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Voltage division is a circuit analysis tool that is used to find the voltage drop across a single resistance from a collection of series-connected resistances when the volt-age drop acr

Trang 1

Summary

• Series resistors can be combined to obtain a single

equivalent resistance according to the equation

#eq = 2 * * = *1 + R 2 + • ' + **'

/ = 1

(See page 58.)

Parallel resistors can be combined to obtain a single

equivalent resistance according to the equation

— = 2 — = — + — + ••• +—•

^eq (=1 Ri Rl Rl Rk

When just two resistors are in parallel, the equation for

equivalent resistance can be simplified to give

Rp-n —

R[Rj

eq /?! + R 2

(See pages 59-60.)

• When voltage is divided between series resistors, as

shown in the figure, the voltage across each resistor can

be found according to the equations

v 2 =

(See page 61.)

Ri

Ri

Ri + R 2 s ' <

)

+

+

v 2 :

Ui

\Ri

When current is divided between parallel resistors, as

shown in the figure, the current through each resistor

can be found according to the equations

R-,

'2

Ri + R 2 V

Ri + Ri

(See page 63.)

Voltage division is a circuit analysis tool that is used to

find the voltage drop across a single resistance from a

collection of series-connected resistances when the volt-age drop across the collection is known:

Ri

R eq where Vj is the voltage drop across the resistance Rj

and v is the voltage drop across the series-connected

resistances whose equivalent resistance is i?eq (See page 65.)

Current division is a circuit analysis tool that is used to

find the current through a single resistance from a col-lection of parallel-connected resistances when the cur-rent into the collection is known:

Rcq

where /,- is the current through the resistance Rj and i is

the current into the parallel-connected resistances

whose equivalent resistance is R cq (See page 65.)

A voltmeter measures voltage and must be placed in

par-allel with the voltage being measured An ideal voltmeter has infinite internal resistance and thus does not alter the voltage being measured (See page 66.)

An ammeter measures current and must be placed in

series with the current being measured An ideal amme-ter has zero inamme-ternal resistance and thus does not alamme-ter the current being measured (See page 66.)

Digital meters and analog meters have internal

resist-ance, which influences the value of the circuit variable being measured Meters based on the d'Arsonval meter movement deliberately include internal resistance as a way to limit the current in the movement's coil (See page 67.)

The Wheatstone bridge circuit is used to make precise

measurements of a resistor's value using four resistors, a dc voltage source, and a galvanometer A Wheatstone bridge

is balanced when the resistors obey Eq 3.33, resulting in

a galvanometer reading of 0 A (See page 69.)

A circuit with three resistors connected in a A

configu-ration (or a IT configuconfigu-ration) can be transformed into an

equivalent circuit in which the three resistors are Y con-nected (or T concon-nected) The A-to-Y transformation is given by Eqs 3.44-3.46; the Y-to-A transformation is given by Eqs 3.47-3.49 (See page 72.)

Trang 2

Problems

Sections 3.1-3.2

3.1 For each of the circuits shown,

a) identify the resistors connected in series,

b) simplify the circuit by replacing the

series-connected resistors with equivalent resistors

3.2 For each of the circuits shown in Fig P3.2,

a) identify the resistors connected in parallel,

b) simplify the circuit by replacing the

parallel-connected resistors with equivalent resistors

3.3 Find the equivalent resistance seen by the source in

each of the circuits of Problem 3.1

3.4 Find the equivalent resistance seen by the source in each of the circuits of Problem 3.2

3.5 Find the equivalent resistance R a ^ for each of the

PSPICE circuits in Fig P3.5

MULTISIM

3.6 Find the equivalent resistance #at, for each of the

PSPICE c i r c u i t s in Fig P3.6

MULTISIM °

Figure P3.1

10V

6 0

>vw- 120

^ W v <

4 a:

(a)

9 0

7 0 : 3mA( f

200 mV

300 O

W V

500 O

Figure P3.2

60 V 1000¾ 25 0.¾ 22 O

(a)

©

2kO

50 mA t 10 kO

6kO

- ^ W v — i

9kO% 18 kO:

(b)

250 O

/ VW—r

(c)

Figure P3.5

10 O

:5 O f 2 0 O

6 0

b»—"vW-(a)

