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A PHP Error was encountered Severity: Notice Message: Undefined variable: finfo Filename: controllers/post.php Line Number: 592 A PHP Error was encountered Severity: Warning Message: finfo_file() expects parameter to be resource, null given Filename: controllers/post.php Line Number: 592 ?ࡱ?>�� ?????t?[??2bjbj 8Hpa!\pa!\? ????? 8D ?d(>��>��>��((($-!?R??("((???>��>��?(?>��?>��(>��B T ?0?5$?5$5$?$((((( ((??(((?((((5$((((((((( >�� : ? thi minh h?a THPTQG m?n H?a H?c nm 2017 - B? GD&T - l n C?u 1: Trong c?ng nghi?p, ? i?u ch NaOH ng ?i ta i?n ph?n dung d?ch ch t X (c? m?ng ngn) Ch t X l? A Na2SO4 B NaNO3 C Na2CO3 D NaCl C?u 2: Kh? sinh tr ?ng h?p n?o sau ?y kh?ng g?y ? nhi?m kh?ng kh?? A Qu? tr?nh un n u, ?t l? s ?i sinh ho t B Qu? tr?nh quang h?p c?a c?y xanh C Qu? tr?nh ?t nhi? n li?u ?ng c ? t? D Qu? tr?nh ?t nhi?n li?u l? cao C?u 3: Ch t n?o sau ?y v?a ph n ?ng v?i dung d?ch NaOH v?a ph n ?ng v?i dung d?ch HCl? A AlCl3 B Al2(SO4)3 C NaAlO2 D Al2O3 C?u 4: Oxit n?o sau ?y t?c d?ng v?i dung d?ch HCl sinh h?n h?p mu?i? A Al2O3 B Fe3O4 C CaO D Na2O C?u 5: Polime n?o sau ?y ?c t?ng h?p b ng ph n ?ng tr?ng h?p? A Polisaccarit B Poli(vinyl clorua) C Poli(etylen terephatalat) D Nilon-6,6 C?u 6: Cho dung d?ch FeCl3 t?c d?ng v?i dung d?ch NaOH t o th?nh kt t?a c? m?u A n?u ? B tr ng C xanh th m D tr ng xanh C?u 7: S n ph m c?a ph n ?ng este h?a gi?a ancol metylic v? axit propionic l? A propyl propionat B metyl propionat C propyl fomat D metyl axetat C?u 8: Dung d?ch ch t n?o sau ?y kh?ng l?m qu? t?m chuy? n m?u? A Etylamin B Anilin C Metylamin D Trimetylamin C?u 9: Trong c?c kim lo i: Al, Mg, Fe v? Cu, kim lo i c? t?nh kh? m nh nh t l? A Cu B Mg C Fe D Al C?u 10: Ch t n?o sau ?y kh?ng ph n ?ng v?i NaOH dung d?ch? A Gly-Ala B Glyxin C Metylamin D Metyl fomat C?u 11: ? v?i l? nguy?n li?u c? s n t? nhi?n, ?c d?ng l?m v t li?u x?y d?ng, s n xu t v?i, Nung 100 kg ? v?i (ch?a 80% CaCO3 v? kh?i l ?ng, c?n l i l? t p ch t tr ) n kh?i l ?ng kh?ng ?i, thu ?c m kg ch t r n Gi? tr? c?a m l? A 80,0 B 44,8 C 64,8 D 56,0 C?u 12: Kim lo i crom tan ?c dung d?ch A HNO3 (c, ngu?i) B H2SO4 (c, ngu?i) C HCl (n?ng) D NaOH (lo?ng) C?u 13: Cho