Tài liệu ôn tập vật lý 9 rất hay

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HD: V� c � d � cha�y qua da�y da�n t� le� thua�n v��i hie�u �ie�n the� �a�t va�o hai �a�u da�y da�n �o� ne�n:V��i U1 = 12V th� I1 = 0,5AV��i U2 = 36V th� I2 =# EMBED Equation.3 ###Do�ng �ie�n cha�y qua mo�t da�y da�n co� c���ng �o� la� 6mA no� ����c ma�c va�o h� t 12V Muo�n do�ng �ie�n cha�y qua da�y da�n �o� co� c���ng �o� gia�m �i 4mA th� hie�u �ie�n the� la� bao nhie�u? HD: Do�ng �ie�n co� c���ng �o� gia�m �i mA t��c la� I = 2mA C���ng �o� do�ng �ie�n gia�m �i la�n=> U gia�m �i la�n �o� U2 = 4VCho �ie�n tr�� R= 15# EMBED Equation.3 ###Khi ma�c �ie�n tr�� na�y va�o hie�u �ie�n the� 6V th� do�ng �ie�n cha�y qua no� co� c���ng �o� ba�ng bao nhie�u? Muo�n c���ng �o� do�ng �ie�n cha�y qua �ie�n tr�� ta�ng the�m 0,3A so v��i tr���ng h��p tre�n th� hie�u �ie�n the� �a�t va�o hai �a�u �ie�n tr�� �o� la� bao nhie�uHD: a)I= # EMBED Equation.3 ### b) U� = RI�= 15* 0,7 = 10,5V ( I� = 0,4+0,3=0,7A)4 Co� hai bo�ng �e�n ghi 110V-75W va� 110V-25W So sa�nh �ie�n tr�� cu�a hai bo�ng �e�n tre�n? HD: T�nh �ie�n tr�� cu�a mo�i bo�ng �e�n ro�i so sa�nh5 Mo�t da�y da�n ����c ma�c va�o hie�u �ie�n the� 6V th� c���ng �o� do�ng �ie�n cha�y qua no� la� 0,3A Mo�t ba�n ho�c sinh no�i ra�ng: Ne�u gia�m hie�u �ie�n the� �a�t va�o hai �a�u da�y da�n �i 2V th� c���ng �o� do�ng �ie�n cha�y qua da�y da�n �o� co� c���ng �o� la� 0,15 A Theo em ke�t qua� na�y la� �u�ng hay sai? V� sao? HD: Khi hie�u �ie�n the� gia�m �i 2V t��c la� U2 = 6-2=4V C���ng �o� do�ng �ie�n �o� la� I2 = I1.U2/U1 = 0,3.4/6 = 0,2AVa�y ke�t qua� �� �a�y la� sai ba�n �a� nha�m la� hie�u �ie�n the� gia�m �i V ch�� kho�ng pha�i hie�u �ie�n the� gia�m �i hai la�n6 La�m th� nghie�m kha�o sa�t s�� phu� thuo�c cu�a c���ng �o� do�ng �ie�n va�o hie�u �ie�n the� �a�t gi��a hai �a�u va�t da�n ba�ng kim loa�i, ng���i ta thu ����c ba�ng so� lie�u sau: U(v)#0#1,5#3,0#4,5#6,0#7,5#9,0##I(A)#0#0,31#0,61#0,90#0,129#0,149#0,178##R(# EMBED Equation.3 ###)#########Ve� �o� th� bie�u die�n s�� phu� thuo�c I va�o U Ne�u bo� qua nh��ng sai so� phe�p �o th� �ie�n tr�� cu�a va�t da�n �o� ba�ng bao nhie�u? 