Ạ 400. B. 200. C. 100. D. 300.
B a i 19: Chat thuoc loai disaccarit la
Ạ glucozọ B. saccarozcf. C. xenlulozd. D. fructozcf.
B a i 20: De l a m mem nirdc curng v i n h cufu, ta dung dung dich
Ạ Ca(N03)2. B. NaCl. C. H C l . D. Na2C03.
B a i 21: Oxi hoa CH3CH2OH bSng CuO dun nong, t h u dirge andehit c6 cong thuTc la
Ạ CH3CHỌ B. CH3CH2CHỌ C. CH2 = C H - C H O . D. H C H O .
B a i 22: Cong thufc chung cua day dong dang ancol no, đn ehiJe, mach hof la
Ạ C„H2„_iOH (n > 3). B. C„H2n.iOH (n > 1). C. C n H 2 n ^ i C H 0 (n > 0). D. C n H g n + i C O O H (n > 0). B a i 23: Chat phan iJng dirge vdi dung dich N a O H tao k e t tua la
Ạ KNO3. B. FeClg. C. BaCl2. D. K2SO4. B a i 24: Phaong phap t h i c h hgp dieu che k i m loai Ca tCr CaCl2 la
Ạ n h i e t phan CaCl2.
B. dung Na khilf Câ"^ trong dung dich CaCl2.
C. dien phan dung dich CaCl2.
D. dien phan CaCl2 nong chaỵ
B a i 25: Chat phan ufng dirge vdi dung dich H2SO4 tao r a k e t tua la Ạ N a O H . B. Na2C03. C. BaClz. D. NaCl.
B a i 26: Este etylfomiat CO cong thiJe la
Ạ CH3COOCH3. B. HCOOC2H5.
C. HCOOCH = CH2. D. HCOOCH3.
B a i 27: A x i t axetie CH3COOH khong phan lifng v d i
Ạ Na2S04. B. N a O H . C. Na2C03. D. CaO
B a i 28: De phan bi§t dung dich AICI3 va dung dich K C l ta dung dung dich
B a i 29: Chat phan uTng dUdc v d i AgNOs trong dung dich NH3, dun nong
tao ra k i m loai A g la '
Ạ C H 3 N H 2 . B. C H 3 C H 2 O H . C. C H 3 C H O . D. C H 3 C O O H .
B a i 30: Cho 4,4 gam mot andehit no, don chiJc, mach hd X phan ufng
hoan toan v d i mot Itrcmg dir AgNOs trong dung dich N H 3 , dun nong
thu dugfc 21,6 gam k i m loai Ag. Cong thiJc cua X la
Ạ C H 3 C H O . B. C 3 H 7 C H O . C. H C H O . D. C 2 H 5 C H O .
B a i 31: H a i k i m loai deu phan dng v d i dung dich Cu(N03)2 giai phong k i m loai Cu la
Ạ A l va Fẹ B. Fe va A u . C. A l va Ag. D. Fe va Ag.
B a i 32: Qua t r i n h nhieu phan tuT nho (monome) ket hop v d i nhau thanh (adsbygoogle = window.adsbygoogle || []).push({});
phan t i l Idn (polime) dong t h d i giai phong nhufng phan tOf nifdc goi la
phan ufng
Ạ nhiet phan. B. trao doị C. t r u n g hop. D. truing ngiing.
B a i 33: Cap chat khong xay ra phan ufng la
Ạ Fe + Cu(N03)2. B. Cu + AgNOg.
C. Zn + Fe(N03)2. D- A g + Cu(N03)2.
B a i 34: Chat phan ufng ducfc v d i Cu( 0 H ) 2 tao ra dung dich mau xanh lam la
Ạ phenol. B. etyl axetat. C. ancol etylic. D. glixerol.
B a i 35: A x i t aminoaxetic ( N H 2 C H 2 C O O H ) tac dung difcifc v d i dung dich
Ạ NaNOọ B. NaCl. C. N a O H . D. Na2S04.
