Phân Dạng Và Phươg Pháp Giải Bài Tập Hoá Học 11 Phần Vô Cơ Phần 3

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Phân Dạng Và Phươg Pháp Giải Bài Tập Hoá Học 11 Phần Vô Cơ Phần 3

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Phân Dạng Và Phươg Pháp Giải Bài Tập Hoá Học 11 Phần Vô Cơ Phần 3 tài liệu, giáo án, bài giảng , luận văn, luận án, đồ á...

hSn dgng vi phaong ph^p gii\a hpc 11 VP co - D5 Xuan Hung ;:au 13. Cho quy tim h1n lu'cJt vao tiTng mau thuT: Mau lam quy hoa xanh la K2CO3 va NaOH MSu lam quy hoa do la HNO3 va (NH4)2S04 Ca(N03)2 khong doi mau quy tim Cho Ca(N03)2 vao 2 mau lam quy tim hoa xanh, mau tao kct tua la K2CO3 mau con lai la NaOH. Lay NaOH cho vao 2 mau lam quy tim hoa do. Man giai phong khi c6 miii khai la (NH4)2S04, con lai la HNO3. Hoac lay K2CO3 cho vao 2 mau Ircn, mau c6 giiii phong khi la HNO3 => Chon A ;:au 14. Goi cong thtfc ciia muoi nitrat la .M(N03)n 2M(N03)n '—^ MzOn + 2nN02 + n/202 a a/2 na na/4 Ta CO a(M + 62n) = 9,4 (1) 0,5a(2M+16ii) = 4 (2) (M+62n) 9,4 Lay (1): (2) ta du^dc: M = 32n. M + 8n 4 Khi n = 2 thl M = 64. Vay muoi nilral la Cu(N03)2 => Chon C :au 15. Goi X, y la so mol ciia KNO3 va Cu(N03)2 trong hon hdp PhiTcfng trinh phan uTng xay ra: 2KNO3.— 2x 2Cu(N03)2 2y -> 2KNO2 + O2 2x X -i^2Cu0 + 4y Ta CO he phiAJng trinh: 4NO2 + O2 y 10L2x + 188.2y = 95,4 32(x + y)4-46.4y x + 5y = 37,82 Giai he tim x, y tiT do chpn ke't qua dung. => Chon B 'au 16. Phiin ufng nhict phan: Pb(N03)2 —^ PbO + 2NO2 + I/2O2 X 2x x/2 Goi X la so mol Pb(N03)2 da nhiet phan: Khoi iMng khi thoat ra = 2x.46 + 0,5x.32 = 66,2 - 55,4 = 10,8 => X = 0,1 mol Vay hieu sual phan iJng la: H = 50% => Chon D on :&u 17. The tich khi thoat ra = 2.5x x 22,4 = 5,6 lit Chon A 18. Cac phu'cfng tnnh phan tfng xay ra: 2NaN03 —^ 2NaN02 + O2 (1) 2x X 2CuO + 4NO2 + O2 (2) 4y (3) 2Cu(N03)2 |.2y 4NO2 + O2 + 2H2O -> 4HNO3 4y y 4y So mol O2 tao ra d (1) va (2) la: x + y, sau phan tirng (3) con lai la x mol Ta CO X = 1,12/22,4 = 0,05 mol => khoi li/dng NaNOa = 2.0,05.85 = 8,5 g i=> Khoi lifdng Cu(N03)2 = 18,8 g => Chon A. &u 19. Phi^dng trinh phan iJng xay ra: 2N0 + O2 -> 2NO2 Trirdc pif 3 2 (lit) Phantfng 3 1,5 Sau phan iJug 0 0,5 3 Hon hdp sau phan uTng gdm O2 dirO,5 lit, N2 8 lit, NO2 3 lit The tich hon hdp lii: 11,5 lit => Chpn A. -Su 20. Xct cac qua irinh cho-nhan electron: Qua trinh cho e: Al- 3e->Ar' 39x 13x 2N^' + 8e-> 2N*' 16x 2x Qua trinh nhan e N^' + . 3e ^ N^' 3x x 2N^' + lOe^ 20x 2x N2 Pa c6: 5x = 2 mol => x = 0,4 mol mAi = 13.0,4.27 = 140,4 g => Chon C. C3u 21. Phi/dng trinh phan (Jng: 3M + 4nHN03 -> 3M(N03)„ + nNO + 2nH20 => Chon C Cau 22. Lap lujin, rut difdc M = 32n M la Cu => Chpn C 191 Phan djing phuBng ph^p gijii H6a hgc 11 VP co - D5 Xuan Himg Cfiu 23. Cu -> Cu(N03)2 ^ Cu(OH)2 CuO Ta c6: So mol dong ban dau = 3.2/64 = 0,05 mol => ncu = nc„c) = 0,05 mol => X = 0,05.80 = 4 gam => Chon A Cfiu 24. Phifdng irinh phan uTng xiiy ra: 3Cu + 8HNO, -)• 3Cu(NO,)2 + 2NO + 4H2O X 2 x/3 Cu + 4HN0,-> Cu(N03)2 + 2NO2 + 2H2O y - 2y -^ 30 + 2y.46 Ta c6: x + y = 0,2 mol, mill khac = 38 => X = 3y => X = 0.15.y = 0,05 mol => Vkhi = (2x/3 + 2y).22,4 = 4,48 lit => Chon C Cau 25. PhUitiig liinh phan u^ng: 2x8Al + .30HNO., -> 8AI(NO.,).i + 3N2O + I5H2O 3xlOAl + 36HNO., ^ 10A1(NO.,)., + 3N2 + I8H2O 46A1 + 168HNO, -> 46Al(NOj)., + 6N2O + 9N2 + 84H2O Vijy li Ic Al: N:0 : NO = 46 : 6 : 9 => Chon B. Cau 26. So mol HNO, phan iJ-ng = 3 X .so mol Al + so mol NO + 2 x so mol N2O + 2 x so mol N2 = 3. 