ĐỀ LUYỆN THI ĐẠI HỌC SỐ 1 MÔN VẬT LÝ !"#!$%%%%%%%%%%%%&'%%%%(( Câu 1:)"*+, /0--1234"45$678 9 : ;<$=π>π?@9 A ;<$π=?@9 < ;A$=π>π?@9 / ;A$π=?( BC98-D0 -EF"*( A. 9;G$=> B. ?AH$=AG ππ += tx C. ?AH$=G ππ += tx D. ?/H$=G ππ −= tx Câu 2:&+92I,52".$20,FJ#K A. ,FL9J8$8( B. ,F8$8( C. ,FM9J8$8( D. ,F8$N8$8( Câu 3:O$8không7PI$2 A. Q72C1RLS( B. Q7T2C1S"*I( C. Q7UF( D. Q7"*6V"SJ( Câu 4:8T2sai"1-W-TX2E"J82C#67!L82( A. Y82"118"JX2E( B. Y82"12$N8"J( C. Y82"1-$8Z-6[8"J( D. Y82"1$6F"J( Câu 5: ,FX2-,,F A. M7L\6#L]80^LD]2$8( B. _L\1WLJLD]2$8( C. M7L\LJ`8-67( D. M7L\80^`8N8( Câu 6:JJaQ7-,b25c20RC25M"d-,N6]('-T#aQ "V2 a' ;$:π=e?"2 'Q ;$=:πf?=e?(T2_,2-,]2 aQ ( A. aQ 2 A A $=: ?e= π B. aQ 2 A $ : e < π = π + ÷ C. aQ 2 A$ : e < π = π + ÷ D. aQ 2 A$ : e < π = π − ÷ Câu 7:8T2-L7"1-LS < A. LS <-F$g0dB80dd-( B. hS*-TJiX2C( C. e*67S\"*67iX2C( D. &.20RC-W,27 ( Câu 8:Q2.L]F& : c& A 6,282G(&702.CJ7V$7 A(#& : & A X2$8-F$6+-J A. j B. C. G D. < Câu 9:Q03-,75$6k;G lX2-JJhmQLSR8c04n8L]-S$2I JICS$2I78D+-J(-,02d-,c]-+M20RCm; :Hπ= ? A. Q≈<c:/(: fG o( B. Q≈:cG(: fG o C. Q≈pc<p(: fG o D. Q≈c/A(: fG o Câu 10:)N390--123"V#-p"2L:$(J;c"*-X2"DPR` 12RdJ-(EX2B---F"*LMAc<jG$LTi-T -F!6 A. /q B. jpcGG C. GGcjp D. GpcjG Câu 11:PI$2-RCkhôngMr A. P-R92C#J( B. r2C#X28I0Cs( C. RC,FX2-,( D. tS7LSLP( Câu 12:)"*0--123"V5$6`G l(NI-T"*-i"DP7-9 : ;f cGa=a#-0-?-]"DP7-9 A ;>cGa A. :H:$( B. :$( C. :HA$( D. :H<$( Câu 13:8F$2-RCF7T9MC,FX2-,KY8$8)W ]2" A. WV( B. W$R8J( C. ILJLS$( D. 8RC( Câu 14:8C8-,9C12 A. -TM6-X2CSU$620RC"M$6W+( B. -TM6-X2CSU$620RC C. -TM6-X2CSM$620RC"M$6W+( D. -TM6-X2CSU$6W+( Câu 15:8T2$L7"18C]] A. YM$6"30RCb2_Ic-03-,2_IM( B. )26MP#-0RCM-,cM048CU]-TU,2-,]( C. YJ_Ibc8C]]9LS#2d-,U( D. YU$6"30RCb2_Ic,2-,][-522_IU( Câu 16:&2Ac-79J^2I79JM/5(Q2L8BI79J A. :( B. :cG( C. A( D. <( Câu 17:-JJhmQLSR8c-,[-5220RC"-52b25h LST` A. πH/ B. πHA C. πH:A D. <πH/ Câu 18:)-JJhcmcQN6](Q20RC25M(!u h cu mc u Q ,2-,]+-Jb -52-,bc-5220RC"-52d-,(']u m ;Au h ;Au C. Y]2*0V-RC"1-, [03-,",2-,][-52J-,- A. 2*7vH/ B. 2$V7<vH/ C. 2*7vH< D. 2$V7vH/ Câu 19: ,F8$8$+L]F$78$8\B-12L, A. Q4"4#-( B. Q45$6"-,LS-E( C. Q45$6"4-12L,]2$8( D. Q45$6"4#-( Câu 20:&7o)]7e,w75$6:) l(V$7( A. G B. < C. :( D. :( Câu 21:Q!PIkhông-L7"1J0-mQ A. wUF-,*2bd-,Q( B. wUF-,"UFi4]#255$62( C. -JmQ0-+0"UF-,"i]#X2J"V 2( D. wUFi*2b2Mm( Câu 22:P,"18$8xfRcL$882cq(YM8i L-]Ac-$N]2"L7V$7λ;cp/µ(eR$8*/"*p=4 P$"V"RP[?82-J A. <cA( B. :cp( C. pc/( D. /cq( Câu 23:yM_,J A : > A : → < A > : ><cAG=)e?(']-dL6 A : ∆ ; cA/2":2;<:=)e?(wUF#L]J < A A. qcGA=)e? B. cA/=)e? C. jcjA=)e? D. GcAA=)e? Câu 24:QN39z-_c397L6FLS-8LT( 3-b"DPR` -FL{9260Vz-_-J<.M70-( 3+,G 0-IA$(Q; A π ;:H$ A (Z$6-V+-.+-J"+-.+T239L 0- A. G B. / C. j D. < Câu 25:|$N-WP$PR{R,-FR A. 74-8bJdL82( B. 745$68bJdL82( C. 74#-8bJdL82( D. 74#--F8b4JdJ-TL82( Câu 26:&2:UcL6FI79JM-<5( \$2AUcL6FI79J# M-#25$"V-52( A. 5( B. p5( C. :A5( D. /cG5 Câu 27:&+0--,i+0J0-0,F A. i7( B. +M( C. b-,( D. M_-,i( Câu 28:QJN8JRmc$2M_2-FJ62(yM_C\ C2UF#2KQ] ;:cj<2@ 9 ;/c:G2(" m ;jc://2( A. yM_\UF:G)e( B. yM_2UF:jc/:)e( C. yM_2UF:G)e( (yM_\UF:jc/:)e Câu 29:W"-52J-,hmQ6],2-,]9C1278D,20dLS-E ,2-,],20d#85ghcmc"Q-12`2"`Ae(YdD6N,2 -D,],20d-52-,b` A. < A e B. : A e C. Ae D. :e Câu 30:)JR7L6F;GcpjG(: fAj L-2CT-"V-U/cjq)e( FJR A. <cqjG(: fA L(H$ B. jcjG(: fA L(H$( C. Ac/(: fA L(H$( D. qcq(: fA L(H$( Câu 31:)"*7L6F0--123"V#-a(Y2LU<5UF "*C-E]K A. M<5(B. U5(C. M5D. U<5 Câu 32:)"*0--123c:+,-F<0-5(}2B-"* 02CTq$p/('#-0-"* A. < B. A C. / D. G Câu 33:)"*8.J"S92X2M7,- A. #: Q( B. ,-S( C. # Y( D. # Q( Câu 34: JR A: q/ y I79J( &2LRBcJR$7 a(q/":Ap( B. q":AA( C. qA":A/( D. qp":Aq( Câu 35:Q]2_9J7V$7λ;c/µ"]X2-,(QS8 LJa;Ae(8D,2-,]-W"-52"-T,#203X2 -,(Q;pcpAG(: f</ ~$";<(: q H$(:e;:cp(: f: ~ A. u aY ≤f:cAe( B. u aY ≤f:c/e( C. u aY ≤f:c:e( D. u aY ≤:cGe( Câu 36:Q03-,9C127-:cGa5$6G lX220RC25Mc7-+Mm; AHπ ( ,2-,]-520RC A. u;Ae( B. u;<e( C. u;<e( D. u;<Ae( Câu 37:Q]2"]X2-,8_9J7V$7λ;/"λ•;cAGµ IC"*6-52+-JX2-,I-S2(r8-DS8LJ (Q;pcpAG(: f</ ~$";<(: q H$( A. a;<cjG(: f: ~( B. a;Ac<qG(: f:q ~( C. a;GcpAG(: f: ~( D. a;:cqjG(: f: ~( Câu 38:W"-52-JJhmQLSR8,2-,]2;:$:π=e?03-, X2J;$:π=a?