ĐỀ KIỂM TRA 1 TIẾT HKII NĂM HỌC 2012 – 2013 LẦN 1 (12 NC)

[r]

KrEM

TRA

I

TrET MOw:

vAr

Li

Lop.r2

-

nrANc

cA^o"

NAtvt

Hec

z0t2

-zals.

EE2

L Con 16c

ld xo

gOm rnQt v$t

m

vi

ld xo

c6 d0 cimg

k

dao dQng clidu hda,

kl:i

rnic

thOrn

vlo

vflt m mQt vQt

khdc co

khdi luqng

giip lan

vflt

m

thi

chu

k!

dao dQng c'ia

ch[rr6

)::

:

r

A

tang 10n

l6n

B

giam dr

tAn

C tiirig 16n

I&n

' :,,

D

gi"im Ai

;

tan

2

Troig

giao thca

s6ng

co

irqg iO1 hai ngu0n cl0ng pha

tlii

,

t4i

C tO-"g sO.ady cgc d4i hay t6ng s6 ddy c;;c tiOu lu6n ludn

lI

m$t sd 16,

D

t6ng sO d6y cuc dai ld mQt s6 16 vd t6ng s6 ddy cgc ti0u lh mQt,

ehhn

3" S6ng

t6t

trqp

li

hai s6ng c6

+

"*!

.a"

16,

"t "g

bi0n

EO

.rBsctng

tdn s6

vi

r10 lQch pha khdng d6i theo

thoi

gian

e

cryne bi6n d0,

ctng

pha

D

cing

ten sQ

vi

d0 lQoh pha thay d6i theo

thli

gian DO

"6

*Orrg

amg

iay

ra tr0n mQt sgi d6y dan frOi v<vi hai dAu ddy dAu ld

nrit

s6ng

thi

A

chiAu dhi d0y bAng mQt phan tu bu6c s6ng

?

b."."," s.o.1s.lrio.1ru"on {,n"g bang chiAu

deitay.

C chi6u ddi d0y bAng mQ! sO nguyOl l6n nira budc s6ng

D bu6c s6ng bdng mQt s6 le len chiOu

dli

d6y

5

Khi

c6 s6ng drmg tr0n d6y

AB

thi

A

s0 nrit

bing

sO Uung n6u

B

cO Ainn

C sO nut

bing

sO bUng n6u B

tp

do

6 Chon cdu sai ?

A

DAi lugng dflc

tnmg

cho dQ cao ctra 6m th tdn s0

B

Ecrn

v!

cua cudrng d0

6m]e

W/rrf

C

Mirc

culng

dO

a;

tinh

bing

Ben (B) hay dAxiben (dB)

D

Cudrng dO dm ld dai lugng dflc tnmg ho.dQ to c{ra 6m

7

TairrguOi chi nghe

dugc

cuc 6m co tAn sO

nim

trong

khoing

,,F

B

sO bpng hcrn sO

D

sO bpng hcrn s0

nirt mQt don

vi

n6u B

tg

do

nrit

m$t

don

vi

n6u

B

cO dinh

A

1i2 8.1,/4

9 Trong thf nghiQm giao thoa s6ng tr€n mflt nu6c, hai ngu6n t<Ct trgp Sr , Sz dao dQng chu

k]

0,2 s,

tgi

mQt

ai0m

Pf

c6ch Sr, 52 nhirng

khoing

dr=lLcm,

dz=13cm

s6ng c6 bi6n dQ

cpc d4i Gifia

M

vi

duong trung

tr.uc ctra SrSz kh6ng

c6

ddy cgc d4r kh6c V$n t6c truy€n s6ng trOn

m{t nu6c

1}r bao nhi0u ?

A v-20cm/s

B

v-5cmls

C

v-lUcmls

I) v-lAAcmls

L0 MQt dng s6o

dai

80 cm,

hd

hai cldu,

tao

mQt s6ng

drlng

trong

dng

s6o

vdi,6m

li

cr.rc

d?i d hai

ddu

dng,

khoing

gifra dng s6o c6 hai

nft

s6ng Brrdc s6ng cria 6m

li

A.'7u=2Ocm

B

l,=40cm

C

l,=80cm

D.i,=160cm.

