Solution manual mechanics of materials 8th edition hibbeler chapter 12

... x2 = 12 From Eqs (1) and (3) 1920 + C1 = -( -1920 + C3) C1 = -C3 v1 = v2 (5) x1 = x2 = 12 at 7680 + 12C1 = -7680 + 12C3 C3 - C1 = 128 0 (6) Solving Eqs (5) and (6) yields: C3 = 640 80 lb 12 in... The post and the beam are made of material having a modulus of elasticity of E = 200 GPa 30 kN/m A 6m Equations of Equilibrium Referring to the free-body diagram of the beam, Fig a, + ©F = 0;... 30 (12) = a + ©MA = 0; Ans (1) FB(6) + Cy (12) - 30 (12) (6) = (2) Method of superposition: Referring to Fig b and the table in the Appendix, the necessary deflections are (vB)1 = (vB)2 = 5(30) A 12