Tài liệu ElectrCircuitAnalysisUsingMATLAB Phần 5 pdf

... t dt xt 5 4 4 4 4 () () () () === • (5. 25) Using Equations (5. 24) and (5. 25) , we get xt ut xt xt xt xt 44321 63 4 8 2() () () () () () • =− − − − (5. 26) From the Equations (5. 25) and (5. 26), ... obtained from Example 5. 5 are identical. Example 5. 8 For Figure 5. 11, if vt ut S () () = 5 where ut () is the unit step function and RRR K 123 10 === Ω , CC F 12 5 =...

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... kmAV= 25 2 ./ , plot the current i DS for the following values of V GS : 1 .5, 2.0, 2 .5, , 5 V. 2.3 Plot the voltage across a parallel RLC circuit given as vt e t t ( ) sin( ) = 5 1000 2 π ... θ = 15 0 and n = 1 to 20. 2 .5 The table below shows the grades of three examinations of ten students in a class. STUDENT EXAM #1 EXAM #2 EXAM #3 1 81 78 83 2 7...

Ngày tải lên: 25/01/2014, 13:20

... t1 = 1 2 3 4 5 6 Non-unity, positive or negative increments, may be specified. For example, the statement t2 = 3:-0 .5: 1 will result in t2 = 3.0000 2 .50 00 2.0000 1 .50 00 1.0000 ... linspace(2, 6, 8) will generate the vector t4 = Columns 1 through 7 2.0000 2 .57 14 3.1429 3.7143 4.2 857 4. 857 1 5. 4286 Column 8 6.0000 Individual elements in...

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... 01-2008 3 tuankhanhti@yahoo.com BK TPHCM 01-2008 4 tuankhanhti@yahoo.com BK TPHCM 01-2008 5 tuankhanhti@yahoo.com BK TPHCM 01-2008 6 tuankhanhti@yahoo.com BK TPHCM 01-2008 7 tuankhanhti@yahoo.com

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