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2 C� �i�n tr� nh� ���c m�c v�i nhau, m�i c�i c� �i�n tr� R C� th� m�c ch�ng theo bao nhi�u c�ch kh�c �� t�o th�nh m�t �o�n m�ch ? T�nh �i�n tr� c�a t�ng �o�n m�ch ��? 3 M�t m�ch �i�n ���c m�c nh� h�nh v� Trong �� R1 = 35 (, R2 = 60 ( Ampe k� A1 ch� 2.4A.#T�nh c��ng �� d�ng �i�n ch�y qua R2 ? R1 S� ch� c�a V�n k� l� bao nhi�u? S� ch� c�a Ampe k� A l� bao nhi�u? R24 Ba �i�n tr� R1 = 24 (; R2 = (; R3 = ( ���c m�c th�nh m�t �o�n m�ch song song C��ng �� d�ng �i�n ch�y qua m�ch ch�nh l� 4A T�nh �i�n tr� t��ng ���ng c�a �o�n m�ch? T�nh c��ng �� d�ng �i�n ch�y qua m�i �o�n m�ch r�? #5 Cho m�ch �i�n nh� h�nh v� Cho bi�t: UAB = 70V; r1 =15 ( ; R2 = 30 (; R3 = 60 ( A R1 C B a) T�nh �i�n tr� t��ng ���ng c�a to�n m�ch �i�n ? b) T�nh c��ng �� d�ng �i�n qua c�c �i�n ? C� ba �i�n tr� R1 = (; R2 = (; R3 = 24 ( ���c m�c v�o hai �i�m A, B c� hi�u �i�n th� 12V T�nh �i�n tr� t��ng ���ng c�a �o�n m�ch? R1 r2 #T�nh c��ng �� d�ng �i�n qua m�i �i�n tr� ? A B c) T�nh hi�u �i�n th� gi�a hai ��u �i�n R3tr� R1 v� R2? #7 C� �i�n tr� c� gi� tr� R N�u c�c c�ch m�c c�c �i�n tr� �� th�nh m�t m�ch �i�n ? T�nh �i�n tr� t��ng ���ng c�a m�i �o�n m�ch �� ? ##8 Cho m�ch �i�n nh� h�nh v� Trong ��: ## R1 = R2 = 4( ; R3 = 6( ; ## R4 = 5( ; r5 = R6 = 10( ; T�nh �i�n tr� t��ng ���ng to�n m�ch ? ##9 Cho m�ch �i�n nh� h�nh v� Trong �� R1 = 45 ( # Ampe k� A1 ch� 1.2A, Ampe k� a ch� 2.8A #T�nh hi�u �i�n th� UAB c�a �o�n m�ch? #T�nh �i�n tr� R2? ( 54V; 33.75( )10 Cho m�ch �i�n nh� h�nh v� Bi�t R1 = 20( , s� ch� c�a c�c Ampe k� A v� A2# l�n l��t l� 4A v� 2,2A ### a) X�c ��nh hi�u �i�n th� gi�a hai ��u �o�n m�ch# v� gi� tr� �i�n tr� R2 ? # b) Gi� nguy�n hi�u �i�n th� gi�a hai ��u �o�n m�ch, # thay R1 b�ng �i�n tr� R3 th� th�y ampe k� A ch� 5,2A S� ch� c�a ampe k� A2 �� l� bao nhi�u ? T�nh �i�n tr� R3 ( 36V; 16.36( ; 2.2A ; 12( )#11 M�c hai �i�n tr� R1, R2 v�o hai �i�m A, B c� hi�u �i�n th� 90V N�u m�c R1 v� R2 n�i ti�p th� d�ng �i�n c�a m�ch l� 1A.N�u m�c R1 v� R2 song song th� d�ng �i�n qua m�ch ch�nh l� 4,5A H�y x�c ��nh �i�n tr� R1 v� R2 ? ### ( 30( v� 60( )##########12 Cho m�ch �i�n nh� h�nh v� Bi�t v�n k� M N######### ch� 84V, ampe k� A ch� 4,2A, �i�n tr�## R1 = 52,5( ### T�m s� ch� c�a c�c ampe k� A1 , A2 v� t�nh �i�n tr� R2 ( 1.6A; 2.6A; 32.3( ) #13 Cho m�ch �i�n nh� h�nh v� ##### Hi�u �i�n th� gi�a hai ��u �o�n m�ch UMN = 60V.