Đang tải... (xem toàn văn)
hien tugng quang diQn ngoeiC. hiQn tuqng quang diQn tropg D..[r]
(1)Bt ruEI\{ TRA 1 rrfr nnoN vaT Lr LOp 12 I\ANG CAO - CHTION G + 7
NAna Hgc 2otz - zot3
Thiri gian lim bi,i: 45 phrit Sd lugng: 30 cflu I "'
CAu 1: Kim lo4i c6 cdng thodt electron ld A =2,62 eV Khi chi6u vio kim lopi ndy d6ng thoi hai-b&c xa
c6 bu6c s6ng 1,1 = 0,4pm vd\,2- Q,2trtmthi hiQn tugng quang diQn :
A xiy ra v6i chhai birc xp
C khOng xity ruyli cdhai birc xp
C4g 2: Gi6i hAn quang dien cira Na ih 0,5 quang diqn ctra k6m th
A.0,36 pm- 8.0,63 trrm C.0,261:m D.0,62 pm
9ffu 3: ei6t c6ng su6t cria ngudn sang c6 bu6c s6ng L = 0,3pm le 2,5W HiQu suSt luqmg ttrlir LVo
Cudmg dO &dng quang diQn li6o hda 1)
A.6mA B 0,6mA C.0,6A D 6UA
CAu 4: Bi€t bu6c s6ng cria v4ch Ho vd HB quang ph6 ctra hidr6 leng luqt lh l,o = 0,6563pm vi l,B = 0,4861pm Hdy tim bu6c s6ng ctra v4ch ttli,ntr6t trong ddy pasen
A L,8744pm B L,7413pm C L,6939pm D 1,8913pm
Cfiu 5: COng thodt electr6n ctra mQt kim loai lh Ao, gi6i h4n quang diQn lh 0 Khi chitiu vho bC m{t
kim lopi d6 chr)m birc xa c6 thi dOng neng ban d6u cuc dai cria electron qu ang diqn b6ng :
A,2AA B'Ao c" 3Ao
C0u 6: Khi 0lectr6n nguyOn ttt hidr6 bhuyOn tu qui d4o dtng c6 n5ng luqmg E, - - 0,85eV sang qui d4o dimg c6 ndng lugng E* - - 13,60eV thi nguyOn ttphhtbric x4 diQn tu c6 budc s6ng
4.0,0974 pm B 0,4340 pm C.0,4860 pm.D.0,6563 pm
Cau Z: Cfrieu m6t chr)m bric x4 dorn s6c c6 bu6c s6ng 0,2pm vho mQt qu6 cAu bang d6ng , dat cO l{p vC
di$n Gi6i hqn quang diQn cfia ddng lb 0,3pm Ei0n th0 circ d4i mi qu6 cAu.d4t duo c so v6i d6t li
A 1,134V 8.2,47 V c 3,12Y D.4,26 V
CAy 8: Khi chi6u brtc x4 c6 bu6c s6ng L vdo bA m{t mgt kim loai thi hiQu diQn th6 hem le 4,8V N6u chi6u vdo kim loai d6 bu6c s6ng il" th\hiQu diQn ttr6 tram la 1,6V Gi6i han quang diQn cria kim 1o4i d6 th:
A 6L.
Cf,u 9: Ph6t bi6u nio sau dAy ld khilng-drtng theo thuy6t luq,ng tir anh s6ng?
A chrim 6nh s6ng li mQt chim h4t, m5i hpt {u-oc gqi li mQt photon mang ndng lugng B Cudrng dQ chtm
Th r*g ti lQ thufln voi s5 ph6t6n hong chim
C Khi 6nh sdng truyAn di cdcph6tdn kh6ng d6i, kh6ng phli thu6cvlo khoang c6ch dt5n ngu6n sang D c6cphotdn c6 n6ng luqng bdng vi chring lan truyAn vcri t5c dQ bang
Ciu 10: OOi vcri nguy6n tft hi&6 , bi6u thrlc ndo du6i day chi ban kinh r iira qu! dao drmg thir n ctra
A r = Ilro B r = flTto C rz = nLt, D f -w:
CAu 11: Sg ph6t s6ng cira ngu6n s6ng nio du6i ddy ggi lh sg ph6t quang ?
