Aerospace Technologies Advancements 2012 Part 5 potx
... Shuler, R.L.; Kouba, C. & O'Neill, P.M. (20 05) . “SEU Performance of TAG Based Flip-Flops”, IEEE TNS, Vol. 52 , NO 6, Dec. 20 05, pp 255 0 – 255 3. Shuler, R.L.; Balasubramanian, A.; Narasimham, ... [MeV-cm 2 /mg] Fluence [16 .5 MEV Proton- Particles] 1 15 2.48x 10 -14 4x10 10 2 30 2.29x 10 -14 4x10 10 3 45 2 .51 x 10 -14 4x10 10 4 60 2.80x 10 -14 4x10 10 5 7...
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Aerospace Technologies Advancements 2012 Part 4 potx
... Aerospace Technologies Advancements 102 1.0E-10 1.0E-09 1.0E-08 1.0E-07 1.0E-06 0 1020304 050 6070 LET (MeV-cm 2 /mg) DFF Cross-Section (cm 2 /DFF) 2MHz 16MHz 50 MHz Fig. 15. A3P 250 -PQ208 ... Reprogrammable and Non-Volatile Radiation-Tolerant FPGA: RT ProASIC®3 93 0 5 10 15 20 25 30 35 40 45 50 0 1020304 050 60708090100 X-Ray Total Dose (Krad(Si)) % Degradatio...
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... FPGAs. Aerospace Technologies Advancements 102 1.0E-10 1.0E-09 1.0E-08 1.0E-07 1.0E-06 0 1020304 050 6070 LET (MeV-cm 2 /mg) DFF Cross-Section (cm 2 /DFF) 2MHz 16MHz 50 MHz Fig. 15. A3P 250 -PQ208 ... Shuler, R.L.; Kouba, C. & O'Neill, P.M. (20 05) . “SEU Performance of TAG Based Flip-Flops”, IEEE TNS, Vol. 52 , NO 6, Dec. 20 05, pp 255 0 – 255 3. Shuler, R.L.; Bal...
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... China Sea. Aerospace Technologies Advancements 456 Channel 2 Reflectance (%) Frequency in Percent 1 059 0 756 0 453 0 150 35 30 25 20 15 10 5 0 Mean StDev N 62.90 10.93 960 4.163 2. 655 21761 Variable Cloud ... array Aerospace Technologies Advancements 458 Ratio of Channel 2 and Channel 1 Reflectance Frequency in Percent 0.9000.8 250 . 750 0.6 750 .6000 .52...
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Aerospace Technologies Advancements 2012 Part 3 pot
... (HDL) Aerospace Technologies Advancements 60 Fig. 2. Configuration of Flexible Spacecraft Fig. 3. Dynamic Model of Flexible Spacecraft Aerospace Technologies Advancements 56 i ini 0 0 0 d ⎡ ⎤ ⎢ ⎥ ⎢ ⎥ ⎢ ⎥ = ⎢ ⎥ ⎢ ⎥ ⎢ ⎥ ⎣ ⎦ d # ... aspects of Aerospace Technologies Advancements 66 Fig. 4. Angular Displacement Response of Main Body Fig. 5. Angu...
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Aerospace Technologies Advancements 2012 Part 7 ppt
... 24 dBi 1 .5 dBi 25 dBi 4 dBi Output Power 47 dBm 30 dBm 40 dBm 33 dBm Attenuation 154 dB 154 dB 169 dB 169 dB RX Antenna Gain 1 .5 dBi 24 dBi 4 dBi 25 dBi RX Sensitivity -103 -1 15 dBm -118 ... Assist Suspension or PEGASUS suspension system for their Micro5 testbed rover (Kubota et al., 20 05) . Aerospace Technologies Advancements 172 • Dynamic RAM (DRAM): it is the m...
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Aerospace Technologies Advancements 2012 Part 9 ppt
... November–December 2006, pp 12 25 1230. Aerospace Technologies Advancements 252 L1/L2/L5 signals, also to receive the GALILEO E1/E5/E6 signals, and to receive GLONASS’s L1/L2/L5 signals as well (Yen ... 1996). 1 http://en.wikipedia.org/wiki/Occultation [cited 1 July. 2009]. Aerospace Technologies Advancements 254 7 .5 Science segment The data receiving and proc...
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Aerospace Technologies Advancements 2012 Part 10 docx
... for Solid Rocket Motors 279 0 5 10 15 20 25 30 700 800 900 1000 x, m Pressure p, psi 14 30 46 62 88 800 700 600 50 0 78 0 5 10 15 20 25 30 0 50 100 150 200 250 300 x, m Velocity u, m/sec 88 62 46 30 14 78 ... equations of motion. Aerospace Technologies Advancements 280 0 5 10 15 20 25 30 700 800 900 x , m Pressure p, psi 60 76 76 60 700 600 50 0 72 72 0...
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Aerospace Technologies Advancements 2012 Part 12 pptx
... 10 -1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1 -1 .5 -1 -0 .5 0 0 .5 1 1 .5 0 0.1 0.2 0.3 0.4 0 .5 0.6 0.7 0.8 0.9 1 BT b =1 BT b =0 ,5 BT b =0,3 Time in half bit p erio d g(t) Aerospace Technologies Advancements 338 A. ... and phyCORE-MCF54 85 SOM Module from PHYTEC are shown in fig. 5. (a) (b) Fig. 5. SSTL OBC 386 (a) and phyCORE-MCF54 85 SOM Module from PHY...
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Aerospace Technologies Advancements 2012 Part 13 ppt
... 67.2 951 1 .59 41 67.2910 67.2992 Pert1=pert2 Std = 1/10 C = 1/2 65. 3106 1.8880 65. 3 057 65. 3 155 Ind Std = 1/10 C = 1/2 67. 057 9 1.6499 67. 053 6 67.0622 Ind Std = 1 C = 1/2 60 .59 88 3.6930 ... 67.3279 1 .59 10 67.3238 67.3320 Pert1=pert2 Std = 1 C = 0 65. 9497 1.73 35 65. 9 452 65. 954 2 Ind Std = 1/10 C = 0 67.1 959 1.6200 67.1917 67.2001 Ind Std = 1...
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