30 kO i 60 kO 1200 kO \ 50 kO

(b)

Figure P3.6

15 0

25 0

12 0

24 0

->vw-(a)

12()0 | 6 0 O | 2 0 O

7 0

- V W 5 0

b • 'vw

(b)

50 0

40 O

140

24 0

(c)

Trang 3

3.7 a) In the circuits in Fig P3.7(a)-(c), find the

equiv-alent resistance /?., h

MULTISIM u

b) For each circuit find the p o w e r delivered by the

source

3.8 a) Find t h e p o w e r dissipated in each resistor in the

circuit shown in Fie 3.9

MULTISIM °

b) Find the p o w e r delivered by the 120 V source

c) Show that the p o w e r delivered equals the p o w e r

dissipated

3.9 a) Show that the solution of the circuit in Fig 3.9

(see E x a m p l e 3.1) satisfies Kirchhoffs current

law at junctions x a n d y

b) Show that the solution of the circuit in Fig 3.9

satisfies Kirchhoffs voltage law a r o u n d every

closed loop

Sections 3.3-3.4

3.10 Find the p o w e r dissipated in the 5 ft resistor in the

PSPICE circuit in Fig P3.10

MULTISIM ^

Figure P3.10

PSPICE

MULTISIM

3.11 For the circuit in Fig P3.11 calculate

PSPICE

MULTISIM a ) V (> nd l a

b) the p o w e r dissipated in the 6 ft resistor

c) the p o w e r d e v e l o p e d by the current source

Figure P3.ll

3.12 a) Find an expression for the equivalent resistance

of two resistors of value R in series

b) Find an expression for the equivalent resistance

of n resistors of value R in series

c) Using the results of (a), design a resistive net-work with an equivalent resistance of 3 kft using two resistors with the same value from A p p e n d i x

H d) Using the results of (b), design a resistive

net-w o r k net-with an equivalent resistance of 4 kft using

a m i n i m u m n u m b e r of identical resistors from

A p p e n d i x H

3.13 a) Find an expression for the equivalent resistance

of two resistors of value R in parallel

b) Find an expression for the equivalent resistance

of n resistors of value R in parallel

c) Using the results of (a), design a resistive

net-w o r k net-with an equivalent resistance of 5 kft using two resistors with the s a m e value from

A p p e n d i x H d) Using the results of (b), design a resistive net-work with an equivalent resistance of 4 kft using

a m i n i m u m n u m b e r of identical resistors from

A p p e n d i x H

3.14 In the voltage-divider circuit shown in Fig P3.14, the

PSPICE no - l o a d value of vn is 4 V W h e n the load resistance

MULTISIM , , , , , , ,

R L is attached across the terminals a and b, v() drops

t o 3 V Find RL

Figure P3.14

20 V

40 ft

Figure P3.7

15 V

6ft

b 2ft

i5 A 60 ft

5.6 ft

A/W-12 ft

(c)

Trang 4

DESIGN

PROBLEM

PSPICE

HULTISIM

3.15 a) Calculate the no-load voltage v„ for the

voltage-divider circuit shown in Fig P3.15

b) Calculate the power dissipated in Rx and R2

c) Assume that only 0.5 W resistors are available

The no-load voltage is to be the same as in (a)

Specify the smallest ohmic values of R] and R2

Figure P3.15

DE5IGN

PROBLEM

PSPICE

MULTISIM

/?i|4.7kfi

160 V ©

/?2<3.3kfl v„

3.16 The no-load voltage in the voltage-divider circuit

shown in Fig P3.16 is 8 V The smallest load resistor

that is ever connected to the divider is 3.6 kfl When

the divider is loaded, v() is not to drop below 7.5 V

a) Design the divider circuit to meet the

specifica-tions just mentioned Specify the numerical values

of /?, and R2

b) Assume the power ratings of commercially

available resistors are 1/16,1/8,1/4,1, and 2 W

What power rating would you specify?

Figure P3.16

40 V

3.17 Assume the voltage divider in Fig P3.16 has been

constructed from 1 W resistors What is the smallest

resistor from Appendix H that can be used as R L

before one of the resistors in the divider is

operat-ing at its dissipation limit?