A Ngqn nisn B Ednpin C Con dom d6m b Ng6i sao bEng
Cd 12: MOt ch6t ph6t quang c6 ., k&6 ndng ph6t rainhsdng mlu lUc khi duqc kich tt i.t pnat sang Hoi khi chi0u anh sring dcm sic ndo ducri rl6y thi cnat dO s6 ph6t quang ?
A D6 sAm B E6 tuoi C Vlng D Tim
CAu 13: LazentbikhOng ho4t dQng theo nguyOn tic ndo ducri ddy ?
A DUa v}o sU ph rt x? ctlmimg B T?o sg d6o 10n met d0
C Dga vho sp t6i hqrp gita electrdn vh 15 trdng D st dpng budng cQng hucmg
Cflu 14: N6u quan niQm anh sring chi c6 tinh ch6t s6ng th\khiig tfr6 giai thich duqc hiQn tugng nlo
iT?li?J?*q6rrhs6ng B Giao rhoa 6nh s6ng Cf,u L5: Pin quang diQn hopt dQni dUa vho A hien tugng quang diQn ngoei
C hien tugngtansic 6nhs6ng
C QuarLgdi$n D Phhnx46nhs6ng. buoc s6ng ,3h- +
B xAy vdi bric x? Ir , khOng xay vdi birc x?Lz
D xhy vdi birc xeXz ,*hon g xay vdi bilc x? Ir
pm C0ng thodt ctra k6m lon hcrn ctra Na le 1 ,4 hn Gi6i han
c.4h. D u"
B hiQn tuqng quang diQn tropg D sU phatquang oiua cdc chet
D.]a,
J
(2)C6u 16: Trong thf nghiQm khe IAng, ta c6 a: 0,5mm, D :2m thi nghiQm v6i 6nh sring c6 bu6c s6ng l,
= 0,5ltm Khoang c6ch gitia hai v6n sring nim 6 hai dAu ld 32mm S5 vdn sdng q-uan s5t dugc ttOn mdn Ih
A 15 B 16 C.17 D 18
Cf,u 17: Trong thf nghiQm giao thoa tffi sang kh Young, cho khodng cdch2 khe li.1mm; mdn E cdch}
khe 2m Ngu5n sring S ph6t d6ng thdi'2 birc xp f,r = 0,460pm vd 1.2 Van s6ng bfc 4 dua / trnng v6i
vOn s6ng bQc ctra ?\2 Tfnh budc s6ng Lr:
*$
A.0,512pm B.0,586pm C.0,613pm D.0,520pm.
Cf,u 18: Trong thf nghiQm Young vd giao thoa 5nh s6ng, nguli ta duoc khoang v6n lI Xdt hai di6m M vi N ctng & mQt phia vcri vdn sang chinh gita O, OM : 5,6 mm vh ON Gita M vh N c6 sO v6n s6ng li
A g " B '7
trong thinghi$m. A.0,50pm.
A x, = (2k +1), B xt - (k++) lD
/,a
;
1,1 2.L0'pt*
= 12,88mm
D xt-ki"
D ChLkhi b ap suat cao c.6.
C6u 19: Thlrc hiQn giao thoa 6nh sing2 khe Young c6ch a: l,2mm c6 khoang v6n li lmm Di D.5.
C.0,54pm.