gam h?n h?p X g?m Ag v? Al v?o dung d?ch HCl d Sau ph n ?ng x y ho?n to?n, thu ?c 3,36 l?t kh? H2 (ktc) Ph n trm kh?i l ?ng c?a Al X l? A 54,0% B 49,6% C 27,0% D 48,6% C?u 14: Kh? ho?n to?n 32 gam CuO th?nh kim lo i c n v?a ? V l?t kh? CO (ktc) Gi? tr? c?a V l? A 13,44 B 8,96 C 4,48 D 6,72 C?u 15: Cho h?n h?p g?m CH3COOC2H5 v? CH3COONH4 t?c d?ng v?a ? v?i 200 ml dung d?ch NaOH 1M, thu ?c dung d?ch ch?a m gam mu?i Gi? tr? c?a m l? A 19,6 B 9,8 C 16,4 D 8,2 C?u 16: Cho h?n h?p Zn v? Fe v?o dung d?ch h?n h?p Cu(NO3)2 v? AgNO3, sau c?c ph n ?ng x y ho?n to?n, thu ?c h?n h?p hai kim lo i Hai kim lo i ? l? A Fe, Cu B Cu, Ag C Zn, Ag D Fe, Ag C?u 17: H?a tan ho?n to?n 9,4 gam K2O v?o 70,6 gam n ?c, thu ?c dung d?ch KOH c? n?ng ? x% Gi? tr? c?a x l? A 14 B 18 C 22 D 16 C?u 18: Cho axit acrylic t?c d?ng v?i ancol n ch?c X, thu ?c este Y Trong Y, oxi chim 32% v? kh?i l ?ng C?ng th?c c?a Y l? A C2H3COOCH3 B CH3COOC2H5 C C2H5COOC2H3 D C2H3COOC2H5 C?u 19: Cho d?y c?c ch t sau: tripanmitin, axit aminoaxetic, Ala-Gly-Glu, etyl propionat S? ch t d?y c? ph n ?ng v?i dung d?ch NaOH (un n?ng) l? A B C D C?u 20: Ph?t bi?u n?o sau ?y sai? A Protein l? c s? t o n?n s? s?ng B Protein n gi n l? nh?ng ch t c? t?i a 10 li?n kt peptit C Protein b? th?y ph?n nh? x?c t?c axit, baz ho c enzim D Protein c? ph n ?ng m?u biure C?u 21: X? ph?ng h?a ho?n to?n este X m ch h? dung d?ch NaOH, thu ?c h?n h?p c?c ch t h?u c g?m: (COONa)2, CH3CHO v? C2H5OH C?ng th?c ph?n t? c?a X l? A C6H10O4 B C6H10O2 C C6H8O2 D C6H8O4 C?u 22: Th?c hi?n th? nghi?m i?u ch kh? X, kh? X ?c thu v?o b?nh tam gi?c theo h?nh v sau: Th? nghi?m ? l? A Cho dung d?ch HCl v?o b?nh ?ng b?t CaCO3 B Cho dung d?ch H2SO4 c v?o b?nh ?ng l? kim lo i Cu C Cho dung d?ch H2SO4 lo?ng v?o b?nh ?ng h t kim lo i Zn D Cho dung d?ch HCl c v?o b?nh ?ng tinh th? K2Cr2O7 C?u 23: Cho m gam b?t s t v?o dung d?ch HNO3, sau ph n ?ng ho?n to?n, thu ?c 2,24 l?t kh? NO (s n ph m kh? nh t c?a N+5, ? ktc) v? 2,4 gam ch t r n Gi? tr? c?a m l? A 8,0 B 10,8 C 8,4 D 5,6 C?u 24: H?n h?p E g?m ba amin no, n ch?c ?t ch?y ho?n to?n m gam E b ng O2, thu ?c CO2,H2O v? 0,672 l?t kh? N2 (ktc) M t kh?c, ? t?c d?ng v?i m gam E c n v?a ? V ml dung d?ch HCl 1M Gi? tr? c?a V