3.18 Specify the resistors in the circuit in Fig P3.18 to

PROBLEM meet the following design criteria:

i H = 1 mA; vg = 1 V; iY = 2i 2 ;

i 2 = 2i3; and i3 = 2iA

Figure P3.18

3.19

PSPICE

a) The voltage divider in Fig P3.19(a) is loaded

with the voltage divider shown in Fig P3.19(b);

that is, a is connected to a', and b is connected to

b' Find vlt

b) Now assume the voltage divider in Fig P3.19(b)

is connected to the voltage divider in Fig P3.19(a) by means of a current-controlled

voltage source as shown in Fig P3.19(c) Find va

c) What effect does adding the dependent-voltage source have on the operation of the voltage divider that is connected to the 380 V source?

Figure P3.19

75 kn

380 V 25 kO

- • b

40 kO a'o vw f •

60kft:

b'<

(a)

75 kil

(b)

40 kn

^vw—

380 V 25 kH > 25,000/ 60 kn:

3.20 There is often a need to produce more than one

PROBLEM voltage using a voltage divider For example, the memory components of many personal computers require voltages of —12 V, 5 V, and +12 V, all with respect to a common reference terminal Select the

values of R],R 2 , and /?3 in the circuit in Fig P3.20 to meet the following design requirements:

a) The total power supplied to the divider circuit

by the 24 V source is 80 W when the divider is unloaded

b) The three voltages, all measured with respect to

the common reference terminal, are V\ = 12 V,

v 2 = 5 V, and v$ ~ - 1 2 V

Figure P3.20

24 V ©

'ih

/?,;

-• Common

* , :

3.21

PSPICE

MULTISIM

»3

a) Show that the current in the kth branch of the

circuit in Fig P3.21(a) is equal to the source current

i s times the conductance of the kth branch divided

by the sum of the conductances, that is,

h

ipk

G t + G 2 + G 3 + • • • + G k + • • • + G>

Trang 5

b) Use the result derived in (a) to calculate the

cur-rent in the 5 0 resistor in the circuit in

Fig.P3.21(b)

Figure P3.21

(a)

0.5 a ^5 o f 8 a f io ft ^20 a ^ 40 a

L

(b)

3.22 A voltage divider like that in Fig 3.13 is to be

PROBLEM designed so that v0 = kv s at no load (RL = oo) and

v 0 = avs at full load (RL = Ra ) Note that by

defini-tion a < k < 1

a) Show that

and

_ k - a

R\ - — ; K

ak

b) Specify the numerical values of R[ and R2 if

k = 0.85, a = 0.80, and R 0 = 34 kO

c) If v s = 60 V, specify the maximum power that

will be dissipated in R\ and R 2

d) Assume the load resistor is accidentally short

circuited How much power is dissipated in Rx

and /?2?

3.24 Look at the circuit in Fig P3.2(b)

a) Use current division to find the current flowing from top to bottom in the 10 kfi resistor b) Using your result from (a), find the voltage drop across the 10 k l l resistor, positive at the top c) Starting with your result from (b), use voltage division to find the voltage drop across the 2 kfl resistor, positive at the top

d) Using your result from part (c), find the current through the 2 kH resistor from top to bottom e) Starting with your result from part (d), use cur-rent division to find the curcur-rent through the

18 kft resistor from top to bottom

3.25 Find vx and v2 in the circuit in Fig P3.25

PSPICE MULTISIM

Figure P3.25

t'2130 a

40 a

3.26 Find va in the circuit in Fig P3.26

PSPICE MULTISIM

Figure P3.26

18 mA

12 k a

3.23 Look at the circuit in Fig P3.2(a)

a) Use voltage division to find the voltage drop

across the 18 II resistor, positive at the left

b) Using your result from (a), find the current

flow-ing in the 18 il resistor from left to right

c) Starting with your result from (b), use current

division to find the current in the 25 fi resistor

from top to bottom

d) Using your result from part (c), find the voltage

drop across the 25 Q resistor, positive at the top

e) Starting with your result from (d), use voltage

division to find the voltage drop across the 10 fl

resistor, positive on the left

3.27 a) Find the voltage v x in the circuit in Fig P3.27

PSPICE

MULTISIM b) Replace the 18 V source with a general voltage

source equal to Vs Assume V s is positive at the upper terminal Find v x as a function of V y

