Mô hình xác suất và một số ứng dụng trong kinh tế

BO GIAO DUC VA DAO TAO TRUONG BAI HOC KINH TE TP HO CHi MINH NGUYEN A I ' vAN si , , ' A' A MO HIND XAC SUAT VA MOT SO • tfNG DUNG TRONG KIND TE • - ' ,;: _, ~ CHUYEN NGANH : DIEU KHIEN HQC KINH TE MA so: 5.02.20 LU~N AN TIEN si KINH TE NGU'OI HU'ONG DAN KHOA HQC : - PGS D~G HAN - GS TS TRu'dNG TP HO CHi MINH - 2001 VAN KIIANG L(11 CAM DOAN Toi xin cam doan day Hi cong trlnh nghien cuu cua rieng toi Cac s6li~u, ke't qua neu lu~n an la trung thlfc Nhung ke't lu~n cua lu~n an chua tung du' ;:::1 thl ke't lu~n tr~ng thai i h6i qui 90 ? 3.2.6.2 Luu kiem tra tr~ng thai hoi qui Begin Tfnh p Pn *define wind zzzz from 2,2 to 32, 60 nozoom nofloat *acti wind zzzz 92 k=1 whil t k=k+1 this form tichmatran(k) thisform.kiemtrahoiquy(k) m.exit=.t for i= to m.sc if test(i)=O m.exit=.f endif endfor if (k % 1000 = 0) or m.exit clear ? ?k for h1 = to m.sc ? for h2 = to m.sc ?? tran(tich(h1, h2)A(lfk), "999.99999999") next next endif if m.exit exit endif · if inkey()=27 exit endif if lastkey()=32 inkey(O) endif enddo *rele wind zzzz thisform.ghikq(2, "") thisform.ghikq(l, "Ma {rn P"+allt(str(m.k,6))) 93 for i= to m.sc m.kq="" for j= to m.sc m.kq=m.kq+tran(tich(i,j), '999 99999999') endfor thisform.ghikq(2,m.kq) endfor thisform.ghikq(2," ") thisform.ghikq(l,"Ki~m tra: ") m.kq="" for i= to m.sc m.kq=m.kq+tran(test(i), '9')+space(8) endfor thisform.ghikq(2,m.kq) xemmatran.release sele kq go top report form i_kqhq preview Ke't qua ki~m tra Voi s6li