Mot hanh trinh du lich cho dia diSm du lich i phai duoc xay d\II1g sao cho xu~t phat tir dia diem i di qua mot s6 dia diSm khac r6i phai quay I~ dia diSm xu~t ph at i voi t6ng chi phi du[r]
(1)BO GIAO Dl}C vA DAo T~O DE KY THI CHQN HQC SINH GIOI ouoc GIA THPT NA.M2013 TID CHiNH THirC Mon:TINHQC Thai gian: 180 phut (khong k€ thai gian giao dJ) Ngay thi thir hai: (DJ thi 12/0112013 co 03 trang, 03 bili) TONG QVAN NGAy THI THUHAI Ten hili File chuang trinh File dfr lieu VaG File Idtqua Bili 4' TrQn xau STMERGE.* STMERGE.lNP STMERGE.OUT Bai5 Hanh trinh du lich TOURS.* TOURS.lNP TOURS.OUT Bili6 San xu&t ORGAN.* ORGAN.lNP ORGAN.OUT db chol DAu * dU'Q'cthay th~ bOi PAS ho~c CP,P cua ngon ngfr I~p trinh dU'Q'csir dung tuong irng I:i Pascal ho~c C++ Hay l~p trinn giiii cdc hili todn sau: Bai (6 c1i~m) TrQn xau Cho hai Xl1Uky tv: x = X!, X2, , Xm va Y = Yl, Y2, , Yn' Cfrn Xl1Ydung Xl1uT = tJ, tz, , tm+n gam telt ca cac ky tu Xl1UX va telt ca cac kY tu Xl1UY, cho cac ky tv X xUelthien T thee dung thir tir xUelthien X va cac ky tv Y xuat hien T theo dung thir t\l' xuelt hien Y, dang thai voi t6ng chi phi tron lil nho nhc1t.T6ng chi phi tron hai Xl1UX va Y d8 thu m+n-I duoc Xl1UT duoc tinh b61 cong thirc: c(T) = Lc(t k , t hi); do, cac chi phi C(tk, h+l) duoc k=1 tinh nhu sau: • NSu hai ky tv.lien tiSp tk, tHI diroc lc1yill cling mot Xl1UXho~c Y thi C(tk, tk+J) = 0; • NSu hai ky t\1'lien tiep ts, tHI lil Xi, Yj thi chi phi phai tra h1CCXi, Yj) NSu hai ky tu lien tiSp tk, tk+! la Yj, Xi thi chi phi phai tra la c(Yj, Xi) = CCXi,Yj) Yeu cAu: Tim each Xl1Ydung Xl1UT vai t6ng chi phi nho nhat DiI' li~u: Vao ill file van ban STMERGE.INP: Dong dfru tien chua Q la s& hrong b9 dfr lieu, Ti~p dSn la Q nh6m dong, m6i nh6m cho thong tin v~ mot b9 dfr lieu thee khuon dang sau: • Dong thir nhelt chua hai s&nguyen dirong m, n n ::;1000); • Dong thir i s6 m dong ti6p thee chua n s6 nguyen duong, m6i s& khong vuot qua 109: CCXi,YI), CCXi, Y2), , CCXi, Yn), i = 1, 2, , m em, Kit qua: Ghi file van ban STMERGE.OUT gam Q dong, m6i dong chua mot s&nguyen la t6ng chi phi thee each Xl1Ydung Xl1UT tim duoc nrong irng voi b9 dtr lieu vao Vi du: STMERGE INP 3 30 15 STMERGE.OUT Rang bUQc: • C6 60% s6 test irng voi 60% s&di~m cua bai c6 m, n :5 10 Trang 113 (2) Bai (7 di6m) Hanh trinh du llch Cong ty du rich X co du an t6 chirc cac hanh trinh du lich vung lanh th6 gom n diSm du lich diem, duoc danh s6 ill d~n n H~ thong giao thong vung g6m m tuyen duong mot chieu khac nhau, tuyen duong thir j (j = 1, 2, , m) cho phep di tic dia diSm Uj d~n dia diSm