l? A 45 B 60 C 15 D 30 C?u 25: i?n ph?n (v?i i?n c?c tr , c ?ng ? d?ng i?n kh?ng ?i) dung d?ch mu?i nitrat c?a m?t kim lo i M (c? h?a tr? kh?ng ?i) Sau th?i gian t gi?y, kh?i l ?ng dung d?ch gi m 6,96 gam v? t i catot ch? thu ?c a gam kim lo i M Sau th?i gian 2t gi?y, kh?i l ?ng dung d?ch gi m 11,78 gam v? t i catot tho?t 0,224 l?t kh? (ktc) Gi? tr? c?a a l? A 8,64 B 6,40 C 6,48 D 5,60 C?u 26: Cho c?c ph?t bi?u sau: (a) Th?y ph?n vinyl axetat b ng NaOH un n?ng, thu ?c natri axetat v? fomanehit (b) Polietilen ?c i?u ch b ng ph n ?ng tr?ng ng ng (c) ? i?u ki?n th ?ng, anilin l? ch t kh? (d) Xenluloz thu?c lo i polisaccarit (e) Th?y ph?n ho?n to?n anbumin thu ?c h?n h?p -amino axit (g) ? i?u ki?n th?ch h?p, triolein tham gia ph n ?ng c?ng H2 S? ph?t bi?u ?ng l? A B C D C?u 27: Cho s ? chuy?n h?a: EMBED Equation.DSMT4 Bit c?c ch t Y, Z, T l? c?c h? p ch t c?a crom C?c ch t X, Y, Z, T l n l ?t l? A Fe(SO4)3, Cr2(SO4)3, Cr(OH)3, KCrO2 B FeSO4, CrSO4, KCrO2 , K2CrO4 C FeSO4, Cr2(SO4)3, KCrO2, K2CrO4 D FeSO4, Cr2(SO4)3, Cr(OH)3, K2Cr2O7 C?u 28: Cho mol triglixerit X t?c d?ng v?i dung d?ch NaOH d , thu ?c mol glixerol, mol natri panmitat v? mol natri oleat Ph?t bi?u n?o sau ?y sai? A Ph?n t? X c? li?n kt ? B C? ?ng ph?n c u t o th?a m?n t?nh ch t c?a X C C?ng th?c ph?n t? ch t X l? C52H96O6 D mol X l?m m t m?u t?i a mol Br2 dung d?ch C?u 29: Tin h?nh c?c th? nghi?m sau: (a) i?n ph? n NaCl n?ng ch y (b) i?n ph?n dung d?ch CuSO4 (i?n c?c tr ) (c) Cho m u K v?o dung d?ch AlCl3 (d) Cho Fe v?o dung d?ch CuSO4 (e) Cho Ag v?o dung d?ch HCl (g) Cho Cu v?o dung d?ch h?n h?p Cu(NO3)2 v? NaHSO4 S? th? nghi?m thu ?c ch t kh? l? A B C D C?u 30: Cho mol ch t X (C9H8O4, ch?a v?ng benzen) t?c d?ng ht v?i NaOH d , thu ?c mol ch t Y, mol ch t Z v? mol H2O Ch t Z t?c d?ng v?i dung d?ch H2SO4 lo?ng thu ?c ch t h?u c T Ph?t bi?u n?o sau ?y sai? A Ch t T t?c d?ng v?i NaOH theo t? l? mol : B Ch t Y c? ph n ?ng tr?ng b c C Ph?n t? ch t Z c? nguy?n t? oxi D Ch t X t?c d?ng v?i NaOH theo t? l? mol : C?u 31: Cho c?c ph?t bi?u sau: (a) T t c c?c peptit ?u c? ph n ?ng m?u biure (b) Mu?i phenylamoni clorua kh?ng tan n ? c (c) ? i?u ki?n th ?ng, metylamin v? imetylamin l? nh?ng ch t kh? (d) Trong ph?n