####### Bi�t R1 = 3R2 v� R3 =8( s� ch� c�a ### Ampe k� A l� 4A T�nh c��ng �� d�ng �i�n qua## c�c �i�n tr� R1 v� R2 v� gi� tr� c�c �i�n tr� R1 v� R2 #### ( 1A; 3A; 28( ;28/3( )###14 Cho m�ch �i�n nh� h�nh v� Trong �� R1= 4( ,# R2 = 10( , R3 = 15(, hi�u �i�n th� UCB = 5,4V T�nh �i�n tr� t��ng ���ng RAB c�a �o�n m�ch.#T�nh c��ng �� d�ng �i�n qua m�i �i�n tr� v� s� ch� c�a ampe k� A ( 10( ; 0.9A; 0.54A; 0.36A)15 Cho m�ch �i�n nh� h�nh v� Bi�t R1 = 4( , R2 = 6( , R3 = 15( Hi�u �i�n th� gi�a hai ��u# �o�n m�ch UAB = 36V R1 R2#T�nh �i�n tr� t��ng ���ng c�a �o�n m�ch.#T�m s� ch� c�a Ampe k� A v� t�nh R3 hi�u �i�n th� hai ��u c�c �i�n tr� R1, R2 ( 6(; 6A; 3.6A; 14.4V; 21.6V)16 Cho m�ch �i�n nh� h�nh v� A B Bi�t R1 =12( , R2 = 18( , R3 = 20( ,# Rx c� th� thay ��i ���c Hi�u �i�n th� gi�a hai R1 R2 # ��u �o�n m�ch UAB = 45V.## a) Cho Rx = 25( T�nh �i�n tr� t��ng ���ng A B c�a m�ch v� c��ng �� d�ng �i�n m�ch ch�nh b) ��nh gi� tr� Rx �� cho c��ng �� d�ng �i�n qua Rx nh� h�n hai l�n c��ng �� d�ng �i�n qua �i�n tr� R1 ( 18(; 2.5A; 40( )17 Cho m�ch �i�n nh� h�nh v� R2 D R3 ##Trong ��: R1 = 15( ; R2 = ( ; R3 = 7( ; R4 = 10 ( A R1 C ##Hi�u �i�n th� UAB = 35V T�nh �i�n tr� t��ng ���ng c�a to�n m�ch T�nh c��ng �� d�ng �i�n qua c�c �i�n tr�.T�nh c�c hi�u �i�n th� UAC v� UAD ( 20(; 1.75A; 0.875A; 26.25V; 28.875V) 18 Tr�n h�nh v� l� m�t m�ch �i�n c� hai c�ng t�c R1 R4 K2 ### K1 v� K2 C�c �i�n tr� R1 = 12,5( , R2 = 4( , R3 = 6( K1# Hi�u �i�n th� hai ��u �o�n m�ch UMN = 48,5V.## a) K1 ��ng, K2 ng�t T�m c��ng �� d�ng �i�n qua c�c �i�n tr� b) K1 ng�t, K2 ��ng C��ng �� d�ng �i�n qua R4 l� 1A T�nh R4 M N c) K1 v� K2 c�ng ��ng, t�nh �i�n tr� t��ng ���ng c�a c� m�ch, t� �� suy c��ng �� d�ng �i�n m�ch ch�nh ? ( 2.94A; 30(; 3A)#S� ph� thu�c c�a �i�n tr� v�o chi�u d�i, ti�t di�nv� v�t li�u l�m d�y d�n - Bi�n tr� Tr�n m�t bi�n tr� c� ghi 25( - 1A Con s� 25( - 1A cho bi�t �i�u g� ? Hi�u �i�n th� l�n nh�t ���c ph�p ��t v�o hai ��u bi�n tr� l� bao nhi�u ? Bi�n tr� l�m b�ng nicom c� �i�n tr� su�t 1.1.10-6(m, c� chi�u d�i 24m T�nh ti�t di�n c�a d�y d�n d�ng l�m bi�n tr� ? M�t d�y d�n l�m b�ng Constantan c� �i�n tr� su�t ( = 0.5.10-6 (m, c� chi�u d�i l = 20m v� c� ti�t di�n ��u S = 0.4mm2 Con s� ( = 0.5.10-6 (m cho bi�t �i�u g� ? T�nh �i�n tr� c�a d�y d�n �� ��t v�o hai ��u m�t cu�n d�y d�n l�m b�ng ��ng m�t hi�u �i�n th� U = 17V th� c��ng �� d�ng �i�n qua d�y d�n l� I = 5A Bi�t ti�t di�n c�a d�y d�n l� 1.5 mm, �i�n tr� su�t l� 1.7.1-8 (m T�nh chi�u d�i c�a d�y d�n M�t d�y d�n l�m b�ng ��ng d�i 30m, c� ti�t di�n 1.5mm2 ���c m�c v�o hi�u �i�n th� 30.8V T�nh c��ng �� d�ng �i�n qua d�y d�n n�y, bi�t ( = 1.7.10-8(m M�t b�ng ��n c� ghi 18V - 1A m�c n�i ti�p v�i m�t bi�n tr� ch�y �� s� d�ng v�i hi�u �i�n th� kh�ng ��i 24V �i�u ch�nh �� bi�n tr� c� gi� tr� Rb = 12( T�nh to�n v� n�u nh�n x�t v� �� s�ng c�a b�ng ��n.H�i ph�i �i�u ch�nh bi�n tr� c� gi� tr� bao nhi�u �� ��n s�ng b�nh th��ng ? Hai b�ng ��n c� c�ng hi�u �i�n th� ��nh m�c l� U1 = U2 =6V, s�ng b�nh th��ng c�c b�ng ��n c� �i�n tr� t��ng �ng l� R1 = 6( v� R2= 12( C�n m�c hai b�ng n�y v�i m�t bi�n tr� v�o hi�u �i�n th� U = 9V �� hai b�ng s�ng b�nh th��ng V� s� �� m�ch �i�n tr�n v� t�nh �i�n tr� c�a bi�n tr� �� B�i t�p S� ph� thu�c c�a �i�n tr� v�o chi�u d�i, ti�t di�nv� v�t li�u l�m d�y d�n - Bi�n tr�.B�i M�t bi�n tr� ch�y c� �i�n tr� l�n nh�t l� 50( D�y �i�n tr� c�a bi�n tr� l� m�t h�p kim nicr�m c� ti�t di�n 0,11mm2 v� ���c cu�n ��u xung quanh m�t l�i s� tr�n c� ���ng k�nh 2,5cm T�nh s� v�ng d�y c�a bi�n tr� n�y.Bi�t c��ng �� d�ng �i�n l�n nh�t m� day n�y c� th� ch�u ���c l� 1,8A H�i c� th� ��t v�o hai ��u d�y c� ��nh c�a bi�n tr� m�t hi�u �i�n th� l�n nh�t l� bao nhi�u �� bi�n tr� kh�ng b� h�ng B�i M�t b�ng ��n c� ghi 18V - 1A m�c n�i ti�p v�i m�t bi�n tr� ch�y �� s� d�ng v�i ngu�n �i�n c� hi�u �i�n th� kkh�ng ��i 24V.�i�u ch�nh bi�n tr� ��n gi� tr� Rb = 12( H�y t�nh to�n v� n�u nh�n x�t v� �� s�ng c�a b�ng ��n.H�i ph�i �i�u ch�nh bi�n tr� c� gi� tr� �i�n tr� bao nhi�u �� ��n c� th� s�ng b�nh th��ng B� qua �i�n tr� c�c d�y n�i B�i C� hai b�ng ��n m� s�ng b�nh th��ng c� �i�n tr� t��ng �ng l� R1= 16( v� R2 = 12( D�ng �i�n ch�y qua hai ��n ��u c� c��ng �� ��nh m�c l� I = 0,8A Hai ��n n�y ���c m�c n�i ti�p v�i v� v�i m�t bi�n tr� v�o hai ��u �o�n m�ch c� hi�u �i�n th� U = 28,4V.T�nh �i�n tr� c�a bi�n tr� �� hai ��n s�ng b�nh th��ng.Khi ��n s�ng b�nh th��ng, s� v�ng d�y c�a bi�n tr� c� d�ng �i�n ch�y qua ch� b�ng 