Khi thanh kim lopi chuyi5n dQng trong tu truong thi hong thanh xudt hi6n su6t diQn dQng cim.. ' img.[r]
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2nfr
onKrffi,1 IH*A:I }-HKII
MON[: VAT LY 11 TN {
{:} Mfl OO:301
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B C D
16 t7 18 t9 20 2\ 22 23 24 25 26 27 28 29 30
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B C D
DiAu nio sau tl6y khilngitung ldri#6i ve hign tugng.cim tmg tliQn tu ?
A Trong hiQn tuqng cem rrirng Aiei t", tu trudmg biiSn thi€n c6 th6 sinh ddng diQn
B Thi rgnie* rA nieo tuqng cim ung iliQn tu c6 th6 dugc tpo bing nam ch6m diQn ho{c nam chdm vinh cftu
C Ddng ctiQn cim img m4ch chi tdn tAi khi c6 tri th6ng bi6n thi6n qua m4ch
p nOng diQn cim rmg cO tt O *u6t hiQn mpch kin nim y6n tu truong d6u
tvtft mQt nguli dpt kh6ng khi nhin xuiSng d6y mQt ch$u c6 chria mQt chdt ldng sudt c6 chitii r,r6t n Chi6u cao lcrp cfr6t tOng ld 25 cm MEt thily diry ch$u dudrng nhu crich mpt thoang mQt khoang li h thi
A.h<20cm B.h<25cm C.h=25cm.
D k1r6ng tfr6 t6t lufn dugc vi chua ti6t ctrii5t su6t n cria ch6t ldng li bao nhi6u
ChiiSu mQt chtrm s6ng song song khdng khi t6i m{t nudc (n= 413) vdi g6c tdi la 45o G6c
hqp boi tia khfc x4 vi tia tdi li
A 7}r5o B 450 c.25,5o D 12,9o
4 Til th6ng qua mQt khung dey bidn ddi, khoing thdi gian 0,3 (s) til thdng giim til 1,2 (Wb)
xudng cbn 0,6 (Wb) Sudt Agn dQng cim rlng xudt hi0n khung c6 dQ ton bang:
A.6 (V) 8.2 (V) c 1(v). D.0 (v).
MOt tia sring di tL kliOng khi vio mQt ch6t l6ng su6t v6i g6c tdi h 60'thi g6c.khric x4 ld
306 Cho n6n tOr ffi s6ng kh6ng khi H i.tO* q/s Vfln ttic 6nh s6ng ch6t l6ng li
A 1,73.108 m/s 8.2,!2.108 mls C 1,73.10t km/s D.2,12.100 km/s
Hign tuqng phan x4 todn phin duqc tmg dpng dp
e.'Ctr6 iaJfiiof, cni6u hfu cria xe e Ch6 tpo guong phdng, gucrng cAu C ChiS tpo sgi quang hgc D 3 cdu tr6n d6u dring
2
3
5
6
(2)7 Bidu thrlc tinh sudt diQn dQng trr cim li: j
A.e=-gA ats B.e=L.I C.e=e1 Lo-z.nz.\ D =-L*
8 MOt ban mdt song song c6 bd dhy 15 (cm), chi6t sudt n = 1,5 duo.c dgt khOng khi Chidu tdi
b6n mQt tia s6ng SI c6 g6c tdi 300 Khoang c6ch gita gi6 ciatia t6i vi tia 16 li:
A d;6,16 (cm) B d = 4,15 (cm) C d = 3,25 (em) D d = 2,91 (cm).
g MQt tia sang di tu m6i truong chi6t quang hcrn sang m6i trudrng k6m chiSt quang gi€t g6c gioi
h4n phan x4toan pfran U irn, d0 lQch lon nh6t cria tia tdi vi tia khric x4 ld
A.i*n B 90o- isr, " C 90o+ ish D 180o + irn
10 MQt khung day ph&ng, diQn tich}S (cm') gdm l0 vbng d6y, khung dfly dugc dit trong tt trudrng c6 cAm ung til vu6ng g6c v6i mAt phfrng khung vd c6 dO l6n t[ng ddn tt 0 ddn 2,4.10'3 (T) trong \
khoang thtti gian 0,4 (s) Sudt diQn dQng cim rfoig xudt hiOn khung khoang thdi gian
c6 tt truhng bidn thi6n lh:
A 1,5.10-2 (mV) B 1,5.10-5 (V) C 0,15 (mV) D 0,15.10'6 ry).