13. 0,4 + 0,4 + 2.2.0,4 + 2.2.0,4 = 19,2 mol => The lich axil la 38,4 lil => Chon A. Cau 27. Tinh difdc so mol = 0.1 mol so mol NO.r = 0,04 mol va so mol Cu = 0,0375 mol Phifdng irinh phan i?ng dang ion nil gon: 3Cu + 8H^+2NOr-»3Cu'^+2NO + 4H20 Tri/ckphanifng 0,0375 0,1 0,04 0,0375 0,1 0,04 Xcll Ic ~ — 3 8 2 Qua li Ig lhay NO,' diT, Cu va H^phiin iJng hcl so mol NO = 0,025 mol ^ V = 0,56 lil =^ Chon D. Cfiu 28. Ctic phu-cJng Irinh phan I'rng: 3M + 4nl INO,, -> 3M(N03)„ + nNO + 2nH20 a mol a a n/3 2M + mH2S04 M2(S04),„ + mHj a mol a/2 am/2 Theo de ra: an/3 = am/2 => n : m = 3 : 2. V4y kirn loiii c6 hoa trj lhay doi a(M+62.3) 159,21 100 , giai ra ta CO M = 56 M la Fe -(2M+ 96.2) 2 =^ Chon A. iu 29. Tinh so mol cac chat: nNaOH=«'7.0,2 = 0,14 (mol) nH,po4 =0,1.1 = 0,1 (mol) X^ttllc -11N20H_ = 0:14^1 4 nH3i'04 O'l NaOH + H3PO4 NaH2P04 + H2O 2Na0H + H.,P04 -> Na2HP04 + 2H2O =>Chpn B. Cfiu 30. So mol ciic chat: 44 nNaOH= —-l'l(mol) • tao 2 muo'i n 39,2 H,P04 = 0,4 (mol) K 98 Xet ti Ic: -^^^^^ = — = 2,75 => tao 2 mucn nH.,P04 2NaOH + H3PO4 -> Na2HP04 + 2H2O 2x X X 3NaOH + H.,P04 -> Na,P04 + 3H2O 3y y y Ta CO 2x + 3y = 1,1 va X + y = 0,4 X = 0,1 va y = 0,3. Tinh khoi Ming cac muo'i la chon diTctc kcl qua => Chon D -fiu 31. Xcl qua trinh Ca3(P04)2 1 mol 2551 mol .SiO, ,C,1 ->2P- -^PA -).2H3P04 2 mol 5102 mol Khoi li/c.»ng bol quang la: 2551.310. 100 100 1 90 73 1000 -' = 1203,6 kg ^ Chon C. Phan dgng va phuong ph^p giai H6a hpc 11 VP cd - D8 Xuan Hi^ig Q£Mng3. CACBON - SnJC A. T6M TAT Li THUYET Khai qu^t ve nhom cacbon: Nhom cacbon gom : cacbon (C), silic (Si), gemani (Ge), thiec (Sn) (Pb) deu thuoc nguyen to p, cau hinh electron ngoai ciing : ns^ npl I. CACBON - Cau hinh electron : ls^2s^2p^ - Cac so oxi hoa cua C : -4; 0; +2 va +4. - Cac dang thu hinh : kirn cifdng, than chi, fuleren * Tinh chat hoa hoc : The hien tinh khuT hoSc tinh oxi h6a nhiftig chu yeu la tinh khuT. 1. Tinh khur a) Tac dung vdi oxi: C + O2 > CO^ 0 „ +2 CO2 + C 2CO b) Tac dung vdi hdp chat: C +4HN03dac —^ CO2 + 4NO2 + 2H2O. 2. Tinh oxi hoa a) Vdi hidro : C + 2H2 '" > CH4 0 „ -4 b) Vdi kim loai: 3C + 4A1 —^ AI4C3 * PhUcmfi trinh dieu che : CH4 '" ' C + 2H2. II. H0P CHAT CUA CACBON 1. Cacbon mono oxit (CO) : C^O * La mot oxit khong tao muoi (oxit trung tinh) * CO the hi?n tinh khijr: +2 ,„ +4 • 2C0 +O2 —^ 2C.O2 +2 „ +4 4C0 + FejO* —^ 3Fe + 4CO2 - * Dieu che : - Trong phong thi nghiem : HCOOH > CO + H2O (axit fomic) - Trong cong nghiep : C + H2O , -'"^""^^ CO + H2 CO2 + C 2CO +4 2. Cacbon dioxit (COg) : 0=C=0 - La mot oxit axit. - Tan trong niTdc dung dich axit cacbonic. CO2 + H2O ^ H2CO3 - Tac dung diTdc vdi oxit bazd, bazd -> muo'i cacbonat. CO2 + 2K0H, > K2CO3 + H2O - Tac dung vdi chat khuf manh : 0 +4 , +2 0 2Mg + CO2 —^ 2MgO + C * Dieu che : CaCOj + 2HC1:—> CaCb + C02t + H2O. 3. Axit cacbonic (H2CO3) va mu6li cacbonat a) Axit cacbonic (H2CO3): ^ C=0 H-0 - La axit raft yeu, kem ben. - La mot diaxit, tao ra hai loai muoi: + muoi cacbonat (COf") + muoi hidrocacbonat (HCOJ). b) Muoi cacbonat: - Tac dung vdi axit -> C02t NaHC03 + HCl > NaCl + CO2T + H2O Na2C03 + 2HC1 > 2NaCl + C02t + H2O - Tac dung vdi dung dich kiem : KOH + KHCO3 > K2CO3 + H2O - Phan iJng nhi$t phan : BaC03 BaO + C02t 2NaHC03 Na2C03 + COzt + H2O. III. SILIC VA H0P CHAT CUA SILIC 1. Silic (Si = 28) ( - Cau hinh electron : 1 2s^ 2p'* 3s^ 3pl Cd so oxi hda : -4; 0; +2 vi +4. - Cdc dang thO hinh : silic tinh th^ va silic v6 dinh hinh. J Phan danp vS phuonfl ph^p giai H6a hgc 11 VP CO - B6 Xufln Hung 0 +4 a) Tinh khuf: Si + O2 > SiOj Si + 2NaOH + H2O > Na^SiOj + 2H2t b) Tinh oxi h6a : Tac dung vdi kirn loai -> silixua kim loai. 0 -4 2Mg + Si > Mg2Si (magie sihxua) * Dieu che: - Trong phong thi nghiem : Si02 + 2Mg 2MgO + Si - Trong cong nghiep : Si02 + 2C Si + 2CO. 2. H^p chS't cua silic +4 a) Silic dioxit (SiOg) - La oxit axit: SiOz + 2NaOH NajSiOj + HjO SiOz + NazCOj NajSiOs + CO2 - Si02 tan trong axit flohidric (dCing kh^c thiiy tinh) Si02 + 4HF ).SiF4 + 2H20. b) Axit silixic muoi sihcat: - Axit silixic (HzSiOs) : chS't dang keo, khong tan trong ntfdc, de ma't niTdc khi dun n6ng. HzSiOj -A SiOa + H2O - Muoi silicat : trong dung dich, silicat cua kim loai kiem bi thuy phan manh tao ra moi trtfdng kiem. Na2Si03 + 2H2O2NaOH + H2Si03. B. PHAN LOAI VA PHiTdNG PHAP GIAI CAC DANG BAI TAP Dang 1. - L^p phi/cfng trihh h6a hoc - Viet chudi phan CTng - Di4u ch§' c6c chfi't BAI TAP MAU VA BAI TAP AP DUNG Bai 1. Lap phtfdng trinh h6a hoc cua cic phan tfng sau dSy : a) C + H2S04d5cCO2 + SO2+? b) C + HNO3 dj. NO2 + CO2 +? c) C + CaO CaCz + CO 126 I d) C + SiOj > Si + CO. Gidi a) C + 2H2SO4,,,. b) C + 4HN03,^, c) 3C + CaO —^ d) 2C + SiOz —^ +4 COj + 2SO2 +2H2O 4N02+ C62 + 2H20 CaC2 + CO Si + 2C0. Bai 2. Viet cac phiTdng trinh phan iJng theo scJ do sau : CaCl2-^ CaS04 ^^^CaO (9) (7? (8) (1) (2) (3) (4) (5) (6) (7) (8) (9) CO2 Ca3(P04)2 Giai -> CaCOj + 2KC1 Ca(HC03)2 CaCl2 + K2C03 CaCOj CaO + CO2 CaO + CO2 > CaCOs Ca(HC03)2 CaCOj + CO2 + H2O CaC03 + CO2 + H2O > Ca(HC03)2 CaCOj + 2HC1 > CaClz + C02t + H2O 3CaC03 + 2H,P04 > Ca3(P04)2 + SCOjT + 3H2O 3CaO + 2H3P04 > Ca3(P04)2 + SHjO Ca(HC03)2 + 2HC1 > CaCb + 2CO2 + 2H2O (10) CaC03 + H2S04 > CaS04 + CO2 + H2O. B4i3. a) Lam the nao de chuyen NaHCOj thknh Na2C03, Ca(HC03)2 thanh CaC03 va ngi/dc lai. b) Khi nung ndng kem oxit vdi than c6c thi tao th^nh mot chat khi chdy di/dc. Viet phiTdng trinh phan tfng hoa hoc cua phan tfng. Giai a)* chuyen NaHCOj thanh Na2C03 ta cho NaHC03 tic dung vdi dung dich NaOH. NaHC03 + NaOH > Na2C03 + H2O * Dl chuyen Ca(HC03)2 thanh CaC03 ta dem muoi Ca(HC03)2 khan nung i nhi^t. 127 Phan dgng phJong ph^p giSi H6a hgc 11 va cO - D8 Xufln Hung Ca(HC03)2 CaCOj + CO2 + H2O * NgiTdc lai : chuyen NajCOj thanh NaHCOj va CaCOj th^nh Ca(HC03)2 ta cho hai muoi Na2C03 va CaCOs Ian liTcJt vao dung dich CO2 bao hoa. Na2C03 + CO2 + H2O > 2NaHC03 CaCOa + CO2 + H2O > Ca(HC03)2. b) ZnO + C Zn + CO 2C0 + 02-^ 2CO2. Bai 4. Hoan thanh can hkng cac phan uTng oxi hoa khuT sau : a) Ca3(S04)2 + CI2 + C > POCI3 + CO + CaCl2 b) CS2 + 02^ CO2 +? c) FexOy + CO FeO + CO2 d) CuO + C ^ ? + CO2 e) Ca3(P04)2 + Si02 + C P + CaSiOj + CO f) Mn04 +C6H|206 + H^ g) C,2H220n + H2S04dac- > Mn^* + CO2 + a) Ca3(P04)2 + 6CL + 6C -> COzt + H2O + SOzt. Gidi -> 2POCI3 + 6C0 + 3CaCl2 +2 -I 0 b) CSj + 3O2 -^-^ +2y/x +2 c) Fe^O, +(y-x)CO +4-2 +4-2 CO2 + 2SO2 +2 +4 xFeO +(y-x) CO^ +2 0 d) 2CuO + C +4 2Cu + CO, e) Ca3(P04)2 + 3Si02+ 5C 0 24MnO; + 5QH,206 + 72H*• 2P + 3CaSi03+ 5 CO 24Mn^++ 3OCO2 + 66H2O 24 X 5 X +7 Mn +5e- 0 6C +2 -> Mn +4 -> 6 C + 6 X 4e hay 24KMn04 + SCfiHuOe + 36H2SO4 • -> 24MnS04 + I2K2SO4 + + 30CO2t + 66H2O g) C,2H220„ + 24H2SO4 +4 -> 12 CO J +35H2O+ 24SO2T 1 X 24 X 0 12c — +6 S +2e- +4 -> 12c + 12x4e +4 -> S . 