t? peptit m ch h? Gly-Ala-Gly c? nguy?n t? oxi (e) ? i?u ki?n th ?ng, amino axit l? nh?ng ch t l?ng S? ph?t bi?u ?ng l? A B C D C?u 32: Ancol etylic ?c i?u ch b ng c?ch l?n men tinh b?t theo s ?: EMBED Equation.DSMT4 ? i?u ch 10 l?t ancol etylic 46o c n m kg g o (ch?a 75% tinh b?t, c?n l i l? t p ch t tr ) Bit hi?u su t c?a c qu? tr?nh l? 80% v? kh?i l ?ng ri?ng c?a ancol etylic nguy?n ch t l? 0,8 g/ml Gi? tr? c?a m l? A 3,600 B 6,912 C 10,800 D 8,100 C?u 33: S?c t? t? kh? CO2 n d v?o dung d?ch g?m a mol NaOH v? b mol Ca(OH)2 S? ph? thu?c c?a s? mol kt t?a CaCO3 v?o s? mol CO2 ?c bi?u di?n theo ? th? sau: T? l? a : b t ng ?ng l? A : B : C : D : C?u 34: H?n h?p E g?m ch t X (C3H10N2O4) v? ch t Y (C3H12N2O3) Ch t X l? mu?i c?a axit h?u c a ch?c, ch t Y l? mu?i c?a m?t axit v? c Cho 2,62 gam E t?c d?ng v?i dung d?ch NaOH d , un n?ng, thu ?c 0,04 mol h?n h?p hai kh? (c? t? l? mol : 3) v? dung d?ch ch?a m gam mu?i Gi? tr? c?a m l? A 2,40 B 2,54 C 3,46 D 2,26 C?u 35: i?n ph?n dung d?ch NaCl (i?n c?c tr , m?ng ngn x?p), thu ?c dung d?ch X H p th? CO2 d v?o X, thu ?c dung d?ch ch t Y Cho Y t?c d?ng v?i Ca(OH)2 theo t? l? mol : 1, t o ch t Z tan n ?c Ch t Z l? A Ca(HCO3)2 B Na2CO3 C NaOH D NaHCO3 C?u 36: Cho ch t: NaOH, HCl, AgNO3, HNO3, Cl2 S? ch t t?c d?ng ?c v?i dung d?ch Fe(NO3)2 l? A B C D C?u 37: H?n h?p T g?m este n ch?c X, Y (MX < MY) un n?ng 15 gam T v?i m?t l ?ng dung d? ch NaOH v?a ?, thu ?c m gam h?n h?p Z g?m ancol (c? ph?n t? kh?i h n k?m 14u) v? h?n h?p hai mu?i ?t ch?y m gam Z, thu ?c 9,408 l?t CO2 (ktc) v? 10,8 gam H2O Ph n trm kh?i l ?ng c?a X T l? A 59,2% B 40,8% C 70,4% D 29,6% C?u 38: H p th? ht 4,48 l?t kh? CO2 (ktc) v?o dung d?ch ch?a x mol KOH v? y mol K2CO3, thu ?c 200 ml dung d?ch X Cho t? t? n ht 100 ml dung d?ch X v?o 300 ml dung d?ch HCl 0,5M, thu ?c 2,688 l?t kh? (ktc) M t kh?c, cho 100 ml dung d?ch X t?c d?ng v?i dung d?ch Ba(OH)2 d , thu ?c 39,4 gam kt t?a Gi? tr? c?a x l? A 0,10 B 0,20 C 0,05 D 0,30 C?u 39: H?n h?p E g?m ch t: X (l? este c?a amino axit); Y v? Z l? hai peptit m ch h?, h n k?m m?t nguy?n t? nit (?u ch?a ?t nh t hai lo i g?c amino axit, MY < MZ) Cho 36 gam E t?c d?ng v?a ? v?i 0,44 mol NaOH, thu ?c 7,36 gam ancol no, n ch?c, m