B a i 36: Cau h i n h electron cua nguyen tuf Na (Z = 11)
•Ạ ls'2s'V3s'. • . B. ls22s'2p^
C. l s W 2 p ' 3 s \ ' b . lsW2p^3s'3p\
B a i 37: Cho phan ufng a A l + bHNOa c A1(N03)3 + dNO + e H 2 0
He so a, b, c, d, e la cac so nguyen, t o i gian. Tong (a+b) bSng
Ạ 5. B. 4. C. 7. D. 6.
B a i 38: Chat phan ufng Axiqc v d i CaCOs la
Ạ C H 3 C H 2 O H . B. CeHsOH.
C. C H 2 = C H - C O O H . D. CeHgNHz (anilin)
B a i 39: K i m loai khong phan ufng v d i nifdc d nhiet do thadng la
Ạ Fẹ B. Nạ C. Bạ D. K.
B a i 40: H a i k i m loai A l va Cu deu phan ufng dadc vdi dung dich
Ạ NaCl loang. B. H 2 S O 4 loang. C. H N O 3 loang. D. N a O H loang
DE THI THljr TOT NGHlfP THPT
Mon t h i : Hoa hoc - Ban cO ban
O e 4 B a i 1 : Cho cac phat bieu B a i 1 : Cho cac phat bieu
Mk^^ (a) Nguyen tic san xuat gang la l a m giam ham liicfng cac tap chat C,
• Si, M n , S.. CO trong quSng sat bang each oxi hoa chiing roi loai bọ
(b) Nguyen tac san xuat thep la thiTc hien qua t r i n h khuf quang sat oxit bang CO d nhiet dp caọ
(c) H a m lifpng %C c6 trong thep la 0 , 0 1 - 2%. (adsbygoogle = window.adsbygoogle || []).push({});
t Phat bieu d i i n g lả
Ạ (c) B. (a), (b), (c) C. (b), (c) D. (a), (b)
B a i 2: Cho 0,01 mol aminoaxit (A) tac dung du vdi 80 m l dung dich H C l 0,125 M . Co can t h i thu di/pc 1,835 gam muoị Khoi Itfong phan tuf cua (A) lả
Ạ 120 B. 150 C. 147 D. 97
B a i 3: Lay thanh k i m loai R hoa t r i I I nhiing vao 250 m l đ C U S O 4 1,4 M . Sau k h i phan dng hoan toan nhan tháy khd'i krgng thanh k i m loai R giam 0,35 gam. Xac d i n h k i m loai R.
Ạ Zn (65) B. Fe (56) C. M g (24). D. Cr (52)
B a i 4: Cho 4,32 gam A l t h i khuf het bao nhieu gam oxit sat tir. Biet san pham cuoi cung la Fe
. . ' A . 41,76-gam ' JB.;.l%92.gậ_*. ; G. 20,8g gam- D. 83,52 gam.*.' .
•Bai 5: L a y 7 , 0 4 g'am est.e e4H80.2'x8ipiiDilg-hoa trong m o i triidrig N a O H
du t h i thu diipc 6,56 gam muoị. Cong thufc cau tao cua este lả
Ạ C 2 H 5 C O O C H 3 • B. H C O O C H 2- C H, - C H 3
C; H C O O C H( C H 3 ) 2 D. C H 3 C O O C 2 H 5
B a i 6: T i n h dan dien theo chieu tang dan lả
Ạ Cu < Ag < Fe B. Fe < Cu < A g C. Fe < Ag < Cu D. A g < Cu < Fe
B a i 7: N h o m k i m loai nao c6 the dieu che bang phifang phap nhiet luyen?
