Bài giảng thiết kế đường ôtô 2 P6 doc

TRặèNG AI HOĩC BAẽCH KHOA N BM ặèNG T - ặèNG TP Hỡnh 13.12a. Toỏn xỏc nh ng sut ct am i vi nn t 7 E 1 E 2 = 5 1 0 1 5 2 0 2 5 3 0 4 0 5 0 4 0 0 3 0 0 2 0 0 10 0 46 44 42 38 36 34 32 28 26 24 22 18 16 14 12 7 5 p a m h / D 4 . 0 0 . 0 4 0 0 . 0 3 5 3 . 5 0 . 0 3 0 3 . 0 0 . 0 2 5 2 . 5 0 . 0 2 0 2 . 0 0 . 0 1 5 1 . 5 0 . 0 1 0 1 0 . 0 0 5 0 . 5 0 0 TS Phan Cao Th Thit k ng ụtụ (Phn 2) Trang: 30 TRặèNG AI HOĩC BAẽCH KHOA N BM ặèNG T - ặèNG TP TS Phan Cao Th Thit k ng ụtụ (Phn 2) Trang: 31 0 . 1 0 . 0 1 0 . 0 2 0 . 2 0 . 0 3 0 . 3 0 . 0 4 0 . 4 0 . 0 5 0 . 5 0 . 0 6 0 . 6 0 . 0 7 0 . 7 0 . 0 8 0 . 8 0 . 0 9 0 . 9 0 . 1 0 1 . 0 0 . 1 1 1 . 1 0 . 1 2 1 . 2 0 . 1 3 1 . 3 0 . 1 4 1 . 4 0 . 1 5 1 . 5 0 . 1 6 1 . 6 0 . 1 7 1 . 7 0 . 1 8 1 . 8 0 . 1 9 1 . 9 0 . 2 0 2 . 0 h / D a m p S ơ đ ồ t í n h t o á n E 1 E 2 , c , D p h 6 8 1 0 1 2 1 4 1 6 1 8 2 0 2 2 2 4 2 6 2 8 3 0 3 2 3 4 3 6 3 8 4 0 4 2 4 4 4 6 4 0 0 3 0 0 1 0 0 2 0 0 E 1 E 2 = 5 1 0 2 0 3 0 5 0 Hỗnh 13-16. Toaùn õọử xaùc õởnh ổùng suỏỳt cừt chuớ õọỹng am cuớa lồùp dổồùi hóỷ 2 lồùp khi caùc lồùp cuỡng laỡm vióỷc (Duỡng cho nóửn õỏỳt ) TRặèNG AI HOĩC BAẽCH KHOA N BM ặèNG T - ặèNG TP 0 . 1 0 0 . 2 0 . 4 0 . 5 0 . 6 0 . 7 0 . 8 0 . 9 1 . 0 1 . 1 1 . 2 1 . 3 1 . 4 1 . 5 1 . 6 1 . 7 1 . 8 1 . 9 2 . 0 0 . 0 0 2 0 . 0 0 4 0 . 0 0 6 0 . 0 0 8 0 . 0 1 0 0 . 0 1 2 0 . 0 1 4 0 . 0 1 6 0 . 0 1 8 0 . 0 2 0 0 . 0 2 2 0 . 0 2 4 0 . 0 2 6 0 . 0 2 8 0 . 0 3 0 0 . 0 3 2 0 . 0 3 4 0 . 0 3 6 0 . 0 3 8 0 . 0 4 0 46 0 4 4 0 4 2 0 = 4 0 0 3 8 0 3 6 0 3 4 0 3 2 0 3 0 0 = 2 0 . 3 h / D a m / p 0 E 2 E 1 3 5 7 1 0 2 0 2 5 3 0 1 5 Hỗnh 13-12. Toaùn õọử xaùc õởnh ổùng suỏỳt cừt chuớ õọỹng am cuớa lồùp dổồùi hóỷ 2 lồùp khi coù thóứ chuyóứn vở tổỷ do giổợa 2 lồùp (chi tióỳt cuớa toaùn õọử 9-14) TS Phan Cao Th Thit k ng ụtụ (Phn 2) Trang: 32 TRặèNG AI HOĩC BAẽCH KHOA N BM ặèNG T - ặèNG TP 0.03 0.02 0.01 0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 =5 0 =10 0 =13 0 =20 0 =30 0 =40 0 20 40 60 80 100 Chióửu daỡy mỷt õổồỡng h(cm) ab ab Hỗnh 13-12. Toaùn õọử xaùc õởnh ổùng suỏỳt cừt chuớ õọỹng am do tro ỹ n g lổồ ỹ n g baớn thỏn m ỷ t õổồỡn g g ỏ y r a TS Phan Cao Th Thit k ng ụtụ (Phn 2) Trang: 33 TRặèNG AI HOĩC BAẽCH KHOA N BM ặèNG T - ặèNG TP 0 . 