ch h? v? 45,34 gam ba mu?i c?a glyxin, alanin, valin (trong ? c? 0,1 mol mu?i c?a alanin) M t kh?c, ?t ch?y ho?n to?n 36 gam E O2 d ,thu ?c CO2, N2 v? 1,38 mol H2O Ph n trm kh?i l ?ng c?a Y E l? A 18,39% B 20,72% C 27,58% D 43,33% C?u 40: H?a tan ht h?n h?p X g?m 5,6 gam Fe; 27 gam Fe(NO3)2 v? m gam Al dung d?ch ch?a 0,61 mol HCl Sau c?c ph n ?ng x y ho?n to?n, thu ?c dung d?ch Y ch? ch?a 47,455 gam mu?i trung h?a v? 2,352 l?t (ktc) h?n h?p kh? Z g?m NO v? N2O T? kh?i c?a Z so v?i H2 l? 16 Gi? tr? c?a m l? A 1,080 B 4,185 C 5,400 D 2,160 ?p ?n 1-D2-B3-D4-B5-B6-A7-B8-B9-B10-C11-C12-C13-A14-B15-C16-B17-A18-D19-B20-B21-D22C23-B24-B25-C26-A27-C28-C29-A30-A31-A32-C33-A34-B35-C36-A37-A38-A39-A40-A L?I GI I CHI TI T C?u 1: ?p ?n D 2NaCl + 2H2O ->�� 2NaOH + H2 ! + Cl2 ! C?u 2: ?p ?n B A C + O2 ! CO2 B CO2 + 12 H2O ! C6H12O6 + O2 + H2O C Bao g?m c?c kh? CO (cacbon oxit), HC (hyr? cacbon) v? NOx (nit oxit) & D Qu? tr?nh ?t ch?y nhi?n li?u sinh c?c kh? ?c nh H2S, NOx, SO2, CO& C?u 3: ?p ?n D Ch t v?a t?c d?ng ?c v?i HCl v? NaOH l? ch t l ?ng t?nh C?u 4: ?p ?n B A Al2O3 + 6HCl ! 2AlCl3 + 3H2O B 8HCl + Fe3O4 ! FeCl2 + 4H2O + 2FeCl3 C CaO + 2HCl ! CaCl2 + H2O D Na2O + 2HCl ! 2NaCl+ H2O C?u 5: ?p ?n B C?u 6: ?p ?n A 3NaOH + FeCl3 ! 3NaCl + Fe(OH)3 ! C?u 7: ?p ?n B CH3OH + CH3CH2COOH EMBED Equation.DSMT4 CH3CH2COOCH3 C?u 8: ?p ?n B Amin th m kh?ng ?i m?u qu? t?m C?u 9: ?p ?n B C?u 10: ?p ?n C Amin c? t?nh bazo kh?ng ph n ?ng v?i NaOH C?u 11: ?p ?n C mCaCO3 = 100 80% = 80kg nCaCO3 = 0,8kmol nCO2 = nCaCO3 = 0,8kmol m = mCaCO3 + mCO2 = 100 0,8 44 = 64,8kg C?u 12: ?p ?n C Crom b? th? ?ng HNO3 v? H2SO4 c ngu?i Crom tan NaOH c n?ng Cr + 2HCl CrCl2 + H2 C?u 13: ?p ?n A Ph ng ph?p: B o to?n e C?ch gi i: Khi cho t?c d?ng v?i HCl ch? c? Al ph n ?ng Ag kh?ng ph n ?ng v?i axit kh?ng c? t?nh oxi h?a nH2 = 0,15mol B o to?n e: nAl = 2/3nH2 = 0,1 mol =>�� %Al = 54% C?u 14: 6D~P R T V X Z ^ ` d f h j n p x z | ~ >�� @ B D F H ?????ķ ? Ϣ???? Ϣ????ώ?ķ ? Ī?h?h?h? 5\h2`F5 B*phh?h? H*h %ah2`F5 B*phh?fh2`F5 B*phh2`F h, h2`F h?h? zOv ZhՕ?d K?? N}p ʴ.%Bࡱ*oP 2/? ä?4P|&}.?Ca ?$! O z@kЈ,jC"J?I ????? 1#? 0}??s F `:?oF `F `?K?#?0?E ?@y?#?0#?0?%?F `F`"?c
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