Ạ M g , Cu, Fe B. Fe, C i , Cu C. Ag, K, Fe D. Al, Na, Cu
B a i 8: Cac phat bieu dung ve peptit va protein lả (1) L i e n ket peptit la l i e n ket - C O - N H -
(2) So lien k e t peptit trong p h a n ttf peptit c6 n goc amino axit l a ( n - 1 )
(3) Cho p e p t i t G l y - A l a - G l y - G l y - V a l t h u o c l o a i t e t r a p e p t i t
(4) P r o t e i n l a nhuTng p o l i p e p t i t c6 p h a n tuf k h o i \dn tix v a i chuc n g h i n
d e n h a n g t r i e u d v C ' (5) P r o t e i n con g o i l a a b u m i n ( 1 6 n g t r a n g trutng)
(6) P r o t e i n c h i c6 t r o n g d o n g v a t
A . (1), (3), (4), (5), (6) B . (3), (5), (6) C. (1), (2), (3) (4), (5), (6) D . (1), (2), (4) C. (1), (2), (3) (4), (5), (6) D . (1), (2), (4)
B a i 9: Cho cac c h a t : Fe(N03)3, F e , A g N 0 3 , Cụ So cSp c h a t tac d u n g vdi n h a u CO x a y r a phifcfng t r i n h p h a n uTng lả
A . 2 B . 5 C. 4 D . 3
B a i 10: Cho V l i t d d N a O H 0,2 M vao d d chufa 0,15 m o l AICI3 t h u dtfoc 9,36 g a m k e t t u a . G i a t r i cua V lả
A . 1,8 l i t hoac 2,4 l i t B . 2,2 l i t hoSc 2,4 l i t
C. 0,6 l i t D . 2,4 l i t hoSc 3,6 l i t .
B a i 11: Cho este c6 c o n g thufc p h a n tuf l a C4H8O2 di/oc tao r a boti ancol
m e t y l i c . T e n cua este lả (adsbygoogle = window.adsbygoogle || []).push({});
A . e t y l a x e t a t B . i s o p r o p y l f o m a t
C. m e t y l p r o p i o n a t D . p r o p y l f o m a t .
B a i 12: Cho cong thufc a m i n o a x i t la C3H7NO2. So d o n g p h a n a m i n o a x i t lả A . 2 B . 4 C. 3 D . 5
B a i 13: De p h a n b i e t dMc cac d d m a t n h a n : a b u m i n , glucozcf, ancol
e t y l i c , g l i x e r o l c h i can d u n g 1 t h u o c thuf naỏ
A . d d HNO3 B . C u ( 0 H ) 2 / 0 H -
C. Q u y t i m D . A g N O s / N H g
B a i 14: Cho puf: Z n + Cu ^ Zn^* + Cụ P h a t bieu nao s a i ve p h a n utng?
A . Z n o x i hoa duac Cu^^ B . T i n h o x i hoa Zn^^ < C u ^*
C. T i n h khuf Z n > C u D . Cu^^ o x i hoa dugc Z n .
B a i 15: Cho cac p o h m e : (a) n i l o n - 6 , 6 ; (b) P V C ; (c) cao su b u n a ; (d)
p o l i p e p t i t ; (e) t h i i y t i n h hQu cọ C h a t nao difoc d i e u che b S n g phuong
p h a p t r u n g hofp?
A . (b), ((d), (e) B . (b), (c), (e)
C. (b), (c) D . (a), (b), (c), (e)
C a u 16: Cho m o t l o a i t i n h b o t v a m o t l o a i P E c6 K L P T t r u n g b i n h
tLfOng iJng l a : 172530 d v C v a 2 8 0 0 0 0 d v C . So m S t x i c h t u o n g ilng
t r o n g m o i l o a i p o l i m e t r e n lả
A . 1065 v a 5 6 0 0 0 0 B . 10065 v a 10000 C. 1065 v a 10000 D . 10000 v a 1065.
B a i 17: SSp x e p cac a m i n sau d a y t h e o c h i e u t i n h bazo t a n g d a n .
(a) m e t y l a m i n , (b) a m o n i a c , (c) d i p h e n y l a m i n , (d) d i m e t y l a m i n , (e) N a O H , (f) a n i l i n
A . (a) < (b) < (f) < (d) < (c) < (e) B . (c) < (f) < (b) < (a) < (d) < (e) C. (a) < (c) < (d) < (e) < (b) < (f) D . (a) < (c) < (e) < (d) < (b) < (f).