Figure P3.27

18V

Trang 6

3.28 Find i a and i g in the circuit in Fig P3.28

'5P1CE _ „ _ _

Fiqure P3.28

1 2 f t

i3 n

3.32 Suppose the d'Arsonval voltmeter described in Problem 3.31 is used to measure the voltage across the 45 ft resistor in Fig P3.32

a) What will the voltmeter read?

b) Find the percentage of error in the voltmeter reading if

( measured value

% error = - 1 I X 100

\ true value Figure P3.32

3.29 For the circuit in Fig P3.29, calculate (a) ig and

PSPKE (b) the power dissipated in the 30 ft resistor

4ULTISIM

Figure P3.29

3.30 The current in the 12 ft resistor in the circuit in

PSPICE Fig P3.30 is 1 A, as shown

WLTISIM

a) Find vg

b) Find the power dissipated in the 20 ft resistor

Figure P3.30

Section 3.5

3.31 A d'Arsonval voltmeter is shown in Fig P3.31 Find

the value of Rv for each of the following full-scale

readings: (a) 50 V, (b) 5 V, (c) 250 mV, and (d) 25 mV

3.33 The ammeter in the circuit in Fig P3.33 has a resist-ance of 0.1 ft Using the definition of the percent-age error in a meter reading found in Problem 3.32, what is the percentage of error in the reading of this ammeter?

Figure P3.33

60 ft

'VW-3.34 The ammeter described in Problem 3.33 is used to

measure the current i0 in the circuit in Fig P3.32 What

is the percentage of error in the measured value?

3.35 a) Show for the ammeter circuit in Fig P3.35 that

the current in the d'Arsonval movement is always 1/25th of the current being measured b) What would the fraction be if the 100 mV, 2 m A movement were used in a 5 A ammeter?

c) Would you expect a uniform scale on a dc d'Arsonval ammeter?

100 mV, 2 raA

-AAA *

(25/12) ft

Trang 7

PSPICE

MULTISIM

3.36 A shunt resistor and a 50 mV, 1 mA d'Arsonval

movement are used to build a 5 A ammeter A

resistance of 20 mO is placed across the terminals

of the ammeter What is the new full-scale range of

the ammeter?

3.37 The elements in the circuit in Fig 2.24 have the

follow-ing values: flj = 20 kO,, R2 = 80 kft, Rc = 0.82 kfl,

R E = 0.2 kO, Vcc = 7.5 V, V() = 0.6 V, and j3 = 39

a) Calculate the value of i B in microamperes

b) Assume that a digital multimeter, when used as a

dc ammeter, has a resistance of 1 kfl If the

meter is inserted between terminals b and 2 to

measure the current i Br what will the meter read?

c) Using the calculated value of i R in (a) as the

cor-rect value, what is the percentage of error in the

measurement?

3.38

DESIGN

PROBLEM

A d'Arsonval ammeter is shown in Fig P3.38

Design a set of d'Arsonval ammeters to read the

fol-lowing full-scale current readings: (a) 10 A, (b) 1 A,

(c) 50 mA, and (d) 2 mA Specify the shunt resistor

for each ammeter

Figure P3.38

3.39 A d'Arsonval movement is rated at 1 mA and

PROBLEM 50 m V- Assume 0.5 W precision resistors are

avail-able to use as shunts What is the largest

full-scale-reading ammeter that can be designed using a

single resistor? Explain

3.40 The voltmeter shown in Fig P3.40(a) has a

full-scale reading of 750 V The meter movement is

rated 75 mV and 1.5 mA What is the percentage of

error in the meter reading if it is used to measure

the voltage v in the circuit of Fig P3.40(b)?