128 ai 5. Bo tuc chuSi phan ufiig, viet cdc phtfdng trinh phan uTng (m6i mui ten 1^ mot phan tfng). Cho biet B Ik khi dting nap cho c^c binh chi?a lufa (dap t^t luTa). A Ik khodng san phd bien thUcJng dilng 6i san xuS't voi song. A, ^' NaQH D HCl (Trich TS DHQC TP.HCM) Gidi A:CaC03 B : CO2 C : NaHC03 D : NazCOj E:Ca(0H)2 F: CaCb CaCOj CaO + CO2 C02 + NaOH >NaHC03 C02 + 2NaOH >Na2C03 + H20 NaHC03 + NaOH > Na2C03 + H2O Na2C03 + HCl > NaHC03 + NaCl NaHC03 + Ca(0H)2 > NaOH + CaCOj + H2O NasCOj + CaCla > CaCOj + 2NaCl. Bai 6. Tur nguyen lieu chinh Ih muoi an, dd voi, ntfdc, khong khi va cha't xuc tic c6 du. Viet cac phiTdng trinh dieu che cac cha't sau: a) NH4HCO3 b) (NH4)2C03 c) NajCOj. Gidi a) 2NaCl + 2H2O —. > 2NaOH + Hzt + C^t ^ CO mang ngSn ^ CaC03 CaO + CO2 (H6a long khong khi sau do chiftig cS't phan doan Ian luTdt ISy N2 roi den O2). N2 + 3H2 , • 2NH3 p CO2 + NH3 + H2O > NH4HCO3 b) NH4HCO3 + NH3 > (NH4)2C03 c) (NH4)2C03 + 2NaOH > NazCOj + 2NH3 + 2H2O hoac C02 + 2NaOH >Na2C03 + H20. Bai 7. Cho cic cha't CaC03, dung dich NaOH, dung dich NaHCOj, dung dich HCl. Vid't cdc phiTdng trmh phan tfng hoa hoc xay ra khi cho cic chS't tac dung vdi nhau tilfng d6i mot. (TNTHPT) 129 Phan d?ng va phuong ph&p giai H6a hpc 11 V6 cd - D8 XuSn Hung Gidi CaCOj + 2HC1 > CaCb + COzt + H2O NaOH + NaHCOj > NaiCOj + H2O NaOH + HCl > NaCl + H2O NaHCOj + HCl > NaCl + COst + HjO. Bai 8. Co cac chat sau : CO2, Na2C03, C, NaOH, NazSiOj, HjSiOj. Hay lap thanh mot day chuyen hoa gifl"a cac chat va vie't cac phiTcJng trinh hoa hpc. Gidi Day sd do bien hoa : C CO2 N&iCOi NaOH NazSiOj HiSiOj t <5> (1) C + 02-^C02 (2) CO2 + 2Na0H > NaiCOj + H2O (3) Na2C03 + Ba(0H)2 > BaCOj + 2NaOH (4) 2NaOH + Si02 > NazSiOj + H2O (5) NazSiOj + 2HC1 > 2NaCl + H2Si03 (6) Na2Si03 + CO2 + H2O > NazCOj + H2Si03. Bai 9. Nhiet phan mot lirpng CaC03, sau mot th6i gian di/cJc chS't r^n A khi B. Cho khi B hap thu hoan toan vao dung dich KOH, thu difdc dung dich D. Dung dich tic dung dU'dc vdi dung dich BaCl2 va vdi dung dich NaOH. Cho r^n A tac dung vdi dung dich HCl di/, diTdc khi B va dung dich E. Co can dung dich E difdc muoi khan F. Dipn phan muoi F nong chay, di/dc kim loai M. Viet phiTdng trinh hoa hoc cua cac phan tfng xay ra. Giai KHCO, A : CaO; CaC03 duf B : CO2 Dung dich D [K2CO3 Muoi khan F : CaClj Dung dich E : CaCl2 M : Ca. CaCOj CaO + CO2 CO2 + KOH )-KHC03 CO2 + 2K0H —y K2CO3 + H2O Ca0 + 2HC1 >CaCl2 + H20 CaC03 + 2HCl > CaClz + COzt + H2O K2CO3 + BaClz > BaCOjJ- + 2KC1 2KHGO3 + 2NaOH > K2CO3 + Na2C03 + 2H2O CaClj -^2SL> Ca + Cbt. 'Bai 10. Viet cdc phiTcfng trinh h6a hoc theo cdc set do sau : a) Silic dioxit > natri silica^—-+^aA^^ dioxit magie silixua < silic b) CO2 > CaC03 > Ca(HC03)2 > CO2 > C > CO >• CO2. Gidi a) Si02 >-Na2Si03 • HzSiOs >• Si02 Mg2Si < Si Si02 + 2NaOH > NazSiOj + H2O Na2Si03 + CO2 + H2O > Na2C03 + H2Si03 H2Si03 -A Si02 + H2O Si02 + 2C Si + 2C0 Si + O2 SiOz Si + 2Mg Mg2Si Si + 2NaOH + H2O > Na2Si03 + 2H2t. b) CO2 + Ca(OH)2 > CaC03 + H2O CaC03 + CO2 + H2O >Ca(HC03)2 Ca(HC03)2 CaC03 + CO2 + H2O CO2 + 2Mg 2MgO + C C + CO2 2C0 CO + O2 CO2. Bai 11. a) Vie't phuTdng trinh hoa hoc cua phan iJng m6 ta thuy tinh bi axit HF an m6n. Biet r!ing thanh phan chu yeu cua thiiy tinh Ik NaiSiOj (Na20.Si02) CaSi03 (CaO.Si02). b) Tilf Si02 vk c&c hda cha't can thiet khac hay vi^t phifdng trinh hda hpc cia cic phan urng dieu ch^ axit silixic. Gidi a) Na2Si03 + 6HF - - -> SiF4t + 2NaF + 3H2O CaSiOa + 6HF > SiF^ + CaF2 + SH.O b) Si02 + 2NaOH > NajSiOj + H2O Na2Si03 + CO2 + H2O )-Na2C0, + H2Si03. Bai 12. Bo tuc va hoan thanh cac phan iJng sau : Cacbon + HNO3 jsc > A + NO2 + HjO A + cacbon > B B + CI2 photgen HCOOH B + H2O B + O2 A A + NaOH >C + H20 C + Si02 > D + A D + A + H2O >C + E E Si02 + H2O. Gidi A:C02 B:CO C: Na2C03 D : Na2Si03 E : H2Si03 Photgen : COCI2. C + 4HNO3 JSC > CO2 + 4NO2 + 2H2O CO2 + C-A2CO CO + CI2 ^ COCI2 HCOOH "a^Q^dac^ CO + H2O 2C0 + 02-^ 2CO2 C02 + 2NaOH )• Na2C03 + H2O Na2C03 + Si02 Na2Si03 + CO2 Na2Si03 + CO2 + H2O >Na2C03 + H2Si03 H2Si03 Si02 + H2O. Dang 2. Nhcjn bi§'t, tach rdi, tinh chd' c6c chd't: CO, CO2, SiOa, muoi cacbonat BAI TAP MAU VA BAI T^P AP DyNG Bai 1. C6 ba khi gom CO, HCl va SO2 difng trong ba binh rieng bi$t. Trlnh bay phUdng phdp hoa hoc de phan bi$t tiTng khi. Viet c^c phiTdng trinh h6a hoc. Giai - Dan ba khi trdn Ian lifdt vao dung dich ntfdc voi trong dir. khi n^o tao kd't tua tr^ng la SO2, con lai la CO va HCl. SO2 + Ca(0H)2 > CaS03i + H2O - Cho quy tim am Ian liTcJt vao hai khi con lai, khi n^o lam cho quy tim am h6a do la HCl. Con lai la CO. 132 jgifAMfivnar ki 2. Trinh bay phifdng phap h6a hoc de tach rieng cac chat : AI2O3, SiOa, MgO ra khoi hon hdp ciia chung. Gidi Cho hon hdp ba oxit AI2O3, Si02 va MgO v^o dung dich axit HCl duf ta t^ch diidc SiOz khong tan c6n lai dung dich gom AICI3, MgCh va HCl dU. AI2O3 + 6HC1 > 2AICI3 + 3H2O MgO + 2HC1 > MgClj + H2O _ Cho dung djch NaOH diT vao dung dich thu diTdc ta tach diTcJc Mg(0H)2 va dung dich g6m NaA102, NaCl, NaOH duf, sau do lay Mg(OH)2 dem nung ta diTdc MgO. AlCl3 + 3NaOH > 3NaCl + Al(0H)3i Al(OH)3 + NaOH > NaAIO2 + 2H2O MgCl2 + 2NaOH > 2NaCl + Mg(OH)24' Mg(OH)2 MgO + H2O - Thdi CO2 v^o dung dich thu dmc ta difdc ket tua A1(0H)3 sau do dem nung ra thu diTdc AI2O3. CO2 + NaA102 + 2H2O > NaHCOj + Al(OH)34' 2Al(OH)3 AI2O3 + 3H2O. Bai 3. a) Lam the n£lo de loai hdi nirdc va khi CO2 c6 Ian trong khi CO? Viet cac phU'dng trinh hoa hoc. b) Hay phan biet khi CO va khi H2 b^ng phiTdng phap hoa hoc. Viet phiTdng trinh hoa hoc cua phan itng de minh hoa. Gidi a) Dan hon hdp khi qua nuTdc v6i trong thi khi CO2 bi giff lai CO2 + Ca(0H)2 > CaC03>l + H2O Tiep tuc cho hon hdp khi con lai di qua H2SO4 dam dSc thi H2O bi giff lai c5n CO thi khong, do do thu dffdc CO tinh khiet. b) Cho hai khi Ian Iffdt dem dot chay, sau do dan san pham di qua nffdc voi trong dir, thay nifdc voi trong hoa due thi khi ban dau la CO, con lai la khi hidro. 2CO + 02-^ 2CO2 2H2 + 02-^ 2H2O CO2 + Ca(OH)2 > CaCOji + H2O. Bai 4. Co mpt hon hdp khi gom cacbon dioxit va Iffu huj'nh dioxit. Trinh bay phifdng phdp hoa hoc de chffng minh sif c6 mat cua moi khi trong hon hdp. 133 Phan dgng va phuong ph^p giSi H6a hpc 11 VP co - D5 Xuan Hung Gidi Dan h§n hcJp hai khi CO2 SO2 di qua dung dich brom c6 miu da cam, thS'y khi nao l^m cho dung dich brom mat mau d6 la SO2. SO2 + Br2 + 2H2O > H2SO4 + 2HBr Dan khi c6n lai qua dung djch midc voi trong dif thay xua't hien ket tua thi do la CO2. CO2 + Ca(OH)2 > CaCOji + H2O. Bai 5. L^m the nSo de tach rieng tCfng khi CO va CO2 ra khoi hon hcJp cfia chung : a) Bing phiTdng phdp v$t li. b) B^ng phiTdng