B a i 18: P h a n tuf p o l i m e bao g o m sU iSp d i l 5 p l a i cua r a t n h i e u cac
A . m o n o m e B . d o a n m a c h C. n g u y e n to D . m a t x i c h cau t r u e B a i 19: C h a t n a o k h o n g c6 k h a n a n g t h a m g i a p h a n ufng t h u y p h a n ? A . x e n l u l o z a B . fructoza C. saccarozo D . t i n h b o t B a i 20: T h u y p h a n t r i s t e a r i n t r o n g m o i trufcfng k i e m N a O H t h u di/gfc san p h a m lả A . n a t r i s t e a r a t v a g l i x e r o l B . n a t r i s t e a r a t v a e t i l e n g l i c o l C. n a t r i o l e a t v a g l i x e r o l D . k a l i s t e a r a t v a g l i x e r o l . B a i 21: Cho h o n h o p F e , A g , C u . C h o n t h u o c thuf de t a c h A g n g u y e n l u o n g r a k h o i h o n h o p lả
A . d d CUSO4 B . d d H C l C. d d AgNOa D . d d FeCh
B a i 22: Cho d u n g d i c h g o m cac m u o i : F e C l 2 , MgCl2, AICI3 t d c d u n g h o a n t o a n v d i d u n g d i c h N a O H da, loc l a y k e t t u a d e m n h i e t p h a n t r o n g
k h o n g k h i d e n k h o i li/Ong k h o n g d o i t h i t h u d\Jac c h a t r ^ n Ik?
A . F e O , M g O B . Fe203, M g O , AI2O3
C. FezOs, M g O D . F e O , M g O , AI2O3.
B a i 23: H a p c h a t cua n g u y e n t o n a o t h a i r a t r o n g s i n h b o a t g a y t h u n g t a n g ozon? (adsbygoogle = window.adsbygoogle || []).push({});
A . C a c b o n B . N i t d C. L o u h u y n h D . Clo B a i 24: D u n g d i c h F e S 0 4 v a d u n g d i c h CUSO4 deu tac d u n g dtrgtc v d i B a i 24: D u n g d i c h F e S 0 4 v a d u n g d i c h CUSO4 deu tac d u n g dtrgtc v d i
B a i 25: Cho 7,168 l i t CO2 dkc vao 140 m l đ Că0H)2 2 M . T m h khoi lugfng ket tuả
Ạ 24 gam B. 32 gam C. 4 gam D. 28 gam B a i 26: N h o m chat nao deu c6 t i n h lifSng tinh?
Ạ C6H5-NH2, A1(0H)3, C r ( 0 H ) 3
B. H2N-CH(CH3)-COOH, Fe(0H)3, CăHC03)2 C. H 2 N - C H 2- C O O H , CraOs, NaHCOa C. H 2 N - C H 2- C O O H , CraOs, NaHCOa
D. H 2 N - ( C H 2) 6- N H 2 , Zn(0H)2, AI2O3
B a i 27: Cho 16,74 gam a n i h n tac dung hoan toan vdi dung dich Br2 tinh m ket tiia thu duoc?
Ạ 19,8 gam B. 118,8 gam C. 29,7 gam D. 59,4 gam B a i 28: Can 120 m l đ K O H 0,2 M de trung hoa 224 gam chat beọ Tinh
chi so axit cua chat beỏ
Ạ 6 B. 5 C. 8 D. 7.
B a i 29: Xac dinh k h o i iMng phan t u gan dung cua protein X c6 0,16 %
lUu huynh, biet r a n g cac 1 phan tuf protein chi chufa 1 nguyen tuf liJu huynh.
Ạ 50 dvC B. 2000 dvC C. 20000 dvC D. 50000 dvC. B a i 30: H a n che cua xa phong lả
Ạ nguyen lieu san xuat kho k i e m
B. gay h a i cho da