Vj voi chi phi di lai la s6 nguyen duong c(Uj, Vj) vAn d~ d?t cho cong ty la xay dung cac hanh trinh du lich cho m6i diSm du lich Mot hanh trinh du lich cho dia diSm du lich i phai duoc xay d\II1g cho xu~t phat tir dia diem i di qua mot s6 dia diSm khac r6i phai quay I~ dia diSm xu~t ph at i voi t6ng chi phi (duoc tinh nhtr la t6ng chi phi cua cac tuyen dirong rna hanh trinh di qua) nho nhk Yeu ciu: V6i m6i dia diSm du liclr i (i = 1,2, , n), hay tinh chi phi cua hanh trinh du lich cho dia diSm i thoa man cac di~u kien da neu, Dtr li~u: Vao tir file van ban TOURS.INP: Dong dAu tien chua T la s6 hrong bO dfr lieu, Tiep den la T nhom dong, m6i nhom cho thong tin v~ mot bO du lieu theo khuon dang sau: • Dong thir nhat chua hai s6 nguyen dirong n va m; • Dong thir j s6 m dong ti~p thee chua ba s6 nguyen dirong Uj, Vj, c( uj, Vj) cho biet thong tin v~ tuyen duong thir ) Gia thiet la Uj i- Vj; ctu], Vj) < 106,j = 1,2, , m K~t qua: Ghi file van ban TOURS.OUT g6m T nhorn dong nrong img voi T bO du lieu vao, m6i nhorn gorn n dong, dong thir i ghi chi phi cua hanh trinh du lich cho dia diSm i Qui tree: Ghi s6 -1 tren dong i neu khong tim duoc hanh trinh du lich cho dia diSm i thea man yeu du d?t Vi du: TOURS OUT TOURS.INP 11 11 11 3 -1 Hinh minh ho'il 355 5·3 567 Rang bUQc: • Co 30% s6 test irng voi 30% s6 diem cua bai co n::; 20 • Co 30% s6 test irng voi 30% s6 di€m cua bai co 20 < n::: 100, m::: 104• • Co 40% s6 test irng voi 40% s6 diem cua bai co 100 < n :::103, m ~ 105 Bai (7 di6m) San xuit de, choi Hang san xuat d6 choi XYZ da mua cac 10 hang 6ng dan d€ hun nguyen lieu san xu~t dan 6ng M6i 10 g6m n (n > 2) 6ng dim v6i dO cao doi mot khac IAn luQ't la hi, h2, , hn d€ k.hi nh~c cong go vao cac 6ug dan v6i cao khac nhau, chung se phat cac am khae ang dan thu i co tn;mg Iuqng hi h;xm (1 ~ i ~ n) Quy trinh san xu~t dan eua hang thvc hi~n thee day chuy~u tv dong hoa hoim toan nhu sau: B~t dAu, robot A se tv doug rna mot 10va xep IAnluQ't n 6ng co cao hi, h2, , hn len day chuy~n Tiep theo, cac 6ng se duQ'c robot B phan s (1 < S :s n) 10 Lo thu nh~t g6m cac 6ng tir d~n kl' 10 thu hai g6m eac 6ng tir i(J+ den k2, ,10 thu s g6m"cae 6ng tic ks-I+ d~n n (1 :s kl < k2 < < ks-I < n) M6i mot 10 se dUQ'echuySn cho robot C dS l~p ghep th~nh mot chi~e dan Robot C se ti~n hanh s~p xep cae 6ng mot day Trang 2/3 (3) dam bao di€u kien co khong qua w vi tri rna 6ng dirng tnroc cao hon 6ng dung li€n ke sau no (n~u co) Co th€ co nhieu phuong an s~p x~p cac 6ng dan mQt 16 thoa man di~u ki~n M6i mQt phuong an nhir v~y se duoc goi hl rnQt