75% so v�i t�ng s� v�ng d�y c�a bi�n tr� T�nh �i�n tr� c�a bi�n tr� ? B�i Cho m�ch �i�n nh� h�nh v� AB l� m�t# bi�n tr� c� ch�y C L�c ��u ��y ch�y C v� �i�m A �� bi�n tr� c� �i�n tr� l�n nh�t B AKhi d�ch chuy�n ch�y C v� ph�a B th� �� s�ng c�a b�ng ��n thay ��i nh� th� n�o? Gi�i th�ch? Bi�t �i�n tr� c�a b�ng ��n l� R� = 18( �i�n tr� to�n ph�n c�a bi�n tr� l� 42( v� ch�y C � �i�m # ch�nh gi�a AB Hi�u �i�n th� ngu�n cung c�p l� 46,8V T�nh c��ng �� d�ng �i�n qua ��n ��? B�i Cho m�ch �i�n nh� h�nh v�, �� b�ng ��n c� hi�u �i�n th� ��nh m�c 24V v� c��ng �� d�ng �i�n ��nh m�c 0,6A ���c m�c v�i m�t bi�n tr� ch�y �� s� d�ng v�i ngu�n �i�n c� hi�u �i�n th� kh�ng ��i 30V a) �� ��n s�ng b�nh th��ng th� ph�i �i�u ch�nh bi�n tr� c� �i�n tr� l� bao nhi�u? B� qua �i�n tr� � d�y n�i b) N�u bi�n tr� c� �i�n tr� l�n nh�t l� 40( th� ��n s�ng b�nh th��ng d�ng �i�n ch�y qua bao nhi�u ph�n tr�m ( %) t�ng s� v�ng d�y c�a bi�n tr�? B�i Hai b�ng ��n c� hi�u �i�n th� ��nh m�c l� U1= 12V, U2 = 24V, s�ng b�nh th��ng c� �i�n tr� t��ng �ng l� R1 = 6( v� R2 = 4( C�n m�c hai ��n n�y v�i m�t bi�n tr� v�o hi�u �i�n th� U = 36V �� hai ��n s�ng b�nh th��ng.V� s� �� c�a m�ch �i�n T�nh �i�n tr� c�a bi�n tr� ��.* B�I T�P PH�N �I�N N�NGBa�i 1: Mo�t da�y da�n ba�ng nike�lin co� chie�u da�i 100m, tie�t die�n 0,5mm2 ����c ma�c va�o nguo�n �ie�n co� hie�u �ie�n the� 120V.1/ T�nh �ie�n tr�� cu�a da�y.2/ T�nh c���ng �o� do�ng �ie�n qua da�y.H���ng da�n # EMBED Equation.3 ###1/ �ie�n tr�� cu�a da�y:# EMBED Equation.3 �o� do�ng �ie�n qua da�y:# EMBED Equation.3 ### ###2/ C���ng ... kim loa�i, ng���i ta thu ����c ba�ng so� lie�u sau: U(v)#0#1,5#3,0#4,5#6,0#7,5 #9, 0##I(A)#0#0,31#0,61#0 ,90 #0,1 29# 0,1 49# 0,178##R(# EMBED Equation.3 ###)#########Ve� �o� th� bie�u die�n s�� phu� thuo�c... #c#�#n# #x#�#c# ###�#n#h# #l#�#.##A#.# #2#2#0#V#-#8#8#0#W# # # # # # # #B#.# #2#2#0#V#- #9# 9#0#W# # # # # #C#.# #9# 0#0#W#-#2#2#0#V# # # # # #D#.# #8#0#0#W#-#2#2#0#V##C#�#u# #4#0#:# #(#H#i#�#u#)# #M#�#t#... chi�u t� c� tay ��n ng�n tay gi�a h��ng theo chi�u d�ng �i�n th� ng�n tay c�i cho�i 90 0 ch� chi�u c�a l�c �i�n t� .9 C�ng su�t hao ph� to� nhi�t tr�n ���ng d�y t�i �i�n.P = # EMBED Equation.3 ###

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