1 0 . 2 0 . 3 0 . 4 0 . 5 0 . 6 0 . 7 0 . 8 0 . 9 h / D 0 0 . 2 0 . 4 0 . 6 0 . 8 1 . 0 1 . 2 1 . 4 1 . 6 1 . 8 a m / p 1 . 0 1 . 5 2 . 0 2 .5 3 . 0 3 . 5 4 5 6 8 = 1 0 E t b E c h m E 1 E 2 E 3 E c h m D E t b p h h 1 h 2 h 3 Hình 13-17. Toán đồ xác định ứn g suất cắt hoạt độn g lớn nhất trong lớp bêtông nhựa TS Phan Cao Th Thit k ng ụtụ (Phn 2) Trang: 34 TRặèNG AI HOĩC BAẽCH KHOA N BM ặèNG T - ặèNG TP E 3 E 2 E 1 h 1 E c h m D p = 1 E 0 E 1 /E c h m 1 . 5 2 2 . 5 3 4 5 7 8 1 0 1 2 1 5 2 0 3 0 5 0 1 0 0 0 0 . 1 0 . 2 0 . 3 0 . 4 0 . 5 0 . 6 0 . 7 0 . 8 0 . 9 1 . 0 h 1 /D 0 . 2 0 . 4 0 . 6 0 . 8 1 . 0 1 . 2 1 . 4 1 . 6 1 . 8 2 . 0 2 . 2 2 . 4 2 . 6 2 . 8 3 . 0 3 . 2 3 . 4 3 . 6 3 . 8 4 . 0 4 . 2 4 . 4 4 . 6 4 . 8 5 . 0 k u Hỗnh 13-13. Toaùn õọử xaùc õởnh ổùng suỏỳt keùo uọỳn õồn vở ku ồớ lồùp mỷt TS Phan Cao Th Thit k ng ụtụ (Phn 2) Trang: 35 . 0 . 1 0 . 0 1 0 . 0 2 0 . 2 0 . 0 3 0 . 3 0 . 0 4 0 . 4 0 . 0 5 0 . 5 0 . 0 6 0 . 6 0 . 0 7 0 . 7 0 . 0 8 0 . 8 0 . 0 9 0 . 9 0 . 1 0 1 . 0 0 . 1 1 1 . 1 0 . 1 2 1 . 2 0 . 1 3 1 . 3 0 . 1 4 1 . 4 0 . 1 5 1 . 5 0 . 1 6 1 . 6 0 . 1 7 1 . 7 0 . 1 8 1 . 8 0 . 1 9 1 . 9 0 . 2 0 2 . 0 h / D a m p S ơ đ ồ t í n h t o á n E 1 E 2 , c , D p h 6 8 1 0 1 2 1 4 1 6 1 8 2 0 2 2 2 4 2 6 2 8 3 0 3 2 3 4 3 6 3 8 4 0 4 2 4 4 4 6 4 0 0 3 0 0 1 0 0 2 0 0 E 1 E 2 = 5 1 0 2 0 3 0 5 0 Hỗnh. Hỡnh 13.12a. Toỏn xỏc nh ng sut ct am i vi nn t 7 E 1 E 2 = 5 1 0 1 5 2 0 2 5 3 0 4 0 5 0 4 0 0 3 0 0 2 0 0 10 0 46 44 42 38 36 34 32 28 26 24 22 18 16 14 12 7 5 p a m h / D 4 . 0 0 . 0 4 0 0 . 0 3 5 3 . 5 0 . 0 3 0 3 . 0 0 . 0 2 5 2 . 5 0 . 0 2 0 2 . 0 0 . 0 1 5 1 . 5 0 . 0 1 0 1 0 . 0 0 5 0 . 5 0 0 TS. 0 . 1 0 0 . 2 0 . 4 0 . 5 0 . 6 0 . 7 0 . 8 0 . 9 1 . 0 1 . 1 1 . 2 1 . 3 1 . 4 1 . 5 1 . 6 1 . 7 1 . 8 1 . 9 2 . 0 0 . 0 0 2 0 . 0 0 4 0 . 0 0 6 0 . 0 0 8 0 . 0 1 0 0 . 0 1 2 0 . 0 1 4 0 . 0 1 6 0 . 0 1 8 0 . 0 2 0 0 . 0 2 2 0 . 0 2 4 0 . 0 2 6 0 . 0 2 8 0 . 0 3 0 0 . 0 3 2 0 . 0 3 4 0 . 0 3 6 0 . 0 3 8 0 . 0 4 0 46 0 4 4 0 4 2 0 = 4 0 0 3 8 0 3 6 0 3 4 0 3 2 0 3 0 0 = 2 0 . 3 h / D a m / p 0 E 2 E 1 3 5 7 1 0 2 0 2 5 3 0 1 5