loai dan Sau khao sat thi hieu ngiroi tieu dung, Ban giam d6c nh~ thay: hrong hop ly cua mot chiec dan (duoc tinh boi tAng hrong cua cac 6ng dan) la mQt s6 khong nho han bmin va khong 16'11han bmax; ngoai ra, khong co hai khach hang nao lai muon dung dan gi6ng D~ thdy, 86 luong loai dan khac co thS tao phu thuoc vao viec phan n 6ng s 10 Do do, Ban giam d6e muon Iva chon each phan n 6ng s 10 cho tAng lUQ11gcac 6ng mlii 10 deu nfun doan nr bmin dSn bmax va s6 hrong cac loai dan 6ng khac co th€ san xudt duoc la nhieu nhat Vi du: V6i n = 5; s = 2; w = 2; m = 1~bmin = 9; bmax = 12 va day cac 6ng voi dQ cao la 4,6,2,3, co each phan 6ng 10 c?n: Cach phfm to thu- IIhat: Lo g6m cac bng voi cac hrong nrong (rug la 4, 6, Lo g6rn cac 6ng voi cac hrong nrong irng Ia 3, Lo thir nhdt co th€ san xudt cac loai dan: • S6 hrong loai dan khong co vi tri nao rna 6ng dung truce cao hon bng li8n k~ sau no la (2~ 4-6); • S6 hrong Ioai dan co dung vi trf rna bng dung truoc cao hon 6ng li€n k~ sau no la (2-6-4, 4-2-6,4-6-2, 6-2-4); • S61uQ'llg loai dan co dung vi tri rna 6ng dirng tnroc cao h0116ng lien k~ sau no la (6-4-2); Do do, tir cac 6ng 10 thir nh~t co th8 san xudt loai dan Tir cac 6ng 10 thir hai c6 th~ san xuftt them loai dan moi (3-7, 7-3) V~y, thea each phan 10thir nhAt co th€ san xudt loai dan Cach phallio thu- hal: Lo g6rn cac 6ng voi cac hrong tirong (rug la 4,6 Lo gam cac 6ng voi cac hrong nrong (rug hi 2, 3, Tinh tuong tv nhu tren, each phan 10 cho phep san xuftt lo~i dan V~y, dap s6 dn tim la Yeu cAu: Hay tim cach phan n 6ng s 16 thoa man cae di~u ki~n d~t va cho s6 lUQ'llgcac lo~i dan 6ng khac co th6 san xudt dUQ'cla nhi~u nhftt Dfi' li~u: Vao til file van ban ORGAN.INP: Dong d~u tien chua T la s61uQ'llg bQ dil' li~u Ti~p d~n la T nhom dong, rn6i nhom cho thong tin mQt be)dil' li~u theo khuon d~g sau: • Dong thu nhdt chua sau s6 nguyen duong n, s, W, m, bmin, bmax; • Dong thu hai gam n s6 nguyen,duong h], h2, '" hn mo ta de)cao cua n 6ng Gia thi~t la: hi < 106, i = 1, 2, , n; bmin, bmax< 109; m < 100 Dil' li~u dam bao bai toan Iuon co 101 giro ve K~t qua: Ghi file van ban ORGAN.OUT g6m T dong, m6i dong chua mQt s6 nguyen lit s6 1u9'llgcac lo~i dan khac tim dUQ'ctuang Ung vai bQ dfr li~u vao Vi d\1: ORGAN.INP ORGAN OUT 2 12 Rang bU9C: • Co 30% s6 test Ung v&i 30% s6 di6m cua bai co n ~ 10 • Co 30% s6 test (eng voi 30% s6 di6rn cua bai co 10 < n ~ 30 • Co 40% s6 test (eng v6i 40% s6 di~m cua bili co 30 < n :=:; 200 • • Thi sinh khong dul)'c sit d1:lngted li?u Ccm b(j coi thi khong giai thich gi them _{ Het Trang 3/3 (4)