Figure P3.40

750 V

30 m A M ) 25 kfR 125 kO f v

Common

3.41 You have been told that the dc voltage of a power supply is about 350 V When you go to the instrument room to get a dc voltmeter to measure the power supply voltage, you find that there are only two dc voltmeters available One voltmeter is rated 300 V

full scale and has a sensitivity of 900 fl/V The other

voltmeter is rated 150 V full scale and has a

sensitiv-ity of 1200 fl/V {Hint: you can find the effective

resistance of a voltmeter by multiplying its rated full-scale voltage and its sensitivity.)

a) How can you use the two voltmeters to check the power supply voltage?

b) What is the maximum voltage that can be measured?

c) If the power supply voltage is 320 V, what will each voltmeter read?

3.42 Assume that in addition to the two voltmeters described in Problem 3.41, a 50 k(l precision

resis-tor is also available The 50 kft resisresis-tor is

con-nected in series with the series-concon-nected voltmeters This circuit is then connected across the terminals of the power supply The reading on the 300 V meter is 205.2 V and the reading on the

150 V meter is 136.8 V What is the voltage of the power supply?

3.43 The voltage-divider circuit shown in Fig P3.43 is designed so that the no-load output voltage is 7/9ths of the input voltage A d'Arsonval volt-meter having a sensitivity of 100 fl/V and a full-scale rating of 200 V is used to check the operation

of the circuit

a) What will the voltmeter read if it is placed across the 180 V source?

b) What will the voltmeter read if it is placed across the 70 kO resistor?

c) What will the voltmeter read if it is placed across the 20 kil resistor?

d) Will the voltmeter readings obtained in parts (b) and (c) add to the reading recorded in part (a)? Explain why or why not

Figure P3.43

180 V

:20 Ml

:70kfi i\,

(bj

Trang 8

3.44 The circuit model of a dc voltage source is shown in

Fig P3.44 The following voltage measurements are

made at the terminals of the source: (1) With the

terminals of the source open, the voltage is

meas-ured at 50 raV, and (2) with a 15 Mfi resistor

con-nected to the terminals, the voltage is measured at

48.75 mV All measurements are made with a digital

voltmeter that has a meter resistance of 10 MH

a) What is the internal voltage of the source (v s ) in

millivolts?

b) What is the internal resistance of the source (Rs )

in kilo-ohms?

Figure P3.44

Terminals of ' the source

Figure P3.46

3.45 Assume in designing the multirange voltmeter

PROBLEM shown in Fig P3.45 that you ignore the resistance of

the meter movement

a) Specify the values of R iy R2, and R$

b) For each of the three ranges, calculate the

percent-age of error that this design strategy produces

Figure P3.45

100 V i • A W

-10

V»-I V '

* 2 -AA/V

*3

0 50 m V

2 m A

DESIGN

PROBLEM

Common

3.46 Design a d'Arsonval voltmeter that will have the

three voltage ranges shown in Fig P3.46

a) Specify the values of Rh R 2 , and 7?3

b) Assume that a 750 kil resistor is connected

between the 150 V terminal and the common

terminal The voltmeter is then connected to an

unknown voltage using the common terminal

and the 300 V terminal The voltmeter reads

288 V What is the unknown voltage?

c) What is the maximum voltage the voltmeter in (b)

can measure?

• 300 V

- • 1 5 0 V

•30 V

y x 5 0 m V

/J 1mA

1 Common

3.47 A 600 kH resistor is connected from the 200 V

ter-minal to the common terter-minal of a dual-scale volt-meter, as shown in Fig P3.47(a) This modified voltmeter is then used to measure the voltage across the 360 kO resistor in the circuit in Fig P3.47(b) a) What is the reading on the 500 V scale of the meter?

b) What is the percentage of error in the measured voltage?

Figure P3.47

r

500 V

600 k Q

40 k O

• ,

- • 5 0 0 VI

600 V © 360 m

Modified | voltmeter I

I

I .Common

— • I

J (b)

Trang 9

Sections 3.6-3.7 Figure P3.53

3.48 Assume the ideal voltage source in Fig 3.26 is

replaced by an ideal current source Show that

Eq 3.33 is still valid

3.49 Find the power dissipated in the 3 kQ, resistor in the

PSPICE circuit in Fig P3.49

Figure P3.49

192 V

750 n

A W

25 kfl

3.50 Find the detector current id in the unbalanced

SPICE bridge in Fig P3.50 if the voltage drop across the

detector is negligible

Figure P3.50

75 V

20 kn

3.51 The bridge circuit shown in Fig 3.26 is energized

PSPICE from a 24 V dc source The bridge is balanced when

MULT1SIM _ „

R l = 500 H, /?2 = 1000 n , and R3 = 750 IX

a) What is the value of Rx t

b) How much current (in milliamperes) does the dc

source supply?

c) Which resistor in the circuit absorbs the most

power? How much power does it absorb?

d) Which resistor absorbs the least power? How

much power does it absorb?

