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RAW1#EB@G17 II Chương trình nâng caoE10 câu, từ câu 51 đến câu 60) Câu 51:<->9;(=#(1'3Z)*(d'%31k%+s=g9h(59I ->9;(=#(1'3Z)*( 1k%1_)-Z7>0 A. 7a7j)*(>9;( B. 1)*(41C. 7a7j>51 D. 7a7jd'" Câu 52:b*1#>g1>HR#(T7+s7A@PQI(+07*>HR#14)*1`(IAQ@z7s)%(M+N= 12![(P(9:-%='3q1#4+s 1!%)n'W@17zj#1-q'$9h(9h(=]$%#)*( 1k%+sS(>0 A. RAW-EB@w D π G17 B. RAW1#EB@G17 C. RAW1#EB@w W π G17 D. RAW1#EB@€ W π G17 Câu 53:b*!"Rj14)9:(Ie@17d'%3m(x+,-(-% 1(41Ia()r-B@%$z W <- :-)-Z7A@7*)-Z7J=+0Rj14#<)*(41ϕ @ ABPe=%$<-:-)-Z7AW(-% 1-UV '3U+0(-% 1V"V'3U1k%)-Z7J>0 A. WPe7z W {B@@7z W B. WPe7z W {e@7z W C. e7z W {B@@7z W D. @Pe7z W {B@@7z W Câu 54:&-1-U'%-!`1R<)hg114n “ B AWB@ Be ‘+0“ W ApB@ Be ‘+0#!q7S7*I-7 >#<-$X(>071% 1k%U!0#d'%()-/(9:-%_3† (-Y%+s 1!%)n'151)<-1k%1"1 d'%(j>j1=a!`=%Ii-1% >0![(Wn (-,-<1k%I-7>#<-)4>0 A. @PD•B@ BD ‘ B. BP‚eB@ BD ‘ C. BPQeB@ Be ‘ D. BPD•B@ Be ‘ Câu 55:="-)_Rj7(n)|(>0d'61n'd'%3)q'14!"IDp•@I7-% 19,(27<-7* )-Z7b=7S)_M+o)*D@ @ >0EB(03AOPDQB@ Q G A. @P•17z W B. •PB17z W C. BP•17z W D. BP•7z W Câu 56:-/11k%.)-/=#(7<1$%#)*(8!-U-j#V9h(=] dA? # 1#E W T π w π G<-:-)-Z7A Q T P%14 A. c(>9;()-/=9:(151)<- B. -/11k%.151)<- C. H()-/d'%1'*$23![(@ D. -/')-/U(-Y%%-!6.![(@ Câu 57:=#()#<7<18P7g1 --UV)%(R™3=%-/9;(1*(9M(c($nn $H()-/+0(-Y('31"1a( 1k%7<1PIU>'s0#%')23>0không đúng~ A. / 1a('_1k%)#<7<1(-67 B. 9:()*-/'$.(1k%$H()-/(-67 C. -/"V-/'$.(=.c( D. -/"V-/'$.(=)-/=M(-67 Câu 58:K-U)*(c(d'%31k%+sJ(_V! >n)*(c(d'%31k%+sKP1H7a7j)*( >9;(1k%+sJ![(7*Vn%-7a7j)*(>9;(1k%KK-U7a7jd'"1k%+sJ![( BI(7 W ]7a7jd'"1k%+sK![( A. @PeI(7 W B. BDI(7 W C. OI(7 W D. QI(7 W Câu 59:<2 WB@ Po >01_V4(R<V"=%-%Ž+0!-U)r-0<2!<-:-)-Z7P x>/(-Y% <21]+0 <#=#(7t'>0eP+s3<-:-)-Z703x>/I ->9;(<1]+0 I ->9;(<#>0 A. QP‚@e B. @PW@Q C. @PB‚D D. eP@‚• Câu 60:=#(1"1<11.*V)014"1$.( A. >07c()*1%#+0)*#1k%27 B. (-Y1#27V"=%14n r)N C. =")9;1<V27+0-U(T>071#-U()0=#(=˜# D. +m%I'3U1)<-27P+m%<#=%27g1=-(1k%27$#)0V"=% €€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€€ €€€€€€€€€€€œ€€€€€€€€€€ =%(Dz•€bv)q-BpW made dap an made dap an made dap an made dap an 132 BK 132 pBK 209 BK 209 pB 132 W 132 pW 209 WK 209 pW 132 pJ 132 ppK 209 p 209 ppK 132 Q 132 pQ 209 QJ 209 pQ 132 eK 132 pe 209 e 209 peK 132 DK 132 pD 209 DJ 209 pDJ 132 • 132 p• 209 •K 209 p• 132 OK 132 pOJ 209 O 209 pOJ 132 ‚K 132 p‚J 209 ‚ 209 p‚K 132 B@J 132 Q@J 209 B@ 209 Q@ 132 BB 132 QBJ 209 BBJ 209 QB 132 BWJ 132 QW 209 BWJ 209 QWK 132 BpK 132 QpK 209 Bp 209 QpK 132 BQJ 132 QQ 209 BQ 209 QQK 132 BeK 132 QeJ 209 BeK 209 QeK 132 BDJ 132 QDJ 209 BDJ 209 QD 132 B•J 132 Q•K 209 B• 209 Q• 132 BO 132 QO 209 BOK 209 QOJ 132 B‚K 132 Q‚ 209 B‚K 209 Q‚ 132 W@ 132 e@ 209 W@ 209 e@J 132 WBK 132 eB 209 WBK 209 eBJ 132 WW 132 eW 209 WWJ 209 eWK 132 Wp 132 epJ 209 Wp 209 epK 132 WQ 132 eQ 209 WQ 209 eQK 132 We 132 ee 209 WeK 209 eeJ 132 WDK 132 eD 209 WDK 209 eDK 132 W• 132 e• 209 W•J 209 e•J 132 WOK 132 eOK 209 WO 209 eO 132 W‚ 132 e‚J 209 W‚ 209 e‚ 132 p@ 132 D@ 209 p@K 209 D@J =%(•z•€bv)q-BpW . ĐỀ THI THỬ ĐẠI HOC, CAO ĐẲNG NĂM 2009 - LẦN II MÔN: Vật lí Thời gian làm bài: 90 phút . !%-%)iP+0(+0>.1Ia(>4=%Ii->c(I B. PHẦN RIÊNG CHO CÁC THÍ SINH Thí sinh chỉ được làm một trong hai chương trình sau I. Chương trình cơ bảnE10câu, từ câu 41 đến câu 50) Câu 41:S7*)-/"V'A– @ 1#—+,-—P– @ Ia()r-+0#%-)n')#<7<18Ia( V2"-/"V-/'$.(%-)n')-/=M'n>0O@P%-)n'1'*$23'n167>0BW@ +0%-)n'.)-/>0D@/. !"#$% Mã đề thi 132 A. PHẦN CHUNG CHO TẤT CẢ CÁC THÍ SINH (40 câu từ câu 1 đến câu 40) Câu 1:&'($%#)*(+,-.)-/+01'*$2314)*51678)%($%#)*(5$#(9:-%)# )9;1)-/1151)<-=7*!6.>0? @ AB@ CD EFG+0$H()-/151)<-=#(I'( @ AB@EJG K9,14()-/L1*(9M(+,-I'(14(-"=N A.