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Job Number Sheet Job Title Software Consultants (Pty) Ltd Internet: http://www.prokon.com E-Mail : mail@prokon.com Client Calcs by Checked by Date V1-B1 General column design by PROKON  C13 (GenCol Ver W3.0.12 - 12 Dec 2016) Design code : Eurocode - 2004 Eurocode 2 - 2004 Y General design parameters: 2000 Given: l = 3.200 m fck = 44 MPa fy = 490 MPa Ac = 3739407 mm² X X -1000 -2000 Design approach: The column is designed using the following procedure: (1) The column design charts are constructed (2) The design axis and design ultimate moment are determined (3) The design axial force and moment capacity is checked on the relevant design chart (4) The procedure is repeated for each load case (5) The critical load case is identified as the case yielding the lowest safety factor about the design axis Through inspection: Load case 14 is critical Check column slenderness: End fixity and bracing for bending about the Design axis: The column is unbraced Effective length factor ß = 0.75 Effective column height: lo = ß l = 75 ×3.2 = 2.400 m Column slenderness about weakest axis: 1000 Y -1000 -2000 -3000 -3000 Assumptions: (1) The general conditions of clause 5.8.8.2 are applicable (2) The specified design axial loads include the self-weight of the column (3) The design axial loads are taken constant over the height of the column 1000 Job Number Sheet Job Title Software Consultants (Pty) Ltd Internet: http://www.prokon.com E-Mail : mail@prokon.com max_sl = = Client Calcs by Checked by Date lo r 2.4 1.0058 = 2.386 Minimum Moments for Design: Check for mininum eccentricity: Check that the eccentricity exceeds the minimum in the plane of bending: 5.2(7) eminx = = q l0 005 ×2.4 = 0.0060 m 5.2(7) eminy = = q l0 005 ×2.4 = 0.0060 m Use emin = 20mm 6.1 (4) Mminx = eminx N = 02 ×7 209.4 = 144.188 kNm Check if the column is slender: Ned = 7209.4 kN 5.8.3.1 Job Number Sheet Job Title Software Consultants (Pty) Ltd Internet: http://www.prokon.com E-Mail : mail@prokon.com f cd = acc f ck 1.50 = ×44.4 1.50 Client Calcs by Checked by Date = 29.600 MPa f yd = fy 1.15 = 490 1.15 = 426.087 MPa 5.5.3.1 (1) n= = Ned Ac f cd 7209×103 3739×103 ×29.6 = 0.0651 Check slenderness 5.8.3.1 (1) A = 0.7 5.8.8.3 (3) w= = As f yd Ac f cd 75595 ×426.09 3739×103 ×29.6 = 0.2910 5.8.3.1 (1) B = + w = + ×.291 = 1.258 Larger end moment Job Number Sheet Job Title Software Consultants (Pty) Ltd Internet: http://www.prokon.com E-Mail : mail@prokon.com Client Calcs by Checked by Date M02 = 26510.1 kNm Smaller end moment M01 = 17724.8 kNm 5.8.3.1 (1) rm = = M01 M02 17725 26510 = 0.6686 Unbraced therefore set rm = 5.8.3.1 (1) C = 1.7 - rm = 1.7 - = 0.7000 5.8.3.1 (1) llim = 20 A B C n = 20 ×.7 ×1.2578 ×.7 06513 = 48.300 l = 2.39 

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