W q = 0.075m 25 W/m K 50 2-293 0.8 0.075m 5. 67 10 50 2 243 K mK ππ − ′ ⋅+...

Ngày tải lên: 08/08/2014, 17:20

... 0 15 30 45 60 0 50 80.33 85. 16 80.33 50 15 50 63 .58 67.73 63 .58 50 30 50 56 .27 58 .58 56 .27 50 45 50 52 .91 54 .07 52 .91 50 60 50 51 .32 51 .86 51 .32 50 75 50 50 .51 50 .72 50 .51 50 90 50 50 50 50 50 The ... ° C. y\x 0 25 50 75 100 1 25 150 1 75 200 2 25 250 2 75 300 0 180.7 180.2 178.4 1 75. 4 171.1 1 65. 3 158 .1 149.6 140.1 129.9 119.4 108.7 98.0 25 204.2 203.6 201.6 198.2 193.3 186.7 178.3 168.4 157 .4 1 45. 6 133.4 ... 62 .5 K, the system of finite-difference equations is () 1s24s T 0. 25 T T T T 15. 6 25 =++++ (1) () 2s 351 T 0. 25 T T T T 15. 6 25 =++++ (2) () 3s262 T 0. 25 T T T T 15. 6 25 =++++ (3) () 4 151 s T 0.25...

Ngày tải lên: 08/08/2014, 17:20

... 3 25 3 25 3 25 1 18 304.2 324.7 3 25 3 25 3 25 3 25 3 25 3 25 2 36 303.2 3 15. 3 324 .5 3 25 3 25 3 25 3 25 3 25 3 54 294.7 313.7 320.3 324 .5 3 25 3 25 3 25 3 25 4 72 293.0 307.8 318.9 322 .5 324 .5 3 25 3 25 3 25 ... p ⋅∆ t = 300 p (s) = 5 p (min). pt(min) T 0 T 1 T 2 T 3 T L ( ° C) 0 0 85 85 85 85 20 1 85 85 85 52 .5 20 2 10 85 85 68.8 52 .5 20 3 85 76.9 68.8 44.4 20 4 20 76.9 76.9 60.7 44.4 20 5 76.9 68.8 60.7 ... 3 25 3 25 5 90 287.6 3 05. 8 3 15. 2 321 .5 323 .5 324 .5 3 25 3 25 6 108 2 85. 6 301.6 313 .5 319.3 322.7 324.0 324 .5 3 25 7 126 281.8 299 .5 310 .5 317.9 321.4 323.3 324.2 8 144 279.8 296.2 308.6 3 15. 8 320.4...

Ngày tải lên: 08/08/2014, 17:20

Ngày tải lên: 08/08/2014, 17:20

Ngày tải lên: 08/08/2014, 17:20

Ngày tải lên: 08/08/2014, 17:20

Ngày tải lên: 08/08/2014, 17:20

Ngày tải lên: 08/08/2014, 17:20

Ngày tải lên: 08/08/2014, 17:20

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Ngày tải lên: 28/12/2013, 22:19

... distribution of air pollutants Change in microclimate As ecological indicator Decomposition of the ozone layer Health-pollution relationships 5 5 4 4 -5 5 5 3 3 3 5 5 5 5 3 4 4 ... Network Models 226 5. 3 Network Analysis 230 5. 4 ECOPATH Software 236 5. 5 Response Models 248 6. Modelling Population Dynamics 257 6.1 Introduction 257 6.2 Basic Concepts 257 6.3 Growth Models ... Application of Conceptual Diagrams 211 4.3 Types of Conceptual Diagrams 214 4.4. The Conceptual Diagram as Modelling Tool 221 Problems 223 5. Static Models 2 25 5. 1 Introduction 2 25 5. 2 Network...

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Ngày tải lên: 01/04/2014, 11:53

... student using this Manual, you are using it without permission. Page 25 - 2 PROPRIETARY MATERIAL. â The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual may be displayed, ... using this Manual, you are using it without permission. Page 6 - 4 PROPRIETARY MATERIAL. â The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual may ... using it without permission. Page 25 - 3 PROPRIETARY MATERIAL. â The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual may be displayed, reproduced or distributed...

Ngày tải lên: 01/04/2014, 11:53