Solution manual fundamentals of electric circuits 3rd edition chapter12

... AB = I a = I AB ∠ - 30° 11.24 ∠ - 31° ∠ - 30° = 6.489∠ - 1° A I BC = I AB ∠ - 120° = 6.489∠ - 121° A I CA = I AB ∠120° = 6.489∠119° A PROPRIETARY MATERIAL © 2007 The McGraw-Hill Companies, Inc... ∠0° V Chapter 12, Solution 16 (a) I CA = - I AC = 10∠ (-3 0° + 180°) = 10∠150° This implies that I AB = 10 ∠30° I BC = 10∠ - 90° I a = I AB ∠ - 30° = 17.32∠0° A I b = 17.32∠ - 120° A I c = 17.32∠120°... − I CA = I AB ∠ - 30° I a = 5.47 ∠ - 48.43° = 9.474∠ - 48.43° A I b = I a ∠ - 120° = 9.474∠ - 168.43° A I c = I a ∠120° = 9.474∠71.57° A PROPRIETARY MATERIAL © 2007 The McGraw-Hill Companies,