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1 Con lic ld xo g6m mQt vflt m Vd lb xo c6 dQ ctug k dao dQne diAu hda, khi mdc th65n vdo vft m mQt v6t kh6c c6 kh6i luq;g g6p i fa" vflt m thi chrt kj dao dQng cria chung
A tdng l6n ldn B giAm di 3 16n C tAng len mn D gi6m di 2 lan
2 Trong giao thoa s6ng ccr hgc vO! hai ngu6n d6ng pha thi 4 !
e tOng sO ddy cyc dai ld mQt s6 chdn L L - L
g.q6r[ o aay cuc ti6u ta m-Ot sore :'- L
C t6ng s6.day cyc d4r hay tdng s6 d6y clrc ti6u ludn ludn th mQt sO 16
O tOrrg s6 Aiy cgc dai limQt sO 16 vet6ng sd ddy cgc ti6u li mQt ch[n. S6ng t<$t trgn ld hai s6ng c6 '
A ctng tdn s6, cirng bi6n dQ B ctng ,?" tq vd dQ lQch pha kh6ng d6i theo thoi gian C
".1"g bi6n dQ, cing pha D.Su"g t6n
s6 vd d0 lQch pha thay d6i theo thdi gian Ee c6 s6ng dime
",ey trOn mQt sqi d6y dhn trOi voi hai dAu d6y ddu ld nrit s6ng
thi A chiAu ddi ddy bEng mQt phq t" budc s6ng ' fi A
B bu6c s6ng lu6n lu6n dirng b[ng chi€u dni ddy l*= L
I*
C chi6u dni d0y bdng mQt sti nguy6n l6n nria bu6c s6ng
D budc s6ng b6ng mQt s6le mn chiAu dli ddy
5 Klri c6 s6ng dimg trOn.day Ap thf gn
= S["q = b-+ l.
A sO nrit b[ng sO bgng nOu B cO dinh 'rt- )v'J B s6 bung hon s6 nrit mQt dcm vi n6u B t.u
C s6 nirt banE sO bqng n0u B t.u do OOtr D s6 bUng hcvn s6 nirt mQt don vf n6u B cO Ainn Chgn c0u sai ?
A Dai lugng d{c trrmg cho dQ cao cria am le Frr.6.
B Ecvn vi cria cudrng d0 am le W/nt'.
C Mrlc culng dO am tfnh b6ng Ben (B) hay dAxiben (dB) D Cudrng d0 em ld dAi lugng d{c trmg cho i10 to cta 6m
T.Tainguoi chi nghe dugc c6c 6m c6 tan s6 nim trong khoing A t$r t6Hz 200OHz
c tir 16 KHz-20000 KHz
B tir l6Hz - 20000H2 D tii 20 KHz- 2000 K}{z
I Yr:ddy
dnn
"u "nte;.t7l,n aAu co dinh song dimg tren ddy c6 *r";:;fl jlTff t-=LL
9 Trong thf nghiQm giao thoa s6ng trOn m{t nudc, hai ngu6n k6t hqrp Sr , Sz dao dQng Ehu k} 0,2 s, t4i mQt
ai6m Vt cich Sr, Sz nhimg khoang dr=lLcm, dr=L3cm s6ngc6 bi6n d0 cUc ttai Gita M vd dudmg trung truc cira S1S2 kh6ng c6 ddy cgc d4r kh6c Vfln t6c truy6n s6ng tr0n m{t nudc 1} bao nhi6u ?
A y= 20cmls B v= 5cmls C v=tocmls D v=tO0cml s
L0 MQt dng si{o dai 80 cm, hd hai ddu, tAo ra mQt s6ng itrlng trong dng s6o vdi 6m li crfc ttai hai ildu
dng, kho6ng gifra dng s6o c6 hai nrit s6ng Brrdc s6ng cria 6m ld
A l,=2Acm B.)u=40cm C.),=80cm D l"=160cm.
LL S6ng dimg tr6n d0y AB c6 chi6u aa$fZcm voi dAu B c6 Ainn Tan sO dao ttQng cira dEV lI.5OHz, vQn t6c
truy6nJngtrOndayh 4mts.Tr0nd0yc6.L l.=0,0Q L= l- t L=P -$nrit;4 bung B.4 nrit;4 bung C nrit; bung '- D 9 nrit; 8 bftg
(12;tr/1Ot s6ng co hgc truytin dgc theo tryc Ox c6 phuong trinh a = 28cos(2ox - 2000t) (cm), troqg d6 x li to4
\dAo*tinhlangm6t(m),tldttroigiandugctinhUanggi6y(s).VantOcctras6ngli \/
=A - [,/Xlt-t
4.334 m/s B 100m/s C 314mls D.331mls ' - f - Jg fi
13 Voi mQt s6ng am, kfii mirc'cuong d0 em tdngth€m 20dB thi
""1ng gg i1n ta"g -y_
A 100 hn B 100016n C 20 Hn D 200lan (7t]n-)
M A bO mat mQt ch6t 16ng c6 hai ngudn ph6t s6ng t<6t trqi,p 51 vi 52 c6ch 20cm Hai nguiin dao dOng theo phucrng thdrg dimg c6 phucrng tdnh lan lq$ Le ur = 5cos4Oact (mm) vh uz = 5cos(40nt + n){mm) TOc
dQ truyAn s6ng trOn m4ichdil6ng ld 80cm/s SO diem dao dQng vcri bi6n ttQ qUc d4i tr€n doan thang SrSz ld
A 11 8.9 -y= C 10 f ;0,0( D.8 l={
15 Hai 18c dcm c6 chu ki Hn luqt li T1 = 1,5s vd T2:2s dao dQng nh6 trong'hai m{t phAng song song
Hai lic ctng qua vi tri cdn b6ng theo cDng chi6u hic t: 0 X6c dinh thdi di€m gan nn6t ma hiQn tuqng
tr0n t6i diOn?