I Mot diQn tich S ddt tt trudng fldu c6 cfrm ftig tt B, g6c gifra vecto cim rlng tt vi di6n tfch S li a Tir th6ng qua diQn tich S duo c tinh theo c6ng thrlc:
A (D = BS.sinu B (D= BS.cosa C (D= BS.tanq, D (D= BS.ctanq.
12 HiQn tuqng.ty cim ld hi$n tuqmg cim img iliQn tir do sg bitin thi6n tu th6ng qua m4ch gAy b&i A sU chuy6n dgng cria nam ch6m vdi mpch
B sU bi6n thi6n cria chinh cudrng ttQ tli€n truryng mpch C sU chuyAn dQng cria mpch vdi nam chdm
D sU bi6n thi6n cria tir truong Trdi ditt
13 PhAt bitSu ndo dudi ddy ld sai?
Su6t di6n dQng t.u cim c6 girl tri l6n khi
A ddng diQn tdng nhanh B Ddng diQn giim nhanh
C Ddng diQn c6 giri tri lcrn D Ddng iti€n bi6n thi6n nhanh,
14 Trong khoing thdi gian 0,01 s, ddng diQn m4ch tnng tt6u tit 1,2 A diSn 3,7 Avi su6t diQn dQng tU cim ld 40 V D0 $ cflm cta 6ng d6y li
A 1,6 mH B 16 mH C 160 mH D 1,6 H
15 Ong dey (1) 96 cuqg tiiit diQn v6! ting d6y (2) nhung chi€u dni ting vd sti vdng d6y rtdu nhi€u hcrn
g6p ddi .Ti s6 hg s6 Lu cim cria ting ft; vOi Ong (2) je
A.1 8.2 C.4 D.8
16 Chgn cdu dung nh6t
Trong cuQn d6y adn Un xu6t hi$n ddng diQn cim fmg xoay chiAu khi sii duong sr?c tt xuy6n qua diQn tich S cria cuQn dAy
A Ludn ludn tIng B LuOn ludn gi6m
(3)17 Bi6u thtic nio dudi d6y bi€u di6n mQt dpi luqng c6 don vi li v6-be $fb)? '
A B(ffi2) B I(rR2) c nn2e D nR'z/B
s
18.MOt diy ddn c6 chiAu dii x6c Ainn Aub c qu6n tren 6ng ddy dai I vi b6n kinh ting r thi c6 hq sO t.u
cim 0,2mH N6u qu6n d6y din d6 trOn 6ng ddy c6 cung chi6u dii nhtmg ti6t dien tlng g6p el6i
thi he s6 t.u cem ctu ting dfly ld
A 0,2mH , B 0,1mH C 0,4mH D 0,8mH 19 Ph6t bidu nho sau diy li khOng dfng?
