1 SLIDES OF COURSE EE2011 Electrical Electronics Engineering Prof Ho Pham Huy Anh March 2022 http //www4 hcmut edu vn/~hphanh/teach php 2 COURSE OUTLINE 1 Course Title Electrical Electronics Engineeri[.]
SLIDES OF COURSE EE2011 Electrical-Electronics Engineering Prof Ho Pham Huy Anh March 2022 http://www4.hcmut.edu.vn/~hphanh/teach.php COURSE OUTLINE Course Title: Electrical-Electronics Engineering (EE2011) 60 Total Hours: Evaluation: Homeworks & Exercises : 30% • Final Test: 70% Course - References: [1] Schaum’s – Theory and Problems of Circuit Analysis McGraw Hill - 2007 [2] Schaum’s – Electric Machines and Electro-mechanics McGraw Hill - 2007 Course - References: (cont.) [3] Nilsson – ELECTRIC CIRCUITS_Solution Manual– John Wiley & Sons - 2007 [4] Fitzgerald – Electric Machinery McGraw Hill – 2005 [5] Nguyễn Kim Đính – Kỹ Thuật Điện – Nhà Xuất Bản Đại Học Quốc Gia TPHCM - 2021 [6] Nguyễn Kim Đính – Bài Tập Kỹ Thuật Điện Nhà Xuất Bản Đại Học Quốc Gia TPHCM – 2021 CONTENTS CHAPTER CHAPTER CHAPTER CHAPTER CHAPTER CHAPTER CHAPTER CHAPTER CHAPTER CHAPTER CHAPTER CHAPTER Fundamentals of Electrical Circuits Sinusoidal Circuits Solving Methods for Sinusoidal Circuits Three-Phase Circuits Fundamentals of Electrical Machines Transformers Three-Phase Induction Motors Three-Phase Synchronous Generators DC Machines 10 Diode and Applied Circuits 11 Transistor and Applied Circuits 12 Opamp and Applied Circuits 1st Part: Electrical Circuit: Chapters 2nd Part: Electrical Machines (Transformer, ASM3 pha, syndronous Generator, DC Machine) 3rd part: Electronic Devices and Application Circuits DETAILED CONTENTS Fundamentals of Electrical Circuits 1.1 Components of Electrical Circuits 1.2 Construction of Electrical Circuits 1.3 Parameters of Electrical Component 1.4 Fundamental Electrical Components 1.5 Two Kirchhoff Laws Sinusoidal Electrical Circuits 2.1 General Concepts of Sinusoidal Circuits 2.2 Effective Voltage and Effective Current 2.3 Presentation of Sinusoidal Voltage and Current with Vector 2.4 Voltage – Current Relation of Load 2.5 Impedance Vector and Impedance Triangle of Load 2.6 Power Absorption of Load 2.7 Vector Representation of Voltage, Current, Impedance and Power 2.8 Power Factor 2.9 Active Power Measurement with Watt-Meter 2.10 Complex Number 2.11 Presentation of Sinusoidal Circuits with Complex Number Solving Methods for Sinusoidal Circuits 3.1 General Concepts 3.2 Serial Connection Method Voltage Division Formula 3.3 Parallel Connection Method Current Division Formula 3.4 Method of Y Conversion 3.5 Method of Mesh Current 3.6 Method of Node Voltage 3.7 Proportional Principle Three-Phase Electrical Circuits 4.1 Sources and Loads of Equivalent Three-Phase Circuits 4.2 System of Equivalent Three-Phase Circuits 4.3 System of Equivalent Three-Phase Y - Circuits, Zl = 4.4 System of Equivalent Three-Phase Y - Circuits, Zl ≠ 4.5 System of Non-Equivalent Three-Phase Y - Circuits, Zl = 4.6 System of Non-Equivalent Three-Phase Y - Y Circuits, Zl = 4.7 System of Equivalent Three-Phase Circuits with Multiple Loads 4.8 System of Equivalent Three-Phase Circuits with Loads of Threephase Motors Fundamentals of Electrical Machines 5.1 Faraday Law 5.2 Magnetic Force Law 5.3 Ampere Law 5.4 Forward Magnetic Problem: Know , Find F Transformers 6.1 General Concepts 6.2 Construction of Transformers 6.3 Ideal Transformer Concept 6.4 Equivalent Circuit and Equations of Transformer 6.5 Open Circuit Regime of Transformer 6.6 Short Circuit Regime of Transformer 6.7 Loaded Operation Regime of Transformer 10 Calculation ΔU% based on (UT, IT) Using (8.9), with Ia = IT chosen as reference, we have Vector Diagram presented in Fig 8.4 Iö Iö 0 Iö Fig.8.4 U T U T U T cos jU T sin E g U T cos Rö Iö j (U T sin X s Iö ) ! E p E g (U T cos Rö Iö )2 (U T sin X s Iö )2 (8.9) ! cos treå sin 0; cos sớm sin 129 8.5 Power Factor, Loss, and Efficient Ratio of 3ÞSG Block Diagram (Fig 8.5) P1 = Input Mechanic Power P2 = Output Electrical power Schematic circuit (Fig 8.6) Fig 8.5 Fig 8.6 130 Power Flow Chart of 3ÞSG (Fig 8.6) P1 = Input Mechanical Power Pt = Magnetizing Loss Pđư = Armature Copper Loss = Pđs = Stator Copper Loss Pkt = Excited Loss = Pñr = RT Copper Loss Pmq = Friction & Ventilation Loss (or Mechanical Loss) Pth = Pt + Pđư + Pkt + Pmq = Total Losses P2 = P1 – Pth = Output Electrical Power ! P2 HS % 100 P1 (8.10) 131 Statements of P1 and P2 Power Based on Fig 8.2, 8.3, & 8.6 P1 M1 (8.11) 2 n/60 = 0,105n (8.12) ! P1(W); M1(N.m); (rad/s); and n(v/p) (8.13) P2 3U d Id cos (8.14) Pđư 3Rư Iư2 (8.15) Pkt Rf Ik2 (8.16) 9, 55 P1 (W ) M1 ( N m) n(v/p) (8.17) 8.6 Input Torque of 3ÞSG 132 Chapter DC Direct Current Machines 9.1 Structure of DC Machines Stator (ST) (Inductive Side) a Steel Core ST b Winding ST (STW) or Excited Winding (EW) installed on 2p poles Rotor (RT) (Armature Side) a Steel Core RT b Winding RT (RTW) or Armature Winding (AW) Collecting Rings (Rectifier Rings) Used to rectify the alternative current to direct current 133 9.2 Working Principle of DC Machines (DCMC) S1 Supply current Ik to excited winding, we have the flux Φ = Φ(Ik) S2 Use primary motor as to rotate RT with speed n RT coil with length l run through flux (with Flux Density B (Fig 9.1)) at speed v Hence in the coil induces the inductive EMF e (see Fig 5.2) Fig 9.1 e = Bvl (9.1) S3 Collecting Rings rectify and connect into the EMF E 9.3 The EMF Value of DC Machine ! E = Ke.n.Φ (9.2) 134 9.4 Separated Exciting DC Generator Excited Circuit (Fig 9.2a) similar to the excited circuit of 3ÞSG (see Fig 8.3) Armature Circuit (Fig 9.2b) a) E Fig 9.2 b) Rö = Armature resistance RT = Load resistance = Electro-Motif Force (EMF) UT = Load Voltage ΔUa = Voltage Drop over Ra Ia = Armature Current IT = Load Current U T RT IT U ö Rö Iö (9.3) (9.4) Iö IT (9.5) E U T Rö Iö (9.6) 135 9.5 Parallel Exciting DC Generator (Shunt DC Generator) Equivalent Circuit (EC) (Fig 9.3) and Equations Fig 9.3 U ö Rö Iö U T Rf Ik RT IT (9.7) Iö IT Ik (9.8) E U T Rö Iö (9.9) (9.10) 136 Power Factor, Losses and Efficiency of Shunt DC Generator (Fig 9.3) P1 = Input Mechanical Power Pt = Magnetizing Loss Pca = Armature Copper Loss = Pcr = RT Copper Loss Pkt = Excited Loss = Pcs = ST Copper Loss Pmq = Frictional & Ventilating Loss (Mechanical Loss) Pth = Pt + Pca + Pkt + Pmq = Total Losses P2 = P1 – Pth = Output Electrical Power ! P2 HS % 100 P1 (9.11) (9.12) Input Torque of Primary Motor applied to the Shunt DC Generator 137 ! similar to (8.21) of 3ÞSG 9.6 Working Principle of DC Motor (DCM) Fig 9.4 Fig 9.5 S1 Supply current Ik to excited winding, the flux Φ = Φ(Ik) is formed with the flux density B (see Fig 9.5) S2 Supply current Iö to armature winding, we have current Ia/2a run through armature winding Consequently Magnetic Force F appeared to rotate the rotor ! F = B(Ia/2a)l (9.13) 138 9.7 Speed of DC Motor Fig 9.4 gives: U E U ö E Rö Iö U Rö Iö E n K E K E (9.14) (9.15) 9.8 Torque of DC Motor We have B from flux Φ and torque M from force F Hence from (9.13), we have the Total Torque (corresponding to Total Mechanical Output) is calculated as follows (9.16) M K M Iö ! Graph F = F(Ik) has the same Magnetizing Curve as B = B(H) 139 9.9 Shunt DC Motor (Shunt DCM) Equivalent Circuit (EC) (Fig 9.6) and principal Equations Fig 9.6 U ö Rö Iö (9.17) I Iö Ik (9.19) U Rf I k (9.18) U E Rö Iö (9.20) 140 Power Factor, Loss, and Efficient Ratio of Shunt DC Motor P1 = Input Electrical Power Pkt = Excited Loss = Pñs = ST Copper Loss Pö = P1 – Pkt = RT Input Power (Armature Input Power) Pđư = Armature Copper Loss = Pđr = RT Copper Loss Pc = Pư – Pđư = Total Mechanical Power Pt = Magnetizing Loss Pmq = Frictional & Ventilating Loss (Mechanical Loss) Po = Pt + Pmq = No-Load Loss (Rotating Loss) (9.21) P2 = Pc – Po = Output Mechanical Power Pth = P1 – P2 = Pkt + Pđư +Pt + Pmq = Total Losses (9.22) P2 HS % 100 P1 (9.23) ! 141 Fig 9.7 Statements of P1 and P2 based on Fig 9.7 P1 UI; Pö UIö ; Pc EIư (9.24) Pkt Rf Ik2 ; Pđư Rö Iö2 (9.25) 142 Torque of Shunt DC Motor (9.26) Pc M K M Iö a Total Torque (9.27) Pt Pmq P0 b Rotating Loss Torque M0 P2 (9.28) c Output Torque M2 M M0 If (U1, Ia1, F1, n1, M1) and (U2, Ia2, F2, n2, M2) are parameters of the 1st and 2nd working regimes; then from (9.15) and (9.16), we have U Rö Iö 1 n2 E2 1 (9.29) n1 E1 U1 Rö Iö ! M2 Iö (9.30) M1 1 Iö 143 ...COURSE OUTLINE Course Title: Electrical-Electronics Engineering (EE2011) 60 Total Hours: Evaluation: Homeworks & Exercises