A 6s B 2,5s c L,32s D 3,5s
16 MOt vflt dlo dQng diAu hba vcvi bi6n d0 A Khi li d0 x - A/3 thi
(2)L7 MOt chet di6m dao dQne di6u hda thUc hiQn 2A T*= dao dQng 3h 60s
I
q-r
Ch9n40c thcvi
t
-t \\t1
.t li- t t9
glanla luc Cnat , A, Olem , o.o
L9 MOt vQt dao dQng di6u hdzi c6 dO 16m vfln tdc cyc d4i li,3l,4cm/s L5y n =3,14 f6c d0 !ry+S binh cria
vft trong mQt chu ki dao tlQng Id U,nn# g =- 4-b = e'W! /Ucr,x
,A^p0cm/s B 10cm/s c 0 V+;= G - -ryItt"illr 7p .f ,@lWEt con l6c don g6m qu6 cAu c6.kh6i luqmg m treo vio m$t sqi d6! c6 chidu'dei l Tt vf @.can b5.tg,
IruyAn cho qu6 n4ng vfln t6,c-2mls.Ley e: 10m/s2 DQ cao lcm nhat mi quq n{ng d4t {ygc so voi yi tri c6n bang le Y"Fr:A ul I
- Uj\$6 [-l n = L (r wrn^'a w
A.Zm B.0,8m.?- P c.zo"hcm." I i*;.20"#
=+-21 Trong ctng mQt thoi gian, 18c dcrn tfrri Lfr6t thyc hiQn {uqc 10 dao dQng, cop 16c <Iqp th,i hai thgc.
hiQnducy.c2}daoAQ"e.risOchiAudlictrachirngli [, 1.* k = [9t I:l
A rr:r g.!r=L c.b=2 , ' , loz " o.W]+ $r JyL' lbu
l, l, l, l t- - il,r_ L
22.Dao ttQng t6ng hgp cria hai dao t1Qng di6u hda ctng phucmg, cung tffis6 c6 phucmg trinh
x = 3cos( * - 4> (cm) Bitit dao dQng thri nh6t c6 phucmg trinh x1 = 5cos(rt * 1> (cm) Dao dQng thrl hai c6 o,u, uu ruunnuo* duu rn *-@ -}F = AL + tr .f J* fs ,rs
A -'-" - 8.cm vi { rad B 2 cm vd Lrad C.2 cmui - 5T ,u6 D 8 cm ui, - Yrua
- - 6 - 6
23 Hil dao dQng di0u hda ctng phuong, Cung tan s6, ctng bi6n d0, c6 d0 lQch pha ld n/3 Dao d$ng t6ng
hqrpc6bi6nt1Q^ldl0Jrcm.Bi6ndQctram6idaodQngthlnhpnantn A( : Ut-*tJt = -lI
A loJicm ' ' B 10cm c 10J; cm o ro{} "*:
24 Phuong trinh vQn tiSc cira mQt vQt dao <tQng diAu hda: v = A acosrrtlt I(5t luan ndLo sau ddy ld thing?
A G6c thdi eian li hic ch6t di6m di qua vi tri cdn bdng theo chiAu ducmg
A.8cm. B 12cm C 14cm D.6cm.
B Gdc thoi gian li hic ch6t di€m c6 tga dQ x : -[
C Gi5c thdi gian li hic ctrAt AiOm c6 tga dQ x : A.
D GOc thcri gian 1I hic chdt di6m c6 tga d0 x : A, ho{c x : - A
zi.Tqlctng mQt vi tri tlia lf, ntiu chiAu d^di l[c dcm tdng4 tan tfri chu k] dao dQng di6u hol cira n6
A tSng lAn B gifim 4ldn. C gi6m Zlen. D t6n g 41An
26.XetmQt vft dao dQng di6u hoh v<yi biOn dO A, tan sO g6c a Tai vi tri c6 li d0 x v{t c6 vfln t6c v H0
thrlc nio sau ddy ld kh6ng dung ?
*f = a'(N - *') B Az-={'t* C a.2 - A'-*' D o)'=
@ru^irQ crra 0"" uo,*,a,noG4#SHH.:Ctffir/;"ti* dao d6ng phdn c6
A Aq = (2n+l)n B AE = (.2n +.1)r,// C Aq =Znlt D A<p =
28 Khi tan sO dao dQng ctra ngo4i lgc b6ng tan s5 dao <lQng riOng cria hQ dao dQne thi
A Bi6n d0 dao dQng kh6ng d6i B Bien d0 dao dQng t6ng
#-<-NAng luqng dao <lQng kh6ng d6i D Bi6n t10 dao dQlg dat crrqdai f@)vt1T
""" rt il;ffi rqi iuy c6 chieu ddi 0,1m vi qui n{ng c6 kh5ii"qnglOe -*g diQn tich 10
-7C
dao dQng trong.diQn trucrng iIAu vecto cudng <10 <liQn trucrng E c6 phucrre thAtg dimg hudng xu5ng, E = 104V/m.lAy e: 10m/s2 Tinh chu ki dao dQng cira l6c?
A.0,625 s B 1 s c 1,625 s
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