PowerPoint Presentation C2H5COOC2H5 Đáp án có 2 oxi=> n=2=> CTPT C4H8O2 => ESTE CH3COOC2H5 RCOONa + NaOH RH + Na2CO3 CaO, t0 (CH4) (R= CH3 ) RCOOR’ + NaOH RCOONa + R’OH nC4H8O2 =0,12 (mol) RCOOR’ + NaOH RCOONa + R’OH 0,12 (mol) 0,12 (mol) M RCOONa= 8,16 0,12= 68 => M R + 67= 68 => MR=1 => R là H => X là HCOOC3H7 => X là Propyl fomat Câu A Glu > 2 Ag 0,1 0,05 mglu=0,05*180=9 Xenlulozo xenlulozo trinitrat 1/297 (M=297) 1/297 mxenlulozo = 1/297 * 162 90%=0,6061 (tấn) Hao hụt 10%=> H%=90% n C[.]