16 câu hóa học AMINO AXIT PEPTIT rất cơ bản

Truy cp website www.tailieupro.com nhn thờm nhiu ti liu hn Luyn thi THPT QUC GIA HểA HC-PHM CễNG TUN T (0938.934.492)-facebook.com/tuantu.itus https://www.facebook.com/tailieupro/ GII CHI TIT AMINO AXIT PEPTIT C BN QU SINH NHT HC TRề D, EM BIT RI! https://www.facebook.com/tailieupro/ https://www.facebook.com/tailieupro/ https://www.facebook.com/tailieupro/ https://www.facebook.com/tailieupro/ https://www.facebook.com/tailieupro/ https://www.facebook.com/tailieupro/ https://www.facebook.com/tailieupro/ https://www.facebook.com/tailieupro/ https://www.facebook.com/tailieupro/ https://www.facebook.com/tailieupro/ https://www.facebook.com/tailieupro/ https://www.facebook.com/tailieupro https://www.facebook.com/tailieupro https://www.facebook.com/tailieupro https://www.facebook.com/tailieupro https://www.facebook.com/tailieupro https://www.facebook.com/tailieupro https://www.facebook.com/tailieupr https://www.facebook.com/tailieupr https://www.facebook.com/tailieupr https://www.facebook.com/tailieupr Cõu 1: Amino axit X phõn t ch cha hai loi nhúm chc Cho 0,1 mol X tỏc dng va vi 0,2 mol NaOH, thu c 17,7 gam mui S nguyờn t hiro phõn t X l A B C D Hng dn gii (NH )a R(C OOH)b + bNaOH (NH )a R(C OONa)b 0,2mol 17,7 0,2.22 Tăng giảm khối lượng 17,7 gam 0,1 X có dạng (NH )a R(C OOH)2 R 16a 43 M X 133 133 MODE TABLE a X H2 N C H3 (COOH)2 R 27 Cõu 2: Hn hp X gm cht Y (C2H8N2O4) v cht Z (C4H8N2O3); ú, Y l mui axit a chc, Z l ipeptit mch h Cho 25,6 gam X tỏc dng vi dung dch NaOH d, un núng, thu c 0,2 mol khớ Mt khỏc 25,6 gam X tỏc dng vi dung dch HCl d, thu c m gam cht hu c Giỏ tr ca m l A 23,80 B 31,30 C 16,95 D 20,15 Hng dn gii NaOH dư 0, mol NH3 Y : (COONH )2 : 0,1 mol X Z : C H8 N O3 : 0,1mol 25,6 gam NH Cl : hợp chất vô (COOH)2 0,1 mol Muối HCl dư Mui + H2O khớ ch sinh t Y v ú l khớ NH3 +) Trong dung dch NaOH: Peptit + nNaOH 25,6 0,1.124 BTNT N n(COONH4 )2 0,1 mol nC 4H8N2 O3 0,1 mol 132 n(COONH4 )2 n(COOH)2 0,1 mol BTNT C Mui +) Trong dung dch HCl: Peptit + (n1)H2O + nHCl Mui Z l ipeptit n = Khi ú: Peptit + H2O + 2HCl mmuối mpeptit mH2O mHCl (132 18 36,5) 0,1 31,30 gam BTKL Cõu 3: Khi cho mol amino axit X (ch cha nhúm chc COOH v NH2) tỏc dng ht vi axit HCl thu c 169,5 gam mui Mt khỏc, cho mol X tỏc dng ht vi dung dch NaOH thu c 177 gam mui Cụng thc phõn t ca X l A C3H7NO2 B C4H7NO4 C C4H6N2O2 D C5H7NO2 Hng dn gii X l Amino axit ch cha nhúm chc NH2 v nhúm chc COOH CTPT X: (H2N)nR(COOH)m n õy ta cú cỏch gii nh sau: Cỏch 1: Nhn xột t cỏc ỏp ỏn ta thy A, B, D cú N cú nhúm NH2 Khụng mt tớnh tng quỏt, ta gi s X cú nhúm NH2 ú CTPT X l H2NR(COOH)m Ng dy mun thỡ phớ mt c ngy, tui niờn m khụng hc thỡ phớ mt c cuc i Cm n quớ giỏo viờn ó cho i nhng ti liu tuyt vi