A Sau khi qugt diQn ho4t dQng, tathdy quat dien bi n6ng l€n Su n6ng l€n ctra quat di€n mQt phdn li do dbng diQn Fuc0 xudt hi$h 16i s6t ctra ctra quat di6n gdy ru
B Sau khi sieu diOn hoat d6.ng, tathdy nu6c sieu n6ng l€n Sg n6ng l€n cira nudc chir ydu li ddng di€n Fuc0 xudt hiQn nudc gfly
C Khi ding lb vi s6ng dd nuong bdnh, b6nh bi n6ng lOn Srl n6ng 16n ctra b6nh lh dbng diQn \ Fuc0 xudt hiQn b6nh g&y
D M6y bidn thddtng trong gia dinh khi hoat dQng bi n6ng l6n Sg n6ng lOn cira m6y bidn thd
chri ydu li do dbng diQn Fuc0 l6i sit cira m6y bidn thd gdy ru
e
20 Chqn ph6t bi€u dring
A Khi thanh kim lopi chuyi5n dQng tu truong thi hong xudt hi6n su6t diQn dQng cim
' img
B-Khithanhkimlo4ichuy6nd$ngeiite6cdu6,ttgsr?etirfhttrongtha[rhxu6thi€nsu5tdiend0ng cim img
C Khi thanh kim 1o4i chuyiSn dQng cdt c6c dulng sftc tir thi trong xu6t hi0n ddng di$n cAm
ung
D Khi thanh kim logi chuy6n d6ng tu trucrng thi trong xu6t hi6n ddng diQn cim img
2 t Nang lugng tt truong cu6n dAy khi c6 dbng di€n chay qua duo c x6c dinh theo cOng thfc:
.l^leE2
A.W=lCU' B.W=1LI' C.w= D.w=-1.10'B'V
2 2 9.10'.8n 8n
22.M0t 6ng d6y 0,4H dang tich lfiy mQt ndng luqng 8mJ Ddng di$n qua n6 li
A.O,2A B.5A C.4A D.O.O4A
23.Chi6tsu6t ti dtii cria,m6i truong klrric x4 vd m6i truong t6i A lu6n ludn lon hcrn
B ludn ludn nh6 hon I
C.tuy thuQc vfln t6c ar-rh srf,ng hai m6i trutrng D Triy thuQc vio g6c tdi vd g6c khtic x4
24.Ch9nph5t biOu sai
Cho mQt chtm tia sing song song tdi mflt ph6n c6ch hai m6i truong
(4)B G6c khric xp c6 the l6n hon hay nh6 hon g6c tdi i
C.Chii5tsu6tn2ctam6itruongkh[cxpcangtcrnthichrimtiabigdykhriccdngnhi€u.
D G6c lQch cria chirm tia khi di qru m4t phdn c6ch cdmg ltu khi chilft suSt tuyet d6i cria hai m6i
trudng cang kh6c
25 Dong diQn Fu-cO kh6ngxu6t hiQn hong truong hgp nio sau ddy ?
A KhOi d6ng chuyOn itQng tu truong tt0u cit c6c <Iudrng sfc tir
B L6 nhdm dao dQng tu truong
C Kh6i thriy.ngdn nim trong tu truong bii5n thi€n D Kh6i luu hulnh nim trong tt truong biiSn thi6n
26 MQt d6n diQn dai 40 (cm), chuydn d6ng tinh tiSn tr) truirng ddu, c6m rtng tt bang 0,4
(T) Vecto vQn tdc ctra vuOng g6c vdi vd hgp vdi c6c duirng srlc til mQt g6c a00, dQ
l6n v = (m/s) Sudt diQn dQng gita hai ddu ld:
A.0,4 (V) 8.0,8 (V) c.40 (v). D 80 (V).
.28 Nguyen nhin giy ru sudt diQn dQng cAm fng trong diy ddn chuydn d0.ng tt trudng lI: A Lr;c ho6 hgc tr4c dung l€n c6c Olectron llm cdc Olectro:r dich chuydn tir ddu niy sang ddu kia
ctra
B Lgc Lorenxo tdc dung l€n c6c €lectron lim c6c €lectron dich chuydn tt ddu niy sang ddu kia
ctra
C Lgc ma s6t gifra vi mOi truong ngodi lim c6c €lectron dfch chuydn tt ddu niy sang ddu
kia cira
D, Lgc tt t6c dung l6n do4n dAy d6n khdng c6 ddng diQn d4t tt trudng ldm c6c €lectron dich chuydn tt ddu nhy sang ddu kia cira
29 MQt day df,n dei 20 (cm) chuydn dQng tinh tidn til truong ddu c6 B = 5.10-4 (D.
Vecto vfi tdc cira vu0ng g6c vdi thanh, vu0ng goc vdi vecto cAm rfoig til vi c6 dQ lfu 5 1m/s) Sudt diQn dQng cim tlng li:
A.0,05 (v). 8.50 (mV) C.5 (mV) D.0,5 (mV)
30 Chi0u mQt tia s6ng fu chfu long c6 chi6t sudt 1;5
A 350 B 530 C 900
27 .M$t con c6 tronq khOi Uang s&6t ( n:
ThAt sg cA n[m c6ch lop b6ng
A.31 cm 8.46 cm C
1,,3) duqc nhin thfly n6m c6ch mpt lop blng 40 cm
52 cm D 80 cm
vdi g6c tfi 60o khOng khi Gdc khric xA le
D Khdng x6c dinh dugc
t