Tài liệu ElectrCircuitAnalysisUsingMATLAB Phần 5 pdf
Tài liệu ElectrCircuitAnalysisUsingMATLAB Phần 5 pdf
... t
dt
xt
5
4
4
4
4
()
() ()
()
===
•
(5. 25)
Using Equations (5. 24) and (5. 25) , we get
xt ut xt xt xt xt
44321
63 4 8 2() () () () () ()
•
=− − − −
(5. 26)
From the Equations (5. 25) and (5. 26), ... obtained from Example
5. 5 are identical.
Example 5. 8
For Figure 5. 11, if
vt ut
S
() ()
=
5
where
ut
()
is the unit step function and
RRR K
123
10
=== Ω
,
CC F
12
5
=...
Tài liệu ElectrCircuitAnalysisUsingMATLAB Phần 2 pdf
...
kmAV=
25
2
./
, plot the current
i
DS
for the following values of
V
GS
: 1 .5, 2.0, 2 .5, , 5 V.
2.3 Plot the voltage across a parallel RLC circuit given as
vt e t
t
( ) sin( )
=
5 1000
2
π
...
θ
= 15
0
and
n
= 1 to
20.
2 .5 The table below shows the grades of three examinations of ten
students in a class.
STUDENT EXAM #1 EXAM #2 EXAM #3
1 81 78 83
2 7...
Tài liệu ElectrCircuitAnalysisUsingMATLAB Phần 1 pdf
...
t1 =
1 2 3 4 5 6
Non-unity, positive or negative increments, may be specified. For example,
the statement
t2 = 3:-0 .5: 1
will result in
t2 =
3.0000 2 .50 00 2.0000 1 .50 00 1.0000
... linspace(2, 6, 8)
will generate the vector
t4 =
Columns 1 through 7
2.0000 2 .57 14 3.1429 3.7143 4.2 857 4. 857 1
5. 4286
Column 8
6.0000
Individual elements in...
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Tài liệu Proe phần 5 pptx
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