11 S6ng dimg tr6n ddy

AB

c6 chidu dhi 32cm

voi

dAu,B cO ainfr

fan

sO dao d$ng cira ddy

li

50H2,

v{n

ti5c

truydn s6ng trOn ddy

ld

4mls TrCn ddy c6

A.5nft;4bpng

B.4nrit;4bung,

C.8

nrit;8bung

D.9htit;8bung

12 }d}ts6ng

co hgc truyOn dgc theo trVc Ox c6 phucmg

trinh

a = 28cos(20x - 20001)

(im),

trong d6

x

ld to4

dQdu<l.ctint'_uangm6t(m),tldthdigiandugctinnuanggi6y(s).vantocctras6ng1d

A

334 m/s

B

100m/s

C.3l4m/s.

D 331m/s 13

Vdi

mQt s6ng am,

khi

mirc'cudrng d0 em tdng th0m 20dB

thi

cucrng d0 6m t6ng

e,

t00

16,

n

1OOO

len

C

201an

O ZOO ta.,

M

A bA mat mQt ch6t 16ng c6 hai ngu6n ph6t s6ng t<6t trq,p Sr

vi

Sz cSch 20cm Hai ngu6n dao dQng

theo phucrng thdng dimg c6 phucrng trinfr mn

luqt

th

ur

= 5cos4Orct (mm) vh

uz=

5cos(4Ozct + zu)(mm)

T6c

dQ tryyAn s6ng trOn

m{ichAi

long

li

80cm/s Sd di€m dao dQng

voi

biOn d0 cqc dei tr6n do4n thang SrSz lh

A

11

8.9

c

10

D.8

1-5 Hai l6c dcrn c6 chu

ki

lAn

luqt

la

Tt =

1,5s

vh

Tz:2s

dao dQngnh6

trong

hai

m{t

pha"g

song'song

Hai l6c

cing

qua

vi tri

cdn bang theo cDng chiOu hic

t:

0 X6c dinh

thti

AiCm gan nh6t ma hiQn tugng

tr6n t6i di0n?

A

6s

A tir

l6Hz-2000H2

C

tir

16

KHz-20000

KHz

S MQt dffy dhn c6 chi6u dai 1, hai"dAu

B 2,5s

i6

M$t

v$t dao dQng

ditu

hda v,5i

A

thCI ndng

b[ng

L/3 dQng n6ng

C th0

n[ng

bing

Ll}

dQng ndng

B.,ttr

16Hz

- 2000AHz

D

tir 20

KHz'-

2000

KHz

cO dinh S6ng dnng trdn d6y c6 brr**; s6ng dAi n1l6t ia

C

1

Ll

.21.

C

L,32s

D

3,5s bi0ri ,J0

A Kf i

li

,i0

n -=

Ai}

tiii

B

the ndng

bing

3 dQng

ning.

'i

!i'

t

17 MOt chAt diOm dao dQng di0u hOa thr;c hiQn VA dao dQng 60s

Chsn,g{c

thdi

gian

l}

iiib6n6t

Oi6m oang

o

vl rn

Dren am

Thdi

gian ng6n ntrAt ctr6t di6m qua

q

tn

co 11

de

-rc =

-*

kC

tir

iric

Uit

eAu dao dQng

le

A

1,25s

B

1s

C

1,75s

,*

D

1,5s

18 MOt 18c

lb xo

dao dQng diOu hda theo phu<mg thdng dimg

voi

t6c dQ

ffic

20 rad/s Chi0u ddi

lb

xo

o

vi

tri

cdn Uand

la

10cm

Tai

vi

tri x

:

2cm

qui

n{ng

c6 vdn

t6c

4QJicmls

ChiAu dei 16n nh6t ctra

ld

xo

-:

\r

q

A

8cm

B.lZcm

C

14cm

19 MOt

vflt

dao ilQng diOu hdd c6 dO

ltu

vfn

t6c

cgc dpi

ld

31,4cmls

vflt mQt chu

ki

dao dQng

li

A

20cm,/s B " 10cm/s.

20;="MQt t6c dryn g$m que cAu cd

kh0i

truyAn cho qu6 nflng

vfln

tOc

}m/s

LSy g

:

b6ng lh

A.2m.

lLz

L4

A

B rg' cxn

vh

l-

rud

6

?3

F{ai dao CQng di0u hda

liv tri co

tii$n

Sq

th 10jA

ctrri

D.6cm

'r'

Lily

tf,

-::3,!4

TOc d0

trung binh

cria

C

0n

D

15cm/s

lugrig

rn treo vho mQt

sgi

d6y

co

chiAu

dei

1

Tt

vi tri

cdn

bing,

10rn/s' DO cao 16n ntr6t mh qua nfing dat

dugc

so

vdi

vi

trf

c6n

C

}}Jlcm.