C tr,Smm D.Zmlrt" '
, A,
trong su6t c6 gie ffi nr , {tz, t\ tucrng lmg vdi cdc miu: tim, d6,
8.0,60pm. D 0,66 Lt rn
Ceu Z0: Trong thi nghiQm Young v0 giao thoa rffi silng, ngudn s6ng S ph6t d6ng thoi 2btrc x4 c6 bu6c
s6ng ld Xt= 0,42ltm vi 1,, = 0,7 pm Khoang c6ch hai khe 51 vi Sz th a = 0,8mm, mh"n 6nh c6ch khe ld D =2,4m Tinh khoang c6ch tir vdn t6i tltl 3 cira bric x4 1,, vlL vfin t6i thf 5 cira br?c *q ?"r
A.9,45mm. 8.6,30mm. C 8,15mfi1 D.6,45mm.
Cdru 2l: ThUc hiOn thi nghiQm giao thoa 5nh s6ng kh Young, S1S2 = a = 0,5mm Khoang c6ch tir m{t
-phdng hai khe ddn man li D:2rtt Bu6c s6ng anh sang 1} ), = 0,5pm.'Ei0m M trOn min c6ch vhn s6ng trung tlm 9mm li
A v6n s6ng bflc 3 B v6n sdng bQc 4 C vOn tAi tnri + D v6n t6i tfrt S
Cd:u4z C[i6" hai khe thi nghiQm I6ng vO giao thoa 5nh sring, bang dnh.sring dcrn sic c6 budc s6ng 0,6prn, ngudi ta dugc khoang c6ch ngiin nh6t gifa vdn s6ng bflc vi vOn tdi thri 6 g6n nh6t bEng
3grm gi6t khoang cdchtt hai tr;he di5n mdn quan s6t bdng 2 m KhoAng cdch gifia hai khe bdng bao
nhiOu?
A.0,5mm. B 1,0mm
CSu 23; Chi0t sudt cimm$t m6i trucrng lUc thi sC dugc s6p x6p theo thri tg:
A nl ) ng )fLz B rtz ) Ilt )fI3 C nt > rLz )fI3 D n3 ) ot )TLz
Cfru24: Trong thf nghiQm Young vA giao thoa anh sr{ng thi v[ tri vdn t6i dugc x6c dinh bdng c6ng thric: C xt -,klq
a C6rru25t Khi 6nhsr{ng truy6n tu nu6c kh6ng khi thi
A budc s5ng vi tdn s6 5nh sang kh6ng d6i B vfln t6c vd mn s6 anh srlng t6ng C v$nt6c vd bu6c s6ng anh s6ng tdng D vfln tdc vi budc s6n g anhs6ng gi6m
Ci 26z Tia ndLo sau d6y kh6 quan s6t hiQn tugng giao thoa *atZ
A Tia hdng ngo4i B Tia tr? ngofl C Tia X D Anh s6ng nhin th6y Cia27z Quang ptrO fen lpc ph6t bOi hai vflt kh6c thi
A [oe" toin kh6c rqi ohiet Aq B hohn tohn gi6ng mqi nhigt d0 C gi6ng nh zD, n6u m6i vat c6 mQt nhigt dO phri hqp D gi6ng nh zu, n6u chirng c6 ctng nhiQt dO
C6u 28: Ngudn niro sau d6y cho quang ph6 v?ch phat xa
- ". if-vfl-Y\
A Chat khi b 6p suet thdp B Than h6ng C, MAt trli. Ciu29 Tim c6u sai Cho cdc chim s6ng sau: tlng,d6, ving, tim
fffis6ng tim bi lQch vO pbta ddy U"[ mnn ,fri5" nndt t-ctri6t su6t cria lSng tinn A5i vcvi n6 ta tOn ntrdt g Anh s6ng trdng bi tan sic khi di qua l[ng kinh
C tvt6i chirm rffi sring tr6n ddu c6 mQt bu6c s6ng x6c dlnh
O Cfrii5u ffi sang mng vao m6y quang ph6 sE thu duqc quang ph0 fen 4rc
CAu 30: C6c bu6c xp diQn tir:Hdng ngo4i, Tri ngo4i, Varg c6 bu6c s6ng tucmg rlmg th Lr,)r,)"th\:
A \> Lr> Lr B L> Lr> Lr C Lrr 4> lr D Lr> 1,> X, ,