Bai 4: CJiyO ^X CO 2+ ^H^O •

V i3 chat CO so mol bkng nhau nen so nguyen tuf H trong m6i chat la

Bai 4: CJiyO ^X CO 2+ ^H^O •

+ Nhom I : Lam mat mau dung dich brom gom S O 2 va H2S

+ Nhom I I : Khong lam mat mau dung dich brom gom

* Dung Ca

ta nhan biet dirge

va

c6 xuat hien ket tua tring Chon dap an C.

Chon dap an C.

Bai 58:

* Phirong phap thong thiTdng Dat cong thiJc A la

Dat cong thiJc A la

C„H2„.20. ^ ( 6 n + 2 - 2 x ^ Q ^ _^ ^ ^ ^ ^ ^ (n+l)H20

4

+ Theo de: ( 6" + 2 - 2x ^ = 2,5 -> 6n - 2x = 8 ^ n = 2 va x = 2 4

4

* Phirong phap kinh nghiem Vi ^ = 2,5 -> So C = So O = 2

Vi ^ = 2,5 -> So C = So O = 2

" A

Chon dap an B.

Cau 59:

* PhiTdng phap kinh nghiem

+ Ma„.i„ = 3ig8°_2o = 62,5

36,5

+ Goi X la amin c6 phan tijf khoi nho nhat. Theo gia thiet ta c6 X + 10.(X + 14) + 5.(X + 28) = 62,5.(1 + 10 + 5) -> X = 45

X + 10.(X + 14) + 5.(X + 28) = 62,5.(1 + 10 + 5) -> X = 45

+ Suy ra 3 amin tren la:

+ Ap dung cong thufc tinh so dong phan: T = 2 ^ 2^ + 2^ = 14 Chon dap an B.

Chon dap an B.

Bai 60:

m^Oj = 15 - 5,1 = 9,9 gam -> n^ô = 0,225 mol Suy ra m = 0,5.0,225.180.100/90 = 22,5 gam

Suy ra m = 0,5.0,225.180.100/90 = 22,5 gam

Chon dap an B.

DAP AN MA D E 115

Cau DA Cau DA Cau DA Cau DA

1 C 16 A 31 A 46 A

2 D 17 A 32 D 47 D

3 B 18 A 33 D 48 D

4 C 19 D 34 C 49 C

5 A 20 A 35 C 50 C

6 C 21 D 36 B 51 D

7 A 22 B 37 A 52 C

8 B 23 A 38

53 C

9 A 24 D 39 B 54 D

10 D 25 A 40 C 55 B

11 B 26 B 41 A 56 D

12 B 27 B 42 B 57 A

13 B 28 D 43 B 58 C

14 D 29 B 44 B 59 B

15 A 30 A 45 D 60 A

Hiidng dan gidi

Bai 1:

2CH3CH(NH3Cl)COOH +

0,1 -> 0,1 -> 0,2 Phan ling chi tao thanh H 2 O la chat khi c6 can thi bay hoti, cac chat

Phan ling chi tao thanh H 2 O la chat khi c6 can thi bay hoti, cac chat

con lai (san pham va bazcf dif) deu of dang r^n

^ mrin = m^^uiu + m„ , , o H ) , - ^ . . , 0

= 12,55 + 0,15.171 - 0,2.18 =

Chon dap an C.

Bai 4: CJiyO ^

+ ^H^O • 2

2

Theo d l : ^ = o = => = i => X chi CO thé la C H 4 O niH^o 9 9y 9 y 4