phdp hoa hoc. Gidi a) B^ng phiTdng phap vat li: Ncn hon hcfp hai khi di/di dp suat cao, khi CO2 se hoa long diTcJc iich ra ta thu dtfcfc CO2, khi con lai 1^ CO. b) B^ng phiTdng phdp h6a hoc : - Dan hon hdp hai khi di qua dung djch Ca(0H)2 AM, khi CO2 bi gii? lai vl tao kct tiia, c6n lai la khi CO. CO2 + Ca(OH)2 > CaCOji + H2O - Loc lay ket tua cho tdc dung vdi dung dich HCl thu dufdc khi CO2 bay ra. CaCOj + 2HC1 > CaClj + CO2T + H2O. Bai 6, B^ng phtfdng phap nao c6 the nhan ra cdc cha't tin sau day : Na2C03, MgCOj, BaCOj. (Trich TSDH Y Dmc TP.HCM) Giai * Cho niTdc Ian liTdt vao ba mau cha't r^n. - Mau nao tan la Na2C03. - Hai mau con lai khong tan la MgCOs va BaCOa. * Cho dung dich H2SO4 loang Ian liTdt v^o hai mau c6n lai BaCOs va MgCOj. - Mau nao tao ket tua tr^ng v^ c6 khi bay len 1^ BaCOa. BaCO, + H2SO4 > BaS04i + COjt + H.O - Mau CO khi bay len la MgCOj. MgCOj + H2SO4 > MgS04 + CO2T + H2O. B^i 7. a) PhSn biet cdc khi H2S, SO2. CO2 bkng phiTdng phdp hoa hoc Vieft cdc phifdng trinh phan drng tifdng thig. b) Tinh che CO2 c6 Ian mOt it SO2 v^ H2. Vid't cdc phifdng trlnh phan uTng xay ra. (Trich DHMii TP.HCM) 134 Giai ) Dan ba khi lln Itfdt v^o dung djch Pb(N03)2. Khi nko tao ket tua den la H2S. Con lai la CO2 va SO2. H2S + Pb(N03)2 > PbSi + 2HNO3 Dan hai khi con lai Ian Itfdt qua dung dich brom, khi nao lam ma't mau dung dich brom ^ SO2, c6n lai 1^ CO2. SO2 + Br2 + 2H2O > H2SO4 + 2HBr b) Cho hon hdp khi v^o dung djch niTdc brom diT loai di/dc SO2, sau do dan hon hdp khi con lai di qua dung dich ni/dc voi trong ta thu difdc kct tua, cho kct tun tac dung vdi dung dich HCl thu diTdc CO2 tinh khiet. SO2 + Br2 + 2H2O > H2SO4 + 2HBr CO2 + Ca(OH)2 > CaC03i + H2O CaC03 + 2HC1 > CaCl2 + C02t + H2O. Bai 8. Chi c6 nufdc va khi cacbonic c6 the phan biet difdc nam chat bot trang sau day hay khong : Na2S04, BaC03, NaCl, Na2C03, BaS04. Ncu diTdc hiiy trinh bay each phan biet. ; , Gi&i * Cho nirdc Ian liTdt vao ndm mau diTng nam chat hot trcn. - Mau nao tan la : NaCl, Na2S04, NajCO,. - Mau khong tan la BaC03 v^ BaS04. * Thoi khi CO2 vao hai mau thuf khong tan. - Mau nao tan tao thanh dung dich la BaCOj. - Mau nao khong tan la BaS04. BaC03 + CO2 + H2O > Ba(HCO, )- * Lay dung dich thu diTdc d tren cho vao ba mau tan, mau nao tao ket tua la Na2S04 va Na2C03, c6n lai la NaCl Na2S04 + Ba(HC03)2 > ^aSO^i + 2NaHC03 Na2C03 + Ba(HC03)2 > BaCOji + 2NaHC0, * Loc lay ket tua thu difdc, sau do thoi khi CO2 v^ cho ntfdc vao, kcl lOa nao tan la BaCOs -> mau ban dau la Na2C03, mau con lai la Na2S04. Bai 9. Cho dung djch A c6 chtfa cac ion: Na*. NH^', HCO3. SO; , CO^ (khong k^ cdc ion H* v^ OH' cua H2O) chi c6 quy tim vS cdc dung dich HCl. Ba(OH)2 c6 the nhan bie't di/dc cdc ion nao trong dung djch A? (Trich DH Nfiocii Tliunna) Giai Chi CO quy tim vi cdc dung dich HCl, dung dich Ba(OH)2 thi nhan biet difdc 13? Phan dgng phiiong phap glii H6a hqc 11 VP cd - D8 Xuan Hang cdcion: NH+, HCO", SO^", COl~, c6n lai Na^ khong nhan biet dtfcJc . HCl—>H* + cr Ba(OH)2 >Ba'* + 20H- * + HCOJ > C02t + H2O * Ba^* + CO^ > BaC03^ Ba^^ + SO^ > BaS04i * NH; + OH- > NHjt + H2O BaCOj + 2HC1 > BaCh + CO2T + H2O Ba(0H)2 + CO2 > BaCOji + H2O. Bai 10. Co bon lo ma't nhan, moi lo di/ng mot trong cac dung djch sau : NaHCOj, Na2S04, Ba(HC03)2 va Mg(HC03)2. Hay trinh bay each nhan biet tiTng lo, chi dU'Oc dung thdm each dun nong. Gidi * Trich moi lo mot it dc lam mau thiir. * Dem dun nong tifng mau thuT. Hai mau tao ket tua va c6 khi bay ra la Ba(HC03)2 va Mg(HC03)2, ton lai la NaHCOj va Na2S04. Mg(HC03)2 MgC03 + COjt + H2O Ba(HC03)2 BaC03 + C02t + H2O * Lay v^i giot dung dich mot trong hai Ip vuTa tao ket tua cho vao hai dung djch e6n lai thay mau nao tao ket tua tr^ng thi mau thilr nho vao la Ba(HC03)2, mau c6n lai la Mg(HC03)2 ta biet diTdc ong diTng Na2S04. Con lai la NaHCOj. Ba(HC03)2 + Na2S04 > BaS04i + 2NaHC03. Dang 3. Bai t^p ve tinh chdt CO2, mudi cacbonat LiAi y : Tinh cha't CO2 tac dung vdi dung dich kiem : * CO2 phan urng vdi dung dich NaOH (dung djch KOH ) C02 + NaOH >NaHC03 (1) CO2 + 2NaOH > Na2C03 + H2O (2) De xac dinh muo'i tao thinh, phai lap ti le so moi NaOH va CO2 (NaHCOj) 1 < ^^^^ < 2 (NnjCOd "C02 (NaHCOj v^ Na2C03) * CO2 phan urng vdi Ca(OH)2 hay Ba(OH)2: CO2 + Ca(OH)2 > CaC034' + H2O (1) 2CO2 + Ca(OH)2 y Ca(HC03)2 (2) (CaCOj) 1 < -^^^ < 2 (Ca(HC03)2) 'lCa(0H)2 (CaC03 va Ca(HC03)2) Neu nco2 > T^k^t tua ^^i xay ra ck hai phan tfng (1) v^ (2). BAI TAP MAU Bai 1. Cho 224ml khi CO2 (dktc) hap thu het trong 100ml dung dich KOH 0,2M. Tinh khoi li/dng cua nhiifng cha't eo trong dung dich tao thanh. Gidi n^o^ =^^1:^ = 0.01 (moi); n^oH = 0,2.0,1 = 0,02 (moi) 22,4 Ta c6 ti 16 : = — = 2 thu di/dc muoi K2CO3. • nco, 0.01 CO2 + 2K0H > K2CO3 + H2O 0,01 moi 0,01 moi mK.co, =0,01.138 = 1,38 (g). Bai 2. Cho mot coc ni/dc c6 chufa cac ion : Na* (a moi); CI" (b moi); CO3" (c moi); NH+ (d moi) va HCOJ (e moi). a) Tim bieu thufc lien he givta a, b, c, d, e. b) Viet cong thuTc tinh tdng khoi liTdng mu6'i trong dung dich. Gidi a) Ap dung dinh luat bao to^n di^n tich ta c6: a + d = b + 2c + e b) Cong thuTc tinh tdng khoi lifdng mudi: m„.,i = m^^, + m^, + m^^_ + m^^, + m^^^. , m^ufl-i = 23a + 35,5b + 60c + 18d + 61e. I Bai 3. Dan khi CO2 dieu che dUdc b^ng each cho 50g da voi tac dung vdi axit HCl du" di qua dung dich c6 chiira 32g natri hidroxit. Tinh khoi liTdng mudi thu diTdc trong dung djch. Gidi "caco, = ^ = (mol); n,,oH = ^ = ^'^ (moi) 137 Phan d^ng vk phuong phip giai H6a hpc 11 V6 co - 05 Xuan Himg CaCOj + 2HC1 0,5 mol CaClz + COat + HjO 0,5 mol Tacotile: 1< i^ = M = i,6<2 0,5 • thu diTdc hai muoi NaHCOj va NazCOs. C02 + NaOH ).NaHC03 XX X (mol) CO2 + 2NaOH > Na2C03 + H2O y 2y y (mol) Ta CO he phuTdng trinh : x = 0,2 y = o,3 (mol) x + y = 0,5 x + 2y = 0,8 mNaHco, =84.0,2 = 16,8(g); mr,,^co, = 106.0,3 = 31,8 (g). Bai 4. Nung 52,65g CaCOj d 1000"C va cho loan bo liTcJng khi thodt ra hap thu het vao 500ml dung dich NaOH 1,8M. Hoi thu drfdc nhffng mu^i nao? khoi lufdng Ih bao nhieu? Biel rang hieu suat cua phan tfng nhiet phan CaCOj la 95%. Giai -I^^^^CaO + C02t 0,5265 mol CaCOj 0,5265 mol 52,65 n CaCO, 100 = 0,5265 mol Hi^u suat phan lirng 95% : "co2 =^.0,5265 = 0,5 (mol) lUU nNaOH= 1,8.0,5 = 0,9 (mol) Tac6til?: 1 < ilNii2H. = M = l,8<2 ncoj 0,5 =>thu difdc hai muoi NaHCOs \h Na2C03. CO2 + NaOH >NaHC03 a a a CO2 + 2NaOH > Na2C03 + H2O b 2b b a + b = 0,5 Ta CO h$ phifttng trtnh : a + 2b = 0,9 a = 0,1 b = 0,4 (mol) mNaHco, =84.0,1 = 8,4 (g); mN.^cp, =106.0,4 = 42,4 (g). 138 ai 5. Dan 2,36 lit CO2 (15"C 2 atm) qua 40ml dung djch Ba(OH)2 2M. Muoi sinh ra la muoi gi? Tinh nong dp mol cua dung dich muo'i thu duTdc (biet the tich dung dich khong thay doi). Gidi PV 2.2,36 nco2 = — -• = 0,2 (mol) 2,5 > 2 => thu dircfc muo'i Ba(HC03)2. RT 0,082.