Circuit design with VHDL (vietnamese ver )

Circuit design with VHDL (vietnamese ver )

Circuit design with VHDL (vietnamese ver )

... 1Dx1D) x( 2) <= w(2, 1); 1 cặp dấu ngoặc đơn (w is 2D) y( 1)( 1) <= x( 6); y( 2)( 0) <= v( 0)( 0); y( 0)( 0) <= w(3, 3); w(1, 1) <= x( 7); w(3, 0) <= v( 0)( 3); Gán vector: x <= y( 0); hợp ... STD_LOGIC_VECTOR) y( 1)( 7 DOWNTO 3) <= x(4 DOWNTO 0); legal (same type, same size) v( 1)( 7 DOWNTO 3) <= v( 2)(...

Ngày tải lên: 24/03/2014, 23:28

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circuit design with vhdl mit press ebook

circuit design with vhdl mit press ebook

... 9. shift ‘0’ outp( 7) inp( 7) MUX inp( 6) outp( 6) MUX inp( 5) outp( 5) MUX inp ( 4) outp( 4) MUX inp( 3) outp( 3) MUX inp( 2) outp( 2) MUX inp ( 1) outp( 1) MUX inp( 0) outp( 0) MUX Figure P5.7 88 Chapter 5 TLFeBOOK Problem 5.8: Comparator Construct a circuit capable ... this circuit. Note: A complete barrel shifter (with shift ¼ 0tonÀ 1,...

Ngày tải lên: 25/11/2013, 11:38

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Tài liệu Circuit design with VHDL ppt

Tài liệu Circuit design with VHDL ppt

... 5 ENTITY counter IS rst zero (000 0) one (000 1) two (001 0) three (001 1) five (010 1) four (010 0) nine (100 1) six (011 0) eight (100 0) seven (011 1) Figure 8.2 States diagram of example ... However, suppose that now it should count from 0 (‘‘0000’ ) to 15 (‘‘1111’ ). (a) Write a VHDL code for it, then synthesize and simulate your solu...

Ngày tải lên: 12/12/2013, 11:16

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Circuit Design with VHDL pptx

Circuit Design with VHDL pptx

... 9. shift ‘0’ outp( 7) inp( 7) MUX inp( 6) outp( 6) MUX inp( 5) outp( 5) MUX inp ( 4) outp( 4) MUX inp( 3) outp( 3) MUX inp( 2) outp( 2) MUX inp ( 1) outp( 1) MUX inp( 0) outp( 0) MUX Figure P5.7 88 Chapter 5 TLFeBOOK 8.4 Encoding ... b) OR (a AND cin) OR (b AND cin); END dataflow; Circuit Figure 1.3 Example of VHDL code for the full-adder u...

Ngày tải lên: 19/03/2014, 21:20

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Circuit Design with VHDL ppt

Circuit Design with VHDL ppt

... 9. shift ‘0’ outp( 7) inp( 7) MUX inp( 6) outp( 6) MUX inp( 5) outp( 5) MUX inp ( 4) outp( 4) MUX inp( 3) outp( 3) MUX inp( 2) outp( 2) MUX inp ( 1) outp( 1) MUX inp( 0) outp( 0) MUX Figure P5.7 88 Chapter 5 TLFeBOOK 8.4 Encoding ... this circuit. Note: A complete barrel shifter (with shift ¼ 0tonÀ 1, where n is the number of bits) will be se...

Ngày tải lên: 23/03/2014, 08:20

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Circuit design with VHDL (2007)

Circuit design with VHDL (2007)

... a design:  ieee.std_logic_1164 (from the ieee library),  standard (from the std library), and  work (work library). TLFeBOOK with VHDL Volnei A. Pedroni Circuit Design Circuit Design with VHDL Volnei ... 12. 2)  MAC circuit (section 12. 3)  Neural networks (section 12. 5)  Parallel-to-serial converter (section 9. 7)  Parity detector (example 4. 2)  P...

Ngày tải lên: 01/04/2014, 17:41

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Fundamentals of RF Circuit Design With Low Noise Oscillators

Fundamentals of RF Circuit Design With Low Noise Oscillators

... (3.131a/b) where: ∆= − SS SS 11 22 12 21 (3.12 2) 86 Fundamentals of RF Circuit Design V Z b out 02 2 = (2.9 6) Therefore:         + =× 11 2 02 01 ba b V V Z Z in out (2.9 7) () () 211 02 01 b V V ba Z Z in out =×+× (2.9 8) Dividing ... [1]: () 1 2/1 2 1 2 11 2 4 C CBB Sopt −± =Γ (3.14 0) () 2 2/1 2 2 2 22 2 4 C CBB Lopt −± =Γ (3.14 1) BSS 111 2 22...

Ngày tải lên: 08/04/2013, 10:50

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Tài liệu Logic Design with VHDL doc

Tài liệu Logic Design with VHDL doc

... bit_vector(15 downto 0); signal Dividend: bit_vector(31 downto 0); alias Q: bit_vector(15 downto 0) is Dividend(15 downto 0); alias Acc: bit_vector(15 downto 0) is Dividend(31 downto 1 6); begin concurrent ... until rising_edge(CLK); Dbus <= dividendarr(i) (15 downto 0); wait until rising_edge(CLK); Dbus <= divisorarr(i); St <= '0'; dividend <= divid...

Ngày tải lên: 12/12/2013, 09:16

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Circuit design with HDL Chapter 4 Structural modeling pdf

Circuit design with HDL Chapter 4 Structural modeling pdf

... instantiations. and a1(OUT, IN1, IN 2); nand na1(OUT, IN1, IN 2); or or1(OUT, IN1, IN 2); nor nor1(OUT, IN1, IN 2); xor x1(OUT, IN1, IN 2); xnor nx1(OUT, IN1, IN 2); // More than two inputs; 3 input ... signals. not (s1n, s 1); not (s0n, s 0); // 3-input and gates instantiated and (y0, i0, s1n, s0n); and (y1, i1, s1n, s 0); and (y2, i2, s1, s0n); and (y3, i3, s...

Ngày tải lên: 07/03/2014, 14:20

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Circuit design with HDL Chapter 5 Dataflow modeling (Expression) ppt

Circuit design with HDL Chapter 5 Dataflow modeling (Expression) ppt

... c, output y); assign y = a ^ b ^ c; endmodule  Concatenation module add_1bit (input a, b, ci, output s, co); assign #(3, 4) {co, s} = {(a & b)|(b & ci)|(a & ci), a^b^ci}; ... s = a^b^cin; assign cout = (a & b) | (cin & (a^b )) ; endmodule • Let’s design 8-bit adder 20 module comparator (result, A, B, greaterNotLess); parameter width = 8; parameter del...

Ngày tải lên: 16/03/2014, 15:20

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