3.52 In the Wheatstone bridge circuit shown in Fig 3.26,

PSPICE fa & r a tjQ RJR c a n be s et to the following values:

MULT I SIM

0.001, 0.01,0.1,1,10,100, and 1000 The resistor R3

can be varied from 1 to 11,110 ft, in increments of

1 ft An unknown resistor is known to lie between

4 and 5 ft What should be the setting of the R 2 /R\

ratio so that the unknown resistor can be measured

to four significant figures?

3.53 Use a A-to-Y transformation to find the voltages V\

and v-> in the circuit in Fig P3.53

MUITISIM

50 n

3.54 Use a Y-to-A transformation to find (a) i 0 ; (b) i\, (c) i< and (d) the power delivered by the ideal

cur-JLTISIM x v ' « « * * ! •

rent source in the circuit in Fig P3.54

Figure P3.54

320 a

/ „T^ 6 0 o a

3.55 Find i?ab in the circuit in Fig P3.55

PSPICE MULTISIM

Figure P3.55

PSPICE MULTISIH

3.56 a) Find the equivalent resistance Rah in the circuit

in Fig P3.56 by using a A-to-Y transformation

involving the resistors R 2 , R$, and R 4

b) Repeat (a) using a Y-to-A transformation

involving resistors R2 , R4, and R 5

c) Give two additional A-to-Y or Y-to-A

transfor-mations that could be used to find R db

Figure P3.56

^ 2 1 i o n 50 a

40 n

R*

Rsisn R, 4X1

in

Ry

Trang 10

3.57 a) Find the resistance seen by the ideal voltage 3.61 In the circuit in Fig P3.61(a) the device labeled D

PSPICE

MULTISIM source in the circuit in Fig P3.57

b) If vah equals 400 V, how much power is

dissi-pated in the 31 Cl resistor?

Figure P3.57

a

PSPICE MULTISIM

W ab ©

1.5 n

^ v w

-50 n

7i a

60 a :

20 a

100 a

so a

—vw-40 a

3 0 a

3i a

20 a

represents a component that has the equivalent cir-cuit shown in Fig P3.61(b).The labels on the termi-nals of D show how the device is connected to the

circuit Find v x and the power absorbed by the device Figure P3.61

3.58 Find the equivalent resistance R ah in the circuit in

PSPICE F i g p 3 5 8 i

MULTISIM °

32 a

20 a

3.62 Derive Eqs 3.44-3.49 from Eqs 3.41-3.43 The

fol-lowing two hints should help you get started in the right direction:

1) To find Ri as a function of R a , R f} , and R c , first

subtract Eq 3.42 from Eq 3.43 and then add this result to Eq 3.41 Use similar manipulations to

find R2 and R3 as functions of R(l , R b , and R c 2) To find R b as a function of R^, R 2 , and R 3 , take

advantage of the derivations obtained by hint (1), namely, Eqs 3.44-3.46 Note that these equa-tions can be divided to obtain

3.59 Find iQ and the power dissipated in the 140 ft

resis-'SPICE t o r jn t^e cjr c uit |n pig P359,

Figure P3.59

240 V

22 a

3.60 For the circuit shown in Fig P3.60, find (a) i h (b) v,

(c) i2 , and (d) the power supplied by the voltage

JLTISIM

source

Figure P3.60

120 a

or R,

R, Rh,

and

R$ Rb

~7T = ~TT, or R, = —/?»,

Now use these ratios in Eq 3.43 to eliminate R a and R c Use similar manipulations to find R a and

R c as functions of Ri, R2 , and i?3,

3.63 Show that the expressions for A conductances as

functions of the three Y conductances are

n

G,

G2G3

G1G3

+ G 2 + G 3 '

Gi + G2 + G3' where

43 a C - l r - l etc

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