(Eb25-JJ A. h;GΩ( B. h;:Ω( C. h;AΩ( D. h;AΩ( Câu 39:J-,9C12LSR8c,2-,][-52-JJ"- 03-,J5F2;:$:π=e?";:$=:π>πH<?=a?(QS$2I#22 J A. AG€ B. AcG€ C. G€ D. G€ Câu 40:Q-JJhmQ6]c-720RC25Mm;:Hπ= ?@d-,7-,02Q;:p µo"b25h(W,2-,]9C125$6G l"-52-JJ(8Dh-TS $2IJ-J+-J( A. h;AΩ B. h;:Ω C. h;:Ω D. h;AΩ Câu 41:)0RC-.a'0p7-52'6-Dc-52aN"8R-0- "V5$6k;G l(YR2c#0RC7$70i"V<d$7(e*62C1$7#0RC A. ";:GH$( B. ";AqH$( C. ";AH$( D. ";AGH$( Câu 42:w2.$7bn0-"V5$6: lc0-2C1-"V"*6c/H$#nC( #C7A-Ty"}_+-7y};:G(Q#-;:"#-LSC-E L$72C1(w]2J-T-7y7-:-J} A. B. A C. : D. f: Câu 43:Q]2_9J7V$7λ;cGGAµ"VS$2Iy;:cA€"]X2-,c 03X2-,B37-t ;Aa(P,2$2IFg,FX2-,( Q;pcpAG(: f</ ~$@;<(: q H$c;:cp(: f: Q( A. c<j• B. c/AG• C. cGG• D. cpG• Câu 44:)"*0--123"V2L;<c:/$(r8-D0-"*L7X2"DP9; A"V"*6";c/H$( A. B. - / π 0 C. p π 0 D. < π 0 Câu 45:QN390-z-_c5#]NX2"DPR` A. -U`2c"*6`2( B. 6`2c-U`2( C. 6`2c"*6`2( D. IM-12-( Câu 46:QM_JR j < m A :jc<)e+ → α + (YJ-F: #UF\i M_##2KQw a ;pcA<(: A< f: ( A. :<cA(: A< )e( B. qcpq(: A< )e( C. Apc/(: A< )e( D. </cjA(: A< )e( Câu 47:#0RCa'0A7$70i7d$7c-52a6"V2.0-= $7?c-52'6-D(5$60-2.c]"*6$7#0RCAH$( A. AG l B. A l C. G l D. : l Câu 48:QN39."*W0V390c72L‚0-(w]239DNVg 2L‚0-NV A. A T ( B. A( C. ( D. A T ( Câu 49:J2$7"S2C]-12Z-,02dQ;:H/π=o?"-+M 20RCm;:cpHπ= ?(Y-7$72-F75$6#2KmICπ A ;:( A. G l( B. AG l( C. : l( D. A l( Câu 50:)8C8-,9C12NLT2$7,2-,]:Ae( ,2-, ]0RC` A. :pcje B. AjcqGe C. q/cqGe D. pcAqe = ƒ&tw Y „w…†Q&‡ˆw‰tmtŠuhnwY t t? ]]]]]]]]]]]]]]]]]]ư1 A 11 B 21 C 31 D 41 C 2 D 12 D 22 A 32 C 42 A 3 D 13 C 23 C 33 B 43 A 4 A 14 D 24 C 34 C 44 B 5 A 15 A 25 B 35 C 45 B 6 D 16 A 26 A 36 B 46 A 7 C 17 D 27 B 37 A 47 D 8 C 18 D 28 D 38 B 48 D 9 A 19 B 29 B 39 B 49 B 10 C 20 B 30 D 40 C 50 B . t? ]]]]]]]]]]]]]]]]]] 1 A 11 B 21 C 31 D 41 C 2 D 12 D 22 A 32 C 42 A 3 D 13 C 23 C 33 B 43 A 4 A 14 D 24 C 34 C 44 B 5 A 15 A 25 B 35 C 45 B 6 D 16 A 26 A 36 B 46 A 7 C 17 D 27 B 37 A 47 D 8 C 18 D 28 D. ĐỀ LUYỆN THI ĐẠI HỌC SỐ 1 MÔN VẬT LÝ !"#!$%%%%%%%%%%%%&'%%%%(( Câu 1: )"*+,. 4:8T2sai" ;1 -W-TX2E"J82C#67!L82( A. Y82" ;1 1 8"JX2E( B. Y82" ;1 2$N8"J( C. Y82" ;1 -$8Z-6[8"J( D. Y82" ;1 $6F"J( Câu