(15 + 273) nBa(OH), =0,04.2 = 0,08 (mol) Tacotile: J^ = -^ = "Ba(OH)2 0,08 . 2CO2 + Ba(OH)2 >Ba(HC03)2 0,08 mol 0,08 mol N6ng dp mol cua Ba(HC03)2: CM= ^ = ^ = 2 (M). Bai 6. Nung m gam hon hcfp X gom hai muoi cacbonat trung tinh ctia hai kim loai A, B deu c6 hoa tri 2. Sau mot thcfi gian thu diTdc 3,36 lit CO2 (dktc) \h con lai hon hdp r^n Y. Cho Y tac dung vdi dung djch HCI dit roi cho khi thoat ra hap thu hoan toan bdi dung dich Ca(0H)2 di^, thu diTdc 15 gam ket tua. Phan dung djch dem c6 can thu dtfcJc 32,5 gam hon hdp muoi khan. Vie't cac phiTcJng trinh phan iJng va tinh m? (Trich TS DHQG TP. HCM) Gidi Dat cong thiJc cua hai muoi cacbonat \h ACO3 va BCO3. ACO3 —^ AO + C02t BCO3 —^ BO + C02t 3,36 = 0,15 (mol) "CO2-224 Cho Y + dung dich HCI: A0 + 2HC1 >ACl2 + H20 B0 + 2HC1 >BCl2 + H20 ACO3 + 2HC1 > ACI2 + COzt + H2O BCO3 + 2HC1 > BCI2 + COzt + H2O C02 + Ca(OH)2 > CaCOji + HzO 0,15 mol 0,15 mol 'CaCO, 15 100 = 0,15 (mol) 139 [...]... : FejC + 22HN03d^c > 3Fe(N 03) 3 + BNOzt + COzt + + dd A : Fe(N 03) 3; hon hdp khi B: | [CO2 Fe(N 03) 3 + 3NaOH + ket tua A, : Fc(0H )3 > Fe(OH )3> l' + SNaNOj + 2NaOH > NaNOz + NaN 03 + H 2 O CO2 + 2NaOH > NazCOj + H2O NaNOj + hon hdp B| : NaNO, Na^CO, 2NO2 2Fc(OH )3 NaNOi Fe2 03 + SHjO NaN02+ - O 2 T + oxil A 2 : Fe2 03; hon hdp B j : NaNOj Na^COj FejOj + 3C0 > 3 C O 2 + 2Fe 3Fe2 03 + CO — > 2Fe304 + CO2 FciOi... Ca(0H)2 C a C O j i + H2O HCO3- + 0.2 0 ,3 0,2 =^ Encoj = 0.4 + 0.2 = 0.6 mol Theo phan drng (1): np,.co3 > COi^- + H2O 0 ,3 Ba 2+ Ca(HC 03) 2 OH- C 03^ - BaC03i 0 ,3 0 ,3 2+ + S04^" -> B a S 0 4 i Ba 0,1 "coj = 0.6 mol 0,1 m^ = 0 ,3. 197 + 233 .0,1 = 82.4 (g) =!> % F e C 0 3 trong quSng xiderit = ^ ^ ^ ^ 1 0 0 % = 60% 116 BAI TAP AP DUNG Bai 15 TrOn 100ml dung dich A g6m K H C O 3 I M va K2CO3 I M v£lo 100 ml dung... bieu dien sd do chuyen h6a 3 Fe304 + CO > CO2 a) C > CO > FejOi > Fe(N 03) 3 b) CO2 > NuiCOi > Na2Si 03 > HaSiOj c) CO2 > CaC 03 > Ca(HC 03) 2 > CO2 > SiOz / SiF4 > K2Si 03 > K2CO3 > FezOj >C 6 CO2 diT + Ba(0H)2 > 8 C + S >? > > )-?+? + H20 10 Na2SiO3 +? + H2O > KCl >? + NazCOj Bai 9 Khi nung 97,7 gam hon hdp X gom NH4HCO3, NaHC 03 v^ Ca(HC 03) 2 den khoi li/dng khong doi thu difdc 32 ,4 gam chat r^n Y Cho cha't... d?ng vi phuing ph^p giai H6a h^c 11 VP CO - D5 Xuan Hung Yl^co^ = 0,15 + 0,15 = 0 ,3 (mol) Ta CO tdng so mol C O 2 : "co?- Ta thay: 1 < "coj = 0 , 3 (mol); n^|_ = 0 , 3 (mol) X = 32 ,5 - m^ = 32 ,5 - 0 ,3. 2 .35 ,5 = 11, 2 (g) =>[Ba(HC 03) 2]= ^ 0,02M thu duTdc 1 gam ket tua Hay xdc dinh % theo the tich cua CO2 trong 0,125 nen xay ra hai triTdng hdp : CO2 + BaCOj + H2O -> Ba(HC 03) 2 %Vcoj = ^ ^ ^ 1 0 0 % = 2,24%... 100ml dung dich Ba(0H)2 0,5M Tinh khSl Thinh phin % NaHCOj trong h5n hdp: %NaHC 03 = "'^^'^'^•100% = 37 ,28% 33 ,8 Bai 4 MOt hSn h . FejC + 22HN03d^c > 3Fe(N 03) 3 + BNOzt + COzt + 1IH2O + dd A : Fe(N 03) 3; hon hdp khi B: | [CO2 Fe(N 03) 3 + 3NaOH > Fe(OH )3& gt;l' + SNaNOj + ket tua A, : Fc(0H )3 2NO2 +. O2). N2 + 3H2 , • 2NH3 p CO2 + NH3 + H2O > NH4HCO3 b) NH4HCO3 + NH3 > (NH4)2C 03 c) (NH4)2C 03 + 2NaOH > NazCOj + 2NH3 + 2H2O hoac C02 + 2NaOH >Na2C 03 + H20 du" vao dung dich E: HCO3- + OH- 0 ,3 Ba 2+ C 03^ - Ba > COi^- + H2O 0 ,3 BaC03i 0 ,3 0 ,3 + S04^" -> BaS04i 0,1 0,1 m^ = 0 ,3. 197 + 233 .0,1 = 82.4 (g) 2+ Dap an

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