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Cau 7: MQt rnanh thep hinh vuonq earth 5 dm bi cat mot mieng hinh tam qiac d~u nhu hinh ve.. Dien tich phan con lai:.[r]
(1)PHONG GrAo DUC - DAo T~O BlNH TAl'JHUONG DAN cHAM GrAr ToAN TREN MAy TlNH cAM TAY Nam hoc: 2012-1013 .Dt PHONG GIAo Dl,JC - DAo TAO HUY€N SiNH TAN I I DE CHiNH'THUC THI GIAI ToAN TREN MAy TiNH CAM TAY Narn hoc: 2012 - 2013 Thai gian lam bai: 120 phut Thi sinh lam bal tren d~ thi Cnu 'I: Cec ket qua lam iron den cnir s6 th(Jp phan ttur l.oai may tinh thl sinh SLr dunq: Casio fx-570ES : Cau 1: Tfnh a) A = tg3S015'-1 = I - 0,549249 Cos67°20' l (O,5d) b) S = - Cotg62°1O' = - Sin42°35' j l (O,5d) 1,868015 Cau 2: Cho bi~u thirc f(x,Y) = X2 + 2y2- xy - Tlnh gia tri bi~u thuc a) f(x = 0,123; Y = !) = I 0,047879 ~(O,5d) b) f(x = -1,52; Y = ~) = Cau 3: Cho biet n 113 s6 tu nhien Tinh tong T = + + I + _1 2n n =1_: =0 - X cso 5: Tim Ket qua r = x biet - 0,25 x3J5 1,999023 I = Vi +! => x' (1,Od) 15,25 (1,Od) _l = Vi Loi giai 5:3j{ + va g(x) = 2x - Tim s6 du r phep chia f(x) cho g(x) _ r-r- Ket qua T = I Cau 4: Cho hai da thuc f(x) = 2x3 + 4x2 I (O,5d) 15,745956 = Ket qua Js(~2:~)=> Js(~2:~) x =3 (O,5d) (O,5d) x =1 1,031845 Cau ,6: Tim gia tri cac chlJ' s6 a,b,c,d,e,f sac cho abc x def4 = 820216, biet rang a 100nhon b don vi (a,b 113 s6 tl,l' nhien nho hon hoac bang 9; dau chi thu tl,l' cac chlJ' so) Loi giai Ket qua Theo d~ bai thl c = hoac c = (O,5d) *) c = thl abc chi co th~ 113: 954; 844; 734; 624; 514; 404 a= d = b= c= e = f = (O,5d) **) c = thl abc chi co th~ 113:959; 849; 739; 629; 519; 409 Lay 820216 I~n luot chia cho cac s6 tren duoc ket qua Cau 7: MQt rnanh thep hinh vuonq earth dm bi cat mot mieng hinh tam qiac d~u nhu hinh ve Tlnh dien tlch phan lai cua rnanh thep, Lai giai ·0·ten tlIC h t am qrac , d>-a2 eu can hi'a a S = -A J3 Dien tich hinh vuong canh a 113 S2 = a Dien tich phan lai: (O,25d) S = S2 - S1 = a2 - a ; S = 14,174682 Ap dunq voi a = dm ta duoc (O,5d) (O,25d) Ketqua S= I 14,174682 I (2) Cau 8: Hlnh thang vuonq ABCD c6 ABIICD, canh g6c vuonq AD = cm, dU'ang cheo AC = 10cm, g6c 13 = 540 Tlnh dien tlch hlnh thang D Loi giai AH = DC = Jl02 _72 HC HB = - tgB SABCD = -(2 => * = '1 J5i; HC = AD =7 (O,25d) E u t' = - (DC + AB)AD = - (DC + AH + HB)AD SABCD 2 HC tgB DC + -)AD c: + = -(2x-v51 )7 tg54° Cau 9: Tim cac so nquyen duonq x, y sac cho: 3x2 + Loi giai Ta c6: = 1999 - 3x2 > => 0< X < 25,81 (0,5d) l => Y = J1999 - 3x Ta c6 k~t qua: x = (O,5d) = (0,5d) x= 21 Y= 26 Tinh U20bi~t Uo = 1023 K~t qua U1 = Uo + 0,1%Uo U2 = U1 + 0,1%U1 = Uo + 0,1%Uo + 0,1%(Uo + 0,1%Uo) = Uo + 0,1%Uo + (0,1%)2 Uo= Uo(1 + 0,1%f U3 = U2 + 0,1%U2 = Uo(1 + 0,1%)2 + 0,1%Uo(1 + 0,1%)2 = Uo(1 + 0,1%f(1 + 0,1%) = Uo(1 + 0,1%f Un = Uo(1 + 0, 1%)n Ap dunq voi Uo = 1023; n = 20 ta duoc (£)ung hoan toan cho 1,Od) Thi sinh lam each khac dung cho diE§mtU'O'ngdU'O'ng - H~t - (0,25d) S = ' 6-7,-79-0-2-9-1 , K~tqua Cho x nhan cac qia tri 1; 2; 3; ; 25 21; Y 26 Cau 10: Cho day so Un = Un-1 + 0,1 %Un-1 n = 0, 1, 2, Lai giai K~tqua = 1999 ° l H A U20 = I 1043,655541 (3)