D.20cm

,ng,

lac

dcrn

thir

hai

thpc

21

Trong

ctng

mQt thcri gian,

l6c

don

thrl

nh6t

thgc

hiQn duo c

hiQn duo c

2$dao

dQng

Ti

s6 chiAu dhi cira chring lh

,r,1

tr-

r, L

t

A.2-1

Z

t'.:=-

C.Z=Z

8.0,8m.

lL

I

D

2=4

I

u1

2

D a)z= '

Az

-xZ

22.Dao

ilQng tdng hgrp ctra hai dao dQng diAu hba

cing

phucmg, cirng tdn s6 c6 phu<mg

trinh

x

=

3cos(

"t +)

(cm)

gitit

dao dQng

thri

nhAt co phucmg

trinh

x1

=

Scos(rct

*

Z)(cm)

Dao dQng

thrl

hai'c6 bi6n d0 vd pha ban dAu

lh

B

2

cm

vit

Lrad

C.2

cm

ui

-

5o

,u4

D

8 cm

ui

-

5o

,u4

66:6

ctng

phucntg,

clng

tdn s5,

cing

bi0n dQ, c6 ilQ l0ch

pha

lit n/3" Dao dSftg t6ng Bi€n C0 ctra m6i dao dQng thln-h phdn

ld '

,

,

A

10^6

cm

B

10cm

c rolficm.

D

10.E"*.

\z

24

Phucrng

trinh

vfln t6c cria m6J

vft

dao dQng tti6u hba: v = A a)cos rttt

.l<et

lu6n

nio

sau d6y ld rlrring?

a

COc th<ri gian

li

tric chdt di6m di qua

vi

tri

cdn

bing

theo chiAu ducnrg

e

C6c

thoi

fian

lh

hic

ch6t di6m cO tqa AO

* : -a

a C

Ciic thrii

gian th

hic

ctr6t diem c6 tga dQ

x

:

A.

p.C5cttOigi*lhhiccfr6tAiemc6tgadQy:Aho{cx:

-A

!

Zl.Tqicung-mQt vi

trf

rtia

If,

ntiuchi6u

dli

con ldc dcrn tdng

4o,hi

chu

kj,

dao dQng di6u hod cira n6

A

t[ng

Z

tan

B

gienia

lan

C giim2lAn

r

-''

.:

r

-')

tdng

l6n

/

zS.x{tmQt

vft

dao t1Qng Aieu

noi

vrvi biOn dO

A,

tan

sdg6c

at.Taivi

fficE

Ii

d0

x

vft

J6 vOn t6c

v

HQ

thric

nio

sau ddy

li

khdng

dung ?

A

Yz

= a)'{A'

x2)

27.Bi€ntlQ

cria dao dQng tOng'hqrp bang O

#u

dQ lQch pha cira hai dao dOng phAn

c6

gi6*i

A

Arp

-

(2n+1)rc

B

Arp

=

(2n

+1)nl2

C Acp

-2nN

D.Atp=

0 28

Khi

tan,s6 dao d,Qne oua ngopi lpc

bing

tAn sO daq dQngri6ng cira hQ dao d$ne

thi

C Ndng luqrrrg dao dQng kh6ng

d6i

D

Bidn tIQ dao dQng dat cgc d4i

29 MOt l6c dcvn g6m sqi d6y c6 chiAu

dli

0,1m vh qud

n{ng

c6

ttrOi

tuqn&$q,mang

diQn tichJ p* 7C

dao dQng diQn trucme$Au vecto cuirng ttQ tliQn truOmg

E

c6 phucmg thang dimg hucmg

xdlg,

E

=

f0*V/m.Ldy

g:

10m./s'

Tinh

chu

ki

dao dQng cria

I[c?

'$ 0,625s

B

ls

C.1,625s

D.O,375s

30

MOt i6c dcrn dao dQng di6u hba

vdi

chu

ki

T

t4i

noi

c6 gia t6c trgng trudmg.g: ChiAu,dai

dty

treo

i6c

ls.'i

1

t

2 tZ

B

Az

-

x,

+b

C

0)2:u

i_j*_

A

r-*

T2

n-2

\

'""

L8

,

t,

::